SimpleSAMLphp custom authsource without password - php

For one of our customers I need to write a custom authsource module. I allready set up SimpleSAMLphp as an Idp using various authsources like LDAP, SQLauth, etc. All of those authsources have in common that they use a login form and authenticate against the sspmod_core_Auth_UserPassBase class. This means that there will be a login form for username and password etc.
The special case right here is the following:
The SAML installation (IdP) is inside the companies network. If a user (inside of that network/authenticated via AD) visits a host that is inside that network, the username will be automatically injected in its browser and is available via $_SERVER['PHP_AUTH_USER'] and we have the guarantee, that the user is allready "validated".
This means we do not have to "authenticate" the user any more. We do not have to show a login form and just need to mark that user as authenticated.
Now I am a little stuck, because for my understanding it would be a little bit "overdosed" to write an own authsource that extends the default UserPassBase class. I would have to handle empty passwords and automatically forward/post from login form etc.
I guess there is a better way to handle that. The flow would be pretty simple:
SP redirects to IdP. The IdP "login page" reads PHP_AUTH_USER (no output like a login form), authenticates the user (without any further check) and redirects as expected if user was detected correctly. If the PHP_AUTH_USER could not be found in any way, the user will be redirected to some kind of error page.
Any ideas how to solve that the correct way? I guess I will have to write my own completely new authsource class that extends the base SimpleSAML_Auth_Source class? Maybe someone has an example for that situation before I am going to reinvent the wheel!?

Take a look at the exampleAuth:Static authsource. It auto-logs you in as a specific user
'example-static' => array(
'exampleauth:Static',
'uid' => array('testuser'),
'eduPersonAffiliation' => array('member', 'employee'),
'cn' => array('Test User'),
),
You could create your own module like it, but instead of loading attributes from the authsource config, load them based on the username. and do something like
public function authenticate(&$state) {
$user = $_SERVER['PHP_AUTH_USER'];
if ($user) {
$attributes = loadAttributesForUser($user);
$state['Attributes'] = $attributes;
} else {
throw new Exception('No user found');
}
}

Related

Functionality for admin to log in in as user in Laravel 5.3

Building an app in Laravel 5.3, one of the functionalities is for the admin to be able to log into the app as a user, to be able to see what that specific user can see, while maintaining his admin session to be able to go back to the user list and be possible to log in as another user without having to re-authenticate.
Currently implemented the basic out-of-the-box Laravel Auth, meaning if I start another auth session it will terminate my admin session making me having to re-login.
I have checked Laravel Multi Auth but seems to work with two tables (user,admin), which in my case we use one user table and use an ACL for managing roles and deciding whos admin and whos user.
What programming logic ideas do you guys have for this solution? Trying to find other opinions/ideas in how this could be implemented in Laravel 5.x
I've implemented the feature on a project recently. I did this using the session and a middleware. This is how I did it:
Create a controller 'ImpersonateController' and Set two routes for impersonateIn and impersonateOut for the purpose.
Route::get('impersonateIn/{user}', 'ImpersonateController#impersonateIn');
Route::get('impersonateOut', 'ImpersonateController#impersonateOut');
In the ImpersonateController#impersonateIn method just set the user id you want to log in and the URL backUrl into the session variable.
public function impersonateIn($id)
{
session(['impersonated' => $id, 'backUrl' => \URL::previous()]);
return redirect()->to('dashboard');
}
public function impersonateOut()
{
$back_url = Request::session()->get('backUrl');
Request::session()->forget('impersonated', 'secretUrl');
return $back_url ?
redirect()->to($back_url) :
redirect()->to('dashboard');
}
The first part is done. Now every request need to check the if the session has the
impersonated variable set. A good place to do that is a middleware.
Create a middleware to check the session on the handle method. If the impersonated found then log as the user using the Auth::onceUsingId() for the current request only.
class ImpersonateMiddleware
{
public function handle($request, Closure $next)
{
if(Request::session()->has('impersonated'))
{
Auth::onceUsingId(Request::session()->get('impersonated'));
}
}
}
Now you just need to apply the middleware for every request. The best place to do this from the Http/Kernel.php
protected $middlewareGroups = [
'web' => [
//....
\App\Http\Middleware\ImpersonateMiddleware::class,
],
];
The only remaining thing is you need to check the session and replace the logout route to the impersonateOut. Now when the admin logged out from the user will be redirected to the old route.
That's it!
Are you sure you really have to login?
I would stay logged in as admin and simulate user login.
You can allow admin access to all the databases.
In your controller you can use User::find($user_id) instead of Auth::user() for accessing user's data.
https://laravel.com/docs/5.3/database
https://laravel.com/docs/5.3/eloquent
Personaly, I would do this with sessions. I have not used Laravel but I use PHP often, so my answer will be in PHP.
In the header page, you most likely have some kind of session check to see if the user is logged in. For example:
<? php
session_start();
if (isset($_SESSION['user'])){
//do stuff with the user session
} else {
die('User not logged in!');
}
?>
I would change this to something like:
<? php
session_start();
if (isset($_SESSION['fakeuser'])){
//do stuff with the user session
//change logout button to destroy this session instead of logging the user out
}
elseif (isset($_SESSION['user'])){
//do stuff with the user session
} else {
die('User not logged in!');
}
?>
In the page in which you swap users, you would just simply copy the way a session starts when a user logs in. To switch users, you destroy the new 'fakeuser' and you are back to your old session + admin permissions without having to log back in again.
That's the logical approach I would take anyways.

kohana view change according to user logged or not

my question is trivial byt i am new and do not even know what to look for
i am using kohana framework to build my site. I have already learned how to use auth module (more or less) and created login, logout "arhitecture".
When my user is not logged i redirect to login page and when it is I use a view to show user data.
Now i am trying to do something like a page menu when i can see "login" button when user is not logged in, but "logout" button when logged. Do i make myself clear? I assume i cant redirect anywhere as this is a part of the same view. then how do I deterin a view content accordingly to a user state?
I am not looking for a ready code (although that would me apreciated) but a direction on what to look for and what to read about.
For Kohana 3.2 you could check if a user is logged in by calling
Auth::instance()->logged_in();
An option of integration might be to build a base controller where the user is redirected or set in the before action. That way you always have the redirect in 1 place and the user set if there is a valid login.
class Controller_Custom extends Controller {
protected $user;
public function before()
{
if ( ! Auth::instance()->logged_in()) {
$this->request->redirect('url/login/page');
}
$this->user = Auth::instance()->get_user();
}
}
For Kohana 3.3 the redirect request is changed a bit I believe.

CakePHP Stateless (Basic) Auth, where to call $this->Auth->login()?

My CakePHP v2.4.X app supports both Basic and Form authentication (Form is for web users, and Basic is for Stateless access from Android App).
AppController.php contains the following $components declaration:
public $components = array(
'Auth' => array(
'authenticate' => array(
'Basic',
'Form',
),
),
);
From the doc on performing stateless Basic Auth:
"In your login function just call $this->Auth->login() without any checks for POST data."
My issue is that if the user logs in using Basic Auth, they never trigger Users/login - so I am unsure where to place the $this->Auth->login() function.
Do I simply place this code in AppController/beforeFilter() and if the current user is not logged in I attempt login every time? ie:
if($this->Auth->loggedIn() == false)
{
$this->Auth->login();
}
This doesn't seem right to me because if the user is using Form login they'll end up calling $this->Auth->login(); twice [once from AppController/beforeFilter(), and again from UsersController/login()].
Also, when simply loading the login (via GET), the system will attempt to log them in and therefore return an error message.
I am also unsure how to determine if the user did login via Basic (as opposed to Form), and therefore set: "AuthComponent::$sessionKey" to false only when Basic was used.
Any help would be much appreciated.
The manual section related to basic auth doesn't correspond to what you are saying. Since 2.4 basic/digest auth doesn't need a login action at all. Just including Basic in the array for "authenticate" key for auth config is enough. It will automatically cause cake to check for required credentials when trying to access a protected action and if no credential or invalid credentials are provided appropriate headers are returned to the client.
Using both Basic and Form authenticators together can be problematic. I suggest modifying auth config in beforeFilter to use only either one of them conditionally by using appropriate conditions to check if request is from mobile app or not.

Authenticate a user with my own function/api?

When user submits login form, for authenticating that user instead of using cakephp default authentication $this->Auth->login() I want to call some java based api where I will send user id and password entered by user and that api will return user details if user is authentic and false if not. I want to use cakephp AuthComponent for rest of thing (for example: sessions etc) but just for authenticating a user I want to call my api. Is this possible ? can I override some core method ?
Thanks.
I think this covers it, under "Creating Custom Authentication Objects"
http://book.cakephp.org/2.0/en/core-libraries/components/authentication.html
You can create a class extending BaseAuthenticate in Controllers/Component/Auth folder path. There you have to implement an authenticate() method that, if logged successfully, have to return an array with user data, and if not, return false.
Then you tell Auth component to use your custom authenticate when you call it in AppController by:
'Auth' => array(
'authenticate' => array(
'yourNewAuth' => array(
//other stuff
)
)
)
you can set AuthComponent::$sessionKey to false to ensure AuthComponent doesn’t try to read user info from session.
http://api.cakephp.org/2.4/class-AuthComponent.html

CakePhp Auth : Questions

I've to make a cakePhp authentification, and I wish to use the "Auth" component. I'm trying to see if it fill my requirement:
I need to authenticate users with their email OR their customerId, (with an addition password of course). I can't find if it is possible to have two fields(or more) on which the authentication can be done
I've several parts on which I need to be authenticated. But I need differents granularity:
For some things, it's the whole controller which should not be accessible(if possible with exception(e.g. all the "User" controller, except the login/register action) for other I really need that it's the whole controller(e.g. the cart controller)
Sometimes I need that only some actions are unavailable without being logged
Sometimes I need that only a part of the view isn't displayed(e.g. login element not displayed)
Does the component manage action like password change? Because if the user change its password I need that he did not get disconnected.
Thank you very much for your help
The short answer is that yes, you can do these things, but it seems to me that the ACL might be overkill for your needs (but I also tend to avoid the ACL if there's any opening at all to do so). To your points:
As Ivo suggests, you'll need a custom UsersController::login() method to authenticate by multiple fields (If your auth model isn't User, then use the appropriate controller). If the Auth component's login method fails, it passes control to your custom login() method. Here's a snippet from a project I've been working on:
function login() {
# Allow login by either username (legacy) or email.
# If no authenticated user exists at this point then the Auth
# component's login() method has failed and control has been passed
# here for any further handling. Since the expected credentials
# (email and password) have failed we're going to check for
# username and password.
$user = $this->Auth->user();
if( empty( $user ) && !empty( $this->Auth->data['User']['email'] ) && !empty( $this->Auth->data['User']['password'] ) ) {
$user = $this->User->find(
'first',
array(
'recursive' => -1,
'conditions' => array(
'User.username' => $this->Auth->data['User']['email'],
'User.password' => $this->Auth->data['User']['password'],
)
)
);
if( empty( $user ) || !$this->Auth->login( $user ) ) {
# Set the configured flash message b/c login failed after both checks.
$this->Session->setFlash( $this->Auth->loginError, null, array(), 'auth' );
}
}
$this->redirect( $this->Auth->redirect(), null, true );
}
For action access, just use the $this->Auth->allow() and $this->Auth->deny() methods in each relevant controller's beforeFilter() callback. For example, in the UsersController, you may want to do something like this:
public function beforeFilter() {
parent::beforeFilter();
$this->Auth->deny('*');
$this->Auth->allow( 'login', 'logout' );
}
In views, just determine whether the user is authenticated by testing the Auth.User value to determine what to display/hide from anonymous/authenticated:
if( $this->Session->check( 'Auth.User' ) ) { ... }
If the password changes, you can re-authenticate the user transparently by calling $this->Auth->login( $user_data ). I do this, for example, when a user registers. I don't want him/her to have to then go login, so I just login automatically.
Auth doesn't do exactly what you want out of the box. It can only handle whether a user authentification is required to access an action or not. Once the user is logged in, Auth does not care about the user's level access anymore.
If you wish to use more than two fields, I suggest that you extend the AuthComponent and rewrite the login method to fit your needs. I never did it but I imagine that it is reasonably easy.
Regarding your access levels, I would use ACL that can manage access to actions of all the controllers. Once set up, you will have to manually set the permissions for each actions, either using one of the plugins written by the community or manually.
If you wish to disable part of your views you will need to read the permissions to test the user's access level from there. A good thing would be to save the permissions in a cache file or in the session as the user logs in to make it avaiable in the view. Then write your tests and echo what's needed.
(I am using CakePHP 2.0, I don't know how easily you can extend AuthComponent in 1.3 if you're using it)
With Auth, you need to have exactly 2 fields (that you can specify) to authenticate on. One field (password) will be hashed. Yes, all levels of access you want can be specified in Auth: http://book.cakephp.org/view/1251/Setting-Auth-Component-Variables
You'll have to manage the password change, but the users won't get logged out if they change password.
Sometimes I need that only a part of the view isn't displayed(e.g. login element not displayed)
wut?
Create a custom login() which tries to authenticate through either method.
You can also setup the Authenticate variable to do a custom login.
You can specify in different controllers what parts Auth should be allowing to authenticated users. See Auth methods.
You can also use ACL (see the full Cake ACL tutorial, etc) to control granular permissions.
Sometimes I need that only a part of the view isn't displayed
Create an element which checks for Auth->user() to select what content to display.
For the Allow and Deny part can be easily done with the Auth Component.
use something like
$this->allow('*'); // to allow every thing
$this->deny('*'); // to deny every thing
$this->allow('login', 'signup'); // allows login and sign up without being logged in
$this->deny('profile', 'password'); // need to be logged into to access profile and password and rest of the actions are allowed.
For the change of password you can save the changed password to the database and force logout the user and redirect him to login again
$this->Auth->logout(); this forces the user to logout of cakephp Auth
For the first question - loggin in using email or customer id is not directly possible using cakephp Auth component as you will have to define in particular which of them acts as a username.
Alternative solution is you can just copy the Auth Component into your app/controller/component and hack the code.
When you receive the user name you can test it against email and customer id and maintain the flow.
Hope this helps

Categories