Echo two SQL queries in one HTML table - php

Question

I'm trying to display information from two queries in one single table, but can't figure out how to make it work.
This is what I got working with one query:
SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC;
Company Employees
ABC 45
DEF 15
GHI 5
Now beneath that I'd like to have another query that simply counts all rows, giving me the total amount of Employees.
SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC;
SELECT COUNT(*) AS Total FROM Employee_Table;
Company Employees
ABC 40
DEF 15
GHI 5
Total 60
This is what my code looks like right now. I defined two extra variables for my extra query that I want to echo out, but believe this is not the proper way to do it as I get an sqlsrv_fetch_array error.
$query1 = "SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC;";
$query2 = "SELECT COUNT(*) AS Totaal FROM Employee_Table;";
$result1 = sqlsrv_query($conn, $query1);
$result2 = sqlsrv_query($conn, $query2);
echo "<table id='total'>";
echo "<tr><th>Company</th><th>Amount of employees</th></tr>";
while ($row=sqlsrv_fetch_array($result1, $result2)) {
echo "<tr><td>";
echo $row["Company"];
echo "</td><td>";
echo $row["count"];
echo "</td><td>";
echo $row["Total"];
echo "</td></tr>";
}
echo "</table>";
How can this be achieved? I'd appreciate any help

Answer 1

First correct
sqlsrv_fetch_array()
see here http://php.net/manual/de/function.sqlsrv-fetch-array.php
Use just a single query and use mysqli_num_rows() function to count
$count = mysqli_num_rows($result);

Answer 2

I think you can achieve this by using only first query
$query1 = "SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC;";
$result1 = mysql_query($conn, $query1);
$total_employee = 0;
echo "<table id='total'>";
echo "<tr><th>Company</th><th>Amount of employees</th></tr>";
while ($row=mysql_fetch_array($result1)) {
echo "<tr><td>";
echo $row["Company"];
echo "</td><td>";
echo $row["count"];
$total_employee += $row["count"];
echo "</td><td>";
echo "</td></tr>";
}
echo "<tr><td>Total</td><td>$total_employee</td></tr>";
echo "</table>";

Answer 3

You can use only one query:
$result = sqlsrv_query($conn, "SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC");
?>
<table id='total'>
<tr><th>Company</th><th>Amount of employees</th></tr>
<?php
$total = 0;
while ($row=sqlsrv_fetch_array($result)) {
$total += $row["count"];
?>
<tr><td><?= $row["Company"] ?></td><td><?= $row["count"] ?></td></tr>
<?php
}
?>
<tr><td></td><td><?= $total ?></td></tr>
</table>
<?php

Answer 4

Try the following code
$query1 = "SELECT Company,COUNT(*) as count FROM Employee_Table GROUP BY Company ORDER BY count DESC;";
$query2 = "SELECT COUNT(*) AS Totaal FROM Employee_Table;";
$result1 = sqlsrv_query($conn, $query1);
$result2 = sqlsrv_query($conn, $query2);
echo "<table id='total'>";
echo "<tr><th>Company</th><th>Amount of employees</th></tr>";
while ($row=sqlsrv_fetch_array($result1)) {
echo "<tr><td>";
echo $row["Company"];
echo "</td><td>";
echo $row["count"];
echo "</td><td>";
echo "</td></tr>";
}
$rows = sqlsrv_fetch_array($result1)
echo "<tr><td>";
echo $rows["Total"];
echo "</td></tr>";
echo "</table>";