outputting timestamp differential - php

Ok simple enough problem I hope but I'm probably overthinking the solution.
I have a mysql table with a timestamp formatted datetime. This is how it appears in the database (2016-10-08 03:56:26).
I created a function that is suppose to show the difference between the timestamp and the current time (UTC), which is constantly increasing. Please review my code. Currently it works... somewhat. The issue is when a time stamp is created at Noon (CST). The output will say 11hrs have ellapsed which is not true. All help is appreciated.
<?php
// Set timezone
date_default_timezone_set("America/Chicago");
// Time format is UNIX timestamp or
// PHP strtotime compatible strings
function dateDiff($time1, $time2, $precision = 6) {
// If not numeric then convert texts to unix timestamps
if (!is_int($time1)) {
$time1 = strtotime($time1);
}
if (!is_int($time2)) {
$time2 = strtotime($time2);
}
// If time1 is bigger than time2
// Then swap time1 and time2
if ($time1 > $time2) {
$ttime = $time1;
$time1 = $time2;
$time2 = $ttime;
}
// Set up intervals and diffs arrays
$intervals = array('year','month','day','hour','minute','second');
$diffs = array();
// Loop thru all intervals
foreach ($intervals as $interval) {
// Create temp time from time1 and interval
$ttime = strtotime('+1 ' . $interval, $time1);
// Set initial values
$add = 1;
$looped = 0;
// Loop until temp time is smaller than time2
while ($time2 >= $ttime) {
// Create new temp time from time1 and interval
$add++;
$ttime = strtotime("+" . $add . " " . $interval, $time1);
$looped++;
}
$time1 = strtotime("+" . $looped . " " . $interval, $time1);
$diffs[$interval] = $looped;
}
$count = 0;
$times = array();
// Loop thru all diffs
foreach ($diffs as $interval => $value) {
// Break if we have needed precission
if ($count >= $precision) {
break;
}
// Add value and interval
// if value is bigger than 0
if ($value > 0) {
// Add s if value is not 1
if ($value != 1) {
$interval .= "s";
}
// Add value and interval to times array
$times[] = $value . " " . $interval;
$count++;
}
}
// Return string with times
return implode(" ", $times);
}
?>

Use the PHP object oriented date commands to convert a time from one time zone to another before you do your comparison.
http://php.net/manual/en/datetime.settimezone.php

Another approach in PHP is to use Carbon. It has handy methods as well as comparison methods. It's used in Laravel and has a stable position on the market.
Check this: http://carbon.nesbot.com/docs/#api-difference and maybe you'll find out that there's no point of reinventing the wheel.

This worked the best for me. I'll add the link for the question that helped me out with this. LINK HERE
<?php
$dt = new DateTime($row['ticketopen']);
$now = new DateTime('now');
$interval = $dt->diff($now);
?>

Related

Calculating how many years from "from - to" date form in Gravity Forms

I have a form here (https://nursinggroup.com/pharmacist-profile/) where users will put in a date in the form of "mm / yy" for bot a "from" input box and a "to" input box. After the user goes through and adds in all their dates, they submit the form and a PDF is created using Gravity Forms PDF Extended (mPDF). What I need to happen is that during the creation of the PDF I need it to calculate the values for each item and spit out the total amount of years onto the PDF for each one.
So for example, if I enter in the following entries on the online form:
Ambulatory Care "From: 02 / 88" "To: 02 / 98"
Home Healthcare "From: 07 / 02" "To: 07 / 05"
Oncology "From: 09 / 06" "To: 05 / 12"
On the PDF it would spit out the following:
Ambulatory Care 10
Home Healthcare 3
Oncology 5.8
I have read through and tried many different code samples out there, but I am just not skilled enough with this type of PHP to make this work. A few other things to keep in mind. This is on a WordPress site, using Gravity Forms for the forms, and Gravity Forms PDF Extended to create the PDF's from those forms. Another thing to note, is that the entry of the year must remain in yy format versus yyyy The user does not fill in a day as well, only mm / yy
<?php
// Set timezone
date_default_timezone_set("UTC");
// Time format is UNIX timestamp or
// PHP strtotime compatible strings
function dateDiff($time1, $time2, $precision = 6) {
// If not numeric then convert texts to unix timestamps
if (!is_int($time1)) {
$time1 = strtotime($time1);
}
if (!is_int($time2)) {
$time2 = strtotime($time2);
}
// If time1 is bigger than time2
// Then swap time1 and time2
if ($time1 > $time2) {
$ttime = $time1;
$time1 = $time2;
$time2 = $ttime;
}
// Set up intervals and diffs arrays
$intervals = array('year','month','day','hour','minute','second');
$diffs = array();
// Loop thru all intervals
foreach ($intervals as $interval) {
// Create temp time from time1 and interval
$ttime = strtotime('+1 ' . $interval, $time1);
// Set initial values
$add = 1;
$looped = 0;
// Loop until temp time is smaller than time2
while ($time2 >= $ttime) {
// Create new temp time from time1 and interval
$add++;
$ttime = strtotime("+" . $add . " " . $interval, $time1);
$looped++;
}
$time1 = strtotime("+" . $looped . " " . $interval, $time1);
$diffs[$interval] = $looped;
}
$count = 0;
$times = array();
// Loop thru all diffs
foreach ($diffs as $interval => $value) {
// Break if we have needed precission
if ($count >= $precision) {
break;
}
// Add value and interval
// if value is bigger than 0
if ($value > 0) {
// Add s if value is not 1
if ($value != 1) {
$interval .= "s";
}
// Add value and interval to times array
$times[] = $value . " " . $interval;
$count++;
}
}
// Return string with times
return implode(", ", $times);
}
?>
What I would do is create separate fields for the calculated numbers. This way you can output them directly in the PDF via the entry ID rather than having to run any custom during the PDF creation process.
To calculate the number of years, I would recommend using something like this:
http://gravitywiz.com/calculate-number-of-days-between-two-dates/
It will calculate the number of days; however, it could be easily modified to calculate the number of years by changing this line:
dayCount = diff / ( 60 * 60 * 24 * 1000 );
...to this:
dayCount = diff / ( 60 * 60 * 24 * 360 * 1000 );
You could rename the variable as well but you'll need to replace it everywhere it is referenced in the current scope.

Count overall time between two timestamps per user

Currently I'm stuck with some MySQL queries.
I have a table like this:
ID|USERID|USERNAME|STARTTIME|ENDTIME|COMMITTYPE
The users click buttons in a frontend -> Start <- and -> Stop <-.
This creates a db entry with their respective duties, starttime and endtime. So, each click on start creates a new row/entry in the db and will get finished by the click on the stop button.
My problem, is there a chance to count the overall time between the start time and the end time per user and commit type?
This probably work
SELECT USERID, COMMITTYPE, MIN(STARTTIME), MAX(ENDTIME),
SUM(TIME_TO_SEC(TIME_DIFF(ENDTIME - STARTTIME))/3600) hours FROM tablename
GROUP BY USERID, COMMITTYPE
Do you refer to something like this?
SELECT COMMITTYPE, USER, (ENDTIME - STARTTIME) AS ELLAPSED_TIME
FROM YOUR_TABLE GROUP BY COMMITTYPE, USERID;
SELECT DATEDIFF('new_date', 'old_date');
// eg
SELECT DATEDIFF('2006-04-01','2006-04-01');
IG GETTING USE LINUX
<?php
// Set timezone
date_default_timezone_set("UTC");
// Time format is UNIX timestamp or
// PHP strtotime compatible strings
function dateDiff($time1, $time2, $precision = 6) {
// If not numeric then convert texts to unix timestamps
if (!is_int($time1)) {
$time1 = strtotime($time1);
}
if (!is_int($time2)) {
$time2 = strtotime($time2);
}
// If time1 is bigger than time2
// Then swap time1 and time2
if ($time1 > $time2) {
$ttime = $time1;
$time1 = $time2;
$time2 = $ttime;
}
// Set up intervals and diffs arrays
$intervals = array('year','month','day','hour','minute','second');
$diffs = array();
// Loop thru all intervals
foreach ($intervals as $interval) {
// Create temp time from time1 and interval
$ttime = strtotime('+1 ' . $interval, $time1);
// Set initial values
$add = 1;
$looped = 0;
// Loop until temp time is smaller than time2
while ($time2 >= $ttime) {
// Create new temp time from time1 and interval
$add++;
$ttime = strtotime("+" . $add . " " . $interval, $time1);
$looped++;
}
$time1 = strtotime("+" . $looped . " " . $interval, $time1);
$diffs[$interval] = $looped;
}
$count = 0;
$times = array();
// Loop thru all diffs
foreach ($diffs as $interval => $value) {
// Break if we have needed precission
if ($count >= $precision) {
break;
}
// Add value and interval
// if value is bigger than 0
if ($value > 0) {
// Add s if value is not 1
if ($value != 1) {
$interval .= "s";
}
// Add value and interval to times array
$times[] = $value . " " . $interval;
$count++;
}
}
// Return string with times
return implode(", ", $times);
}
?>
///
echo dateDiff("2010-01-26", "2004-01-26") . "\n";
echo dateDiff("2006-04-12 12:30:00", "1987-04-12 12:30:01") . "\n";
echo dateDiff("now", "now +2 months") . "\n";
echo dateDiff("now", "now -6 year -2 months -10 days") . "\n";
echo dateDiff("2009-01-26", "2004-01-26 15:38:11") . "\n";
OUTPUT
6 years
18 years, 11 months, 30 days, 23 hours, 59 minutes, 59 seconds 2
months 6 years, 2 months, 10 days 4 years, 11 months, 30 days, 8
hours, 21 minutes, 49 seconds

Calculate the number of working day hours between two dates (e.g. 8:30 to 17:30 excluding weekends) [duplicate]

I have a function to return the difference between 2 dates, however I need to work out the difference in working hours, assuming Monday to Friday (9am to 5:30pm):
//DATE DIFF FUNCTION
// Set timezone
date_default_timezone_set("GMT");
// Time format is UNIX timestamp or
// PHP strtotime compatible strings
function dateDiff($time1, $time2, $precision = 6) {
// If not numeric then convert texts to unix timestamps
if (!is_int($time1)) {
$time1 = strtotime($time1);
}
if (!is_int($time2)) {
$time2 = strtotime($time2);
}
// If time1 is bigger than time2
// Then swap time1 and time2
if ($time1 > $time2) {
$ttime = $time1;
$time1 = $time2;
$time2 = $ttime;
}
// Set up intervals and diffs arrays
$intervals = array('year','month','day','hour','minute','second');
$diffs = array();
// Loop thru all intervals
foreach ($intervals as $interval) {
// Set default diff to 0
$diffs[$interval] = 0;
// Create temp time from time1 and interval
$ttime = strtotime("+1 " . $interval, $time1);
// Loop until temp time is smaller than time2
while ($time2 >= $ttime) {
$time1 = $ttime;
$diffs[$interval]++;
// Create new temp time from time1 and interval
$ttime = strtotime("+1 " . $interval, $time1);
}
}
$count = 0;
$times = array();
// Loop thru all diffs
foreach ($diffs as $interval => $value) {
// Break if we have needed precission
if ($count >= $precision) {
break;
}
// Add value and interval
// if value is bigger than 0
if ($value > 0) {
// Add s if value is not 1
if ($value != 1) {
$interval .= "s";
}
// Add value and interval to times array
$times[] = $value . " " . $interval;
$count++;
}
}
// Return string with times
return implode(", ", $times);
}
Date 1 = 2012-03-24 03:58:58
Date 2 = 2012-03-22 11:29:16
Is there a simple way of doing this, i.e - calculating the percentage of working hours in a week and dividing the difference using the above function - I have played around with this idea and got some very strange figures...
Or is there better way....?
This example uses PHP's built in DateTime classes to do the date math. How I approached this was to start by counting the number of full working days between the two dates and then multiply that by 8 (see notes). Then it gets the hours worked on the partial days and adds them to the total hours worked. Turning this into a function would be fairly straightforward to do.
Notes:
Does not take timestamps into account. But you already know how to do that.
Does not handle holidays. (That can be easily added by using an array of holidays and adding it to where you filter out Saturdays and Sundays).
Requires PHP 5.3.6+
Assumes an 8 hour workday. If employees do not take lunch change $hours = $days * 8; to $hours = $days * 8.5;
.
<?php
// Initial datetimes
$date1 = new DateTime('2012-03-22 11:29:16');
$date2 = new DateTime('2012-03-24 03:58:58');
// Set first datetime to midnight of next day
$start = clone $date1;
$start->modify('+1 day');
$start->modify('midnight');
// Set second datetime to midnight of that day
$end = clone $date2;
$end->modify('midnight');
// Count the number of full days between both dates
$days = 0;
// Loop through each day between two dates
$interval = new DateInterval('P1D');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
// If it is a weekend don't count it
if (!in_array($dt->format('l'), array('Saturday', 'Sunday'))) {
$days++;
}
}
// Assume 8 hour workdays
$hours = $days * 8;
// Get the number of hours worked on the first day
$date1->modify('5:30 PM');
$diff = $date1->diff($start);
$hours += $diff->h;
// Get the number of hours worked the second day
$date1->modify('8 AM');
$diff = $date2->diff($end);
$hours += $diff->h;
echo $hours;
See it in action
Reference
DateTime Class
DatePeriod Class
DateInterval Class
Here's what I've come up with.
My solution checks the start and end times of the original dates, and adjusts them according to the actual start and end times of the work day (if the original start time is before work's opening time, it sets it to the latter).
After this is done to both start and end times, the times are compared to retrieve a DateInterval diff, calculating the total days, hours, etc. The date range is then checked for any weekend days, and if found, one total day is reduced from the diff.
Finally, the hours are calculated as commented. :)
Cheers to John for inspiring some of this solution, particularly the DatePeriod to check for weekends.
Gold star to anyone who breaks this; I'll be happy to update if anyone finds a loophole!
Gold star to myself, I broke it! Yeah, weekends are still buggy (try starting at 4pm on Saturday and ending at 1pm Monday). I will conquer you, work hours problem!
Ninja edit #2: I think I took care of the weekend bugs by reverting the start and end times to the most recent respective weekday if they fall on a weekend. Got good results after testing a handful of date ranges (starting and ending on the same weekend barfs, as expected). I'm not entirely convinced this is as optimized / simple as it could be, but at least it works better now.
// Settings
$workStartHour = 9;
$workStartMin = 0;
$workEndHour = 17;
$workEndMin = 30;
$workdayHours = 8.5;
$weekends = ['Saturday', 'Sunday'];
$hours = 0;
// Original start and end times, and their clones that we'll modify.
$originalStart = new DateTime('2012-03-22 11:29:16');
$start = clone $originalStart;
// Starting on a weekend? Skip to a weekday.
while (in_array($start->format('l'), $weekends))
{
$start->modify('midnight tomorrow');
}
$originalEnd = new DateTime('2012-03-24 03:58:58');
$end = clone $originalEnd;
// Ending on a weekend? Go back to a weekday.
while (in_array($end->format('l'), $weekends))
{
$end->modify('-1 day')->setTime(23, 59);
}
// Is the start date after the end date? Might happen if start and end
// are on the same weekend (whoops).
if ($start > $end) throw new Exception('Start date is AFTER end date!');
// Are the times outside of normal work hours? If so, adjust.
$startAdj = clone $start;
if ($start < $startAdj->setTime($workStartHour, $workStartMin))
{
// Start is earlier; adjust to real start time.
$start = $startAdj;
}
else if ($start > $startAdj->setTime($workEndHour, $workEndMin))
{
// Start is after close of that day, move to tomorrow.
$start = $startAdj->setTime($workStartHour, $workStartMin)->modify('+1 day');
}
$endAdj = clone $end;
if ($end > $endAdj->setTime($workEndHour, $workEndMin))
{
// End is after; adjust to real end time.
$end = $endAdj;
}
else if ($end < $endAdj->setTime($workStartHour, $workStartMin))
{
// End is before start of that day, move to day before.
$end = $endAdj->setTime($workEndHour, $workEndMin)->modify('-1 day');
}
// Calculate the difference between our modified days.
$diff = $start->diff($end);
// Go through each day using the original values, so we can check for weekends.
$period = new DatePeriod($start, new DateInterval('P1D'), $end);
foreach ($period as $day)
{
// If it's a weekend day, take it out of our total days in the diff.
if (in_array($day->format('l'), ['Saturday', 'Sunday'])) $diff->d--;
}
// Calculate! Days * Hours in a day + hours + minutes converted to hours.
$hours = ($diff->d * $workdayHours) + $diff->h + round($diff->i / 60, 2);
As the old saying goes "if you want something done right do it yourself". Not saying this is optimal but its atleast returning the correct amount of hours for me.
function biss_hours($start, $end){
$startDate = new DateTime($start);
$endDate = new DateTime($end);
$periodInterval = new DateInterval( "PT1H" );
$period = new DatePeriod( $startDate, $periodInterval, $endDate );
$count = 0;
foreach($period as $date){
$startofday = clone $date;
$startofday->setTime(8,30);
$endofday = clone $date;
$endofday->setTime(17,30);
if($date > $startofday && $date <= $endofday && !in_array($date->format('l'), array('Sunday','Saturday'))){
$count++;
}
}
//Get seconds of Start time
$start_d = date("Y-m-d H:00:00", strtotime($start));
$start_d_seconds = strtotime($start_d);
$start_t_seconds = strtotime($start);
$start_seconds = $start_t_seconds - $start_d_seconds;
//Get seconds of End time
$end_d = date("Y-m-d H:00:00", strtotime($end));
$end_d_seconds = strtotime($end_d);
$end_t_seconds = strtotime($end);
$end_seconds = $end_t_seconds - $end_d_seconds;
$diff = $end_seconds-$start_seconds;
if($diff!=0):
$count--;
endif;
$total_min_sec = date('i:s',$diff);
return $count .":".$total_min_sec;
}
$start = '2014-06-23 12:30:00';
$end = '2014-06-27 15:45:00';
$go = biss_hours($start,$end);
echo $go;

PHP Time loop between start time and end time

I have this function that gives me a set of options in a select input.
The options give me times with 5 minute interval.
The problem is when the time is like 23:45, the options will start from 00:10 and loops based on the $j variable.
This is what I want to do in words:
Give me a list of options in 5 minutes interval from $open_time till $close_time.
If the current Time ($timeNow) is greater than the $open_time, set the $open_time to the $timeNow to be shown as first option.
Do this loop only until the $close_time.
I hope this is clear.
Appreciate your help :)
Here is the code:
function selectTimesofDay(){
$output = "";
$now = date('G:i ', time()); // time now
$timeNow = strtotime($now); // strtotime now
$next_five = ceil($timeNow / 300) * 300; // get next 5 minute
// time now rounded to next 10 minute
$round5minNow = date('G:i', strtotime('+15 minutes',$next_five));
$open_time = strtotime('17:00');
$close_time = strtotime('23:59');
// in the middle of working hours, time sets to current
if($timeNow >= $open_time && $timeNow < $close_time){
$open_time = strtotime($round5minNow);
}
$time_diff = round(($close_time - $open_time)/60) ;
if(date('l') == 'Friday'){
$j = ($time_diff/5)+11; // working hours extended untill 1:00 AM
} else{
$j = ($time_diff/5)-1; // working hours untill 12:00 AM
}
for($i = 0; $i <= $j; $i++){
$b = $i*5;
$data = date('l')." - ".date("H:i", strtotime('+'.$b.' minutes', $open_time));
$output .= "<option value=\"{$data}\">";
$output .= $data;
$output .= "</option>";
}
return $output;
}
What you really need is:
function selectTimesOfDay() {
$open_time = strtotime("17:00");
$close_time = strtotime("23:59");
$now = time();
$output = "";
for( $i=$open_time; $i<$close_time; $i+=300) {
if( $i < $now) continue;
$output .= "<option>".date("l - H:i",$i)."</option>";
}
return $output;
}
So what this does is run a loop checking every five-minute interval between opening and closing. Skip it if it is before the curent time, and otherwise add an option.
It's much more efficient than what you were trying to do, and probably easier to understand too.
You can even put this after the loop:
if( $output == "") return "<option disabled>Sorry, we're closed for today</option>";
Also, notice how I left out the value attribute all the time. That's because in the absence of a value, the option's text is used as a value. Thus this solution avoids needless duplication.
Consider taking the hard-coded open and close times out of the function body. The goal with functions is to write code that you can reuse, so if your hours change then you don't have to change with your function, but rather the arguments that are passed to it.
// sample usage: print '<select>'.selectTimesofDay('17:00', '23:59').'</select>';
function selectTimesofDay($start=false, $end=false, $interval='5 minutes'){
$interval = DateInterval::createFromDateString($interval);
$rounding_interval = $interval->i * 60;
$date = new DateTime(
date('Y-m-d H:i', round(strtotime($start) / $rounding_interval) * $rounding_interval)
);
$end = new DateTime(
date('Y-m-d H:i', round(strtotime($end) / $rounding_interval) * $rounding_interval)
);
$opts = array();
while ($date < $end) {
if ($date->getTimestamp() < time()) {
$date->add($interval);
continue;
}
$data = $date->format('l').' - '.$date->format('H:i');
//$opts[] = '<option value="'.$date->getTimestamp().'">'.$data.'</option>'; // < -- pass the timestamp instead of a string?
$opts[] = '<option>'.$data.'</option>';
$date->add($interval);
}
return count($opts) < 1 ?
'<option value="-1">- closed -</option>' :
implode("\n", $opts);
}
Documentation
PHP's DateTime object - http://www.php.net/manual/en/class.datetime.php
PHP's DateInterval object - http://www.php.net/manual/en/dateinterval.format.php
PHP functions - http://www.php.net/manual/en/functions.user-defined.php
PHP function tutorial - http://www.tizag.com/phpT/phpfunctions.php

Calculating the number of days between two dates

I have a mySQL database.
I need to count the number of days between two dates.
My client is going to fill an input hm_date with January 1, 1979 via php form to create a new record.
I need a field total_days to calculate the total number of days from hm_date to the present day. I need this field to always update itself with each passing day.
How do I make hm_date to appear with total days and be always updated?
I asume this can be achieved server-side?
Should I use strototime() ?
You'll want to use MySQL's DATEDIFF()
DATEDIFF() returns expr1 – expr2 expressed as a value in days from one
date to the other. expr1 and expr2 are date or date-and-time
expressions. Only the date parts of the values are used in the
calculation.
mysql> SELECT DATEDIFF('2007-12-31 23:59:59','2007-12-30');
-> 1
mysql> SELECT DATEDIFF('2010-11-30 23:59:59','2010-12-31');
-> -31
Based on your question I think you would want DATE_DIFF(hm_date, CURRENT_DATE). Just make sure hm_date is in YYYY-MM-DD format.
With PHP:
$daydiff = floor( ( strtotime( $endDate ) - strtotime( $startDate ) ) / 86400 );
$startDate and $endDate can be any valid date format explained here:
http://www.php.net/manual/en/datetime.formats.date.php
Its pretty easy but long.. Please follow following codes
<?php
// Set timezone
date_default_timezone_set("UTC");
// Time format is UNIX timestamp or
// PHP strtotime compatible strings
function dateDiff($time1, $time2, $precision = 6) {
// If not numeric then convert texts to unix timestamps
if (!is_int($time1)) {
$time1 = strtotime($time1);
}
if (!is_int($time2)) {
$time2 = strtotime($time2);
}
// If time1 is bigger than time2
// Then swap time1 and time2
if ($time1 > $time2) {
$ttime = $time1;
$time1 = $time2;
$time2 = $ttime;
}
// Set up intervals and diffs arrays
$intervals = array('year','month','day','hour','minute','second');
$diffs = array();
// Loop thru all intervals
foreach ($intervals as $interval) {
// Set default diff to 0
$diffs[$interval] = 0;
// Create temp time from time1 and interval
$ttime = strtotime("+1 " . $interval, $time1);
// Loop until temp time is smaller than time2
while ($time2 >= $ttime) {
$time1 = $ttime;
$diffs[$interval]++;
// Create new temp time from time1 and interval
$ttime = strtotime("+1 " . $interval, $time1);
}
}
$count = 0;
$times = array();
// Loop thru all diffs
foreach ($diffs as $interval => $value) {
// Break if we have needed precission
if ($count >= $precision) {
break;
}
// Add value and interval
// if value is bigger than 0
if ($value > 0) {
// Add s if value is not 1
if ($value != 1) {
$interval .= "s";
}
// Add value and interval to times array
$times[] = $value . " " . $interval;
$count++;
}
}
// Return string with times
return implode(", ", $times);
}
?>
Now try this and see how it shows the difference...
echo dateDiff("2010-01-26", "2004-01-26") . "\n";
echo dateDiff("2006-04-12 12:30:00", "1987-04-12 12:30:01") . "\n";
echo dateDiff("now", "now +2 months") . "\n";
echo dateDiff("now", "now -6 year -2 months -10 days") . "\n";
echo dateDiff("2009-01-26", "2004-01-26 15:38:11") . "\n";

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