Good Day!
I have a dropdown menu which select employee number and shows table data on basis of that particular selection. I have save as pdf code which saves table data in pdf. It is working fine but my table column headers are only shown not the values.
I have dropdown in one file having javascript which is sent to another file where my table is shown.
Below is the code for my all files and what I have tried for this so far.
For Dropdown:
<?php
include("connect-db.php");
?>
<html>
<head>
<title>PHP insertion</title>
<link rel="stylesheet" href="css/insert.css" />
<link rel="stylesheet" href="css/navcss.css" />
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","search_empnumber.php?emp_id="+str,true);
xmlhttp.send();
}
}
/*function showAssessories(acc) {
if (acc == "") {
document.getElementById("txtHint2").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint2").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","getassessories.php?emp_id="+acc,true);
xmlhttp.send();
}
}*/
</script>
</head>
<body>
<div class="maindiv">
<?php include("includes/head.php");?>
<?php include("menu.php");?>
<div class="form_div">
<form>
<div class="forscreen">
<h1>Search Records:</h1>
<p>You may search by Employee Number</p>
<select name="employeenumber" class="input" onchange="showUser(this.value)">
<option value="">Please Select Employee Number:</option>
</div>
<?php
$select_emp="SELECT distinct(emp_number) FROM employees";
$run_emp=mysql_query($select_emp);
while($row=mysql_fetch_array($run_emp)){
$emp_id=$row['emp_id'];
$first_name=$row['first_name'];
$last_name=$row['last_name'];
$emp_number=$row['emp_number'];
$total_printers=$row['total_printers'];
$total_scanners=$row['total_scanners'];
$total_pc=$row['total_pc'];
$total_phones=$row['total_phones'];
$other_equips=$row['other_equips'];
?>
<option value="<?php echo $emp_number;?>"><?php echo $emp_number;?></option>
<?php } ?>
</select>
<html>
</form>
</div>
<br>
<div id="txtHint"></div>
<br>
<div id="txtHint2"></div>
</div>
<?php include 'includes/foot.php';?>
</body>
</html>
The function for dropdown: onchange="showUser(this.value)"
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","search_empnumber.php?emp_id="+str,true);
xmlhttp.send();
}
}
search_empnumber.php File:
<!DOCTYPE html>
<html>
<form action="search_empnumber.php" method="POST">
<input type="submit" value="SAVE AS PDF" class="btnPDF" name="submit" />
</form>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
.link{ color:#00F; cursor:pointer;}
</style>
</head>
<body>
<?php
//$emp_id =($_REQUEST['emp_id']);
$emp_id =($_REQUEST['emp_id']);
$count=1;
include("connect-db.php");
//$sql = "SELECT * from employees where department='".$department."'";
//$sql = "select * from employees as pg inner join accessories as pd on pg.emp_number= pd.emp_number ";
//$result = mysql_query($sql) or die(mysql_error());
//$result = mysql_query($query) or die(mysql_error());
//$emp_id =($_POST['employeenumber']);
$sql="SELECT * FROM employees WHERE emp_number = '".$emp_id."'";
$result = mysql_query($sql) or die(mysql_error());
$count=1;
echo "<table>
<tr>
<th>S.No</th>
<th>First Name</th>
<th>Last Name</th>
<th>Employee Number</th>
<th>Department</th>
<th>Email</th>
<th>Total Printers</th>
<th>Total Scanners</th>
<th>Total Pc</th>
<th>Total Phones</th>
<th>Other Equipments</th>
</tr>";
while($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" . $count . "</td>";
echo "<td>" . $row['first_name'] . "</td>";
echo "<td>" . $row['last_name'] . "</td>";
echo "<td>" . $row['emp_number'] . "</td>";
echo "<td>" . $row['department'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['total_printers'] . "</td>";
echo "<td>" . $row['total_scanners'] . "</td>";
echo "<td>" . $row['total_pc'] . "</td>";
echo "<td>" . $row['total_phones'] . "</td>";
echo "<td>" . $row['other_equips'] . "</td>";
echo "</tr>";
$count++;
}
echo "</table>";
echo '<div class="forscreen">';
// echo '<br />';echo '<button class="btnPrint" type="submit" value="Submit" onclick="window.print()">Print</button>';
//echo '<input type="submit" value="SAVE AS PDF" class="btnPDFsearch" name="submit"/>';
// echo '<input type="submit" value="SAVE AS PDF" class="btnPDF" name="submit" />';
echo '</div>';
echo '<div class="forscreen">';
//echo '<br />';echo '<button class="btnPrevious" type="submit" value="Submit" onclick="history.back(); return false;">Previous Page</button>';
echo '</div>';
?>
</body>
</html>
PDF code (I tried) in same file of search_empnumber:
<?php
error_reporting(E_ALL ^ E_DEPRECATED);
include('connect-db.php');
?>
<?php
//if($_POST['submit']){
if (isset($_POST['submit'])){
require_once 'includes/practice.php';
$pdf->SetFont('times', '', 11);
$tb1 = '</br></br>
<table cellspacing="0" cellpadding="5" border="1">
<tr style="background-color:#f7f7f7;color:#333; ">
<td width="60">First Name</td>
<td width="60">Last Name</td>
<td width="80">Employee Number</td>
<td width="80">Department</td>
<td width="60">Email</td>
<td width="80">Total Printers</td>
<td width="80">Total Scanners</td>
<td width="60">Total PCs</td>
<td width="60">Total Phones</td>
<td width="60">Other Equipments</td>
</tr>
</table>';
include('connect-db.php');
//$emp_id =($_POST['emp_id']);
$emp_id =($_POST['employeenumber']);
$result1= mysql_query("SELECT * FROM employees where emp_number = '".$emp_id."'");
while($row = mysql_fetch_assoc($result1)){
$tb2 = '<table cellspacing="0" cellpadding="5" border="1">
<tr>
<td width="60">' . $row['first_name'] . '</td>
<td width="60">' . $row['last_name'] . '</td>
<td width="80">'. $row['emp_number'] .'</td>
<td width="80">'.$row['department'].'</td>
<td width="60">'.$row['email'].'</td>
<td width="80">'.$row['total_printers'].'</td>
<td width="80">'.$row['total_scanners'].'</td>
<td width="60">'.$row['total_pc'].'</td>
<td width="60">'.$row['total_phones'].'</td>
<td width="60">'.$row['other_equips'].'</td>
</tr>
</table>';
$tb1 = $tb1.$tb2;
}
$pdf->writeHTML($tb1, true, false, false, false, '');
ob_end_clean();
$pdf->Output('Report.pdf', 'D');
}
?>
The files i.e. practoce.php and pdf libraries are not added becuase they are just creating tables in defined formats
You are mixing up GET and POST. Try one (or both) of the following:
1) In the dropdown code, replace <form> with:
<form method="POST">
2) In the table generation code, read the value back with:
$emp_id =($_REQUEST['employeenumber']);
and also:
if (isset($_REQUEST['submit'])){
To add to your problems, in the first version of search_empnumber.php you posted, you read back $emp_id =($_REQUEST['emp_id']); when the posted value will actually be in $_REQUEST['employeenumber'].
I don't know which part is going wrong for you, but there's some strange things going on in that dropdown code:
<select name="employeenumber" class="input" onchange="showUser(this.value)">
<option value="">Please Select Employee Number:</option>
</div> <!-- ISSUE: Closed a div which was never opened. You're lucky the select box even shows anything-->
<?php
$select_emp="SELECT distinct(emp_number) FROM employees";
$run_emp=mysql_query($select_emp);
//ISSUE: You loop through a lot of data, but then do nothing with it. With every pass of the loop, you simply change the variables, and nothing else. I think you meant to move your <option> into the loop
while($row=mysql_fetch_array($run_emp)){
//ISSUE: You only selected 'emp_number' in your query. Most of these array keys are never filled
$emp_id=$row['emp_id'];
$first_name=$row['first_name'];
$last_name=$row['last_name'];
$emp_number=$row['emp_number']; //This is the only one filled
$total_printers=$row['total_printers'];
$total_scanners=$row['total_scanners'];
$total_pc=$row['total_pc'];
$total_phones=$row['total_phones'];
$other_equips=$row['other_equips'];
?>
<!--ISSUE: Only the last $emp_number from the query is filled. The rest you kept overwriting in your loop-->
<option value="<?php echo $emp_number;?>"><?php echo $emp_number;?></option>
<?php } ?>
</select>
Related
i have a drop down list populated from a database(it is the first cell in a table row) then based on that selection i want it to populate the rest of the row from the same database, each cell is a different table in the database, so far i only have it populating the first cell (calories), i can't figure out how to get it to populate the rest of the cells, thanks
<?php
$link=mysqli_connect("localhost", "root", "");
mysqli_select_db($link,"meal_planner");
?>
<!DOCTYPE html>
<html>
<head>
<title>Meal Planner</title>
<link href="main2.css" rel="stylesheet" type="text/css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type="text/javascript">
jQuery(document).ready(function($){
// Hide all panels to start
var panels = $('.accordion > dd').hide();
// Show first panel on load (optional). Remove if you want
panels.first().show();
// On click of panel title
$('.accordion > dt > a').click(function() {
var $this = $(this);
// Slide up all other panels
panels.slideUp();
//Slide down target panel
$this.parent().next().slideDown();
return false;
});
});
</script>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("txtHint").innerHTML = this.responseText;
}
};
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<dl class="accordion">
<dt>Monday</dt>
<dd>
<table>
<tr>
<th>Breakfast</th>
<th>Calories</th>
<th>Protein</th>
<th>Carbs</th>
<th>Fat</th>
<th>Serving Sizing</th>
</tr>
<tr>
<td>
<select name="breakfa"s onchange="showUser(this.value)">
<option value="">Select a Protein:</option>
<?php
$res=mysqli_query($link,"select name, protein_id from protein");
while($row=mysqli_fetch_array($res))
{
?>
<option value="<?php echo $row["protein_id"]; ?>"><?php echo $row["name"]; ?></option>
<?php
}
?>
</select>
</td>
<td><div id="txtHint"><b>0</b></div></td>
<td>50</td>
<td>50</td>
<td>50</td>
<td><input type="" name=""></td>
</tr>
</table>
</dd>
<dt>Tuesday</dt>
<dd>TEST</dd>
<dt>Wednesday</dt>
<dd>TEST.</dd>
</dl>
</body>
</html>
php
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','','meal_planner');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"ajax_demo");
$sql="SELECT * FROM protein WHERE protein_id = '".$q."'";
$result = mysqli_query($con,$sql);
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['calories'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
After advice taken from the community i started work on a AJAX/php script to retrieve data based on a variable from a MySQL database. It works reasonably well now i'd like to be able to click on any of the variables that are shown and that take you to another page whilst remembering your selection. Is this possible?
Here is a link to my website.
Here is my PokemonFight.php code:
<!DOCTYPE html>
<html>
<head>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","getpokemon.php?q="+str,true);
xmlhttp.send();
}
}
</script>
<style>
table {
font-family: arial, sans-serif;
border-collapse: collapse;
width: 100%
}
td, th {
border: 1px solid #dddddd;
text-align: left;
padding: 8px
}
</style>
<title>Pokemon Fight!</title>
</head>
<body>
<h1><center>Pokemon Fight!</center></h1>
<h2>Select your type!</h2>
<form>
<select name="test" onchange="showUser(this.value)">
<option value="">Select a Pokemon Type!:</option>
<option value="1">Normal</option>
<option value="2">Fire</option>
<option value="3">Fighting</option>
<option value="4">Water</option>
<option value="5">Flying</option>
<option value="6">Grass</option>
<option value="7">Poison</option>
<option value="8">Electric</option>
<option value="9">Ground</option>
<option value="10">Psychic</option>
<option value="11">Rock</option>
<option value="12">Ice</option>
<option value="13">Bug</option>
<option value="14">Dragon</option>
<option value="15">Ghost</option>
<option value="16">Dark</option>
<option value="17">Steel</option>
<option value="18">Fairy</option>
</select>
</form>
<br>
<div id="txtHint"><b>Pokemon info will be listed here...</b></div>
</body>
</html>
Here is my getpokemon.php code:
</head>
<body>
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','password','pokemon');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"pokemon");
$sql="SELECT * FROM test WHERE id = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>Pokemon Name</th>
<th>PokedexID</th>
<th>Move 1</th>
<th>Move 2</th>
<th>Move 3</th>
<th>Move 4</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['PokedexID'] . "</td>";
echo "<td>" . $row['Pokemon_Move_1'] . "</td>";
echo "<td>" . $row['Pokemon_Move_2'] . "</td>";
echo "<td>" . $row['Pokemon_Move_3'] . "</td>";
echo "<td>" . $row['Pokemon_Move_4'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
</body>
</html>
The folowing piece of code was what i wasn't understanding but replacing what i previously with this new piece of code added a hyperlink on the Pokemon name which links to another page that i'm creating with an ID value of the PokedexID. Hope this helps anyone that was as stuck as i was.
Before Code:
echo "<td>" . $row['PokedexID'] . "</td>";
After Code:
echo "<td><a href=' viewpokemon.php?PokedexID=" . $row["PokedexID"] . "'>" . $row["Pokemon_Name"] . "</a></td>"
I am using ajax to fetch information for my database and im running into a problem. nothing is being shown in return.
I have a select list that calls for a js script to run onchange, that calls for the php file to get the database information and return it in a table.
the problem is that upon the onchange event, I have a table show up with just the table heads but no information below. I checked console and the error Im getting is this:
GET http://lineofcode.com/favicon.ico 401 (Unauthorized)
thats the only error that shows. What am i doing wrong? why is my table blank?
html
<p>Please select a team name from the list to view table</p>
<form>
<select name="users" onchange="showTeam(this.value)">
<option value="">Select a team:</option>
<option value="1">bobcats</option>
<option value="2">rangers</option>
<option value="3">hawks</option>
<option value="4">rockets</option>
</select>
</form>
<br>
<div id="teamInfo"><b></b></div>
JS script
// script for onchange event
function showTeam(str) {
if (str == "") {
document.getElementById("teamInfo").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("teamInfo").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","phpfiles/getTeam.php?q="+str,true);
xmlhttp.send();
}
}
php file
<!DOCTYPE html>
<html>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','....','.....','....');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"ajax_demo");
$sql="SELECT * FROM teams WHERE teamname = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>teamname</th>
<th>city</th>
<th>bestplayer</th>
<th>yearformed</th>
<th>website</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['teamname'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['bestplayer'] . "</td>";
echo "<td>" . $row['yearformed'] . "</td>";
echo "<td>" . $row['website'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
Just an observation but shouldn`t code be like this ?
xmlhttp.open("GET","phpfiles/getTeam.php?q="+str,true);
xmlhttp.send();
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("teamInfo").innerHTML = xmlhttp.responseText;
}
};
Also try to print_r($_GET) to see if the value is being posted
Not sure if this is the problem but you are using intval() --e.g. for converting input string to integers --and your teamnames in your database won't match that (assuming you've given your teams names and not numbers).
I've put together the form below that allows a user to retrieve database records from the date they select from a drop down menu.
<html>
<head>
<script type="text/javascript">
function ajaxFunction(name)
{
var browser = navigator.appName;
if(browser == "Microsoft Internet Explorer")
{
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
else
{// code for IE6, IE5
xmlhttp=new XMLHttpRequest();
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("my_div").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getrecords.php?dateoftrip="+name,true);
xmlhttp.send();
}
function getquerystring() {
var form = document.forms['frm1'];
var word = form.word.value;
qstr = 'w=' + escape(word); // NOTE: no '?' before querystring
return qstr;
}
</script>
<style type="text/css">
<!--
.style1 {
font-family: Calibri;
font-size: 14px;
}
-->
</style>
</head>
<body>
<form action="getrecords.php" method="get" name="frm1">
<table width="148" border="0">
<tr>
<td width="152"><p class="style1">Select a date from below</p>
<div align="center">
<?php
include("db.php");
$query="select * from finds group by dateoftrip";
echo '<select onchange="ajaxFunction(this.value)">';
$result=mysql_query($query);
while($rows=mysql_fetch_array($result)){
echo "<option name='name' value=".$rows['dateoftrip'].">".$rows['dateoftrip']."</option>";
}
echo "</select>";
?>
</div></td>
</tr>
</table>
</form>
<div id="my_div"></div>
</body>
</html>
and this is the php script which retrieves the records.
<?php
include("db.php");
$dateoftrip= $_GET['dateoftrip'];
$findname= $_GET['findname'];
$finddescription= $_GET['finddescription'];
$query="select * from finds where dateoftrip='$dateoftrip'";
echo "<table>";
$result=mysql_query($query);
while($rows=mysql_fetch_array($result)){
echo "<tr>";
echo "<td>Find Name : </td>";
echo "<td>".$rows['findname']."</td>";
echo "</tr>";
echo "<tr>";
echo "<td>Find Description : </td>";
echo "<td>".$rows['finddescription']."</td>";
echo "</tr>";
}
echo "</table>";
?>
I'd like to extend the functionality a little if at all possible, by adding a 'All Records' option to the drop down menu which obviously returns all the records for the current user.
I've been searching for this for a few days now, and I haven't found an example where there is this added functionality.
I just wondered whether someone could perhaps provide some guidance on how I may go abut this please.
Amended Form Code
<html>
<head>
<script type="text/javascript">
function ajaxFunction(name)
{
var browser = navigator.appName;
if(browser == "Microsoft Internet Explorer")
{
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
else
{// code for IE6, IE5
xmlhttp=new XMLHttpRequest();
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("my_div").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getrecords.php?dateoftrip="+name,true);
xmlhttp.send();
}
function getquerystring() {
var form = document.forms['frm1'];
var word = form.word.value;
qstr = 'w=' + escape(word); // NOTE: no '?' before querystring
return qstr;
}
</script>
<style type="text/css">
<!--
.style1 {
font-family: Calibri;
font-size: 14px;
}
-->
</style>
</head>
<body>
<form action="getrecords.php" method="get" name="frm1">
<table width="148" border="0">
<tr>
<td width="152"><p class="style1">Select a date from below</p>
<div align="center">
<?php
include("db.php");
$query="select * from finds group by dateoftrip";
echo '<select onchange="ajaxFunction(this.value)"><OPTION name="name" value="ALLRECORDS">';
$result=mysql_query($query);
while($rows=mysql_fetch_array($result)){
echo "<option name='name' value=".$rows['dateoftrip'].">".$rows['dateoftrip']."</option>";
}
echo "</select>";
?>
</div></td>
</tr>
</table>
</form>
<div id="my_div"></div>
</body>
</html>
Create an option for the 'ALL' thing
echo '<select onchange="ajaxFunction(this.value)"><OPTION name="name" value="ALLRECORDS">All Records</option>';
Handle your query for the 'ALL' thing
if ($dateoftrip=="ALLRECORDS") {
$query="select * from finds";
} else {
$query="select * from finds where dateoftrip='$dateoftrip'";
}
On a side note you should look about SQL Injection, not using the '*' selector but typing the explicit name of attributes you search
hello
i get some help here yesterday for a problem i was having tablesorter. if i run the backend query on its own it displays the results ok. but i call it from another page from dropdown it displays all records and no errors are being seen in firebug. where am i going wrong? thanks
this code works on its own.
getuserlog.php
<?php
$q=$_GET["q"];
$con = mysql_connect('localhost', 'root', '');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("sample", $con);
$sql="SELECT * FROM logger_log WHERE idusr_log = '".$q."' order by datein_log desc";
$result = mysql_query($sql);
echo "<table id=\"userlog\" class=\"tablesorter\" cellspacing=\"1\">
<thead>
<tr>
<th align=\"left\">Ip Address</th>
<th align=\"left\">Date In</th>
<th align=\"left\">Date Out</th>
</tr>
</thead>";
echo "<tbody>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ip_log'] . "</td>";
echo "<td>" . date('d/m/Y H:i:s',strtotime($row['datein_log'])) . "</td>";
echo "<td>" . date('d/m/Y H:i:s',strtotime($row['dateout_log'])) . "</td>";
echo "</tr>";
}
echo"</tbody>";
echo "</table>";
mysql_close($con);
?>
<div id="pager" class="pager">
<form>
<img src="css/blue/first.png" class="first"/>
<img src="css/blue/prev.png" class="prev"/>
<input type="text" class="pagedisplay"/>
<img src="css/blue/next.png" class="next"/>
<img src="css/blue/last.png" class="last"/>
<select class="pagesize">
<option selected="selected" value="10">10</option>
<option value="20">20</option>
<option value="30">30</option>
<option value="40">40</option>
</select>
</form>
</div>
<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.pager.js"></script>
<link href="css/blue/style.css" rel="stylesheet" type="text/css" />
<script>
$(function() {
$("#userlog")
.tablesorter({widthFixed: true, widgets: ['zebra']})
.tablesorterPager({container: $("#pager")});
});
</script>
and this is the page i am calling it from.
userlog.php
<script type="text/javascript">
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuserlog.php?q="+str,true);
xmlhttp.send();
}
</script>
<div class="spacer"></div>
<div class="userlogTxt">This report shows all users who have logged in up until: <?php echo date("d/m/Y H:i:s"); ?></div>
<br />
<?php
$conn = mysql_connect('localhost', 'root', '') or die(mysql_error());
mysql_select_db("sample") or die(mysql_error());
$result2 = mysql_query('SELECT * FROM user_usr ORDER BY name_usr ASC', $conn);
echo '<select name="users" onchange="showUser(this.value)">';
echo '<option value="selected">'. 'Select a user' . '</option>';
while ($row = mysql_fetch_assoc($result2))
{
echo '<option value="'.$row['id_usr'].'">'.$row['name_usr'].'</option>';
}
echo '</select>';
?>
<br /><br />
<div id="txtHint" class="userlogTxt">Logging information will be shown here.</div></div>
#inti
it is not pulling any date from the db. just displaying header and pager.
userlog.php
<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.pager.js"></script>
<link href="css/blue/style.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
function showUser(str)
{
$.get("getuserlog.php?q="+str,function(response) {
$("#txtHint").html(response);
// Tablesorter will run, just after you loaded the ajax response
$("#userlog").tablesorter({widthFixed: true, widgets: ['zebra']})
.tablesorterPager({container: $("#pager")
});
});
}
</script>
<div class="spacer"></div>
<div class="userlogTxt">This report shows all users who have logged in up until: <?php echo date("d/m/Y H:i:s"); ?></div>
<br />
<?php
$conn = mysql_connect('localhost', 'root', '') or die(mysql_error());
mysql_select_db("sample") or die(mysql_error());
$result2 = mysql_query('SELECT * FROM user_usr ORDER BY name_usr ASC', $conn);
echo '<select name="users" onchange="showUser(this.value)">';
echo '<option value="selected">'. 'Select a user' . '</option>';
while ($row = mysql_fetch_assoc($result2))
{
echo '<option value="'.$row['id_usr'].'">'.$row['name_usr'].'</option>';
}
echo '</select>';
?>
<br /><br />
<div id="txtHint" class="userlogTxt">Logging information will be shown here.</div></div>
getuserlog.php
<?php
$q=$_GET["q"];
$con = mysql_connect('localhost', 'root', '');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("sample", $con);
$sql="SELECT * FROM logger_log WHERE idusr_log = '".$q."' order by datein_log desc";
$result = mysql_query($sql);
echo "<table id=\"userlog\" class=\"tablesorter\" cellspacing=\"1\">
<thead>
<tr>
<th align=\"left\">Ip Address</th>
<th align=\"left\">Date In</th>
<th align=\"left\">Date Out</th>
</tr>
</thead>";
echo "<tbody>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['ip_log'] . "</td>";
echo "<td>" . date('d/m/Y H:i:s',strtotime($row['datein_log'])) . "</td>";
echo "<td>" . date('d/m/Y H:i:s',strtotime($row['dateout_log'])) . "</td>";
echo "</tr>";
}
echo"</tbody>";
echo "</table>";
mysql_close($con);
?>
<div id="pager" class="pager">
<form>
<img src="css/blue/first.png" class="first"/>
<img src="css/blue/prev.png" class="prev"/>
<input type="text" class="pagedisplay"/>
<img src="css/blue/next.png" class="next"/>
<img src="css/blue/last.png" class="last"/>
<select class="pagesize">
<option selected="selected" value="10">10</option>
<option value="20">20</option>
<option value="30">30</option>
<option value="40">40</option>
</select>
</form>
</div>
where have i gone wrong? thanks
I recommend you, to use the jQuery Ajax functions in userlog.php, and since the script inside getuserlog.php is constant, move it to the userlog.php, something like this:
<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.min.js"></script>
<script type="text/javascript" src="js/jquery.tablesorter.pager.js"></script>
<link href="css/blue/style.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
function showUser(str)
{
$.get("getuserlog.php?q="+str,function(response) {
$("#txtHint").html(response);
// Tablesorter will run, just after you loaded the ajax response
$("#userlog").tablesorter({widthFixed: true, widgets: ['zebra']})
.tablesorterPager({container: $("#pager")});
});
}
</script>
EDIT: Put all you javascript in the main page. The ajax response should only contain the data you want to get from the server.