I have this string
NOTEBOOK > ABC
TABLET > DFG
I want to remove everything after '>' including '>'
I tried this
$category = substr($categoryGet,0,strrpos($categoryGet.">",">"));
No result so far
You can use preg_replace
$category = preg_replace('/>[^>]*$/m', '', $category);
The regular expression matches > followed by any non-> characters until the end of the line. The m modifier makes $ match the end of each line in the string.
$str="NOTEBOOK > ABC
TABLET > DFG";
$x=explode("\n",$str); //break by lines
foreach($x as $y){
$k=explode('>',$y);
echo trim($k[0]); //or that ever form you want the output to be
}
Related
[PHP]I have a variable for storing strings (a BIIGGG page source code as string), I want to echo only interesting strings (that I need to extract to use in a project, dozens of them), and they are inside the quotation marks of the tag
but I just want to capture the values that start with the letter: N (news)
[<a href="/news7044449/exclusive_news_sunday_"]
<a href="/n[ews7044449/exclusive_news_sunday_]"
that is, I think you will have to work with match using: [a href="/n]
how to do that to define that the echo will delete all the texts of the variable, showing only:
note that there are other hrefs tags with values that start with other letters, such as the letter 'P' : href="/profiles... (This does not interest me.)
$string = '</div><span class="news-hd-mark">HD</span></div><p>exclusive_news_sunday_</p><p class="metadata"><span class="bg">Czech AV<span class="mobile-hide"> - 5.4M Views</span>
- <span class="duration">7 min</span></span></p></div><script>xv.thumbs.preparenews(7044449);</script>
<div id="news_31720715" class="thumb-block "><div class="thumb-inside"><div class="thumb"><a href="/news31720715/my_sister_running_every_single_morning"><img src="https://static-hw.xnewss.com/img/lightbox/lightbox-blank.gif"';
I imagine something like this:
$removes_everything_except_values_from_the_href_tag_starting_with_the_letter_n = ('/something regex expresion I think /' or preg_match, substring?);
echo $string = str_replace($removes_everything_except_values_from_the_href_tag_starting_with_the_letter_n,'',$string);
expected output: /news7044449/exclusive_news_sunday_
NOTE: it is not essential to be through a variable, it can be from a .txt file the place where the extracts will be extracted, and not necessarily a variable.
thanks.
I believe this will help her.
<?php
$source = file_get_contents("code.html");
preg_match_all("/<a href=\"(\/n(?:.+?))\"[^>]*>/", $source, $results);
var_export( end($results) );
Step by Step Regex:
Regex Demo
Regex Debugger
To get just the links out of the $results array from Valdeir's answer:
foreach ($results as $r) {
echo $r;
// alt: to display them with an HTML break tag after each one
echo $r."<br>\n";
}
I want to remove empty quote lines at the end of a mail:
> Hello
>
> thats quotet>
>
>
to
> Hello
>
> thats quotet>
But the regex preg_replace("/^>\W*$/m", "", $input_lines) won't do the trick because it also removes the > of the empty line thats not at the end.
edit: And there is still the problem, that only > at the beginning of a line should be removed
Use rtrim, it removes specified characters from the right side of the string. We want to remove ">" and new line characters from the end.
Code:
echo rtrim($input, ">".PHP_EOL);
Result:
> Hello
>
> thats quotet
You can use:
$result = preg_replace('~^(?:^>\h*\R?)*+\z~m', '', $input_lines);
To avoid useless tests you can also try this more hand-driven pattern:
$result = preg_replace('~^(?:^>\h*\R?)*+(*SKIP)\z~m', '', $input_lines);
Very(!) new to regex but...
I have the following text strings outputted from a $title variable:
A. This is a title
B. This is another title
etc...
I'm after the following:
<span>A.</span> This is a title
<span>B.</span> This is another title
etc...
Currently I have the following code:
$title = $element['#title'];
if (preg_match("([A-Z][\.])", $title)) {
return '<li' . drupal_attributes($element['#attributes']) . ">Blarg</li>\n";
} else {
return '<li' . drupal_attributes($element['#attributes']) . '>' . $output . $sub_menu . "</li>\n";
}
This replaces anything A. through to Z. with Blarg however I'm not sure how to progress this?
In the Text Wrangler app I could wrap regex in brackets and output each argument like so:
argument 1 = \1
argument 2 = \2
etc...
I know I need to add an additional regex to grab the remainder of the text string.
Perhaps a regex guru could help and novice out!
Thanks,
Steve
Try
$title = 'A. This is a title';
$title = preg_replace('/^[A-Z]\./', '<span>$0</span>', $title);
echo $title;
// <span>A.</span> This is a title
If the string contains newlines and other titles following them, add the m modifier after the ending delimiter.
If the regex doesn't match then no replacements will be made, so there is no need for the if statement.
Is it always just 2 char ("A.", "B.", "C.",...)
because then you could work with a substring instead of regex.
Just pick of the first 2 chars of the link and wrap the span around the substring
Try this (untested):
$title = $element['#title'];
if (preg_match("/([A-Z]\.)(.*)/", $title, $matches)) {
return '<li' . drupal_attributes($element['#attributes']) . "><span>{$matches[0]</span>{$matches[1]}</li>\n";
} else {
return '<li' . drupal_attributes($element['#attributes']) . '>' . $output . $sub_menu . "</li>\n";
}
The change here was to first add / to the start and end of the string (to denote it's a regex), then remove the [ and ] around the period . because that's just a literal character on its own, then to add another grouping which will match the rest of the string. I also Added a $matches to preg_match() to place these two matches in to to use later, which we do on the next life.
Note: You could also do this instead:
$title = preg_replace('/^([A-Z]\.)/', "<span>$1</span>", $title);
This will simply replace the A-Z followed by the period at the start of the string (denoted with the ^ character) with <span>, that character (grabbed with the brackets) and </span>.
Again, that's not tested, but should give you a headstart :)
I have this:
<div> 16</div>
and I want this:
<div><span>16</span></div>
Currently, this is the only way I can make it work:
preg_replace("/(\D)(16)(\D)/", "$1<span>$2</span>$3", "<div> 16</div>")
If I leave off the $3, I get:
<div><span>16</span>/div>
Not quite sure what your after, but the following is more generic:
$value = "<div> 16 </div>";
echo(preg_replace('%(<(\D+)[^>]*>)\s*([^\s]*)\s*(</\2>)%', '\1<span>\3</span>\4', $value));
Which would result in:
<div><span>16</span></div>
Even if the value were:
<p> 16 </div>
It would result in:
<p><span>16</span></p>
I think you meant to say you're using the following:
print preg_replace("/(\\D+)(16)(\\D+)/", "$1<span>$2</span>$3", "<div>16</div>");
There's nothing wrong with that. $3 is going to contain everything matched in the second (\D+) group. If you leave it off, obviously it's not going to magically appear.
Note that your code in the question had some errors:
You need to escape your \'s in a string.
You need to use \D+ to match multiple characters.
You have a space before 16 in your string, but you're not taking this into account in your regex. I removed the space, but if you want to allow for it you should use \s* to match any number of whitespace characters.
The order of your parameters was incorrect.
Try following -
$str = "<div class=\"number\"> 16</div>";
$formatted_str = preg_replace("/(<div\b[^>]*>)(.*?)<\/div>/i", "$1<span>$2</span></div>", $s);
echo $formatted_str;
This is what ended up working the best:
preg_replace('/(<.*>)\s*('. $page . ')\s*(<.*>)/i', "$1" . '<span class="curPage">' . "$2" . '</span>' . "$3", $pagination)
What I found was that I didn't know for sure what tags would precede or follow the page number.
I need to convert single line comments (//...) to block comments (/*...*/). I have nearly accomplished this in the following code; however, I need the function to skip any single line comment is already in a block comment. Currently it matches any single line comment, even when the single line comment is in a block comment.
## Convert Single Line Comment to Block Comments
function singleLineComments( &$output ) {
$output = preg_replace_callback('#//(.*)#m',
create_function(
'$match',
'return "/* " . trim(mb_substr($match[1], 0)) . " */";'
), $output
);
}
As already mentioned, "//..." can occur inside block comments and string literals. So if you create a small "parser" with the aid f a bit of regex-trickery, you could first match either of those things (string literals or block-comments), and after that, test if "//..." is present.
Here's a small demo:
$code ='A
B
// okay!
/*
C
D
// ignore me E F G
H
*/
I
// yes!
K
L = "foo // bar // string";
done // one more!';
$regex = '#
("(?:\\.|[^\r\n\\"])*+") # group 1: matches double quoted string literals
|
(/\*[\s\S]*?\*/) # group 2: matches multi-line comment blocks
|
(//[^\r\n]*+) # group 3: matches single line comments
#x';
preg_match_all($regex, $code, $matches, PREG_SET_ORDER | PREG_OFFSET_CAPTURE);
foreach($matches as $m) {
if(isset($m[3])) {
echo "replace the string '{$m[3][0]}' starting at offset: {$m[3][1]}\n";
}
}
Which produces the following output:
replace the string '// okay!' starting at offset: 6
replace the string '// yes!' starting at offset: 56
replace the string '// one more!' starting at offset: 102
Of course, there are more string literals possible in PHP, but you get my drift, I presume.
HTH.
You could try a negative look behind: http://www.regular-expressions.info/lookaround.html
## Convert Single Line Comment to Block Comments
function sinlgeLineComments( &$output ) {
$output = preg_replace_callback('#^((?:(?!/\*).)*?)//(.*)#m',
create_function(
'$match',
'return "/* " . trim(mb_substr($match[1], 0)) . " */";'
), $output
);
}
however I worry about possible strings with // in them. like:
$x = "some string // with slashes";
Would get converted.
If your source file is PHP, you could use tokenizer to parse the file with better precision.
http://php.net/manual/en/tokenizer.examples.php
Edit:
Forgot about the fixed length, which you can overcome by nesting the expression. The above should work now. I tested it with:
$foo = "// this is foo";
sinlgeLineComments($foo);
echo $foo . "\n";
$foo2 = "/* something // this is foo2 */";
sinlgeLineComments($foo2);
echo $foo2 . "\n";
$foo3 = "the quick brown fox";
sinlgeLineComments($foo3);
echo $foo3. "\n";;