I am new in codeigniter. I am writing a code. AJAX response is not returning.
Here is my controller:
public function getValue()
{
$this->load->helper('url');
$data = array(
'username' => $this->input->post('username'),
'email'=>$this->input->post('email'),
'address'=>$this->input->post('address')
);
echo json_encode($data);
die;
}
and it is view code:
$( document ).ready(function() {
$('#btn_submit').on("click", function(event){
event.preventDefault();
var username = $('#username').val();
var email = $('#email').val();
var address = $('#address').val();
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>" + "index.php/MyApp/getValue",
dataType: 'json',
async:true,
crossDomain:true,
data: {username: username, email: email, address: address},
success: function ( data) {
console.log(data);
},
error: function ( data ) {
console.log('error');
}
});
});
});
I am new with codeigniter, so I don't know how to return response and work with AJAX. I have coded with the help of web but still getting errors. Please guide me how to fix this. Thanks
Simple answer remove die; from the getValue() function.
Codeigniter does not actually output anything until after the controller finishes execution. The call to die; short circuits the normal operation of the framework and so nothing gets output. In other words, echo json_encode($data); never actually happens.
Please try after setting content-type for the response like below.
header('Content-Type: application/json');
echo json_encode($data);
die;
Ajax response expects json data since your code set dataType: 'json'
Related
I need to pass a json object from JS to PHP, and it will pass, but the result is an empty array.
Ajax request in 'adopt.php':
var info = JSON.stringify(filteredArray);
$.ajax({
type: 'POST',
url: 'ajax.php',
data: {'info': info},
success: function(data){
console.log(data);
}
});
ajax.php code:
if(isset($_POST['info'])){
$_SESSION['array'] = $_POST['info'];
}
back in adopt.php, later:
if(isset($_SESSION['array'])){
$arr = $_SESSION['array'];
echo "console.log('information: ' + $arr);";
}
in both of the console.logs, it returns an empty object. Does anybody know what could be causing this? (i've tried just passing the json without stringifying it, but it throws a jquery error whenever i do this.)
Try below code i think you miss return ajax response
adopt.php
<script>
var info = JSON.stringify(filteredArray);
$.ajax({
type: 'POST',
url: 'ajax.php',
data: {info: info},
success: function(data){
console.log(data);
}
});
</script>
ajax.php
if (isset($_POST['info'])) {
$_SESSION['array'] = $_POST['info'];
echo json_encode(["result" => "success"]);
}
To get the response data from PHP, you need to echo your data to return it to the browser.
In your ajax.php:
if (isset($_POST['info'])) {
$_SESSION['array'] = $_POST['info'];
echo json_encode(['result' => $_SESSION['array']]);
}
Your ajax.php is not returning any data.To get data at the time of success you need to echo the data you want to display on success of your ajax.
First of all thanks all for your help, it's very useful. Im starting with yii and Im a bit lost yet.
I have create a jquery script where I validate a form and then I send it to my controller to work with it and save in the db.
But Im doing it wrong I think I cant connect with my controller. Here is the code:
Jquery script(after all the validate stuff, the variables are fine):
$.ajax({
type: "POST",
url: "<?php echo Yii::app()->request->baseUrl; ?>/proceso/guardarproceso",
data:
{
post_nombre: nombre,
post_empresa: empresa,
post_fechaI: fechaI,
post_fechaF: fechaF,
post_descripcion: descripcion
},
success: function(result)
{
alert(result);
}
});
And my controller ProcesoController:
public function actionGuardarProceso(){
$nombre = $_POST['post_nombre'];
$empresa = $_POST['post_empresa'];
$fechaI = $_POST['post_fechaI'];
$fechaF = $_POST['post_fechaF'];
$descripcion = $_POST['post_descripcion'];
echo $nombre;
}
Im not working with the db yet, I only want to see if I have done it well and the alert(result) shows me the content of $nombre, but instead of that the alert shows me all the html code of the view(yes all xD)
I have done it too:
public function accessRules()
{
return array(
array(
'allow',
'actions'=>array('index','guardarproceso'),
'users'=>array('*'),
),
);
}
But nothing...
Anyone cuold help me or give me some idea? Thank you all again
1st error: url: "<?php echo Yii::app()->request->baseUrl; ?>/proceso/guardarproceso",
replace guardarproceso with guardarProceso
2nd error:
$.ajax({
type: "POST",
url: url,
data: data,
success: success,
dataType: dataType
});
dataType is missing; it should be json
read here http://api.jquery.com/jquery.post/
also, in the controller action actionGuardarProceso, use:
echo json_encode(array('key'=>$nombre));
exit
If a ajax or jquery result prints the html of the page its usually a error in the url.
check your network jumps to see if it goes to the controller action you want.
also baseurl is slower than createUrl. try Yii::app()->createUrl and edit that until it goes to the correct destination.. But the base of my theory is that your url is incorrect.
$.ajax({
type: "POST",
url: "<?php echo Yii::app()->request->baseUrl; ?>/proceso/guardarproceso",
data:
{
post_nombre: nombre,
post_empresa: empresa,
post_fechaI: fechaI,
post_fechaF: fechaF,
post_descripcion: descripcion
},
success: function(result) {
alert(result);
},
error:function(jqXHR, textStatus, errorThrown){
alert('error::'+errorThrown);
}
});
first try this you will get post data or not
public function actionGuardarProceso(){
echo "<pre>";
print_r($_POST);
exit;
}
if not getting any data , try with your model
public function actionGuardarProceso(){
$model = new modelname;
echo $_POST['modelname']['post_nombre'];
exit;
}
else try with the following
public function actionGuardarProceso(){
echo Yii::app()->request->getPost("post_nombre");
exit;
}
i hope you will get now from the above any methods
I have checked around, but can't seem to figure out how this is done.
I would like to send form data to PHP to have it processed and inserted into a database (this is working).
Then I would like to send a variable ($selected_moid) back from PHP to a JavaScript function (the same one if possible) so that it can be used again.
function submit_data() {
"use strict";
$.post('insert.php', $('#formName').formSerialize());
$.get('add_host.cgi?moid='.$selected_moid.');
}
Here is my latest attempt, but still getting errors:
PHP:
$get_moid = "
SELECT ID FROM nagios.view_all_monitored_objects
WHERE CoID='$company'
AND MoTypeID='$type'
AND MoName='$name'
AND DNS='$name.$selected_shortname.mon'
AND IP='$ip'
";
while($MonitoredObjectID = mysql_fetch_row($get_moid)){
//Sets MonitoredObjectID for added/edited device.
$Response = $MonitoredObjectID;
if ($logon_choice = '1') {
$Response = $Response'&'$logon_id;
$Response = $Response'&'$logon_pwd;
}
}
echo json_encode($response);
JS:
function submit_data(action, formName) {
"use strict";
$.ajax({
cache: false,
type: 'POST',
url: 'library/plugins/' + action + '.php',
data: $('#' + formName).serialize(),
success: function (response) {
// PROCESS DATA HERE
var resp = $.parseJSON(response);
$.get('/nagios/cgi-bin/add_host.cgi', {moid: resp });
alert('success!');
},
error: function (response) {
//PROCESS HERE FOR FAILURE
alert('failure 'response);
}
});
}
I am going out on a limb on this since your question is not 100% clear. First of all, Javascript AJAX calls are asynchronous, meaning both the $.get and $.post will be call almost simultaneously.
If you are trying to get the response from one and using it in a second call, then you need to nest them in the success function. Since you are using jQuery, take a look at their API to see the arguments your AJAX call can handle (http://api.jquery.com/jQuery.post/)
$.post('insert.php', $('#formName').formSerialize(),function(data){
$.get('add_host.cgi?moid='+data);
});
In your PHP script, after you have updated the database and everything, just echo the data want. Javascript will take the text and put it in the data variable in the success function.
You need to use a callback function to get the returned value.
function submit_data(action, formName) {
"use strict";
$.post('insert.php', $('#' + formName).formSerialize(), function (selected_moid) {
$.get('add_host.cgi', {moid: selected_moid });
});
}
$("ID OF THE SUBMIT BUTTON").click(function() {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data: $("ID HERE OF THE FORM").serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
return false; //This stops the Button from Actually Preforming
});
Now for the Php
<?php
start_session(); <-- This will make it share the same Session Princables
//error check and soforth use $_POST[] to get everything
$Response = array('success'=>true, 'VAR'=>'DATA'); <--- Success
$Response = array('success'=>false, 'VAR'=>'DATA'); <--- fails
echo json_encode($Response);
?>
I forgot to Mention, this is using JavaScript/jQuery, and ajax to do this.
Example of this as a Function
Var Form_Data = THIS IS THE DATA OF THE FORM;
function YOUR FUNCTION HERE(VARS HERE) {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data:Form_Data.serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
}
Now you could use this as the Button Click which would also function :3
I have a js script that does an ajax request and posts the data to a php script, this script with then echo something back depending if it works or not.
here is the JS
$(document).ready(function(){
var post_data = [];
$('.trade_window').load('signals.php?action=init');
setInterval(function(){
post_data = [ {market_number:1, name:$('.trade_window .market_name_1').text().trim()},
{market_number:2, name:$('.trade_window .market_name_2').text().trim()}];
$.ajax({
url: 'signals.php',
type: 'POST',
contentType: 'application/json; charset=utf-8',
data:{markets:post_data},
dataType: "json",
success: function(response){
console.log("Response was " + response);
},
failure: function(result){
console.log("FAILED");
console.log(result);
}
});
}, 6000);
});
here is the php:
if(isset($_POST["json"]))
{
$json = json_decode($_POST["json"]);
if(!empty($json))
{
echo "IT WORKED!!!!";
}
else
echo "NOT POSTED";
}
So basically, i thought the response in the `success: function(response)' method would be populated with either "IT WORKED!!!" or "NOT POSTED" depending on the if statement in the php. Now everything seem to work because the js script manages to go into the success statement but prints this to the console:
Response was null
I need to be able to get the return from the server in order to update the screen.
Any ideas what I'm doing wrong?
Try:
if(isset($_POST["markets"]))
{
$json = json_decode($_POST["markets"]);
if(!empty($json))
{
echo "IT WORKED!!!!";
}
else
echo "NOT POSTED";
}
use this in your php file
if(isset($_POST["markets"]))
{
}
instead of
if(isset($_POST["json"]))
{
.
.
.
.
}
Obiously the if(isset($_POST["json"])) statement is not invoked, so neither of both echos is executed.
The fact that the function specified in .ajax success is invoked, only tells you that the http connection to the url was successful, it does not indicate successful processing of the data.
You are using "success:" wrong.
Try this instead.
$.post("signals.php", { markets: post_data }).done(function(data) {
/* This will return either "IT WORKED!!!!" or "NOT POSTED" */
alert("The response is: " + data);
});
Also have a look at the jQuery documentation.
http://api.jquery.com/jQuery.post/
Look, You send data in market variable not in json. Please change on single.php code by this.
$json_data = array();
if(isset($_POST["markets"]))
{
// $json = json_decode($_POST["markets"]);
$json = ($_POST["markets"]);
if(!empty($json))
echo "IT WORKED!!!!";
else
echo "NOT POSTED";
}
And change on your ajax function
$(document).ready(function(){
var post_data = [];
$('.trade_window').load('signals.php?action=init');
setInterval(function(){
post_data = [ {market_number:1, name:$('.trade_window .market_name_1').text().trim()},
{market_number:2, name:$('.trade_window .market_name_2').text().trim()}];
$.ajax({
url: 'signals.php',
type: 'post',
// contentType: 'application/json; charset=utf-8',
data:{markets:post_data},
dataType: "json",
success: function(response){
console.log("Response was " + response);
},
failure: function(result){
console.log("FAILED");
console.log(result);
}
});
},6000);
});
You have to you change you $.ajax call with
//below post_data array require quotes for keys like 'market_number' and update with your required data
post_data = [ {'market_number':1, 'name':'name1'},
{'market_number':2, 'name':'name2'}];
//console.log(post_data);
$.ajax({
url: "yourfile.php",
type:'post',
async: true,
data:{'markets':post_data},
dataType:'json',
success: function(data){
console.log(data);
},
});
and you php file will be
<?php
if(isset($_POST['markets']))
{
echo "It worked!!!";
}
else
{
echo "It doesn't worked!!!";
}
//if you want to work with json then below will help you
//$data = json_encode($_POST['markets']);
//print_r($data);
?>
in your php file check the $_POST:
echo(json_encode($_POST));
which will tell if your data has been posted or not and the data structure in $_POST.
I have used the following code to covert the posted data to associative array:
$post_data = json_decode(json_encode($_POST), true);
I'm using zend framework, i would like to get POST data using Jquery ajax post on a to save without refreshing the page.
//submit.js
$(function() {
$('#buttonSaveDetails').click(function (){
var details = $('textarea#details').val();
var id = $('#task_id').val();
$.ajax({
type: 'POST',
url: 'http://localhost/myproject/public/module/save',
async: false,
data: 'id=' + id + '&details=' + details,
success: function(responseText) {
//alert(responseText)
console.log(responseText);
}
});
});
});
On my controller, I just don't know how to retrieve the POST data from ajax.
public function saveAction()
{
$data = $this->_request->getPost();
echo $id = $data['id'];
echo $details = $data['details'];
//this wont work;
}
Thanks in advance.
Set $.ajax's dataType option to 'json', and modify the success callback to read from the received JSON:
$('#buttonSaveDetails').click(function (){
var details = $('textarea#details').val();
var id = $('#task_id').val();
$.ajax({
type: 'POST',
dataType: 'json',
url: 'http://localhost/myproject/public/module/save',
async: false,
// you can use an object here
data: { id: id, details: details },
success: function(json) {
console.log(json.id + ' ' + json.details);
}
});
// you might need to do this, to prevent anchors from following
// or form controls from submitting
return false;
});
And from your controller, send the data like this:
$data = $this->_request->getPost();
echo Zend_Json::encode(array('id' => $data['id'], 'details' => $data['details']));
As a closing point, make sure that automatic view rendering has been disabled, so the only output going back to the client is the JSON object.
Simplest way for getting this is:
$details=$this->getRequest()->getPost('details');
$id= $this->getRequest()->getPost('id');
Hope this will work for you.