How to create if statement inside echo in PHP MySQLi - php

Question

I want to ask,
I have two tables , users and posts with column field
users : user_id, name, email
posts : post_id, user_id, post_title
I want to display all posts from all users,
but I want only logged_in user session to have another two extra button while other public posts only have two button
p/s : I used email column field in users table as login $_SESSION.
<?php
global $connect;
global $user_id;
$sql_post = "SELECT * FROM posts";
$run_post = mysqli_query($connect, $sql_post);
if($run_post && mysqli_num_rows($run_post) > 0 )
{
while($row_post = mysqli_fetch_array($run_post))
{
$post_id = $row_post['post_id'];
$user_id = $row_post['user_id'];
$post_title = $row_post['post_title'];
$sql_user = "SELECT * FROM users WHERE user_id='$user_id'";
$run_user = mysqli_query($connect, $sql_user);
$check_user = mysqli_fetch_array($run_user);
$user_id = $check_user['user_id'];
$user_name = $check_user['name'];
$user_email = $check_user['email'];
$post_output = "<div id='posts_wrap'>
<p>$user_name</p>
<p>$user_email</p>
<p>$post_title</p>
<a href=''><button>Like</button></a>
<a href=''><button>Comment</button></a>
// i want these two button (Edit and Delete) only available to logged in user
<a href=''><button>Edit</button></a>
<a href=''><button>Delete</button></a>
</div>
";
echo $post_output;
}
mysqli_free_result($run_post);
}
else
{
echo "No post yet";
}
?>

Answer 1

After user loggine keep user detail in session and check condition if user logged in or not For example if you are trying to comment and like only for logged in user then you can do somethink like
<?php
session_start();
$_SESSION['email']='email#example.com';
$user_name='dd';
$user_email='ddd';
$post_title='gsdg';
$post_output = "<div id='posts_wrap'><p>$user_name</p><p>$user_email</p><p>$post_title</p>";
if(isset($_SESSION['email'])){
$post_output.="<a href=''><button>Like</button></a><a href=''><button>Comment</button></a> ";
}
// i want these two button (Edit and Delete) only available to logged in user
$post_output.= "<a href=''><button>Edit</button></a><a href=''><button>Delete</button></a> </div>";
print_r($post_output);
?>
in the above code user is logged in so all buttons are visible .if not then its not visible to all .just try to destroy session.i think previous session email still there

Answer 2

i found the solutions . it turns out that i need to create another query and combine the user_id and email to makesure the login is belong to the loggedin user. here's the code
<?php
global $connect;
global $user_id;
$get_post = "SELECT * FROM posts";
$run_post = mysqli_query($connect, $get_post);
if($run_post && mysqli_num_rows($run_post) > 0 )
{
while($row_post = mysqli_fetch_array($run_post))
{
$post_id = $row_post['post_id'];
$user_id = $row_post['user_id'];
$post_title = $row_post['post_title'];
$emailsql = $_SESSION['email'];
$get_email = "SELECT * FROM users WHERE user_id='$user_id' AND email='$emailsql'";
$run_email = mysqli_query($connect, $get_email);
$check_email = mysqli_fetch_array($run_email);
$d_email = $check_email['email'];
$get_user = "SELECT * FROM users WHERE user_id='$user_id'";
$run_user = mysqli_query($connect, $get_user);
$check_user = mysqli_fetch_array($run_user);
$user_id = $check_user['user_id'];
$user_name = $check_user['name'];
echo "<div id='posts_wrap'>
<p><h3><a href='userprofile.php?user_id=$user_id'>$user_name</a></h3></p>
<div id='posts_title'>
<p><h3><a href='post.php?post_id=$post_id'>$post_title</a></h3></p>
</div>
<hr>
<a href=''><button>Like</button></a>
<a href=''><button>Comment</button></a>
";
if($check_email){
echo "
<a href=''><button>Edit</button></a>
<a href=''><button>Delete</button></a>";
}
echo "</div>";
}
mysqli_free_result($run_post);
}
else
{
echo "No post yet";
}
?>