Prints only one value from the record [duplicate] - php

Question

This question already has answers here:
MySQLi query returns only one row
(3 answers)
Closed 6 years ago.
Here, I want to print those value which are in table.
So, my query is like this:
$get_role_query = "SELECT id FROM table WHERE id IN (333,1,2)";
$roleres = mysqli_query($conn,$get_role_query);
$r_id = mysqli_fetch_assoc($roleres);
Here, 333 is not in table but 1 and 2 are in table.
When I am printing this like,
print_r($r_id);
It only gives me 1 but not getting 2 which is also in table. I don't want 333 that is fine. But I am getting only 1, not getting 2.
UPDATED BELOW:
As you all suggest to use while loop, I did like this:
$r_role = mysqli_num_rows($roleres);
for($i=0;$i<=$r_role;$i++)
{
print_r($r_id);
}
But I am getting output like this:
Array
(
[id] => 1
)
Array
(
[id] => 1
)
Array
(
[id] => 1
)
From above query, I just want output like,
Array
(
[0] => 1
[1] => 2
)
Any suggestion would be appreciated.
Thanks.

Answer 1

Use while in order to fetch multiple values from the table:
$get_role_query = "SELECT id FROM table WHERE id IN (333,1,2)";
$roleres = mysqli_query($conn,$get_role_query);
while($r_id = mysqli_fetch_assoc($roleres))
{
echo $r_id['id'];
}

Answer 2

You can also use an object method instead array method.
$get_role_query = "SELECT id FROM table WHERE id IN (333,1,2)";
if ($result = $mysqli->query($get_role_query)) {
/* fetch object array */
while ($obj = $result->fetch_object()) {
echo $obj->id;
}
}
/* free result set */
$result->close();

Answer 3

You are not using mysqli_fetch_assoc() correctly. It fetches one record at a time. Use it as follows:
while($r_id = mysqli_fetch_assoc($roleres))
{
print_r($r_id);
}