I am writing a php script to dissect information copied from an external webpage.
I paste the external data into a text area, which is passed through PHP's post function.
One of the lines looks something like this:
972 Date Name Information
The issue is, the first space after "972" is not actually a space. When I execute the strpos function with needle " ", it returns the position of the space following "Date". Possible solutions are:
Execute strpos which searches for all possible whitespaces.
Find some way to make my browser echo out the actual whitespace code so I know what to enter for the needle.
Suggestions?
You can use Regular Expression to intercept any character that is a whitespace of any kind, plus chr(160) to intercept non-breaking space. This should work:
$str = "972 Date Name Information";
if (preg_match_all('/[\s'.chr(160).']/', $str, $matches, PREG_OFFSET_CAPTURE)) {
print_r($matches);
}
It should give you the following result:
Array
(
[0] => Array
(
[0] => Array
(
[0] => �
[1] => 3
)
[1] => Array
(
[0] =>
[1] => 8
)
[2] => Array
(
[0] =>
[1] => 13
)
)
)
where the numbers at index [1] are the positions of the various whitespace characters in the string.
Related
I am creating one regex to find words after colon in my pdftotext. i
am getting data like:
I am using this xpdf to convert uploaded pdf by user into text format.
$text1 = (new Pdf('C:\xpdf-tools-win-4.00\bin64\pdftotext.exe'))
->setPdf('path')
->setOptions(['layout', 'layout'])
->text();
$string = $text1;
$regex = '/(?<=: ).+/';
preg_match_all($regex, $string, $matches);
In ->setPdf('path') path will be path of uploaded file.
I am getting below data :
Full Name: XYZ
Nationality: Indian
Date of Birth: 1/1/1988
Permanent Residence Address:
In my Above data you can see residence address is empty.
Im writing one regex to find words after colon.
but on $matches it results only:
Current O/P:
Array
(
[0] => Array
(
[0] => xyz
[1] => Indian
[2] => 1/1/1988
)
)
It skips if regex find whitespace or empty value after colon:
I want result with empty value too in array.
Expected O/P:
Array
(
[0] => Array
(
[0] => xyz
[1] => Indian
[2] => 1/1/1988
[3] =>
)
)
Note: The OP has changed his question after several answers were given.
This is an answer to the original question.
Here is one solution, using preg_match_all. We can try matching on the following pattern:
(?<=:)[ ]*(\S*(?:[ ]+\S+)*)
This matches any amount of spaces, following a colon, the whitespace then followed by any number of words. We access the first index of the output array from preg_match_all, because we only want what was captured in the first capture group.
$input = "name: xyz\naddress: db,123,eng.\nage:\ngender: male\nother: hello world goodbye";
preg_match_all ("/(?<=:)[ ]*(\S*(?:[ ]+\S+)*)$/m", $input, $array);
print_r($array[1]);
Array
(
[0] => xyz
[1] => db,123,eng.
[2] =>
[3] => male
[4] => hello world goodbye
)
Using capture groups is a good way to go here, because the captured group, in theory, should appear in the output array, even if there is no captured term.
Your code, $regex = '/\b: \s*'\K[\w-]+/i';, ended right before \K. You have 3 quotes, and the first 2 quotes capture the pattern.
Anyways, what you can do is use groups to capture the output after the colon, including whitespace:
$regex = "^.+: (\s?.*)" should work.
I have a string like that :
0d(Hi)i(Hello)4d(who)i(where)540d(begin)i(began)
And i want to make it an array with that.
I try first to add separator, in order to use the php function explode.
;0,d(Hi),i(Hello);4,d(who),i(where);540,d(begin),i(began)
It works but the problem is I want to minimize the separator to save disk space.
Therefore i want to know by using preg_split, regular expression, if it's possible to have a huge array like that without using separator :
Array ( [0] => Array ( [0] => 0 [1] => d(hi) [2] => i(Hello) )
[1] => Array ( [0] => 4 [1] => d(who) [2] => i(where) )
[2] => Array ( [0] => 540 [1] => d(begin) [2] => i(began) )
)
I try some code & regex, but I saw that the value in the regular expression was not present in the final result (like explode function, in the final array we do not have the delimitor.)
More over, i have some difficulties to build the regex. Here is the one that I made :
$modif = preg_split("/[0-9]+(d(.+))?(i(.+))?/", $data);
I must precise that d() and i() can not be present (but at least one)
Thanks
If you do
preg_match_all('/(\d+)(d\([^()]*\))?(i\([^()]*\))?/', $subject, $result, PREG_SET_ORDER);
on your original string, then you'll get an array where
$result[$i][0]
contains the ith match (i. e. $result[0][0] would be 0d(Hi)i(Hello)) and where
$result[$i][$c]
contains the cth capturing group of the ith match (i. e. $result[0][1] is 0, $result[0][2] is d(Hi) and $result[0][2] is i(Hello)).
Is that what you wanted?
I'm trying to find all shortcodes within a string which looks like this:
[a_col] One
[/a_col]
outside
[b_col]
Two
[/b_col] [c_col] Three [/c_col]
I need the content (eg "Three") and the letter from the col (a, b or c)
Here's the expression I'm using
preg_match_all('#\[(a|b|c)_col\](.*)\[\/\1_col\]#m', $string, $hits);
but $hits contains only the last one.
The content can have any character even "[" or "]"
EDIT:
I would like to get "outside" as well which can be any string (except these cols). How can I handle that or should I parse this in a second step?
This will capture anything in the content, as well as attributes, and will allow any characters in the content.
<?php
$input = '[a_col some="thing"] One[/a_col]
[b_col] Two [/b_col]
[c_col] [Three] [/c_col] ';
preg_match_all('#\[(a|b|c)_col([^\[]*)\](.*?)\[\/\1_col\]#msi', $input, $matches);
print_r($matches);
?>
EDIT:
You may want to then trim the matches, since it appears there may be some whitespace. Alternatively, you can use regex for removing the whitespace in the content:
preg_match_all('#\[(a|b|c)_col([^\[]*)\]\s*(.*?)\s*\[\/\1_col\]#msi', $input, $matches);
OUTPUT:
Array
(
[0] => Array
(
[0] => [a_col some="thing"] One[/a_col]
[1] => [b_col] Two [/b_col]
[2] => [c_col] [Three] [/c_col]
)
[1] => Array
(
[0] => a
[1] => b
[2] => c
)
[2] => Array
(
[0] => some="thing"
[1] =>
[2] =>
)
[3] => Array
(
[0] => One
[1] => Two
[2] => [Three]
)
)
It might also be helpful to use this for capturing the attribute names and values stored in $matches[2]. Consider $atts to be the first element in $matches[2]. Of course, would iterate over the array of attributes and perform this on each.
preg_match_all('#([^="\'\s]+)[\t ]*=[\t ]*("|\')(.*?)\2#', $atts, $att_matches);
This gives an array where the names are stored in $att_matches[1] and their corresponding values are stored in $att_matches[3].
use ((.|\n)*) instead of (.*) to capture multiple lines...
<?php
$string = "
[a_col] One
[/a_col]
[b_col]
Two
[/b_col] [c_col] Three [/c_col]";
preg_match_all('#\[(a|b|c)_col\]((.|\n)*)\[\/\1_col\]#m', $string, $hits);
echo "<textarea style='width:90%;height:90%;'>";
print_r($hits);
echo "</textarea>";
?>
I don't have an environment I can test with here but you could use a look behind and look ahead assertion and a back reference to match tags around the content. Something like this.
(?<=\[(\w)\]).*(?=\[\/\1\])
I am fairly new to regexp and have encountered a regexp that delivers an unexpected result, when trying to match name parts in name of the form firstname-fristname firstname:
preg_match_all('/([^- ])*/i', 'aNNA-äöå Åsa', $result);
gives a print_r($result) that looks like this:
Array
(
[0] => Array
(
[0] => aNNA
[1] =>
[2] => äöå
[3] =>
[4] => Åsa
[5] =>
)
[1] => Array
(
[0] => A
[1] =>
[2] => å
[3] =>
[4] => a
[5] =>
)
)
Now the $result[0] has the items I would want and expect as result, but where the heck do the $results[1] come from - I see it's the word endings, but how come they are matched?
And as a little side question, how do I prevent the empty matches ($results[0][1], $results[0][3], ...), or better even: Why do they show up - they are not not- or not-space either?
Have a try with:
preg_match_all('/([^- ]+)/', 'aNNA-äöå Åsa', $result);
Your regex:
/([^- ])*/i
means: find one char that is not ^ or space and keep it in a group 0 or more times
This one:
/([^- ]+)/
means: find one or more char that is not ^ or space and keep it in a group
Moreover, there's no need for case insensitive.
The * means "0 or more of the preceding." Since a "-" is exactly 0 of the the character class, it is matched. However, since it is omitted from the character class, the capture fails to grab anything, leaving you an empty entry. The expression giving you the expected behavior would be:
preg_match_all('/([^- ])+/i', 'aNNA-äöå Åsa', $result);
("+" means "1 or more of the preceding.")
http://php.net/manual/en/function.preg-match-all.php says:
Orders results so that $matches[0] is an array of full pattern
matches, $matches[1] is an array of strings matched by the first
parenthesized subpattern, and so on.
Check the URL for more details
Note: See the bottom of this post for an explanation for why this wasn't originally working.
In PHP, I am attempting to match lower-case characters at the end of every line in a string buffer.
The regex pattern should be [a-z]$. But that only matches the last letter of the string. I believe this a regex modifier issue; I have experimented with /s /m /D, but nothing appears to match as expected.
<?php
$pattern = '/[a-z]$/';
$string = "this
is
a
broken
sentence";
preg_match_all($pattern, $string, $matches);
print_r($matches);
?>
Here's the output:
Array
(
[0] => Array
(
[0] => e
)
)
Here's what I expect the output to be:
Array (
[0] => Array (
[0] => s
[1] => s
[2] => a
[3] => n
[4] => e
)
)
Any advice?
Update: The PHP source code was written on a Windows machine; text editors in Windows, by convention, represent newlines differently than text editors on Unix system.
It appears that the byte-code representation of Windows text files (inheriting from DOS) was not respected by the PHP regex engine. Converting the end-of-line byte-code format to Unix solved the original problem.
Adam Wagner (see below) has posted a pattern that matches regardless of end-of-line byte-representation.
zerkms has the canonical regular expression, to which I am awarding the answer.
$pattern = '/[a-z]$/m';
$string = "this
is
a
broken
sentence";
preg_match_all($pattern, $string, $matches);
print_r($matches);
http://ideone.com/XkeD2
This will return exactly what you want
As #Will points out, it appears you either want the first char of each string, or your example is wrong. If you want the last char of each line (only if it's a lower-case char) you could try this:
/[a-z](?:\n)|[a-z]$/
The first segment [a-z](?:\n), checks to for lowercase chars before newlines. Then [a-z]$ get the last char of the string (in-case it's not followed by a newline.
With your example string, the output is:
Array
(
[0] => Array
(
[0] => s
[1] => a
[2] => n
[3] => e
)
)
Note - The 's' from 'is' is not present because it is followed by a space. To capture this 's' as well (ignoring trailing spaces), you can update the regex to: /[a-z](?:[ ]*\n)|[a-z](?:[ ]*)$/, which checks for 0 or more spaces immediately before the newline (or end of string). Which outputs:
Array
(
[0] => Array
(
[0] => s
[1] => s
[2] => a
[3] => n
[4] => e
)
)
Update
It appears the line-ending style wasn't liking your regex. To account for crazy line-endings (an other unsavory white-space at the end of the lines), you can use this (and still get the /m goodness).
/[a-z](?:\W*)$/m
It looks like you want to match before every newline, not at the end of the file. Perhaps you want
$pattern = '/[a-z]\n/';