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I'd like my web page to say "Welcome, [Google+ name here]!"
and so I've been looking around for a solution and checking whether or not it is possible to do it without asking him/her to log my website through Google+.
Looking around for it I found some libs:
require_once 'google-api-php-client/apiClient.php';
require_once 'google-api-php-client/contrib/apiOauth2Service.php';
Are these useful to my purposes? And the main question is: is what I wanna do possible (tips?)?
Thanks in advance.
No, that isn't possible. If you want to know who the user is, you'll have to have them provide access to that information via sign-in or with an OAuth scope that allows you to query for their basic profile information.
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I stuck on a small problem. My site has an active page with slug xyz. I want to replace them by an updated page.
So I rename:
xyz -> xyz_old
xyz_new -> xyz
But when I call www.targetsite.com/xyz wordpress performs an 301 redirect to xyz_old
I removed also the content of wp_old_slug_redirect() in query.php to test it, but still the same behavior. Checked also the htaccess file's, no redirections. Checked mysql tables as well, nothing with this slug in postmeta data....
Any idea?
Thanks!
Regards,
Waldemar
Ok... After a lot of effort, I found the reason: Yoast Plugin :-(
The Plugin creates the redirection mapping automatically after rename of the page.
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Could someone please point me where did I go wrong?
I've an apps using PHP and mysql. The thing is, we are using some file uploader plugins that require us to save the unique id that has format something like this a41ddc78-3fee-4bf3-88c1-83028ae22f1. At some point, I need to select data from the database using this fields and as you can see, I can't get the field when I do manual query on it. any help is appreciate on how to solve this problem. Thank you
SELECT * FROM product_image WHERE unique_id = 'a41ddc78-3fee-4bf3-88c1-83028ae22f1'
the query works fine...
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Closed 6 years ago.
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I am trying to create an image that changes dependent on the genre grabbed from an icecast server, I am pretty sure I have the base code correct I think I've just incorrectly inputted the PHP variable.
<?php
$stats = $core->radioInfo( "http://http://sc.onlyhabbo.net:8124/status-json.xsl" );
?>
<img src=http://www.habbo.com/habbo-imaging/avatarimage?user=<?php
echo $stats['genre'];
?>&action=std&direction=2&head_direction=2&gesture=sml&size=m&img_format=gif/>
is the full code. Have I inputted the PHP variable incorrectly
Where are the quotes in your Html?
<img src="http://www.habbo.com/habbo-imaging/avatarimage?user=<?php
echo $stats['genre'];
?>&action=std&direction=2&head_direction=2&gesture=sml&size=m&img_format=gif"/>
UPDATE EVERYBODY
This is now resolved, I decided to go down the CURL route for this, and at first it didn't work until my host raised our CloudLinux Process Limit. I am unsure what the actual issue with this code was, but the CURL route works fine. Thank you for any answers
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Closed 2 years ago.
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So I have a member based website that I submitted to Google. I suppose I accidentally submitted the url with had member's info on it.
For example.
Normal website url.
http://www.mywebsite.com
Submitted website url.
http://www.mywebsite.com
I have a signup form on the index page. And I believe I accidentally used the url when those fields were filled in the input.
So now, the www. extension is associated with those input fields. Every time I use www.mywebsite.com, those input fields with info show up; where if I just use mywebsite.com, the fields will return empty.
I re-submited my website to Google with input fields empty. Hopefully that does the trick, but I am not 100% on that.
What you think?
The best thing is to wait till Google recrawls your website. Other than that you can add your website in Google Webmaster Tools and try to play with it.
Just resubmit your website to google using webmasters tool.. And wait till its indexed again
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Closed 9 years ago.
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I would like to get the regular expression to identify whether a url is a google search home page or search results page .
You can use something like this :
(https?:\/\/www\.google\.(?:(?:com)|(?:co\.in)).*#q=.+)
For Google search result url.
Since in Google the searched word will be there , after q=
DEMO
Explanation: