PHP Implement a trait, override and then calling it's parent trait - php

I'm using Laravel 5.3..
Model.php has the following function:
public function forceDelete()
{
return $this->delete();
}
But, I'm implementing it with the softDeletes trait, which has the following function:
public function forceDelete()
{
$this->forceDeleting = true;
$deleted = $this->delete();
$this->forceDeleting = false;
return $deleted;
}
But, I'm overriding the function, with this:
public function forceDelete()
{
echo "deleting";
return parent::forceDelete();
}
On this last override, on the line where I call parent::forceDelete(), it calls the version from model.php and not from softDeletes.php. How could I make it call from softDeletes instead? Is it even possible?

The best option is to name the trait method inside the class's use statement like this:
class SomeClass extends Model
{
use SomeTrait {
forceDelete as traitForceDelete;
}
public function forceDelete()
{
return $this->traitForceDelete();
}
}

Related

use service invoke function in symfony

Is possible to call invoke function from a service in symfony?
this is the controller
class FooController extends AbstractController
{
private $fooService;
public function __construct(FooService $fooService)
{
$this->fooService = $fooService;
}
#[Route('/foo', name: 'app_foo')]
public function index(): Response
{
return new Response($this->fooService->__invoke());
//is not possible to do
//return new Response($this->fooService());
}
}
and the service
namespace App\Service;
class FooService
{
public function __invoke()
{
return 'hello';
}
}
I have to call __invoke function explicitly instead to make $this->fooService() is not possible to do it?
In PHP the method call has higher priority than property access so you need to use parentheses.
($this->fooService)()
To access the property and call it.

using traits inside laravel controller

I have some repetitive codes inside my laravel(7.23.0)controller
use App\ModelA;
use App\ModelB;
use App\ModelC;
use App\Traits\DbTrait;
class DarsController extends Controller
{
use DbTrait;
public function A($id) {
return ModelA::where('column', $id)->get(*);
}
public function B($id) {
return ModelB::where('column', $id)->get(*);
}
public function C($id){
return ModelC::where('column', $id)->get(*);
}
//the only difference in these codes is model, all codes are the same
}
I had created a folder named Traits and inside that I had defined a trait DbTrait.php
<?php
namespace App\Traits;
trait DbTrait
{
public function getAllz($ModelName , $id){
return $ModelName::where('column', $id)->get('*');
}
}
so I modified my controller's functions to this
public function A($id) {
// return ModelA::where('column', $id)->get(*); works fine
$this->getAllz('ModelA', $id);// throws an error
}
it throws an error message: "Class 'ModelA' not found"
thank you
update:
i should apologize, i am really sorry, 3 of the answer worked, and i see the data inside network tab,i am using vue to display data,
and i think using trait made a complex array
this is my simple vue
axios.get('/api/emla/' + id).then(response =>{
this.data = JSON.parse(JSON.stringify(response.data));
}
Import the classes which will be used in your trait as you have done in the controller class.
use App\ModelA;
use App\ModelB;
use App\ModelC;
the reason you're getting Class 'ModelA' not found is because it's looking for that class in your traits directory, which it won't find. so you need this instead:
<?php
namespace App\Traits;
trait DbTrait
{
public function getAllz($ModelName , $id) {
return app( "\App\\" . $ModelName )::where('column', $id)->get('*');
}
}
assuming that you've defined your models under \App namespace
you need to modify your trait
ModelName::where it try to load the class in trait so use $ModelName->where here $ModelName is already instance of that class so you can call function via -> operator
<?php
namespace App\Traits;
trait DbTrait
{
public function getAllz($ModelName ,$columnName ,$id){
return $ModelName->where($columnName, $id)->get('*');
}
}
and to call this function
$this->getAllz(new ModelA, $id);
this way you don't need to import class inside trait
your final code will be like this
use App\ModelA;
use App\ModelB;
use App\ModelC;
use App\Traits\DbTrait;
class DarsController extends Controller
{
use DbTrait;
public function A($id)
{
return $this->getAllz(new ModelA,'column', $id);
}
public function B($id)
{
return $this->getAllz(new ModelB,'column', $id);
}
public function C($id)
{
return $this->getAllz(new ModelC,'column', $id);
}
}
100% should work if you follow this
public function A($id) {
// return ModelA::where('column', $id)->get(*); works fine
$model = new ModelName(); // new ModelName;
$this->getAllz($model, $id);// throws an error
}
public function getAllz($ModelName , $id){
return $ModelName->where('column', $id)->get('*');
}

Laravel Reusing Controller Logic

I have multiple controllers, with multiple methods, which all return views.
class PageController extends Controller {
public function index()
{
// do lots of stuff
return view('view.name', $lotsOfStuffArray);
}
public function list()
{
//...and so on
}
I now have the need to create an API, which performs much of the same logic as the methods above, but returns a JSON output instead:
class PageApiController extends Controller {
public function index()
{
// do lots of the same stuff
return $lotsOfStuffCollection;
}
public function list()
{
//...and so on
}
What is the best way to accomplish this without having to copy and paste code from one controller to the other?
I've tried placing a lot of the logic into traits and using them in my Eloquent models, but that still requires that I copy and paste code from controller to controller. I should also note its not viable to check expectsJson() and return a response accordingly as I have many, many methods.
Is it a good idea to have the logic stored in a parent class and then create a child controller that responds with a view and a child controller that responds with JSON?
You could abstract the logic to a service class. I have answered a similar question.
You have PageController, PageAPIController and PageService.
class PageService {
public function doStuff()
{
return $stuff;
}
}
class PageController extends Controller {
public function index()
{
$service = new PageService();
$stuff = $service->doStuff();
return $stuff;
}
}
class PageAPIController extends Controller {
public function index()
{
$service = new PageService();
$stuff = $service->doStuff();
return $stuff->toJSON();
}
protected function toJSON(){
//You could also abstract that to a service or a trait.
}
}

Error when implementing the contract in Laravel 5.2

I am following this link to implement it
I did below steps to implement the Contract in my existing class.
Below is the class where I will write some logic also before sending it to controller
namespace App\Classes\BusinessLogic\Role;
use App\Classes\DatabaseLayer\Role\RoleDb;
use App\Classes\Contract\Role\IRole;
class RoleBL implements IRole {
public function All() {
return (new RoleDb())->All();
}
}
Database Function
namespace App\Classes\DatabaseLayer\Role;
class RoleDb {
public function All() {
$Roles = \App\Models\Role\RoleModel
::all();
return $Roles;
}
}
Interface
namespace App\Classes\Contract\Role;
interface IRole {
public function All();
}
Service Provider class
namespace App\Providers\Role;
class RoleServiceProvider extends \Illuminate\Support\ServiceProvider {
public function register()
{
$this->app->bind('App\Classes\Contract\Role\IRole', function($app){
return new \App\Classes\BusinessLogic\Role\RoleBL($app['HttpClient']);
});
}
}
Finally in config/app.php in provider wrote below line.
App\Providers\Role\RoleServiceProvider::class
Controller - Constructor
protected $roles;
public function __construct(\App\Classes\Contract\Role\IRole $_roles) {
parent::__construct();
$roles = $_roles;
}
Controller Action method
public function index(IRole $roles) {
$RoleTypes = $roles->All();
}
So far everything works fine if I keep Interface as parameter in method.
if I try to use the variable $roles in index method and remove the variable, it is always null.
Please guide me if I missed anything?
You incorrectly assign the $roles property in your __construct() method.
Replace
$roles = $_roles;
with
$this->roles = $_roles;
and then in your index method do:
$RoleTypes = $this->roles->All();

phalcon controller indexAction break down

I am new into Phalcon framework. I just got the basic idea about it. Every controller has methods with multiple specific actions. I wrote a huge indexAction method but now I want to break it down with multiple private method so that I can reuse those functionality. But when I try to create any method without action suffix, it returns error(Page Not Found). How can I break it down into multiple methods?
<?php
use Phalcon\Mvc\Controller;
class PostsController extends Controller
{
public function indexAction()
{
$this->someMethod();
}
public function someMethod()
{
//do your things
}
}
Controllers must have the suffix “Controller” while actions the suffix “Action”. A sample of a controller is as follows:
<?php
use Phalcon\Mvc\Controller;
class PostsController extends Controller
{
public function indexAction()
{
}
public function showAction($year, $postTitle)
{
}
}
For calling another method, you would use it straight forward
<?php
use Phalcon\Mvc\Controller;
class PostsController extends Controller
{
public function indexAction()
{
echo $this->showAction();
}
private function showAction()
{
return "show";
}
}
Docs.
What exactly do you want? The answer seems trivial to me.
class YourController extends Phalcon\Mvc\Controller
{
// this method can be called externally because it has the "Action" suffix
public function indexAction()
{
$this->customStuff('value');
$this->more();
}
// this method is only used inside this controller
private function customStuff($parameter)
{
}
private function more()
{
}
}

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