how do i merge array values into single array? - php

Question

I am trying to add(string) array values into single array, I have three array values like below:
Array ( [0] => 15 [1] => 16 )
Array ( [0] => jan [1] => feb )
Array ( [0] => 2012 [1] => 2012 )
and now i want those array in single array like below:
Array ( [0] => 15-jan-2012 [1] => 16-feb-2012 )
So how can i do this in php.

Answer 1

You need this custom code: Too simple, just a loop to access each and every array with there index and store in an array.
$d = array(15, 16);
$m = array("jan", "feb");
$y = array (2012, 2012);
$final = array();
for($i = 0; $i < count($d); $i++){
$final[] = $d[$i]. "-" .$m[$i]. "-" .$y[$i];
}
print_r($final);
Output:
Array ( [0] => 15-jan-2012 [1] => 16-feb-2012 )
you can do it using, array_merge_recursive, but has some difficulties.
ONLINE DEMO

Answer 2

Quick and dirty way, I am supposing that your each array has same length
$a = array ('15','16' );
$b = array ('jan','feb');
$c = array ('2012','2012');
$newArray = array();
for($i=0;$i<=count($a);$i++){
$newArray = $a[$i]. "-" .$b[$i]. "-" .$c[$i];
}
echo '<pre>';
print_r($newArray);
echo '</pre>';

Answer 3

You need a custom code like this one for example:
$arr = [];
$arr1 = [15, 16, 17, ...];
$arr2 = [jan, feb, ...];
$arr3 = [2012, 2012, ...];
for($i=0, $count = count($arr1); i<$count; i++)
{
$arr[] = "$arr1[$i]-arr2[$i]-arr3[$i]";
}
var_dump($arr);

Answer 4

Use array_column to get the required dates array, finally concat it using implode. Something like
$arr1 = array(15, 16);
$arr2 = array('jan', 'feb');
$arr3 = array(2012, 2012);
$date = array($arr1, $arr2, $arr3);
$dates = array(array_column($date, 0), array_column($date, 1));
$reqDate = array();
foreach ($dates as $dateVal) {
$reqDate[] = implode('-', $dateVal);
}
var_dump($reqDate); //your required output

Answer 5

You can write it all in one swoop like so:
$a = [15, 16];
$b = ['jan', 'feb'];
$c = [2012, 2012];
$dates = array_map(function($arr) {
return implode('-', $arr);
}, array_map(null, $a, $b, $c)));