CakePHP 3 Custom Route in Pagination - php

in my routes file i define a route for my controller method
$routes->connect('/category/:cat', ['controller' => 'Categories', 'action' => 'category']);
My controller method is this
public function category(){
$this->paginate = [
'limit' => 2
];
$this->viewBuilder()->layout('newLayout');
$cat = $this->request->params['cat'];
$id = $this->Categories->findBySlug($cat)->select(['id'])->hydrate(false)->toArray();
$cid = $id[0]['id'];
$category = $this->ProductCategories
->find("all")
->select(['id', 'category_id'])
->where(["category_id" => $cid])
->contain(['Products' => function($q){
return $q->select(['id', 'sku', 'product', 'description', 'slug', 'price', 'off', 'stock', 'product_category_id'])
->where(['status' => 1])
->contain(['ProductImages' => function($q){
return $q->select(['product_id','url']);
}]);
}])->hydrate(false);
$categories = $this->paginate($category);
$this->set(compact('categories'));
$this->set('_serialize', ['categories']);
}
And my url look like this:
http://localhost/mizzoli.com/category/Designer-Saree
Now when i click on cake pagination url change to this
http://localhost/mizzoli.com/categories/category?page=2
But actual url i want is like this
http://localhost/mizzoli.com/category/Designer-Saree?page=2
And also i need to pass some extra parameter with pagination url like color, occasion etc. Please help me to get this. I did not find any solution.

I had a similar issue and resolved it by passing the param I needed inside the third parameter of the route definition. Like this:
$routes->connect('/category/:cat', ['controller' => 'Categories', 'action' => 'category'], ['pass' => ['cat']]);
I have #littleylv from the #cakephp IRC channel on Freenode to thank for this solution.
You can read more about passing parameters to actions via routes here: https://book.cakephp.org/3.0/en/development/routing.html#passing-parameters-to-action

Related

Laravel 5 named route with parameter

I'm pretty new on laravel5 and I'm trying to generate dynamically route alias under route.php
This is it:
Route::get('/menu/{category}/{product}/{item}', 'MenuController#listItem')->name('/{category}/{item}');
I already tried with with 'as' and 'uses' and I'm still getting:
/menu/{category}/{product}/{item}
With all parameters replaced by the correct values instead of:
/{category}/{item}
Expounding on what Vinicius Luiz said.
Route::get('/menu/{category}/{product}/{item}', ['as' => 'named.route' , 'uses' => 'MenuController#listItem']);
// to get the actual linke
route('named.route', ['category' => $category->id, 'product' => $product->id, 'item' => $item->id]);
depending, you may not do ->id or anything, you might just pass the whole $category, $product, etc. Depends on how the routing in your controllers is setup.
EDIT:
From your comment, it likes like you want something like:
class MenuController {
public function lisItem($category_name, $product_name) {
$category = Category::where('name', $category_name)->first(['id']);
$product = Product::where('category_id', $category->id)->where('name', $product_name')->first();
}
}
Route::get('/{category}/{item}', ['as' => 'named.route' , 'uses' => 'MenuController#listItem']);
// to get the actual linke
route('named.route', ['category' => $category->id, 'item' => $item->id]);
there is probably a better way to do the queries, but that should work for you.
Try it:
Route::get('/menu/{category}/{product}/{item}', ['as' => 'a.name.to.your.route' , 'uses' => 'MenuController#listItem']);

Routes pagination Cakephp 3

I'm using CakePHP 3 and I want to paginate my users.
However when I click on the second page, the URL looks like /users?page=2 and I expect : /users/2.
I created this route in routes.php :
$routes->connect('/users/:page', ['controller' => 'users', 'action' => 'index'], ['page' => '[0-9]+']);
And in Users/index.ctp before the "prev" button I put :
<?php
$this->Paginator->options([
'url' => [
'controller' => 'users',
'action' => 'index'
]
]);
?>
Now when I click on page 2 for example, /users/2 opens and I got this error message (RuntimeException) :
Unable to locate an object compatible with paginate.
Did I miss something or where I made a mistake ?
Thanks for your help.
The PaginatorHelper has built in the url format, i.e. to use ?page=n. It will also do sorting such as users?page=2&sort=user_id&direction=asc. Your format of /users/{page} does not handle sorting.
If your REALLY want to stick to /users/{page} you'll have to override PaginatorHelper.
try this
in side your controller with paginator component . It works for me
$this->Paginator->paginate('Users')
for custom urlenter code here
u need to implement index action as
public function index($page = null){
$this->Paginator->settings = ['limit' => 15, 'page' => $page];
$this->set('users', $this->Paginator->paginate('Users'));
}

CakePHP friendly seo url

I want to make my url seo friendly. www.example.com/posts/view/1 change for www.example.pl/:slug-:id. Everything works fine, but probably I'm doing something wrong with routing, because when after clicking the urls in paginator, the url is correct, it looks like www.example.pl/:slug-:id , but it appears an error
"The requested address 'www.example.pl/:slug-:id' was not found on this server."
I don't know what's wrong. Here's my code:
Router::connect(
'/:slug-:id',
array(
'controller' => 'posts',
'action' => 'view'
),
array(
'pass' => array('slug' , 'id'),
'id' => '[0-9]+'
)
);
in paginator view:
echo $this->Html->link($ad['Post']['title'], array(
'controller' => 'posts',
'action' => 'view',
'slug' => Inflector::slug($post['Post']['title'],'-'),
'id'=>$post['Post']['id'])
);
I solved the problem.
Its too simple i'll give you an example from my project ..
in your routes.php
Router::connect(
'/:slug-:id',
array('controller'=>'posts','action'=>'view'),
array('pass'=>array('slug','id'),'slug'=>'[a-zA-Z0-9 -]+','id'=>'[0-9]+')
);
your link in views should be like .
$this->Html->link(__('link desu'),array('controller'=>'posts','action'=>'view','id'=>$post['Post']['id'],'slug'=>$post['Post']['slug']));
and your PostsController.php
public function view($slug,$id){
$this->Post->id = $id;
// ....
}
Quick tip : try to create an array in your PostModel to avoid creating it every time in your view .
example :
Post.php
class Post extends AppModel{
// ....
public function afterFind($results,$primary = false){
foreach ($results as $key => $value) {
if(isset($value[$this->alias]['id'])){
$results[$key][$this->alias]['url'] = array(
'controller'=>'posts',
'action'=>'view',
'id'=>$results[$key][$this->alias]['id'],
'slug'=>$results[$key][$this->alias]['slug']
);
}
// ....
}
return $results;
}
}
}
so you can call it in your view simply like that
$this->Html->link(__('link desu'),$post['Post']['url']);
It's probably a problem with the regex on the route. Your slug contain hyphens - which you also use to separate between the slug and the id. i.e.:
example.com/my-slug-has-hyphens-1
The regex is not smart enough to know that the "last" hyphen separates the slug from the id.
To test if this is the problem, try using a route like this '/:slug__:id', just to see if it works.
I solved the problem. In the posts controller my view function was wrong. Here's right correct:
function view($id = null, $slug = null) {
$this->Post->id = $this->params['post'];
$this->set('post', $this->Post->read());
Pass is order sensitive
In the question the route is as follows:
Router::connect(
'/:slug-:id',
array(
'controller' => 'posts',
'action' => 'view'
),
array(
'pass' => array('slug' , 'id'), # <-
'id' => '[0-9]+'
)
);
That means the post function will recieve:
public function view($slug, $id)
As indicated by the edited question, the code is expecting the id to be the first parameter. The easiest solution is simply to specify the passed parameters in the order that they are expected:
...
'pass' => array('id', 'slug'), # <-
Router::connect(
'/:slug/:id',
array(
'controller' => 'posts',
'action' => 'view'
),
array(
'pass' => array('slug' , 'id'),
'id' => '[0-9]+'
)
);
the above code will create correct link as www.example.com/posts/view/title/1
echo $this->Html->link($post['Post']['title'], array('controller' => 'posts', 'action' => 'view', Inflector::slug($post['Post']['title'],'-'),$post['Post']['id']));

CakePHP: Can I Promote active router with Router::promote or some other way?

I've got two or more routes that will be going to the same controller and action. This is fine until I want to use a helper such as the form helper or pagination on the page.
What happens is that the current url changes to whatever is declared first in my routes.php file.
I see there is a way to promote a router with Router::promote but I'm not sure if I can do it based on the current url or router being used or if there's a bett way to do this.
Here's an example of what my router.php looks like:
Router::connect('/cars-for-sale/results/*', array('controller' => 'listings', 'action' => 'results'));
Router::connect('/new-cars/results/*', array('controller' => 'listings', 'action' => 'results'));
Router::connect('/used-cars/results/*', array('controller' => 'listings', 'action' => 'results'));
Let's say for example that I'm at the url domain.com/used-cars/results/ and I'm using the form helper or pagination helper, the url that is being put in the action or href is domain.com/cars-for-sale/results/.
Any help or info would be appreciated.
Routes should be unique and identifiable!
The problem with these Routes is that, basically, you created duplicate URLs not only does this cause problems with CakePHP picking the right route, Google doesn't like that as well; duplicated content will have a negative effect on your SEO ranking!
In order to pick the right URL (Route), CakePHP should be able to do so, based on its parameters; your current Routes do not offer any way to distinguish them.
And neither does your application!
All these URLs will present the same data;
/cars-for-sale/results/
/new-cars/results/
/used-cars/results/
Solution 1 - separate actions
If your application is limited to these three categories, the easiest solution is to create three actions, one per category;
Controller:
class ListingsController extends AppController
{
const CATEGORY_NEW = 1;
const CATEGORY_USED = 2;
const CATEGORY_FOR_SALE = 3;
public $uses = array('Car');
public function forSaleCars()
{
$this->set('cars', $this->Paginator->paginate('Car', array('Car.category_id' => self::CATEGORY_FOR_SALE)));
}
public function newCars()
{
$this->set('cars', $this->Paginator->paginate('Car', array('Car.category_id' => self::CATEGORY_NEW)));
}
public function usedCars()
{
$this->set('cars', $this->Paginator->paginate('Car', array('Car.category_id' => self::CATEGORY_USED)));
}
}
Routes.php
Router::connect(
'/cars-for-sale/results/*',
array('controller' => 'listings', 'action' => 'forSaleCars')
);
Router::connect(
'/new-cars/results/*',
array('controller' => 'listings', 'action' => 'newCars')
);
Router::connect(
'/used-cars/results/*',
array('controller' => 'listings', 'action' => 'usedCars')
);
Solution 2 - Pass the 'category' as parameter
If the list of URLs to be used for the 'listings' will not be fixed and will expand, it may be better to pass the 'filter' as a parameter and include that in your routes;
routes.php
Router::connect(
'/:category/results/*',
array(
'controller' => 'listings',
'action' => 'results',
),
array(
// category: lowercase alphanumeric and dashes, but NO leading/trailing dash
'category' => '[a-z0-9]{1}([a-z0-9\-]{2,}[a-z0-9]{1})?',
// Mark category as 'persistent' so that the Html/PaginatorHelper
// will automatically use the current category to generate links
'persist' => array('category'),
// pass the category as parameter for the 'results' action
'pass' => array('category'),
)
);
Read about the Router API
In your controller:
class ListingsController extends AppController
{
public $uses = array('Car');
/**
* Shows results for the specified category
*
* #param string $category
*
* #throws NotFoundException
*/
public function results($category = null)
{
$categoryId = $this->Car->Category->field('id', array('name' => $category));
if (!$categoryId) {
throw new NotFoundException(__('Unknown category'));
}
$this->set('cars', $this->Paginator->paginate('Car', array('Car.category_id' => $categoryId)));
}
}
And, to create a link to a certain category;
$this->Html->link('New Cars',
array(
'controller' => 'listings',
'action' => 'results',
'category' => 'new-cars'
)
);

How to prevent controller and action from coming up in URL in cakephp?

I have one route that looks like this:
Router::connect('/Album/:slug/:id',array('controller' => 'albums', 'action' => 'photo'),array('pass' => array('slug','id'),'id' => '[0-9]+'));
and another like this:
Router::connect('/Album/:slug/*',array('controller' => 'albums','action' => 'contents'),array('pass' => array('slug')));
for what doesn't match the first. In the 'contents' action of the 'albums' controller, I take care of pagination myself - meaning I retrieve the named parameter 'page'.
A URL for the second route would look like this:
http://somesite.com/Album/foo-bar/page:2
The Above URL indeed works, but when I try to use the HTML Helper (url,link) to output a url like this, it appends the controller and action to the beginning, like this:
http://somesite.com/albums/contents/Album/foo-bar/page:2
Which i don't like.
The code that uses the HtmlHelper is as such:
$html->url(array('/Album/' . $album['Album']['slug'] . '/page:' . $next))
See below url it is very help full to you
http://book.cakephp.org/2.0/en/development/routing.html
Or read it
Passing parameters to action
When connecting routes using Route elements you may want to have routed elements be passed arguments instead. By using the 3rd argument of Router::connect() you can define which route elements should also be made available as passed arguments:
<?php
// SomeController.php
public function view($articleId = null, $slug = null) {
// some code here...
}
// routes.php
Router::connect(
'/blog/:id-:slug', // E.g. /blog/3-CakePHP_Rocks
array('controller' => 'blog', 'action' => 'view'),
array(
// order matters since this will simply map ":id" to $articleId in your action
'pass' => array('id', 'slug'),
'id' => '[0-9]+'
)
);
And now, thanks to the reverse routing capabilities, you can pass in the url array like below and Cake will know how to form the URL as defined in the routes:
// view.ctp
// this will return a link to /blog/3-CakePHP_Rocks
<?php
echo $this->Html->link('CakePHP Rocks', array(
'controller' => 'blog',
'action' => 'view',
'id' => 3,
'slug' => 'CakePHP_Rocks'
));

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