html table mixed up when echo from while loop - php

HTML Table getting mixed up when having echo in while loop. Bellow attached the output image for that. How can i get normal table with loop result? Please note i am getting table data by searching with manual date.
<?php
if (isset($_POST['submit_date'])) {
if (empty($_POST['m_date'])) {
echo '<div class="alert alert-danger">Error: Select date then search</div>';
}else{
$m_date = $_POST['m_date'];
$q = mysqli_query($conn, "SELECT * FROM bazar_dor WHERE m_date='$m_date'");
echo '<table style="width:100%">
<tr>
  <th>Category Name</th>
  <th>Price</th>
  </tr>
<tr>
';
while ($row=mysqli_fetch_array($q)) {
$cat_name = $row['cat_name'];
$price = $row['price'];
echo '<td>'.$cat_name.'</td><td>'.$price.'</td>';
}
echo '</tr></table>';
}
}
?>
the output i am getting from this code

It looks like you'll need to include table rows (<tr>) inside your loop, as well. Your current code outputs all data on the same row, which undoubtedly breaks the table.
echo '<table style="width:100%">
<tr>
<th>Category Name</th>
<th>Price</th>
</tr>';
while ($row=mysqli_fetch_array($q)) {
$cat_name = $row['cat_name'];
$price = $row['price'];
echo '<tr><td>'.$cat_name.'</td><td>'.$price.'</td></tr>';
}
echo '</table>';

Replace your cede with this
<?php if (isset($_POST['submit_date'])) { if (empty($_POST['m_date'])) { echo '<div
class="alert alert-danger">Error: Select date then search</div>'; }else{ $m_date = $_POST['m_date'];
$q = mysqli_query($conn, "SELECT * FROM bazar_dor WHERE m_date='$m_date'");
echo '<table style="width:100%"> <tr>
  <th>Category Name</th>   <th>Price</th>   </tr> ';
while ($row=mysqli_fetch_array($q)) { $cat_name = $row['cat_name'];
$price = $row['price']; echo '<tr><td>'.$cat_name.'</td><td>'.$price.'</td><\tr>';
} echo '</table>';
} } ?>

Related

Total of column in displayed result in PHP

I have a table 'tblexam' which contains State,city,candidate.I want to fetch the data from this table using where clause.I am able to fetch the data but i want to add the sum of Candidate at the last row(As Shown In Picture) how can i do that .
$sql="SELECT *
FROM tblexam
WHERE state='UP'";
$cnt=1;
if($query->rowCount() > 0)
{
foreach($results as $result) {
$cnt=$cnt+1; ?>
<tr class="odd gradeX">
<td class="center"><?php echo htmlentities($cnt);?></td>
<td class="left"align="left"><?php echo htmlentities($result->state);?></td>
<td class="center" align="left"><?php echo htmlentities($result->city);?></td>
<td class="center"align="left"><?php echo htmlentities($result->candidate);?></td>
<?php } ?>
<td class="center"align="left"><?php echo htmlentities($result->Total);?></td>
</tbody>
</table>
Add total while iterating through rows and display it outside the loop, Sample code is given below
$sql = "SELECT * FROM tblexam WHERE city='UP'";
$result = $conn->query($sql);
$numRows = $result->num_rows;
if ($numRows> 0) {
$total = 0;
echo '<table border="1" cellpadding="5" cellspacing="0">';
echo '<tr>';
echo '<th>state</th>';
echo '<th>city</th>';
echo '<th>candidate</th>';
echo '</tr>';
while($row = $result->fetch_assoc()) {
$total+=$row['candidate'];
echo '<tr>';
echo '<td>'.$row['city'].'</td>';
echo '<td>'.$row['state'].'</td>';
echo '<td>'.$row['candidate'].'</td>';
echo '</tr>';
}
echo '<tr>';
echo '<td>Total</td>';
echo '<td> </td>';
echo '<td>'.$total.'</td>';
echo '</tr>';
echo '<table>';
}
Before you start looping the data you can create a variable which you set to 0, inside the loop you can add the result's total to this variable, after the loop, the variable will contain the grand total:
$total = 0;
foreach($results as $result) {
$total += (int)$result->Total;
...
}
// $total = 1425

Display data from SQL query in an HTML table in PHP

I retrieved a list of data from an SQL database and now I would like to display it in a neat table rather than in a list. I managed to find a way to do this (probably not very elegant, though), but the column headers seem to be offset and I have not idea how to fix this.
I'm completely new to PHP, so any hints on how to solve this will be much appreciated!
echo '<table>';
echo '<tr>';
echo '<th>';
echo '<td>Word</td>';
echo '<td>Frequency</td>';
echo '</th>';
echo '</tr>';
$response = $db->query("SELECT * FROM frequencies WHERE freq BETWEEN 900 AND 910 ORDER BY freq");
while ($row = $response->fetch())
{
echo '<tr>';
echo '<td>'.$row['word'].'</td>';
echo '<td>'.$row['freq'].'</td>';
echo '</tr>';
}
echo '</table>';
$response->closeCursor();
A <th> element is a table header element and should be used instead of <td> (table data) element in your header row - it should never be a wrapper around <td> elements.
echo '<table>';
echo '<tr>';
echo '<th>Word</th>';
echo '<th>Frequency</th>';
echo '</tr>';
I prefer combining php and html
<table >
<thead>
<tr>
<th >Word</th>
<th >Frequency</th>
</tr>
</thead>
<?php
$response = $db->query("SELECT * FROM frequencies WHERE freq
BETWEEN 900 AND 910 ORDER BY freq");
?>
<tbody>
<?php
while ( $row = $response->fetch()) {
?>
<tr>
<td><?php echo $row['word']; ?></td>
<td><?php echo $row['freq']; ?></td>
</tr>
<?php }
$response->closeCursor();
?>
</tbody>
</table>

DataTable plugin not working with dynamically generated php table (arrows wouldn't show up too)

I created a table from using php and added the plugin (used demo_table.css). The arrows wouldn't show on the result page and it doesn;t apply any css.
Here is my php code:
$result = mysqli_query($link, $sql);
$num_rows = mysqli_num_rows($result);
echo '<table cellpadding = "0" cellspacing="0" border="0" id="datatables" class="display">';
echo '<thead>';
echo '<tr>';
echo '<th>SNo.</th>
<th>Username</th>
<th>Trip ID</th>
<th>Destination</th>
<th >Leave Date</th>
<th>Return Date</th>
<th>Total</th>
<th>Submit Date</th>
<th >Status</th>
<th >Reason</th>
<th >Update</th>';
echo '</tr>';
echo '</thead>';
echo '<tbody>';
} else {
echo('not valid user');
}
if (!$result) {
die(mysqli_error($link));
}
if ($num_rows<=0){
echo('not valid user');
}
elseif ($num_rows>0){
$i=1;
while($row = mysqli_fetch_assoc($result)) {
$grandtotal = $row['flight_estimate'] + $row['registration_fee'] + $row['total_cost'];
$status = $row['status'];
if(($status == 'Approved') || ($status == 'Denied')){
$newcolumn = '<td></td>';
}
else{
$newcolumn = '<td>Approve/Deny</td>';
}
echo '<tr>';
echo '<td>'. $i++ .'</td><td>'.$row['username'].'</td><td>'.$row['trip_id'].'</td><td>'.$row['destination'].'</td><td>'.date('d/m/Y',strtotime($row['leave_date'])).'</td><td >'.date('d/m/Y',strtotime($row['return_date'])).'</td><td >'. round($grandtotal,2).'</td><td >'.date('d/m/Y',strtotime($row['updateddate'])).'</td><td >'.$row['status'].'</td><td >'.$row['reason'].'</td>'.$newcolumn;
}
echo '</tr>';
echo '</tbody>';
echo '</table>';
}
?>
Is there anything that I'm missing? All it does is center all the column values. But when I click on header nothing happens.
You need to set 'bJQueryUI' to true when you init dataTable
$("#datatables").dataTable({ 'bJQueryUI' : true });
It would help if you posted your js script as that is where your problem is.

How to make 4 items in a row using while loop?

I'm trying to display my products from the database. I'm trying to split it using the if 4%=0, but I can't get it to display 4 items in a row.
Here is my codes:
<table>
<tr>
<?php
include "connect_to_mysql.php";
$split = 0;
$display_all = mysql_query("SELECT * FROM products
ORDER BY FIELD(category, 'ipad','iphone','others')");
while($row=mysql_fetch_array($display_all)) {
$id = $row['id'];
$product_code = $row['product_code'];
$title = $row['title'];
$price = $row['price'];
$split++;
if ($split%4==0){
echo '</tr><tr>';
}
?>
<td>
<table class="normal_text" align="center">
<tr>
<td><a href="product.php?product_id=<?php echo $id?>">
<img width="200px" height="133px" src="products/<?php echo $product_code?>.jpg" />
</a></td>
</tr>
<tr>
<td align="center" style="font-weight:bold"><?php echo $title;?></td>
</tr>
<tr>
<td align="center">$<?php echo $price;?></td>
</tr>
</table>
</td>
<?php
}
?>
</tr>
</table>
You've got the PHP logic before, rather than inside your HTML table output.
Try reorganizing like this:
<?php
include "connect_to_mysql.php";
$split = 0;
$display_all = mysql_query("SELECT * FROM products
ORDER BY FIELD(category, 'ipad','iphone','others')");
?>
<table class="normal_text" align="center">
<tr>
<?php
while($row=mysql_fetch_array($display_all)) {
$id = $row['id'];
$product_code = $row['product_code'];
$title = $row['title'];
$price = $row['price'];
// output product details -- note use of quotes to include PHP vars
$rowHTML = "<td><a href='product.php?product_id=$id'>";
$rowHTML .= "<img width='200px' height='133px' src='products/$product_code.jpg' />";
$rowHTML .= "</a><br/>";
$rowHTML .= "<strong>$title</strong>";
$rowHTML .= "$price</td>";
echo $rowHTML;
$split++;
if ($split%4==0){
echo '</tr><tr>';
}
}
?>
</tr>
</table>
while($row=mysql_fetch_assoc($display_all)) {
$id = $row['id'];
$product_code = $row['product_code'];
$title = $row['title'];
$price = $row['price'];
if ($split % 4 === 0) echo "\n<tr>";
?>
// ONLY <td> CODE </td> here. NO <tr> and NO </table>
<?php
if ($split % 4 === 3) echo "</tr>";
$split++;
}
?>
You are starting and ending at same time and then putting table for each.
You want to start <tr> when %4==0 and end </tr> when %4==3.
Rather than use modulus (%), just add a second variable called $cols, assign it to the amount of columns you want, and compare it. For example:
$rows = 1;
$cols = 4;
$display_all = mysql_query("SELECT * FROM products ORDER BY FIELD(category, 'ipad','iphone','others')");
while($row=mysql_fetch_array($display_all)) {
$id = $row['id'];
$product_code = $row['product_code'];
$title = $row['title'];
$price = $row['price'];
$split++;
if ($rows==$cols){
echo '</tr><tr>';
$rows = 1;
}

Got stuck with populating mysql table in html table [duplicate]

Here the value of $table will be passed from another file and it will be a table name in a database.
With that table name ($table) am trying to fetch its column names and all the values in the table and make the table look like an actual one we see in phpMyAdmin.
As a result of the code below. I can only get the column names. But not the data. Please tell me what should i do to perform the task of showing the datas in the table
<table cellpadding="0" cellspacing="0" border="0" width="100%" class="display" rel="datatable">
<thead>
<tr>
<?php
//echo"select * from $table";
$qq=mysql_query("show columns from $table");
if(mysql_num_rows($qq)>0){
//$i=1;
echo '<tr>';
while($rs = mysql_fetch_row($qq))
{
$sel=mysql_query("select * from $table");
$fetch=mysql_fetch_object($sel);
//while($fetch=mysql_fetch_object($sel))
//{
?>
<td><?php echo $fetch->$rs[0];?></td>
<?php
//}
//$i++;
}
echo '</tr>';
}
else
{
?>
<tr>
<td colspan="11">No data to display</td>
</tr>
<?php
}
?>
</tbody>
</table>
Yes only columns will be printing because you are printing $rs[0];?> where $rs holds object for mysql_query qq and it holds your column query only not
"select * from $table"
this.
Why dont you try displaying columns as a single row in html table and then try displaying data from other php set with seperate query structure .
Hope this way it helps.
I coudn't fix your code because it was getting ugly, so i remade it:
php:
function mysql_fetch_all($res) {
$result = array();
while ($row = mysql_fetch_row($res)) {
$result[] = $row;
}
return $result;
}
function getColumnsAndData($table) {
$table = mysql_real_escape_string($table);
$q1 = mysql_query("show columns from $table");
$q2 = mysql_query("select * from $table");
return array(mysql_fetch_all($q1), mysql_fetch_all($q2));
}
list($columns, $data) = getColumnsAndData($table);
?>
html
<table cellpadding="0" cellspacing="0" border="0" width="100%" class="display" rel="datatable">
<thead>
<tr>
<?php foreach ($columns as $column): ?>
<td><?php echo $column[0] . ' ' . $column[1] ?></td>
<?php endforeach; ?>
<tr>
</thead>
<tbody>
<?php if (count($data) > 0): ?>
<?php foreach ($data as $row): ?>
<tr>
<?php foreach ($row as $value): ?>
<td><?php echo $value ?></td>
<?php endforeach; ?>
<tr>
<?php endforeach; ?>
<?php else: ?>
<tr>
<td>No data to display</td>
</tr>
<?php endif; ?>
</tbody>
</table>

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