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Please help me with this SQL Query.
I have a table "objects". In that table exist field agent. On web site my agent ID is "7".
also I have array with ID's of other agents.
I want to make one SQL query to SELECT all objects FROM objects WHERE agent=7 and also I want to select objects where agent = 4, 5, 8, 9 (id's 4 5 8 9 exist in my array "IDs")
NOW I have SELECT * FROM objects WHERE agent=7 AND status='$st' ORDER BY ID DESC but it select only my objects, I need include in this request another objects of another agents by their ids
You can use IN clause to fetch all the objects
SELECT * FROM objects WHERE agent IN ('4', '5', '7','8','9')
AND status='$st' ORDER BY id DESC
After reading your question a few times to actually get somewhere, I think you are asking to get a range of agents using their IDs.
You can do that by using SQL Code like this:
SELECT * FROM objects WHERE agent IN ('4','5','7','8','9') AND status='$st' ORDER BY id DESC
You could also use WHERE agent > 4
Use below SQL Query
SELECT * FROM objects WHERE agent IN ('4', '5', '7','8','9') AND status='$st' ORDER BY id DESC
All the best!
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I am trying to fetch bulk data from a website database but could not succeed. Can somebody suggest if SQL injection is possible and how to do in this case.
There are many ways to do SQL Injection to a website similar to the one you provided.
In the where clause it is expecting ac_no. I assume that this value is being passed from the browser as user input. In that case you can pass ac_no value along with or 1 = 1. e.g where ac_no = 123 or 1 = 1. It returns everything from the table RollPdf1.
For string comparison you can add "" = "" to the where clause.
If you want to perform other select operations ( if you know other table names) then you can append select statements delmited by ;.
UNION operator :
If you know the data types of the columns selected in the query then you can use UNION to get additional data from other tables.
e.g
original query : select name, age, sex from table1 where id = 1
sql injected query : select name, age, sex from table1 where id = 1 AND 1 = 2 UNION select username, id, password from userstable or someother table.
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I want to fetch random record from the table but repeated game id record is will become out only once at a time. I am sending a screenshot of my table
You need to use MySQL RAND() function.
Query:
SELECT * FROM lessons_game ORDER BY RAND() LIMIT 1
// Put proper fields instead of *
Explanation:
ORDER BY RAND() will shuffle records random records from DB Table.
And we will get random records after we execute the query result set.
We are putting LIMIT 1 so only one record will be pulled out.
Try the following command
SELECT * FROM lessons_game ORDER BY RAND() LIMIT 1
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I have a table called ad_view and it has 18.9 million number of data inside that table.
This is the table design of ad_vew
ad_view
-------
ad_id
network_id
publisher_id
landingpage_id
advertiser_id
I am using this query to get the ad_id and the count of ad_id depending on the network_id, so in this case the network_id is 4.
select ad_id,count(ad_id) as strength
from ad_view
where network_id = 4
group by ad_id
order by strength desc
limit 10
This query takes forever to load. Do you have any suggestion how to make this query fast?
I am not a database expert, if it takes to redesign this table, I would do that.
Any suggestion will be greatly appreciated, thanks!
This will help:
ALTER TABLE ad_view ADD INDEX (network_id, ad_id).
Make sure you have tuned your innodb_buffer_pool_size to hold the frequently-requested portion of your table in memory.
You might like my presentation, How to Design Indexes, Really. That presentation doesn't go into indexing for GROUP BY, but you can think of it like a range condition.
1 Create an index on network_id since you're searching by it
ALTER TABLE `ad_view` ADD INDEX (`network_id`);
2 If you're trying to get the count of ad_id for a given network_id, why do you need ad_id in your results? and why do you need to order by? I don't understand this. If all you want is how many ad_ids for network_id 4, then do:
SELECT COUNT(IF(network_id=4,1,null)) as strength from ad_view
It will return just a number. See this demo
PS: your initial post included a broken query (in the order by clause), which you changed after I made a comment. Your current query still doesn't give you what you say you want. I just tried it on this fiddle
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Now i want like in 2015-08-04 the middle column of 2015-08-04 should be on same line order and 2015-08-05 should come down of both columns like if the both date matches they should be in same order like order by both columns its probably like ledger format my sql query
SELECT i.* , it.name AS type,td.qty AS issue, td.is_from_stock AS issue_qty_type,v.name AS vendor,o.name AS branch,td.date_from AS issue_date,l.name AS location,td.user AS user,td.remarks AS remarks, os.opening_quantity AS initial_stock,os.remaining_stock AS opening_quantity,os.opening_quantity_unit_price As opening_unit
FROM ". $this->tbl_inventories ." AS i
LEFT JOIN ". $this->tbl_inventorytypes ." AS it ON i.type_id = it.id
LEFT JOIN ". $this->tbl_distribution ." AS td ON td.item_id = i.item_id AND td.user_branch = i.user_branch
And i did like ORDER BY purchased_date,td.date_from
First of all, be bit specific on the image you have provided. I think its not possible to sort the data fetched from MySQL by the date directly as you have tried, since MySQL data output represents a single row for each set of data.
You have to breakdown to multiple query and put them in the respective arrays, so that you can filter out the data into final array i.e you have to rearange ta data into new array and display it to the table you have snapshot of.
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I'm trying to create a database that holds all my information with questions, users, answers etc.
I've been thinking all day how to solve this problem of mine. Okey, so the problem is like this:
Let's say I have a table in my DB, with questions (300++) and the user that logs on will get a random question shown. But never the same question again, so I'll need to store this information in a separate table with the user-ID and the question-ID. And I'll need to create another table that stores the answers to the questions.
So how would this PHP/MYSQL-code look like? Because I'll need to find a random question that hasnt been shown to the same user again.
If something is unclear, please let me know. And thanks in advance
You can use RAND() function and NOT IN
Example:
SELECT * FROM `questions` WHERE id NOT IN (5, 3) ORDER BY RAND() LIMIT 1;
You have to fetch question id using sub query
Example
SELECT * FROM `questions` WHERE id NOT IN (SELECT question_id FROM shown_questions WHERE user_id=1) ORDER BY RAND() LIMIT 1;
You can use an outer join to select items that have not been used already. It might be a bit faster than NOT IN if you set up the indexes:
SELECT questions.* FROM questions
LEFT JOIN shown_questions
ON (questions.id=show_questions.question AND user_id=42)
WHERE shown_questions.question IS NULL
ORDER BY RAND() LIMIT 1;