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i have a set of predefined array contains strings and words.I am trying to check whether my string contains at least one word from that array.
$array = array("PHP code tester Sandbox Online","abcd","defg" );
$string = 'code testy';//code is already in that array
i tried many ways,but not correct solution
first method
$i = count(array_intersect($array, explode(" ", preg_replace("/[^A-Za-z0-9' -]/", "", $string))));
echo ($i) ? "found ($i)" : "not found";
second method
if (stripos(json_encode($array),$string) !== false) { echo "found";}
else{ echo "not found";}
I suppose you are looking for a match which is any of the words.
$array = array("PHP code tester Sandbox Online","abcd","defg" );
$string = 'code|testy';
foreach ($array as $item ) {
if(preg_match("/\b{$string}\b/i", $item)) {
var_dump( $item );
}
}
You have to iterate over the array and test each one of the cases separately, first 'code', then 'testy', or whatever you want. If you json_encode, even if you trim both of strings to do this comparaison, the return will be not found.
But in the first string if you had like this
$array = array("PHP code testy Sandbox Online","abcd","defg" );
$string = 'code testy';//code is already in that array
you will get surely a "found" as return.
if (stripos(trim(json_encode($array)),trim($string)) !== false) { echo "found";}
else{ echo "not found";}
You could use explode() to get an array from the strings and then go through each of them.
$array = array("PHP code tester Sandbox Online","abcd","defg" );
$string = 'code testy';
foreach(explode(' ', $string) as $key => $value) {
foreach($array as $arrKey => $arrVal) {
foreach(explode(' ', $arrVal) as $key => $str) {
if ($value == $str) {
echo $str . ' is in array';
}
}
}
}
How can I search a word in a PHP array?
I try in_array, but it find just exactly the same values.
<?php
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (in_array('Peter Parker', $namesArray)) {echo "There is.";}
else {echo "There is not.";}
I want this instance to return true. How can I do it? Is there any function?
Snippet: https://glot.io/snippets/ek086tekl0
I have to say I like the simplicity of Gre_gor's answer, but for a more dynamic method you can also use array_filter():
function my_array_search($array, $needle){
$matches = array_filter($array, function ($haystack) use ($needle){
// return stripos($needle, $haystack) !== false; make the function case insensitive
return strpos($needle, $haystack) !== false;
});
return empty($matches) ? false : $matches;
}
$namesArray = ['Peter', 'Glenn', 'Meg', 'Griffin'];
Examples:
if(my_array_search($namesArray, 'Glenn Quagmire')){
echo 'There is'; // Glenn
} else {
echo 'There is not';
}
// optionally:
if(($retval = my_array_search($namesArray, 'Peter Griffin'))){
echo 'There is';
print_r($retval); // Peter, Griffin.
} else {
echo 'There is not';
}
Now $retval is optional, it captures an array of matching subjects. This works because if the $matches variable in my_array_search is empty, it returns false instead of an empty array.
Explode your string and then check, if there are any same strings in both arrays.
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (array_intersect(explode(' ', 'Peter Parker'), $namesArray))
echo "There is.";
else
echo "There is not.";
You can use Regular Expressions - preg_match ('i' means case insensitive) to check if array contains some words
for example:
$namesArray = array('Peter One', 'Other Peter', 'Glenn', 'Cleveland');
$check = false;
foreach($namesArray as $name)
{
if (preg_match("/.*peter.*/i", $name)) {
$check = true;
break;
}
}
if($check)
{
echo "There is.";
}
else {
echo "There is not.";
}
Hi I'm trying to check if a list of words (or any one of them) exists in a string. I tried some of the examples i found here, but i still can't get it to work correctly.
Any ideas what I'm doing wrong?
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
if (in_array($ss3, $words) )
{
echo "found it";
}
Loop over your array, check for each element if it exists in the string
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
foreach($words as $w){
if (stristr($ss3,$w)!==false)
echo "found $w \n";
}
Fiddle
You need to explode() your $ss3 string and then compare each item with your $words with loop
manual for in_array - http://php.net/manual/en/function.in-array.php
manual for explode() - http://php.net/manual/ru/function.explode.php
$matches = array();
$items = explode(" ",$ss3);
foreach($items as $item){
if(in_array($item, $words)){
$matches[] = $item; // Match found, storing in array
}
}
var_dump($matches); // To see all matches
This is how you will check for existence of a word from a string. Also remember that you must first convert the string to lowercase and then explode it.
$ss3="How to make a book";
$ss3 = strtolower($ss3);
$ss3 = explode(" ", $ss3);
$words = array ("book","paper","page","sheet");
if (in_array($ss3, $words) )
{
echo "found it";
}
Cheers!
You could use regular expressions. It would look something like this:
$ss3 = "How to make a book";
if (preg_match('/book/',$ss3))
echo 'found!!';
in_array will only check the complete string value in an array.
Now you can try this:
$string = 'How to make a book';
$words = array("book","paper","page","sheet");
foreach ($words as $val) {
if (strpos($string, $val) !== FALSE) {
echo "Match found";
return true;
}
}
echo "Not found!";
You can use str_word_count along with array_intersect like as
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
$new_str_array = str_word_count($ss3,1);
$founded_words = array_intersect($words,$new_str_array);
if(count($founded_words) > 0){
echo "Founded : ". implode(',',$founded_words);
}else{
echo "Founded Nothing";
}
Demo
This code will help you for better answer
<?php
$str="Hello World Good";
$word=array("Hello","Good");
$strArray=explode(" ",$str);
foreach($strArray as $val){
if(in_array($val,$word)){
echo $val."<br>";
}
}
?>
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
I am trying to detect whether a string contains at least one URL that is stored in an array.
Here is my array:
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
The string is entered by the user and submitted via PHP. On the confirmation page I would like to check if the URL entered is in the array.
I have tried the following:
$string = 'my domain name is website3.com';
if (in_array($string, $owned_urls))
{
echo "Match found";
return true;
}
else
{
echo "Match not found";
return false;
}
No matter what is inputted the return is always "Match not found".
Is this the correct way of doing things?
Try this.
$string = 'my domain name is website3.com';
foreach ($owned_urls as $url) {
//if (strstr($string, $url)) { // mine version
if (strpos($string, $url) !== FALSE) { // Yoshi version
echo "Match found";
return true;
}
}
echo "Not found!";
return false;
Use stristr() or stripos() if you want to check case-insensitive.
This was a lot easier to do if all you want to do is find a string in an array.
$array = ["they has mystring in it", "some", "other", "elements"];
if (stripos(json_encode($array),'mystring') !== false) {
echo "found mystring";
}
Try this:
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$url_string = end(explode(' ', $string));
if (in_array($url_string,$owned_urls)){
echo "Match found";
return true;
} else {
echo "Match not found";
return false;
}
-
Thanks
Simple str_replace with count parameter would work here:
$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
echo "One of Array value is present in the string.";
}
More Info - https://www.techpurohit.in/extended-behaviour-explode-and-strreplace-php
I think that a faster way is to use preg_match.
$user_input = 'Something website2.com or other';
$owned_urls_array = array('website1.com', 'website2.com', 'website3.com');
if ( preg_match('('.implode('|',$owned_urls_array).')', $user_input)){
echo "Match found";
}else{
echo "Match not found";
}
$string = 'my domain name is website3.com';
$a = array('website1.com','website2.com','website3.com');
$result = count(array_filter($a, create_function('$e','return strstr("'.$string.'", $e);')))>0;
var_dump($result );
output
bool(true)
Here is a mini-function that search all values from an array in a given string.
I use this in my site to check for visitor IP is in my permitted list on certain pages.
function array_in_string($str, array $arr) {
foreach($arr as $arr_value) { //start looping the array
if (stripos($str,$arr_value) !== false) return true; //if $arr_value is found in $str return true
}
return false; //else return false
}
how to use
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
//this example should return FOUND
$string = 'my domain name is website3.com';
if (array_in_string($string, $owned_urls)) {
echo "first: Match found<br>";
}
else {
echo "first: Match not found<br>";
}
//this example should return NOT FOUND
$string = 'my domain name is website4.com';
if (array_in_string($string, $owned_urls)) {
echo "second: Match found<br>";
}
else {
echo "second: Match not found<br>";
}
DEMO: http://phpfiddle.org/lite/code/qf7j-8m09
stripos function is not very strict. it's not case sensitive or it can match a part of a word
http://php.net/manual/ro/function.stripos.php
if you want that search to be case sensitive use strpos
http://php.net/manual/ro/function.strpos.php
for exact match use regex (preg_match), check this guy answer https://stackoverflow.com/a/25633879/4481831
You can concatenate the array values with implode and a separator of |
and then use preg_match to search for the value.
Here is the solution I came up with ...
$emails = array('#gmail', '#hotmail', '#outlook', '#live', '#msn', '#yahoo', '#ymail', '#aol');
$emails = implode('|', $emails);
if(!preg_match("/$emails/i", $email)){
// do something
}
If your $string is always consistent (ie. the domain name is always at the end of the string), you can use explode() with end(), and then use in_array() to check for a match (as pointed out by #Anand Solanki in their answer).
If not, you'd be better off using a regular expression to extract the domain from the string, and then use in_array() to check for a match.
$string = 'There is a url mysite3.com in this string';
preg_match('/(?:http:\/\/)?(?:www.)?([a-z0-9-_]+\.[a-z0-9.]{2,5})/i', $string, $matches);
if (empty($matches[1])) {
// no domain name was found in $string
} else {
if (in_array($matches[1], $owned_urls)) {
// exact match found
} else {
// exact match not found
}
}
The expression above could probably be improved (I'm not particularly knowledgeable in this area)
Here's a demo
You are checking whole string to the array values. So output is always false.
I use both array_filter and strpos in this case.
<?php
$urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$check = array_filter($urls, function($url){
global $string;
if(strpos($string, $url))
return true;
});
echo $check?"found":"not found";
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
for($i=0; $i < count($owned_urls); $i++)
{
if(strpos($string,$owned_urls[$i]) != false)
echo 'Found';
}
$message = "This is test message that contain filter world test3";
$filterWords = array('test1', 'test2', 'test3');
$messageAfterFilter = str_replace($filterWords, '',$message);
if( strlen($messageAfterFilter) != strlen($message) )
echo 'message is filtered';
else
echo 'not filtered';
I find this fast and simple without running loop.
$array = array("this", "that", "there", "here", "where");
$string = "Here comes my string";
$string2 = "I like to Move it! Move it";
$newStr = str_replace($array, "", $string);
if(strcmp($string, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
$newStr = str_replace($array, "", $string2);
if(strcmp($string2, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
Little explanation!
Create new variable with $newStr replacing value in array of original string.
Do string comparison - If value is 0, that means, strings are equal and nothing was replaced, hence no value in array exists in string.
if it is vice versa of 2, i.e, while doing string comparison, both original and new string was not matched, that means, something got replaced, hence value in array exists in string.
$search = "web"
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
foreach ($owned_urls as $key => $value) {
if (stristr($value, $search) == '') {
//not fount
}else{
//found
}
this is the best approach search for any substring , case-insensitive and fast
just like like im mysql
ex:
select * from table where name = "%web%"
I came up with this function which works for me, hope this will help somebody
$word_list = 'word1, word2, word3, word4';
$str = 'This string contains word1 in it';
function checkStringAgainstList($str, $word_list)
{
$word_list = explode(', ', $word_list);
$str = explode(' ', $str);
foreach ($str as $word):
if (in_array(strtolower($word), $word_list)) {
return TRUE;
}
endforeach;
return false;
}
Also, note that answers with strpos() will return true if the matching word is a part of other word. For example if word list contains 'st' and if your string contains 'street', strpos() will return true
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
This is for a chat page. I have a $string = "This dude is a mothertrucker". I have an array of badwords: $bads = array('truck', 'shot', etc). How could I check to see if $string contains any of the words in $bad?
So far I have:
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
// YES! }
}
Except when I do this, when a user types in a word in the $bads list, the output is NO! followed by YES! so for some reason the code is running it twice through.
function contains($str, array $arr)
{
foreach($arr as $a) {
if (stripos($str,$a) !== false) return true;
}
return false;
}
1) The simplest way:
if ( in_array( 'three', ['one', 'three', 'seven'] ))
...
2) Another way (while checking arrays towards another arrays):
$keywords=array('one','two','three');
$targets=array('eleven','six','two');
foreach ( $targets as $string )
{
foreach ( $keywords as $keyword )
{
if ( strpos( $string, $keyword ) !== FALSE )
{ echo "The word appeared !!" }
}
}
can you please try this instead of your code
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot');
foreach($bads as $bad) {
$place = strpos($string, $bad);
if (!empty($place)) {
echo 'Bad word';
exit;
} else {
echo "Good";
}
}
There is a very short php script that you can use to identify bad words in a string which uses str_ireplace as follows:
$string = "This dude is a mean mothertrucker";
$badwords = array('truck', 'shot', 'ass');
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
if ($banstring) {
echo 'Bad words found';
} else {
echo 'No bad words in the string';
}
The single line:
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
does all the work.
You can flip your bad word array and do the same checking much faster. Define each bad word as a key of the array. For example,
//define global variable that is available to too part of php script
//you don't want to redefine the array each time you call the function
//as a work around you may write a class if you don't want global variable
$GLOBALS['bad_words']= array('truck' => true, 'shot' => true);
function containsBadWord($str){
//get rid of extra white spaces at the end and beginning of the string
$str= trim($str);
//replace multiple white spaces next to each other with single space.
//So we don't have problem when we use explode on the string(we dont want empty elements in the array)
$str= preg_replace('/\s+/', ' ', $str);
$word_list= explode(" ", $str);
foreach($word_list as $word){
if( isset($GLOBALS['bad_words'][$word]) ){
return true;
}
}
return false;
}
$string = "This dude is a mothertrucker";
if ( !containsBadWord($string) ){
//doesn't contain bad word
}
else{
//contains bad word
}
In this code we are just checking if an index exist rather than comparing bad word with all the words in the bad word list.
isset is much faster than in_array and marginally faster than array_key_exists.
Make sure none of the values in bad word array are set to null.
isset will return false if the array index is set to null.
Put and exit or die once it find any bad words, like this
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
echo YES;
die(); or exit;
}
}
You can do the filter this way also
$string = "This dude is a mothertrucker";
if (preg_match_all('#\b(truck|shot|etc)\b#', $string )) //add all bad words here.
{
echo "There is a bad word in the string";
}
else {
echo "There is no bad word in the string";
}
Wanted this?
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot', 'mothertrucker');
foreach ($bads as $bad) {
if (strstr($string,$bad) !== false) {
echo 'NO<br>';
}
else {
echo 'YES<br>';
}
}
If you want to do with array_intersect(), then use below code :
function checkString(array $arr, $str) {
$str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase
$matchedString = array_intersect( explode(' ', $str), $arr);
if ( count($matchedString) > 0 ) {
return true;
}
return false;
}
I would go that way if chat string is not that long.
$badwords = array('mothertrucker', 'ash', 'whole');
$chatstr = 'This dude is a mothertrucker';
$chatstrArr = explode(' ',$chatstr);
$badwordfound = false;
foreach ($chatstrArr as $k => $v) {
if (in_array($v,$badwords)) {$badwordfound = true; break;}
foreach($badwords as $kb => $vb) {
if (strstr($v, $kb)) $badwordfound = true;
break;
}
}
if ($badwordfound) { echo 'You\'re nasty!';}
else echo 'GoodGuy!';
$string = "This dude is a good man";
$bad = array('truck','shot','etc');
$flag='0';
foreach($bad as $word){
if(in_array($word,$string))
{
$flag=1;
}
}
if($flag==1)
echo "Exist";
else
echo "Not Exist";