Select query to match to columns - php

Question

I am trying to create a user profile image feature. So far I am able to upload and select an image and display it, but I cannot figure out how to select the image specific to a user. My query was working (though with the issue described above) until I added the code below (//added is what I changed).
I was able to get my insert query to send the user's user_id with it, I just cannot figure out the select part.
My database for this is small, it just has id, user_id, img.
I want to select the img that is in my database that has the user's user_id. I am carrying the user_id with a session and that is what $user_id is.
Anyone see what I am doing wrong in my select query?
function getPhoto($con,$dest)
{
$user_id = ( isset( $_SESSION['user'] ) ? $_SESSION['user'] : "" ); //added
// $result = mysqli_query($con,"SELECT * FROM `profile_img` where `img` = '$dest'");
$result = mysqli_query($con,"SELECT * FROM `profile_img` where `img` = '$user_id'"); //added
if($row = mysqli_fetch_array($result))
return $row;
return 0;
}
Edit: More code.
function getPhoto($con,$dest)
{
$user_id = ( isset( $_SESSION['user'] ) ? $_SESSION['user'] : "" ); //added
// $result = mysqli_query($con,"SELECT * FROM `profile_img` where `img` = '$dest'");
$result = mysqli_query($con,"SELECT * FROM `profile_img` where `user_id` = '$user_id'"); //added
if($row = mysqli_fetch_array($result))
return $row;
return 0;
}
// Make sure all functions above are include here
// Get the database connection
$con = Connection();
// Check for post
if(isset($_POST['create'])) {
// Try uploading
$upload = UploadFile($_FILES);
// If upload fails
if(!$upload['success'])
echo '<h3>Sorry, an error occurred</h3>';
else {
// You could add error handling here based on the results of
// each function's success or failure below.
// Try to save it
$saveToDb = SaveToDb($con,$upload['file']['dest']);
// Get the profile from image name
$profPic = ($saveToDb)? getPhoto($con,$upload['file']['dest']) : false; ?>
<?php
}
}
?>
<img id="profile-pic" src="<?php echo (!empty($profPic) && $profPic != 0)? $profPic['img'] : "profile_images/default.jpg"; ?>" alt="<?php echo (!empty($profPic) && $profPic != 0)? "Profile Picture" : "No Picture"; ?>" />
<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="file" class="inputbarfile" onchange="readURL(this);">
<img width="400px" height="300px" id="file" src="#" alt="your image">
<input type="submit" name="create" id="signinButton" value="Upload">
</form>

Answer 1

This:
$result = mysqli_query($con,"SELECT * FROM `profile_img` where `img` = '$user_id'"); //added
Should be:
$result = mysqli_query($con,"SELECT * FROM `profile_img` where `user_id` = '$user_id'"); //added
Because img column holds the image path and you are comparing user id.