Displaying search results using mysqli multiquery - php

Question

How can i display search results using mysqli multiquery. I want to display values from my listing-details table and from my user table. Here is my code:
$searchquery="SELECT * FROM `listing-details` WHERE `listing-address` LIKE '%" . $address . "%' AND `listing-address-street` LIKE '%" . $street . "%' AND `listing-address-barangay-id` LIKE '%" . $barangay . "%'";
$searchquery.= "SELECT `user.user-username`, `user.user-firstname`, `user.user-lastname`, `listing-details.user-username` FROM `user`, `listing-details` WHERE `listing-details.user-username`=`user.user-username`";
if (mysqli_multi_query($conn, $searchquery)) {
do {
if ($result=mysqli_store_result($conn,$searchquery)){
while($row=mysqli_fetch_row($result)){
$listingid =$row['listing-id'];
$username =$row['user-username'];
$listingbedquantity =$row['listing-bedquantity'];
$listingbedtype =$row['listing-bedtype-id'];
$listingguestsquantity =$row['listing-guestsquantity'];
$listingplacetype =$row['listing-placetype-id'];
$listingpropertytype =$row['listing-propertytype-id'];
$listingbathroomquantity =$row['listing-bathroomquantity'];
$listingaddress =$row['listing-address'];
$listingstreet =$row['listing-address-street'];
$listingbarangay =$row['listing-address-barangay-id'];
$listingamenities =$row['listing-amenities-basic-id'];
$listingsafetyamenities =$row['listing-amenities-safety-id'];
$listingsaphotos =$row['listing-amenities-safety-photos-id'];
$listingspace =$row['listing-space-id'];
$listinglandmark =$row['listing-landmark'];
$listingpreferences =$row['listing-preferences-id'];
$listingphotoset =$row['listing-photosset-id'];
$listingexperience =$row['listing-experience-id'];
$listingfrequency =$row['listing-frequency-id'];
$listingstartdate =$row['listing-startdate'];
$listingrate =$row['listing-rate-id'];
$listingprice =$row['listing-price'];
$listingrules =$row['listing-rules-id'];
$listingtitle =$row['listing-title'];
$listingdescription =$row['listing-description'];
$firstname =$row['user-firstname'];
$lastname =$row['user-lastname'];
echo "<ul>\n";
echo "<li>"."" . "<h2>" . $listingtitle . "</h2></li>\n";
echo "<li><h6>" . $listingaddress . ", " . $listingstreet . ", " . $listingbarangay . "</h6></li>";
echo "<li><i>" . $listingdescription . "</i></li>";
echo "<ul>\n";
echo "<li>"."" . "<h2>" . $listingtitle . "</h2></li>\n";
echo "<li><h6>" . $listingaddress . ", " . $listingstreet . ", " . $listingbarangay . "</h6></li>";
echo "<li><i>" . $listingdescription . "</i></li>";
echo "<li style='float:right;'>By: " . $firstname . " " . $lastname . "</i></li>";
echo "</ul>";
echo "<hr width='80%' noshade='1'>";
}
mysqli_free_result($result);
}
}
while (mysqli_next_result($conn));
}
However, when I get to run it,the page loads, but results won't show. The purpose of it is to be able to display listing details from a listing-details table listed by the complete name from the user table. Two two tables have user-username column as common key.

Answer 1

Like many learners, you are using the wrong tool, simply because you don't know the proper one.
You need not a multiquery (which you never actually need anyway) but a JOIN.
Simply rewrite your two monster queries to a join like this
$searchquery="SELECT l.*, u.`user-username`, u.`user-firstname`, u.`user-lastname`
FROM `listing-details` l, user u
WHERE l.`user-username`=u.`user-username`
AND `listing-address` LIKE ...";
Besides, your quoting is wrong.