select all from two tables with sum cost - php

I try to select all from 2 tables in mysql database with the sum of total cost in the second table
i have a table name tbl_project contain
db_id db_projectname and other column
1 test
2 test2
3 test3
second table name tbl_activities contain
db_id db_projectname db_totalcost
1 test 200
2 test 300
3 test2 800
the out put i want is
test 500
test2 800
test3
i try this query but it didn't give me that result
select tbl_project.db_id, tbl_project.db_projectname,tbl_project.db_location,tbl_project.db_client,tbl_project.db_transferredto,tbl_project.db_psd,tbl_project.db_pdd,tbl_project.db_duration,tbl_project.db_past,tbl_project.db_padd,tbl_project.db_aduration,tbl_project.db_percent,tbl_project.db_pnote,tbl_project.db_user,tbl_project.db_cpercentage,tbl_project.db_epercentage,tbl_project.db_mpercentage,tbl_project.db_status,tbl_project.db_offer,tbl_project.db_sheet,tbl_project.db_invoice,tbl_project.db_po,sum(tbl_activities.db_totalcost) as total_cost from tbl_project,tbl_activities where
tbl_project.db_projectname=tbl_activities.db_projectname
it give me
test but sum of another project and only one project not all

You needed to use LEFT JOIN & GROUP BY
SELECT
tbl_project.db_id,
tbl_project.db_projectname,
tbl_project.db_location,
tbl_project.db_client,
tbl_project.db_transferredto,
tbl_project.db_psd,
tbl_project.db_pdd,
tbl_project.db_duration,
tbl_project.db_past,
tbl_project.db_padd,
tbl_project.db_aduration,
tbl_project.db_percent,
tbl_project.db_pnote,
tbl_project.db_user,
tbl_project.db_cpercentage,
tbl_project.db_epercentage,
tbl_project.db_mpercentage,
tbl_project.db_status,
tbl_project.db_offer,
tbl_project.db_sheet,
tbl_project.db_invoice,
tbl_project.db_po,
sum(
tbl_activities.db_totalcost
) AS total_cost
FROM
tbl_project
LEFT JOIN tbl_activities ON tbl_project.db_projectname = tbl_activities.db_projectname
GROUP BY tbl_project.db_id
Note:
Using aggregate function (e.g. SUM,COUNT..) without GROUP BY collapses the result set into a single row.

try this;
SELECT
db_projectname.db_projectname,SUM(tbl_activities.db_totalcost) AS total_cost
FROM db_projectname
LEFT JOIN tbl_activities
ON
db_projectname.db_projectname = tbl_activities.db_projectname
GROUP BY db_projectname.db_projectname

Related

Get records in two lines with mysql

I have some data in multiple tables i want to join that tables and need to display the result as multiple records below is the table structure
main_table
id name height
1 test1 5.2
2 test2 4.6
child_table
id main_table_id name height
1 1 test3 5.3
2 1 test4 4.5
expecting result like
id name height
1 test1 5.2
1 test3 5.3
1 test4 4.5
How can i achive this using query in MySql expecting suggestions how can i achieve this?
Use UNION
SELECT id, name, height
FROM main_table
WHERE id = 1
UNION
SELECT main_table_id as id, name, height
FROM child_table
WHERE main_table_id = 1
Try using left and colasce
select maintable.id,COALESCE(maintable.name,childtable.name) as name,
COALESCE(maintable.height,childtable.height)
from maintable left join childtable
on maintable.id=childtable.main_table_id
where maintable.id=1

How to sum a column with a foreign value selecting by id

I've a table syntax like this,
- table1
id foreign_table_id
-----------------------
1 2
2 2
3 2
4 1
5 1
6 1
The other table is,
- table2
id value
------------
1 20
2 10
I want to get a summation of table1.foreign_table_id where the data will retrieve from table2.
Like this example should produce the result 90
Please provide any solution.
Use below query.
Select sum(table2.value) as total FROM table1 LEFT JOIN table2 ON table1.foreign_table_id = table2.id
It will give u below result.
Output::
total
-----
90
SELECT SUM(table2.value) AS summation FROM table1 LEFT JOIN table2
ON table2.id = table1.foreign_table_id

Select from three tables

I have three tables where table_2 is the middle(connected) between table_1 and table_3
tables
table_id
...
...
table_rest
rest_id
table_id
...
rest
rest_id
...
...
And the query to select I use
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
WHERE rest_id = '$rest_id'
What I need now is to join in this query another table reserv
id
...
status
To check if status is 0, 1,or 2 to not show me anything if there is no status this mean there is no record to show me. In other words this is resserved system where I show on screen few tables. If status is 0,1,2 thats mean the table is taken. If nothing is found for status this mean that there is no record for table and can be shown to user.
EDIT: Sample scenario
tables
table_id
1
2
3
4
5
rest
rest_id
1
2
table_rest
table_id | rest_id
1 2
2 2
3 2
4 2
5 2
So the query that is above will generate 5 tables for rest_id=2 and none for rest_id=1
So now I have another table
reserv
id | status
1 0
2 1
3 2
So in this table reserv currently are saved 3 tables. The idea is to show me other two whit id=4 and id=5 because they are not in table reserv and don't have any status.
Hope is a little bit more clear now.
You have to point from table reserv to which table is beign booked, let's call it reserv.table_id
SELECT m.table_id, table_name
FROM tables m
JOIN table_rest mr
ON m.table_id = mr.table_id
left join reserv
on reserv.table_id = m.id
WHERE rest_id = '$rest_id'
and reserv.status is null (*note)
*note use 'is' or 'is not' depending of your needs, as far as I read, first seems that you want !=, later that what you want is =
It's better if you provide sample data or sqlfiddle. Based on what I realize: Is this what you want:
select tables.table_id, rest.rest_id
from tables
left join table_rest on table_rest.table_id = tables.table_id
left join rest on rest.rest_id = table_rest.rest_id
where rest.rest_id = '$rest_id'
and tables.table_id not in (select id from reserv)

Selecting rows on Unique Pairs of columns from mysql Table

I have a Table table .
Now this has three columns table_id,content_id,content_type
What i want is to SELECT rows based on unique pairs of columns.
Say For example i have rows like this-->
id|content_id|content_type|
1 1 shirt
2 1 trouser
3 4 skirt
4 4 shirt
5 3 trouser
6 5 jeans
7 1 trouser
8 5 jeans
I want a query which selects Rows with id->1,2,3,4,5,6.
Rows with id->7,8 are not to be selected
Therefore it concludes that i dont want to select complete Duplicates of Rows
You can use a self join to pick a minimum row per group
select t.* from
test t
join (
select min(id) id ,content_id,content_type
from test
group by content_id,content_type
) t1
on(t.id = t1.id
and t.content_id = t1.content_id
and t.content_type = t1.content_type)
Demo
or if there are only these 3 columns in your table then you can simply use min()
select min(id) id ,content_id,content_type
from test
group by content_id,content_type
Demo
This is mysql-specific : If you use the GROUP BY function without using aggregate functions, the group by clause will behave as distinct, and pick up the first distinct row.
select id, content_id, content_type from test group by content_id, content_type order by id
Demo

Fetch data from mapping table if the condition matches in multiple rows

product_id property_id
1 2
1 5
2 2
3 5
I have a mapping table as above. I want to get only product with id =1 if product_id in (2,5). i.e. I want to fetch data if the table contains both 2,5 not the data if it is with property_id only 2 or 5
select group_concat(distinct product_id) product_ids from table where property_id in (2,5)
UPDATE:
The property_id in can be property_id in(2,5,....). I get output from form as 2,5,.... and so on. Its not just for the single case. I just want the output if the condition in property_id in matches the whole series.
This how it could be done
select
product_id from
table_name
where property_id in (2,5)
group by product_id
having count(*) = 2
All you need to change having count(*) = 2 to the number of items inside IN() , right now its 2 and if you are looking at 3 property id then it will be 3 and so on.
select distinct a.product_id
from table a, table b
where a.product_id = b.product_id
and a.property_id = 2
and b.property_id = 5

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