I am trying to print / echo utm_source, utm_medium and utm_campaign query values using this PHP code;
echo $_GET['utm_source'];
But strangely for some unknown reason on my server its not printing the values, when I replace utm_source to something else like test_source I am able to see the value in print.
Never faced any such issue, can anyone guide me here.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php echo $_GET['utm_source']; ?>
</body>
</html>
If your site is using WPengine, you will not be able to get the utm variables (and any additional variables after the utm's) out of the URL using PHP. Some web hosts specifically target and remove these utm parameters from server requests for performance reasons. Tricky part is, utm variables are still going remain in the URL which means that you can retrieve them using Javascript instead if you need to.
Source: WPengine article
https://wpengine.com/support/utm-gclid-variables-caching/
Your original question quoted this code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php $_GET['utm_source']; ?>
</body>
</html>
If you add an echo to this statement it will work
<?php echo $_GET['utm_source']; ?>
when tested using
test.com/test.php?utm_source=1
A safer piece of PHP code would be
<?php
if ( isset($_GET['utm_source']) ) {
echo $_GET['utm_source'];
} else {
echo 'the parameter utm_source is missing';
}
?>
I know it's late. but maybe this answer helps another developer.
// get the value of outlink, source, campaign, medium, content
let url = new URL(window.location.href);
let outlink = url.searchParams.get('outlink'),
utmSource = url.searchParams.get('utm_source'),
utmCampaign = url.searchParams.get('utm_campaign'),
utmMedium = url.searchParams.get('utm_medium'),
utmContent = url.searchParams.get('utm_content');
console.table( { outlink , utmSource, utmCampaign,
utmMedium,utmContent});
Related
I protect page from being access and can only access it by a referrer page, here is my code on landing page
<?php
// request file coming from test referrer
if(stristr($_SERVER['HTTP_REFERER'],"http://aqsv.com/sites2/testreffer/tp1.php"))
{
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<h1>Test Landing Page 1</h1>
</body>
</html>
<?php
}
// redirect to redirect.php
else {
header("Location: http://aqsv.com/sites2/testlander/redirect.php");
}
?>
and this is the referrer page
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Test Refererrer 1</title>
</head>
<body>
<h1>Test Refererrer 2</h1>
Link me to landing page1
</body>
</html>
this work perfectly on single referrer page only, what i want to do is to have multiple referrer page to access the page , Im new to php and really dont have any idea to do this.. I tried adding http referrer using if else like this
<?php
// request file coming from test referrer
if(stristr($_SERVER['HTTP_REFERER'],"http://aqsv.com/sites2/testreffer/tp1.php"));
elseif(stristr($_SERVER['HTTP_REFERER'],"http://aqsv.com/sites2/testreffer/tp2.php"))
{
?>
but the second link is not working. Any help would be highly appreciated. Thanks
You can take an array containing all your valid referrer domain. E.g.
<?php
$valid_domains = array(
'domain1',
'domain2',
'domain3'
);
// The checking for valid domain
if ( in_array($_SERVER['HTTP_REFERER'], $valid_domains) )
{
?>
Your HTML goes here....
<?php
}
?>
Please see http://php.net/manual/en/function.in-array.php
Hope the idea will help you.
The syntax if if/elseif... is:
if (something) {
body
} elseif (somethingelse) {
body
}
But you have no body for your if, only for the elseif, so nothing happens in that case.
Since you want the same body for all your tests, you should just use a single if with multiple conditions connected by OR:
if (stristr($_SERVER['HTTP_REFERER'],"http://aqsv.com/sites2/testreffer/tp1.php") ||
stristr($_SERVER['HTTP_REFERER'],"http://aqsv.com/sites2/testreffer/tp2.php")) {
...
}
Another way you can do this is by putting all the allowed referers in an array, and then doing:
if (in_array(strtolower($_SERVER['HTTP_REFERER']), $allowed_referers)) {
...
}
I use strtolower() to make it case-insensitive, like your original tests.
One field of my mysql table contains body of an email received, now when I fetch this value in variable of PHP and just try to echo it just shows actual code.
How could i make to display as HTML-:
HTML stored in mysql-:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<table width="200" border="1">
<tr>
<td><img src="http://myntra.myntassets.com/assets/banners/2014/3/12/1394610923636-footwear_micro-banner_160_120_mini.jpg" width="700" height="154" /></td>
</tr>
</table>
</body>
</html>
PHP-:
<?php
///......get value from DB and assign it to variable $body.
$body="$content";
echo $body;
?>
When you insert the data into your database I bet you are using html_entities over it.
Which is quite a good thing actually.
To get your html back, try using html_entity_decode() on the content you need to serve as html.
Beware of XSS attacks though.
I am guessing that you want to display the HTML content of your email.htmlentities should work. Try this-
echo htmlentities($body);
try to do this
$body="'".$content."'";
echo $body;
cause when you add single quotation to the html code it's executed before printed
or you have to add \ before every "
for example
<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\">
i tried the both ways and they worked fine
Why I am not able to end a javascript inside a PHP heredoc?
The rest of the code below this line:
</script>
become not part of PHP's code. They become HTML code.
It is like the end script code ends the PHP block.
$headerContent = <<<HEAD
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-US" lang="en-US">
<head>
<title>$title</title>
<meta http-equiv="content-type" content="text/html; charset=iso-8859-2" />
<script>
</script> // Here is the problem
</head> // code here and below becomes not part of PHP.
<body>
.
.
.
HEAD;
Any tips for solving this problem?
Although I can't reproduce this with HEREDOC (it's possible that different versions of PHP behave differently in this respect), </script> is equivalent to ?> in PHP code, because it's a counterpart to <script language="php">. Example:
<script language="php"> $a = 1; </script>
Test: <?= $a ?>
So wherever you encounter problems with the ?> closing tag, you'll also encounter the same problems with the </script> closing tag. One option would be to store this in a variable and use it. Example:
<?php
$endScript = '</' . 'script>';
$headerContent = <<<HEAD
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-US" lang="en-US">
<head>
<title>$title</title>
<meta http-equiv="content-type" content="text/html; charset=iso-8859-2" />
<script>
$endScript
</head>
<body>
.
.
.
HEAD;
I currently have a very simple page that redirects to another URL. However for some reason, I cannot get this to work.
I'm sure there is a very simple solution to this problem and any help to make me understand exactly what's going on would be appreciated.
Here is my page:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test - Youtube</title>
</head>
<body>
<?php
ob_start();
header('Location: vnd.youtube:xjTEqVQVsQs');
ob_end_flush();
?>
</body>
</html>
Thanks
You are having some Outputs on your page before sending header and that's why you can not redirect, you should use output buffering like this:
<?php
ob_start();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test - Youtube</title>
</head>
<body>
<?php
header('Location: vnd.youtube:xjTEqVQVsQs');
die();
?>
</body>
</html>
<?php
ob_end_flush();
?>
<?php
ob_start();
header('Location: vnd.youtube:xjTEqVQVsQs');
ob_end_flush();
?>
remove all the html except above php code if it's only a redirect page.
This is how the code should look like:
<?php
ob_start();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test - Youtube</title>
</head>
<body>
<?php
header('Location: vnd.youtube:xjTEqVQVsQs'); // Are you sure that's the right
address?
?>
</body>
</html>
<?php
ob_end_flush();
?>
Anyway, the page is redirecting to another page, why do you need the html tags?
You should remove all the page content except PHP script:
<?php
ob_start();
header('Location: vnd.youtube:xjTEqVQVsQs');
ob_end_flush();
?>
Or
put your PHP script on top of the page:
<?php
ob_start();
header('Location: vnd.youtube:xjTEqVQVsQs');
ob_end_flush();
?>
Make sure there is no empty space before php tag above.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test - Youtube</title>
</head>
<body>
</body>
</html>
As redirect sends headers to the browser it MUST be sent before any output.
You can use the method below to redirect using a different method depending on whether the headers have been sent:
<?php
function redirect($filename) {
if ( ! headers_sent())
header('Location: '.$filename);
exit; // just a good practice to EXIT after redirecting
else {
echo '<script type="text/javascript">';
echo 'window.location.href="'.$filename.'";';
echo '</script>';
echo '<noscript>';
echo '<meta http-equiv="refresh" content="0;url='.$filename.'" />';
echo '</noscript>';
}
}
redirect('http://www.google.com');
?>
This will fallback to using javascript if the headers have already been sent.
If you want to use the header() method it must be at the top of your code before any other output (including whitespace).
Well, I'm trying to get an iframe from a URL of this sort: http://mydomain.com/frame.php?q=http://someotherdomain.com
For some reason I am getting a server error with this code and cannot figure out why. Does anyone see something wrong?
Thanks!
<?php
$q = $_GET('q');
function getTitle($Url){
$str = file_get_contents($Url);
if(strlen($str)>0){
preg_match("/\<title\>(.*)\<\/title\>/",$str,$title);
return $title[1];
}
};
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><?php echo getTitle($q) ?></title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<?php echo "<iframe src='".$q."' style='width:100%;height:100%;border:0;'></iframe>" ?>
</body>
</html>
Well, for starters, this
$q = $_GET('q');
should be
$q = $_GET['q'];
PLEASE NOTE
This method you are using is highly insecure. Consider a malicious person making the following request.
http://mydomain.com/frame.php?q=..%2F..%2F..%2F..%2Fetc%2Fapache2%2Fhttpd.conf
By providing different values of q, the attacker can potentially read any file readable by the webserver's user.
Try this:
<?php
$URL = parse_url($_SERVER['REQUEST_URI'];
/* make sure the title is the first parameter and only param passed, otherwise include a ltrim to get rid of everything starting with & */
$q = rtrim('=', $URL['query']);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><?php=$q?></title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body style="margin: 0;">
<?php='<iframe src="' . $whateverURL . '" style="width: 100%; height: 100%; border: 0px;" />'?>
</body>
</html>
take a look at your apache log error
it is usually at:
tail -f /var/log/apache2/error.log