Continue to next page when filling in right value - php

I'm making a quiz for my students. I would like to make it in such a way that you can only see question 2 after you solved question 1 (and so on).
My current idea is to make a web page for every question with a form on it:
<FORM action="test.php" method="post">
<I>12 is the right answer:</I>
<INPUT TYPE="text" NAME="name" SIZE="20" MAXLENGTH="30"><BR>
<INPUT TYPE="submit" VALUE="send">
</FORM>
And afterwards, I try to redirect from test.php to next.php whenever the answer is 12 and to current.php when the answer is not 12. Though, I am not able to make this work. Can anyone help me?

Have not written php code for a while now but will try to guide you.
No, you should not create a web page for each question. That is not a scalable approach. Imagine if you have to store 1000 questions over time,period.
Instead use dynamic page loading concept in php. Here what you should be doing:
1.Create a table in whichever database you are using with fields like
Id,question,option1,option2,option3,option4,correctAnswer
Create a php page like quiz.php which reads the question based on questionId stored in the session variable.
Lets say you show the first question in front page, displad the options and showed a submit button.
When the user clicks submit button what should happen is that the same quiz.php page will get called courtsy <form action="quiz.php"> with the user selected answer.
You can then check for the correct answer in php file since you have the correct answer stored in a variable which stores the database fetched result of first question, and if that is correct answer you can update the session with id of next question (increment by 1 or any other mechanism) and query the database table for that question id .
Your html should be written in such a way away which reads the current value stored in $row variable, which stores the result of the query w.r.t to questionId stored in session.
little bit of the code :
quiz.php file:
<?php
$con=mysql_connect($dbserver,$dbusername,$dbpassword);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($dbname, $con);
// Check user answer for previous question
if (isset($_POST['submit'])) {
if(isset($_SESSION['question_id'])){
$previous_question_id = (int) $_POST['question_id'];
// Query database
$getQuestion = "SELECT * from questions_table where id =
$previous_question_id";
$resultOfQuestion = mysqli_query($conn, $getQuestion);
$correct = $row_get_question['correctAnswer'];
$selected_radio = $_POST['answer'];
if ($selected_radio == $correct)
echo "THAT ANSWER IS CORRECT";
$_SESSION['question_id'] = $previous_question_id +1;
$getQuestion = "SELECT * from questions_table where
(id=".$_SESSION['question_id'].")";
$resultOfQuestion = mysqli_query($conn, $getQuestion);
else
echo "THAT ANSWER IS WRONG!";
}
}
if(!isset($_SESSION['question_id'])) {
$_SESSION['question_id']="0";
$getQuestion = mysql_query("SELECT * FROM questions WHERE
(id=".$_SESSION['question_id'].")";
$resultOfQuestion = mysqli_query($conn, $getQuestion);
}
echo "<form action='quiz.php' method='post'>";
while($row = mysql_fetch_array($resultOfQuestion)){
echo " <b>" . $row['question'] . "</b>";
echo "<input type='radio' value='' name='answer' checked />";
echo $row['option1']; echo "<br />";
echo "<input type='radio' value='' name='answer' />";
echo $row['option2'];echo "<br />";
echo "<input type='radio' value='' name='answer' />";
echo $row['option3'];echo "<br />";
echo "<input type='radio' value='' name='answer' />";
echo $row['option4'];echo "<br />";
echo "<input type='submit' name='next' value='next' />";
}

Related

inserting variables into php echo of a submit button

Hi I'm looking to insert a varible into a submit buttons name when I echo it via a loop so that each button has a unique name
$x=0;
$sql = "SELECT * FROM userstats ORDER BY RAND() LIMIT 5; ";
$result = mysqli_query($link,$sql);
echo ("<table>");
echo ("<tr>");
echo ("<th>Name</th>");
echo ("<th>Level</th>");
echo ("<th>Stats</th>");
echo ("<th>Win Chance</th>");
echo ("<th>Action</th>");
echo ("</tr>");
while($row = mysqli_fetch_assoc($result)){
if($row['username'] !== $_SESSION['username']){//add so it dosent put duplicates
echo("<tr>");
echo("<th>".$row['username']." </th>");
echo("<th>Level: ".$row['Level']." </th>");
echo("<th>Player Stats:".$row['Attack']."/".$row['Defence']." </th>");
echo("<th>Win Chance: ");
echo(CalculateWinChance($link,$row['Defence']));
echo("<input type='hidden' name='".$x."hidden1' value='".$row['Defence']."' />");
echo("<input type='hidden' name='".$x."hidden2' value='".$row['username']."' />");
echo("<th><input type='submit' name = 'Attack_Btn".$x."' onclick = 'BattlePlayers()' value ='Attack'></th>");
echo("</tr>");
$x=$x+1;
}
}
echo ("</table>");
I tried the above code but it does not change the name attribute? What am I doing wrong here?
you can put that as an answer can ill accept it :) – GregHBushnell
Posting from comments:
"$ is not empty its prining as expected 01234" - The leading zero is treated as an octal, that's why it's failing. . – Fred -ii
thank you very much that solved it :) what is an octal ? – GregHBushnell
References:
http://php.net/manual/en/language.types.integer.php
https://en.wikipedia.org/wiki/Octal
Footnote:
echo is a language construct and not a "function" per se. So, you can safely omit all of the (), since that's just more code than needed really.
Reference:
http://php.net/manual/en/function.echo.php

How to distribute the results retrieved from database into individual pages?

I'm facing such a problem,
I have a database bank with lots of questions and their joined answers 'multiple choice system'!
I wrote a PHP script to retrieve (15) questions each time a user enters the page, 'index.php' as a radio-buttons.
Now my bass asked me to change the method of showing the questions! so, instead of 15 questions at the same page! he asked to show one question per time, something like this:
================================================================================
1. Question TEXT:
a. 1st variant
b. 2nd variant
c. 3rd variant
d. 4th variant
<NEXT QUESTION>
================================================================================
so by clicking on the button which is a "submit" the script should redirect me to the second part of the file which must show the second question, and from the second as shown above to the third --> forth --> ... --> 15th question
================================================================================
1st question is: Correct //This part will check the correction/incorrection of the previous question -_-
2. Question2 TEXT:
a. 1st variant
b. 2nd variant
c. 3rd variant
d. 4th variant
<NEXT QUESTION>
================================================================================
bottom line, I am able to bring a 15 question on the page and after checking the answers I give the results. but I could figure out how to distribute these questions into individual pages!! as
'index.php?question=1'
'index.php?question=2'
'index.php?question=3'
...
'index.php?question=15'
Thank you guys!
so as I said, I wanted to distribute the results retrieved from one query into individual pages, and I came up with this idea,
1. Did the same query
SELECT * FROM database ORDER BY RAND() LIMIT 10
then I saved the IDz of the retrieved questions into an array just like that
$id = array();
$_SESSION[corr] = 0;
$_SESSION[incorr] = 0;
while ($row = mysql_fetch_assoc($query) {
$id[] = $row[ID];
}
Then I saved the array into a SESSION to pass it in every required page as follows
$_SESSION[ID] = $id;
after that I set a link such as
echo "<a href=test.php?question=1>Click To Start</a>";
and last but not least did something like this
if ($_REQUEST['question'] == '1') {
$id = $_SESSION['id'];
$sql = mysql_query("SELECT * FROM `test` WHERE `id` = '$id[0]'") or die("Error" .mysql_error());
$row = mysql_fetch_assoc($sql);
echo "<font color=green>Correct: " .$_SESSION[corr]. "</font></br>";
echo "<font color=red>Incorrect: " .$_SESSION[incorr]. "</font></br>";
echo "$row[v]<br>";
echo "<form action='test.php?question=2' method='POST'>";
echo "<input type=radio name=answer1 value=1>$row[o1]</input><br>";
echo "<input type=radio name=answer1 value=2>$row[o2]</input><br>";
echo "<input type=radio name=answer1 value=3>$row[o3]</input><br>";
echo "<input type=radio name=answer1 value=4>$row[o4]</input><br>";
echo "<input type=submit name=submit value=Check>";
echo "</form>";
$_SESSION['previous_id'] = $row['id'];
exit;
and in the next part "test.php?question=2"
I firstly checked if the previous question was answered correctly as the following
if ($_REQUEST['question'] == '2') {
$id = $_SESSION['id'];
$answer = $_POST['answer1'];
$grade = mysql_query("SELECT * FROM `test` WHERE `id` = {$_SESSION['previous_id']}") or die();
$right = mysql_fetch_assoc($grade);
if ($answer == $right[g]) {
$_SESSION['corr']++;
echo "<font color=green>Correct</font></br>";
}
else {
$_SESSION['incorr']++;
echo "<font color=red>Incorrect, check lesson #".$right[lvl]."</font></br>";
}
$sql = mysql_query("SELECT * FROM `test` WHERE `id` = '$id[1]'") or die("Error" .mysql_error());
$row = mysql_fetch_assoc($sql);
echo "$row[v]<br>";
echo "<form action='test.php?question=3' method='POST'>";
echo "<input type=radio name=answer2 value=1>$row[o1]</input><br>";
echo "<input type=radio name=answer2 value=2>$row[o2]</input><br>";
echo "<input type=radio name=answer2 value=3>$row[o3]</input><br>";
echo "<input type=radio name=answer2 value=4>$row[o4]</input><br>";
echo "<input type=submit name=submit value=Check>";
echo "</form>";
$_SESSION['previous_id'] = $row['id'];
exit;
}
That worked just 100% as I wanted, but it is just not feeling professional, because I had to rewrite that code, or copy and edit the same above shown codes lots of times, considering I am trying to post 10 or 15 questions separately..
hopefully that helps some one else!

The "LOGIC" in Quizes PHP+MySQL

I have a Database (MySQL) where is a table called: "dbtest" has the following fields,
id + v + o1 + o2 + o3 + o4 + g
to clarify that:
v: are the questions field
o1: the first answer
o2: the second
o3: third
o4: forth
g: is the right answer, where I put the number of the right answer for example, if I had a question with a correct answer "o3" the value of "g" should be "3"
(I did that myself thinking would be easier hopefully)
We yet did not reach the point I know, the thing is that I'm building a quiz program standing on the previous scheme, I made a page that calls the questions from the database and post them one below the other, the code was as the following:
<?php
include "config.inc";
$SQL = "SELECT * FROM test";
$query = mysql_query($SQL) or die();
echo "<form action=grade.php method=POST>";
while ($row = mysql_fetch_assoc($query)) {
echo "<p>$row[id]. ";
echo "$row[v]<br>";
echo "<input type=radio name=answer[$row[id]] value=$row[o1]>$row[o1]</input><br>";
echo "<input type=radio name=answer[$row[id]] value=$row[o2]>$row[o2]</input><br>";
echo "<input type=radio name=answer[$row[id]] value=$row[o3]>$row[o3]</input><br>";
echo "<input type=radio name=answer[$row[id]] value=$row[o4]>$row[o4]</input><br>";
}
echo "<input type=submit name=submit value=Check>";
echo "</form>";
?>
The problem is when I wanted to write the "grade.php" page I fell off an edge, I absolutely lost, I could do it if there was just one question in the database, so no need to enter a loop, but since the database is expected to receive tons of question I lost control.
I was trying something like,
<?php
include "config.inc";
$SQL = "SELECT * FROM test";
$query = mysql_query($SQL) or die();
$n = 0;
while ($row = mysql_fetch_assoc($query)) {
$n++;
$ques[$n] = $_POST['answer'];
if ($ques[$n] == $row[g]) {
echo "<font color=green>Correct</font>"; }
else {
echo "<font color=red>Incorrect<br></font>"; }
}
?>
But did not make it, all what I need is to process the questions and give right/wrong answers, for every right answer (+1) for every wrong one (-1) then I will post the sum mathematically.
In HTML your have to change radio button :
No need to add </input>,
For value you set answer number,
Add quotes for attributes
echo '<input type="radio" name="'.$answer[$row['id']].'" value="1" />'.$row['o1'].'<br>';
echo '<input type="radio" name="'.$answer[$row['id']].'" value="2" />'.$row['o2'].'<br>';
echo '<input type="radio" name="'.$answer[$row['id']].'" value="3" />'.$row['o3'].'<br>';
echo '<input type="radio" name="'.$answer[$row['id']].'" value="4" />'.$row['o4'].'<br>';
In PHP :
You create some variables to store good and bad answers,
You check if value of $row['g'] is equal to answer number
$query = mysql_query("SELECT * FROM test") or die();
$good = 0; // Number of good answers.
$bad = 0; // Number of bad answers.
while ($row = mysql_fetch_assoc($query))
{
if ( $_POST['answer'][$row['id']] == $row['g'] )
{
echo '<span style="color: green;">Correct</span>';
$good++;
}
else
{
echo '<span style="color: red;">Incorrect</span>';
$bad++;
}
}

Accessing a variable from another file in PHP, SQL

<?php
$paseoLocationTo=$_POST['locationTo'];
$paseoLocationFrom=$_POST['locationFrom'];
$PTime=$_POST['time'];
echo"The value of Location to is $paseoLocationTo </br>";
echo"The value of Location from is $paseoLocationFrom </br>";
echo"The value of time is $PTime </br>";
mysql_connect('localhost', 'root', '')
or die(mysql_error());
mysql_select_db('shuttle_service_system')
or die(mysql_error());
$TripID =mysql_query("
SELECT DISTINCT Trip_ID as 'TripID'
FROM trip
WHERE Timeslot LIKE '$PTime' AND Location_From Like '$paseoLocationFrom' AND Location_To LIKE '$paseoLocationTo'
");
echo "<form action='LastPage.php' method='post'>";
while($check = mysql_fetch_array($TripID))
**echo "<name='TripID' id='TripID'>" . $check['TripID'] . " ";**
echo "<p class='sure'> Are you sure with your reservation? </p>";
echo"<input type='submit' value='Submit' class='Log'>";
echo"</form";
?>
From another php file, this the LastPage.php
<?php
**$TripID=$_POST['TripID'];
echo"The value of trip ID is $TripID </br>";**
?>
Hi guys I was wondering why I can't access the "TripID" variable in the other php file? I was accessing it before but now there seems to be a problem, am I doing it right? I'm sorry a php and SQL newbie.
You need to add
<input type="text" name="TripID" value="'.$check['TripID'].'" ... />
in your form in order to retrieve values with $_POST['TripID'].
There is no such thing as
**echo "<name='TripID' id='TripID'>" . $check['TripID'] . " ";**
which was found in your code.
**echo "<name='TripID' id='TripID'>" . $check['TripID'] . " ";**
Looks like that should be:
echo "<input type='text' name='TripID' id='TripID' value='" . $check['TripID'] . "' />";
If you don't want it to be editable, display it then add a hidden field:
echo $check['TripID'];
echo "<input type='hidden' name='TripID' id='TripID' value='" . $check['TripID'] . "' />";
Basically, you're not putting your trip id into an actual form tag, so it's not getting posted over to your LastPage.php.
Edit: fixed the first input to wrap the tripID in the value attribute.
Replace following lines
**echo "<name='TripID' id='TripID'>" . $check['TripID'] . " ";**
with
echo "<input type="hidden" name="TripID" value="'.$check['TripID'].'" />";
So it will not be visible to user on current page but when you will post the Form, it will be available in $_POST['TripID'] variable.
One more thing your tag is not properly closed.
Use MySQLi and prepared statements to prevent SQL injection.
PS: accept the answer if its work for you.
Your form tag is not closed properly. It is now as echo </form";
It should be echo"</form>";
Also you didnt added name in input tag.
It should be
echo"<input type='submit' value="$check['TripID']" name="TripID" class='Log'>";
There is no name tag <name> but you used how?

send id of all selected option from one page to another without $_post[]

<?php
$i=1;
$ph='php';
echo "<form method=\"post\" action=\"\">";
$query=mysql_query("select question,id from ques where category=\"$ph\" order by rand() limit 5",$con);
if(!$query)
{
echo mysql_error().'query failed';
}
$ans=1;
while($value1=mysql_fetch_array($query))
{
echo "Q-$i"." ";
echo $value1['question']."<br />";
$i++;
$qno=$value1['id'];
$query1=mysql_query("select id,option1,option2,option3,option4 from ques where id=$qno");
if(!$query1)
{
echo mysql_error().'query failed';
}
while($value2=mysql_fetch_array($query1))
{
$opt=$value2['option1'];
$opt1=$value2['option2'];
$opt2=$value2['option3'];
$opt3=$value2['option4'];
$id=$value2['id'];
echo "<input type=\"radio\" value=\"$opt\" name=\"$ans\">";
echo "<span class=\"margin\">$opt</h1>";
echo "<input type=\"radio\" value=\"$opt1\" name=\"$ans\">";
echo "<span class=\"margin1\">$opt1</h2>";
echo "<input type=\"radio\" value=\"$opt2\" name=\"$ans\">";
echo "<span class=\"margin2\">$opt2</h3>";
echo "<input type=\"radio\" value=\"$opt3\" name=\"$ans\">";
echo "<span class=\"margin3\">$opt3</h4>"."<br /><br />";
$ans++;
}
}
echo"<center>"."<input type=\"submit\" name=\"submit\" value=\"submit\">"."</center>";
echo "</form>";
if(isset($_POST['submit']))
{
$correct=$_POST[1];
$_SESSION['value']=$correct;
/*$correct1=$_SESSION['value'];
echo $correct1;*/
$correct2=$_POST[2];
$_SESSION['value1']=$correct2;
/*$correct3=$_SESSION['value1'];
echo $correct3;*/
$correct4=$_POST[3];
$_SESSION['value2']=$correct4;
/*$correct5=$_SESSION['value2'];
echo $correct5;*/
$correct6=$_POST[4];
$_SESSION['value3']=$correct6;
/*$correct7=$_SESSION['value3'];
echo $correct7;*/
$correct8=$_POST[5];
$_SESSION['value4']=$correct8;
/*$correct9=$_SESSION['value4'];
echo $correct9;
$j=1;
while($j<=$i-1)
{
$correct=$_POST[$j];
$_SESSION['$j']=$correct;
$j++;
$correct1=$_SESSION['$j'];
echo $correct1."<br />";
}*/
header("location:quizresult.php");
}
?>
I don't know how to send id of selected option to the next page.I want to retrieve the id of selected option in the next page because from this i can get the correct answer of the selected question or any other solution of this and i get the only one id on the next page
There are several ways how to carry over values to the next page. I used the following successfully before:
1. Use a $_SESSION variable
Save the option values in session variables and retrieve them on the next page.
2. Use hidden form fields
You can save them as part of the form but in a hidden form field and retrieve it on the next page via $_POST.
An excellent tutorial (4 pages) for HTML forms and its various inputs is here:
http://www.javascript-coder.com/html-form/html-form-tutorial-p1.phtml
3. Use a http query
You can append a http query to your link to the next page, containing the values, i.e.
http://www.example.com/next-page?option1=value1&option2=value2
On the next page you can use parse_url($url, PHP_URL_QUERY) to extract the values. I would recommend that only if you do not submit a form though. I use this option if I create action buttons that are linking to the next (or the same) page and a single action has to be performed before the page is displayed.
Some generic info about query strings: http://en.wikipedia.org/wiki/Query_string
$qno= $_SESSION['id'] = $value1['id'];
Id is being saved in $_SESSION['id'] and will be available on the ext page also.
retrieve it like this
$id = $_SESSION['id'];

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