I need to replace curl with file_get_content ( I have removed sensitive informations ):
curl -F 'client_id=aaa' \
-F 'client_secret=bbb' \
-F 'grant_type=authorization_code' \
-F 'redirect_uri=http://testtest.altervista.org/instagram/' \
-F 'code=ccc' \
https://api.instagram.com/oauth/access_token
I tryed this but doens't work ( it return nothing ):
$url = 'https://api.instagram.com/oauth/access_token?client_id=aaa&client_secret=bbb&grant_type=authorization_code&redirect_uri=http://testtest.altervista.org/instagram/&code=ccc';
print json_decode(file_get_contents($url));
Why ?
Not sure why you want to change cURL to a file_get_contents, but I would at least make sure to encode the querystring you're trying to use. You could use http_build_query to get proper results
$query = array(
'client_id' => 'aaa',
'client_secret' => 'bbb',
'grant_type' => 'authorization_code',
'redirect_uri' => 'http://testtest.altervista.org/instagram/',
'code' => 'ccc
);
$domain = 'https://api.instagram.com/oauth/access_token?'
$url = $domain . http_build_query($data);
print json_decode( file_get_contents($url) );
Related
I want to pass parameters with cURL or file_get_contents and get it using argv
Using cURL
curl -X POST -H "Content-Type: application/json" -d '{"param1": "MY DATA"}' 'http://[serverIP]/file.php'
using file_get_contents
<?php
$url = 'http://[serverIP]/file.php';
$data = array('param1' => 'MY DATA');
$options = array('http' => array(
'method' => 'POST',
'content' => http_build_query($data)
));
$context = stream_context_create($options);
$result = file_get_contents($url, false, $context);
print_r($result);
and I want this data as an argument - like it should print an array of arguments like
Array
(
[0] => directory/file.php
[1] => MY DATA
)
Please Note that I can use POST/GET method for getting the data but I want to know can I use argv when using curl command or anything else similar?
I can't find the curl equivalent in php for this command
curl -F 'client_id=CLIENT_ID' \
-F 'client_secret=CLIENT_SECRET' \
-F 'grant_type=authorization_code' \
-F 'redirect_uri=AUTHORIZATION_REDIRECT_URI' \
-F 'code=CODE' \
https://api.instagram.com/oauth/access_token
I know it should start like that
$ch = curl_init('https://api.instagram.com/oauth/access_token');
curl_setopt($ch, something, ...);
...
...
One of the equivalents to
curl -F 'client_id=CLIENT_ID' \
-F 'client_secret=CLIENT_SECRET' \
-F 'grant_type=authorization_code' \
-F 'redirect_uri=AUTHORIZATION_REDIRECT_URI' \
-F 'code=CODE' \
https://api.instagram.com/oauth/access_token
would be
$url = 'https://api.instagram.com/oauth/access_token';
$fields = array(
'client_id' => 'CLIENT_ID',
'client_secret' => 'CLIENT_SECRET',
'grant_type' => 'authorization_code',
'redirect_uri' => 'AUTHORIZATION_REDIRECT_URI',
'code' => 'CODE'
);
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);
$result = curl_exec($ch);
curl_close($ch);
Hope I helped! -CM
I'm trying to figure out how to do this CURL command:
curl https://uploads.stripe.com/v1/files \
-u sk_test_OCHANGEDPcDr0: \
-F purpose=identity_document \
-F file="#/path/to/a/file.jpg"
In PHP, I'm using this PHP script:
https://github.com/php-mod/curl
And tried this:
$curl->setBasicAuthentication('-u', 'sk_live_CHANGED');
$curl->post('https://uploads.stripe.com/v1/files', array(
'purpose' => 'dispute_evidence',
'file' => $targetFile,
));
But I think the syntax is completely wrong, I'm really new to curl and don't understand what all the different -u and -F commands PHP equivalents are.
The -u username:password option translates to:
$curl->setBasicAuthentication('username', 'password');
To upload a file, you need to put # before the filename, just like in the curl command.
$curl->post('https://uploads.stripe.com/v1/files', array(
'purpose' => 'dispute_evidence',
'file' => '#' . $targetFile,
));
You'll probably want to try something like this:
$headers = array(
'Authorization: Bearer ' . $your_api_key,
'Content-Type: multipart/form-data'
);
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'https://uploads.stripe.com/v1/files',
CURLOPT_POST => true,
CURLOPT_INFILESIZE => '10000',
CURLOPT_HTTPHEADER => $headers,
CURLOPT_POSTFIELDS => array(
'purpose' => 'dispute_evidence',
'file' => '#' . realpath($path_to_file)
)
));
$resp = curl_exec($curl);
curl_close($curl);
EDIT: Alternatively, you can upload files directly from the browser like this.
If you have a functional curl command invocation, you can get what you are after by adding the --libcurl filename.c option.
This will generate a C program to do what your command line did. Though you are after PHP and not C, this is still useful because they both use the same names for various options.
I am using https://apptweak.io api,
they didn't mention PHP example in their code example...
please tell me, how to understand and write Curl API example into PHP curl
Here is simple "appteak.com" curl example
curl -G https://api.apptweak.com/ios/applications/284993459/informations.json \
-d country=us \
-d language=en \
-d device=iphone \
-H "X-Apptweak-Key: my_api_key"
Here is other example
$ curl -H "X-Apptweak-Key: my_api_key" \
https://api.apptweak.com/android/applications/com.facebook.katana.json?country=be&language=nl
How to write these curl in PHP?
i did this in php, after google, but its not work for me.
// Get cURL resource
$curl = curl_init();
// Set some options - we are passing in a useragent too here
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'https://api.apptweak.com/android/applications/com.facebook.katana.json?country=be&language=nl',
// CURLOPT_USERAGENT => 'Codular Sample cURL Request',
CURLOPT_POST => 1,
CURLOPT_POSTFIELDS => array(
'X-Apptweak-Key' => "my_api_key",
)
));
// Send the request & save response to $resp
$resp = curl_exec($curl);
// Close request to clear up some resources
curl_close($curl);
var_dump($resp ); //return false
I find correct answer
$token = "my_api_key";
$url = "http://URL.com";
$options = array('http' => array(
'header' => array("X-Apptweak-Key: $token"),
));
$context = stream_context_create($options);
$result = file_get_contents($url, 0, $context);
This is a curl request from Stripe API curl method:
curl https://api.stripe.com/v1/accounts \
-u sk_test_**********: \
-d managed=false \
-d country=US \
-d email="bob#example.com"
Right now I have this unirest code:
<?php Unirest\Request::auth(Config::get("stripe.secret.api_key"), '');
$headers = array(
"Content-Type" => "application/json"
);
$body = array(
"managed" => $_managed,
"country" => $_country,
"email" => $_email,
);
$response = Unirest\Request::post("https://api.stripe.com/v1/accounts", $headers, $body);
return array(
'status' => 'success',
'message' => $response
); ?>
Stripe returns method is wrong. I think its the -u param in curl.
I don't have much idea about Unirest. As you are facing issue with -u header, you can use the authorization parameter inside the url as below.
https://sk_test_RxRTXF1CDHuRw3ZUdynxnG6P:#api.stripe.com/v1/accounts
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^