Laravel <br> to newline - php

I know I can do a simple replace when wanting to convert <br> tags to new lines. But I am facing a problem with parsing because provided <br> tags are not empty.
<br style=\"color: rgb(83, 83, 83); font-family: \" helvetica=\"\" ...
Back end is not mine, so there is no point in discussing about good or bad coding here, I am just wondering if there is a solution to replace those with simple new lines.
Something like nl2br() but reverse.
EDIT:
Don't know what use is to show code when I know 'why' is the thing that I've tried not working...but here goes
public function removeSingleHtmlFormatting($single)
{
$single->short_description = str_replace("<br>", "\r\n", $single->short_description);
$single->short_description = strip_tags($single->description);
$single->short_description = preg_replace("/ /", " ", $single->short_description);
}
Of course replace doesn't work because there is no such string to replace...I have no idea where to start parsing it

instead of
str_replace("<br>", "\r\n", $single->short_description);
try
preg_replace("/<br.*>/U", "\r\n", $single->short_description);
This way the regular expression matches <br> including anything inside it, not only empty <br>.

Related

str_ireplace or preg_replace replaced break tag into \r\n

I have read this post that discuss about converting html break tag into a new line in php. Other people said it's work for them but something weird happened to me.
this is the code I use:
$breaks = array("<br />", "<br>", "<br/>");
$jawaban = str_ireplace($breaks, "
", $jawaban1);`
and this is the code they use :
$breaks = array("<br />", "<br>", "<br/>");
$text = str_ireplace($breaks, "\r\n", $text);
both insert "\r\n" into the text , why is this happening ?
screenshot:
if there's any previous post / PHP method let me know
EDIT : adding my code that echo the textbox
<-- THIS WONT WORK -->
$username = $_SESSION['username'];
$unsafenomorsoal = $_POST['nomorsoal'];
$unsafejawaban = $_POST['jawaban'];
$nomorsoal = mysqli_real_escape_string($konek,$unsafenomorsoal);
$jawabannotcut = substr($unsafejawaban,0,50000);
$unsafejawabanfirst = nl2br($jawabannotcut);
$jawaban1 = mysqli_real_escape_string($konek,$unsafejawabanfirst);
$breaks = array("<br />","<br>","<br/>");
$jawaban = str_ireplace($breaks, PHP_EOL, $jawaban1);
$_SESSION['textvaluejawaban'] = $jawaban;
and this is what echoed :
echo "<div class=\"head-main-recent-background\" style=\"background:white;width:99%;color:black;text-align:left;height:1000px;position:relative;top:130px;margin-top:10px;\">- Jawab Soal -<br/>".$jawabanerror."<br/>Nama : ".$_SESSION['username']."<br/>
<form method=\"post\" action=\"prosesjawabsoal.php\">
<input type=\"hidden\" name=\"nomorsoal\" value=\"".$_SESSION['nomorsoal']."\"/>
Jawaban : <br/>
<textarea placeholder=\"Max 40.000 Huruf\" style=\"overflow- x:none;width:99%;height:300px;\" type=\"text\" name=\"jawaban\" maxlength=\"40000\" >".$_SESSION['textvaluejawaban']."</textarea>
<br/>Captcha <br/>
<div style=\"overflow:hidden;\" class=\"g-recaptcha\" data- sitekey=\"6LfYQicTAAAAAFstkQsUDVgQ60x_93obnKAMKIM9\"></div><br/>
<button type=\"submit\" name=\"submit\" style=\"margin-top:10px;height:auto;width:auto;\">Kirim Jawaban</button>
</form>
</div>";
Note : The snippet won't work because it's php
Sorry i used snippet due to error while posting the code !
EDIT :
tried preg_replace() method but still same result
EDIT :
change title to tell that preg_replace not work
Your problem is the mysqli_real_escape_string(). The converts the "\r\n" into a string to make it safe to input into the database. Remove it completely. Instead use htmlspecialchars when you output to screen:
echo htmlspecialchars($myUnsafeVar);
Apply these rules (as a starting point, there's always possible exceptions, but in rare cases):
use mysqli_real_escape_string when inputting strings into a database. It won't do what you expect when outputting to screen - so anything that has been mysql escaped() should not appear on screen.
use htmlspecialchars (which you don't have!) when outputting to screen.
use url_encode for adding stuff into a URL
There are also many different "escape" function (e.g. inserting into JSON, inserting into mysql, inserting into other databases). Use the right one for what you need - and don't use it for other purposes.
Check the functions for more details.
As it currently stands your code is not safe even with all those efforts - but it's really simple to fix!
try with preg_replace() function and no need of \n\r both you can do with \n or PHP_EOL only
$jawaban = preg_replace('#<br\s*?/?>#i', "\n", $jawaban1);
or
$jawaban = preg_replace('#<br\s*?/?>#i', PHP_EOL, $jawaban1);
you must knowing these before working with strings:
"\n\r" means new line.
'\n\r' doesn't mean new line.
doesn't mean new line. It's just HTML number for HTML Symbols. when you are using it, you mean just show \n\r in your browser. this is answer to your question:
both insert "\r\n" into the text , why is this happening?
so, after knowing that, you understand:
if your $jawaban1 string is
Hello <br> and welcome!
and your code is
$breaks = array("<br />", "<br>", "<br/>");
$jawaban = str_ireplace($breaks, "
", $jawaban1);
It means, $jawaban will be exactly like this:
Hello
and welcome!
without any \n\r and just your browser showing it like this:
Hello \n\r and welcome!
If you want to replace all br by \n\r just use the code in your question:
$breaks = array("<br />", "<br>", "<br/>");
$text = str_ireplace($breaks, "\r\n", $text);
About preg_replace()
When you can use str_ireplace, Don't use preg_replace. str_ireplace is faster.
Don't do it if you don't need it
in your code you did this:
$unsafejawabanfirst = nl2br($jawabannotcut);
and right after that you want to replace br with \n\r. It's like do and undo. I see that you are trying to show it again inside textarea element. so don't replace \n\r with br. the solution? don't change \n\r at all and if you want save it to the db just save it with \r\r. when you need it to show outside of textarea element just use nl2br function.
There is always something that saves my day, it is actually a workaround and your question is a trigger for me to get deeper to this matter - once for all.
For now, here you go - nice & sleek workaround:
There is already nl2br() function that replaces inserts <br> tags before new line characters:
Example (codepad):
<?php
// Won't work
$desc = 'Line one\nline two';
// Should work
$desc2 = "Line one\nline two";
echo nl2br($desc);
echo '<br/>';
echo nl2br($desc2);
?>

How to add new line in php echo

The text of story content in my database is:
I want to add\r\nnew line
(no quote)
When I use:
echo nl2br($story->getStoryContent());
to replace the \r\n with br, it doesn't work. The browser still display \r\n. When I view source, the \r\n is still there and br is nowhere to be found also. This is weird because when I test the function nl2br with simple code like:
echo nl2br("Welcome\r\nThis is my HTML document");
it does work. Would you please tell me why it didn't work? Thank you so much.
The following snippet uses a technique that you may like better, as follows:
<?php
$example = "\n\rSome Kind\r of \nText\n\n";
$replace = array("\r\n", "\n\r", "\r", "\n");
$subs = array("","","","");
$text = str_replace($replace, $subs, $example );
var_dump($text); // "Some Kind of Text"
Live demo here
I doubt that you need "\n\r" but I left it in just in case you feel it is really necessary.
This works by having an array of line termination strings to be replaced with an empty string in each case.
I found the answer is pretty simple. I simply use
$text = $this->storyContent;
$text = str_replace("\\r\\n","<br>",$text);
$text = str_replace("\\n\\r","<br>",$text);
$text = str_replace("\\r","<br>",$text);
$text = str_replace("\\n","<br>",$text);

Keep all html whitespaces in php mysql

i want to know how to keep all whitespaces of a text area in php (for send to database), and then echo then back later. I want to do it like stackoverflow does, for codes, which is the best approach?
For now i using this:
$text = str_replace(' ', '&nbs p;', $text);
It keeps the ' ' whitespaces but i won't have tested it with mysql_real_escape and other "inject prevent" methods together.
For better understanding, i want to echo later from db something like:
function jack(){
var x = "blablabla";
}
Thanks for your time.
Code Blocks
If you're trying to just recreate code blocks like:
function test($param){
return TRUE;
}
Then you should be using <pre></pre> tags in your html:
<pre>
function test($param){
return TRUE;
}
</pre>
As plain html will only show one space even if multiple spaces/newlines/tabs are present. Inside of pre tags spaces will be shown as is.
At the moment your html will look something like this:
function test($param){
return TRUE;
}
Which I would suggest isn't desirable...
Escaping
When you use mysql_real_escape you will convert newlines to plain text \n or \r\n. This means that your code would output something like:
function test($param){\n return TRUE;\n}
OR
<pre>function test($param){\n return TRUE;\n}</pre>
To get around this you have to replace the \n or \r\n strings to newline characters.
Assuming that you're going to use pre tags:
echo preg_replace('#(\\\r\\\n|\\\n)#', "\n", $escapedString);
If you want to switch to html line breaks instead you'd have to switch "\n" to <br />. If this were the case you'd also want to switch out space characters with - I suggest using the pre tags.
try this, works excellently
$string = nl2br(str_replace(" ", " ", $string));
echo "$string";

PHP textarea into database

I'm using textarea to get data that I insert into a database.
I'm using htmlspecialchars() to get rid of the single quotes and double quotes but it doesn't convert new lines into something so I'm left with a very long piece of code that doesn't have new lines and looks messy.
I've checked the manual but I can't find how to convert it.
How would I do this?
EDIT:
My intended output is the same as what the user inputted.
So if they inputted into the textarea...
Hi
This is another line
This is another line
It would store into the database like...
Hi\r\nThis is another line\r\n This is another line.
or something like that.
Then when I echo it again then it should be fine.
Anthony,
If you are referring to when you get it back out and you want it to look nice, and you aren't putting it back into a textarea, you can use the mythical function nl2br() to convert new line characters into HTML characters.
$data = 'Testing\r\nThis\r\nagain!\r\n';
echo nl2br($data);
This results in:
Testing
This
again!
I believe what you are looking for is
nl2br($string);
That will convert the returns to <br> tags
I will also give you this script that has worked well for me in the past when nl2br does not.
$remove = array("\r\n", "\n", "\r", "chr(13)", "\t", "\0", "\x0B");
$string = str_replace($order, "<br />", $string);
It should be:
<?php
addslashes( strip_tags( nl2br( $data ) ) );
?>
addslashes : will escape quotes to prevent sql injection
strip_tags : will remove any html tags if any
nl2br : will convert newline into <br />

preg_replace question

I'm trying to use preg_replace to strip out a section of code but I am having problems getting it to work right.
Code Example:
$str = '<p class="code">some string here</p>';
PHP I'm using:
$pattern = array();
$pattern[0] = '!<p class="code">!';
$pattern[1] = '!</p>!';
preg_replace($pattern,"", $str);
This strips out the code just as I want with the exception of the space between the p and class.
Returns:
some string here //notice the single space at the beginning.
I'm trying to get:
some string here //no space at the beginning.
I have been beating my head against the wall trying to find a solution. The reason I'm trying to strip it out in a chunk instead of breaking the preg_replace into pieces is because I don't want to change anything that may be in the string between the tags. Any ideas?
That does not happen for me (and it shouldn't).
It may be a space output somewhere else (use var_dump() to view the string).
You might want to look into this thread to see if you want to switch to using DOMDocument. It'll save you a great deal of headaches trying to parse through HTML.
Robust and Mature HTML Parser for PHP
test:
<?php
$str = '<p class="code">some string here</p>';
$pattern = array();
$pattern[0] = '!<p class="code">!';
$pattern[1] = '!</p>!';
$result = preg_replace($pattern,"", $str);
var_dump($result);
result:
php pregrep.php
string(16) "some string here"
seems to work just fine.
Alex I figured out where I was picking up the extra space.
I was putting that code into a text area like this:
$str = '<p class="code">some string here</p>';
$pattern = array();
$pattern[0] = '!<p class="code">!';
$pattern[1] = '!</p>!';
$strip_str = preg_replace($pattern,"", $str);
<textarea id="code_area" class="syntaxhl" name="code" cols="66" rows="5">
<?php echo $strip_str; ?>
</textarea>
This gave me my extra space but when I changed the code to:
<textarea id="code_area" class="syntaxhl" name="code" cols="66" rows="5"><?php echo $strip_str; ?></textarea>
No line spaces or breaks the extra space went away.
Why not use trim()?
$text = trim($text);
This removes white spaces around strings.

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