i want to check if there is anything behind /index.php/'
parameters must be ignored and the baseurl without /index.php/ also must be ignored.
i know about
if (strpos($url, 'contact') !== false){ }
but i dont know how to use it to check the second part of the url for anything but parameters.
how am i supposed to do this?
example:
localhost:8080/ - returns false.
localhost:8080/index.php - returns false.
localhost:8080/index.php/ - returns false.
localhost:8080/index.php?id=0 - returns false.
localhost:8080/index.php/contact - returns true.
You need to parse the string.
$url = "localhost:8080/index.php/contact?id=0";
// Split the string using delimiter "/index.php/"
$url = explode("/index.php/", $url);
// We have parts
if (isset($url[1])) {
// We want the first part after "/index.php/"
// And we don't want anything after ?
$url = explode("?", $url[1])[0];
// We have no parts, change the array to an empty string
} else {
$url = "";
}
You can regexp what comes after index.php
preg_match("/index\.php\/(.*?)^/ims","localhost:8080/index.php/contact",$matches );
print_r($matches);
Related
how can I write some preg_match() or any other condition to find whether the URL have "php" in the second place. Eg url below "http://a.com/php/abcpdf/".
If the URL have "/php/" in the second place my condition should execute else not.
You can use parse_url function to parse the URL data and process the URI path accordingly.
<?php
$url = 'http://a.com/php/abcpdf/';
$url_data = parse_url($url);
if(strpos(trim($url_data['path'],'/') . "/","php/") !== false){
echo "exists"; // your task
}
Demo: https://3v4l.org/XQlF1
this should match what you need
preg_match("#^/php/#", $_SERVER["REQUEST_URI"])
I need to create a an if statement that fires if there is something after a given string in the URL.
For example, if my string is 'Honda' I need to check if something appears after that word in the url, eg something like:
$brand = "honda";
if (url contains $brand . '/*'){
// Do something.
}
Example urls could be:
mysite.com/honda (which would fail the above)
mysite.com/cars/honda (which would fail the above)
mysite.com/honda/civic (which would pass the above)
mysite.com/honda/accord (which would pass the above)
I know I can use strpos() to detect if the string is within the URL, but how can I detect if anything comes after that?
Use a regular expression that looks for the $brand at the end of the string.
if (! preg_match("/{$brand}$/", $url)) {
// ...
}
If you need to check if the $brand actually appears in the URL before running your end of string check:
if (strpos($brand, $url) !== false && ! preg_match("/{$brand}$/", $url)) {
// ...
}
I have a method of pulling Youtube video data from API links. I use Wordpress and ran into a snag.
In order to pull the thumbnail, views, uploader and video title I need the user to input the 11 character code at the end of watch?v=_______. This is documented with specific instructions for the user, but what if they ignore it and paste the whole url?
// the url 'code' the user should input.
_gXp4hdd2pk
// the wrong way, when the user pastes the whole url.
https://www.youtube.com/watch?v=_gXp4hdd2pk
If the user accidentally pastes the entire URL and not the 11 character code then is there a way I can use PHP to grab either the code or whats at the end of this url (11 characters after 'watch?v='?
Here is my PHP code to pull the data:
// $url is the code at the end of 'watch?v=' that the user inputs
$url = get_post_meta ($post->ID, 'youtube_url', $single = true);
// $code is a variable for placing the $url in a youtube link so I can output it to an API link
$code = 'http://www.youtube.com/watch?v=' . $url;
// $code is called at the end of this oembed code, allowing me to decode json data and pull elements from json to echo in my html
// echoed output returns json file. example: http://www.youtube.com/oembed?url=http://www.youtube.com/watch?v=_gXp4hdd2pk
$json = file_get_contents('http://www.youtube.com/oembed?url='.urlencode($code));
Im looking for something like...
"if user inputs code, use this block of code, else if user inputs whole url use a different block of code, else throw error."
Or... if they use the whole URL can PHP only use a specific section of that url...?
EDIT: Thank you for all the answers! I am new to PHP, so thank you all for your patience. It is difficult for graphic designers to learn PHP, even reading the PHP manual can give us headaches. All of your answers were great and the ones ive tested have worked. Thank you so much :)
Try this,
$code = 'https://www.youtube.com/watch?v=_gXp4hdd2pk';
if (filter_var($code, FILTER_VALIDATE_URL) == TRUE) {
// if `$code` is valid url
$code_arr = explode('?v=', $code);
$query_str = explode('&', $code_arr[1]);
$new_code = $query_str[0];
} else {
// if `$code` is not a valid url like '_gXp4hdd2pk'
$new_code = $code;
}
echo $new_code;
Here's a simple option for you to do, unless you want to use regex like Nisse Engström's Answer.
Using the function parse_url() you could do something like this:
$url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184';
$split = parse_url('https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184');
$params = explode('&', $split['query']);
$video_id = str_replace('v=', '', $params[0]);
now $video_id would return:
_gXp4hdd2pk
from the $url supplied in the above code.
I suggest you read the parse_url() documentation to ensure you understand and grasp it all :-)
Update
for your comment.
You'd use something like this to make sure the parsed value is a valid URL:
// this will check if valid url
if (filter_var($code, FILTER_VALIDATE_URL)) {
// its valid as it returned true
// so run the code
$url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184';
$split = parse_url('https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184');
$params = explode('&', $split['query']);
$video_id = str_replace('v=', '', $params[0]);
} else {
// they must have posted the video code as the if check returned false.
$video_id = $url;
}
Just try as follows ..
$url =" https://www.youtube.com/watch?v=_gXp4hdd2pk";
$url= explode('?v=', $url);
$endofurl = end($url);
echo $endofurl;
Replace $url variable with input .
I instruct my users to copy and paste the whole youtube url.
Then, I do this:
$video_url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk'; // this is from user input
$parsed_url = parse_url($video_url);
parse_str($parsed_url['query'], $query);
$vidID = isset($query['v']) ? $query['v'] : NULL;
$url = "http://gdata.youtube.com/feeds/api/videos/". $vidID; // this is used for the Api
$m = array();
if (preg_match ('#^(https?://www.youtube.com/watch\\?v=)?(.+)$#', $url, $m)) {
$code = $m[2];
} else {
/* No match */
}
The code uses a Regular Expression to match the user input (the subject) against a pattern. The pattern is enclosed in a pair of delimiters (#) of your choice. The rest of the pattern works like this:
^ matches the beginning of the string.
(...) creates a subpattern.
? matches 0 or 1 of the preceeding character or subpattern.
https? matches "http" or "https".
\? matches "?".
(.+) matches 1 or more arbitrary charactes. The . matches any character (except newline). + matches 1 or more of the preceeding character or subpattern.
$ matches the end of the string.
In other words, optionally match an http or https base URL, followed by the video code.
The matches are then written to $m. $m[0] contains the entire string, $m[1] contains the first subpattern (base URL) and $m[2] contains the second subpattern (code).
Basically the problem I am having is I need to write this function that can take a URL like www.stackoverflow.com and just return the "com". But I need to be able to return the same value even if the URL has a period at the end like "www.stackoverflow.com."
This is what I have so far. The if statement is my attempt to return the point in the array before the period but I dont think I am using the if statement correctly. Otherwise the rest of the code does exactly what is supposed to do.
<?php
function getTLD($domain)
{
$domainArray = explode("." , $domain);
$topDomain = end($domainArray);
if ($topDomain == " ")
$changedDomain = prev(end($domainArray));
return $changedDomain;
return $topDomain;
}
?>
Don't use a regex for simple cases like that, it is cpu costly and unreadable. Just remove the final dot if it exists:
function getTLD($domain) {
$domain = rtrim($domain, '.');
return end(explode('.', $domain));
}
The end function is returning an empty string "" (without any spaces). You are comparing $topDomain to single space character so the if is not evaluating to true.
Also prev function requires array input and end($domainArray) is returning a string, so, $changedDomain = prev(end($domainArray)) should throw an E_WARNING.
Since end updates the internal pointer of the array $domainArray, which is already updated when you called $topDomain = end($domainArray), you do not need to call end on $domainArray inside the if block.
Try:
if ($topDomain == "") {
$changedDomain = prev($domainArray);
return $changedDomain; // Will output com
}
Here is the phpfiddle for it.
Use regular expressions for something like this. Try this:
function getTLD($domain) {
return preg_replace("/.*\.([a-z]+)\.?$/i", "$1", $domain );
}
A live example: http://codepad.org/km0vCkLz
Read more about regular expressions and about how to use them: http://www.regular-expressions.info/
I'm trying to check if a user submitted URL is valid, it goes directly to the database when the user hits submit.
So far, I have:
$string = $_POST[url];
if (strpos($string, 'www.') && (strpos($string, '/')))
{
echo 'Good';
}
The submitted page should be a page in a directory, not the main site, so http://www.address.com/page
How can I have it check for the second / without it thinking it's from http:// and that doesn't include .com?
Sample input:
Valid:
http://www.facebook.com/pageName
http://www.facebook.com/pageName/page.html
http://www.facebook.com/pageName/page.*
Invalid:
http://www.facebook.com
facebook.com/pageName
facebook.com
if(!parse_url('http://www.address.com/page', PHP_URL_PATH)) {
echo 'no path found';
}
See parse_url reference.
See the parse_url() function. This will give you the "/page" part of the URL in a separate string, which you can then analyze as desired.
filter_var($url, FILTER_VALIDATE_URL, FILTER_FLAG_PATH_REQUIRED)
More information here :
http://ca.php.net/filter_var
Maybe strrpos will help you. It will locate the last occurrence of a string within a string
To check the format of the URL you could use a regular expression:
preg_match [ http://php.net/manual/en/function.preg-match.php ] is a good start, but a knowledge of regular expressions is needed to make it work.
Additionally, if you actually want to check that it's a valid URL, you could check the URL value to see if it actually resolves to a web page:
function check_404($url) {
$return = #get_headers($url);
if (strpos($return[0], ' 404 ') === false)
return true;
else {
return false;
}
}
Try using a regular expression to see that the URL has the correct structure. Here's more reading on this. You need to learn how PCRE works.
A simple example for what you want (disclaimer: not tested, incomplete).
function isValidUrl($url) {
return preg_match('#http://[^/]+/.+#', $url));
}
From here: http://www.blog.highub.com/regular-expression/php-regex-regular-expression/php-regex-validating-a-url/
<?php
/**
* Validate URL
* Allows for port, path and query string validations
* #param string $url string containing url user input
* #return boolean Returns TRUE/FALSE
*/
function validateURL($url)
{
$pattern = '/^(([\w]+:)?\/\/)?(([\d\w]|%[a-fA-f\d]{2,2})+(:([\d\w]|%[a-fA-f\d]{2,2})+)?#)?([\d\w][-\d\w]{0,253}[\d\w]\.)+[\w]{2,4}(:[\d]+)?(\/([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)*(\?(&?([-+_~.\d\w]|%[a-fA-f\d]{2,2})=?)*)?(#([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)?$/';
return preg_match($pattern, $url);
}
$result = validateURL('http://www.google.com');
print $result;
?>