Count workers in business with branches - php

Question

Select a group, where is one Main and for example 5 Branch. So, the total of places is 6. In each of those 6, search for 3 workers, who is working as job_types LIKE "%C%". If, in one of those 6 places, are 3workers with given parameter, query must get results of all those 6 places.
To clarify: 3 workers must be working in same main/branch.
Because project itself is very dificult, it would be better, to get results using RAW query:
business table
id | mainorbranch | name
--------------------------------------
1 Main Apple
2 Branch Apple London
3 Branch Apple Manchester
4 Main IBM
5 Branch IBM London
etc ...
Relationship
business_branches table
b_id | branch_id | id
--------------------------------------
1 1 1
2 2 1
3 3 1
4 4 4
5 5 4
// etc
people_details table
d_id | id | job_types
--------------------------------------
1 1 C
2 3 D
3 2 F
4 4 C
5 5 C
// etc
people_branches table
pb_id | branch_id | id
--------------------------------------
1 1 3
2 3 2
3 4 4
4 2 5
5 1 1
// etc
What i need to get:
Business id | Name | Postcode
-----------------------------------------
1 Apple postcode
2 Apple 232 postcode
3 Apple 323 postcode
// etc...
DB Structure for Helpers
http://sqlfiddle.com/#!9/206733
Simplified, minified SQL file with total of 110k+ rows
UPDATE
Answer by #KikiTheOne is kinda working, but it gets only half a results. Other half is missing.

Answer 1

as discussed in Chat. here is a solution:
if u Need Company Infos... get them # t1.XXXX like postcode.
i changed
"pb_id" "branch_id" "id"
"1" "1" "3"
"2" "3" "2"
"3" "1" "4"
"4" "1" "5"
"5" "1" "1"
so i get 3 People in 1 branch
SELECT
t1.id as "Business id",
t1.name as Name,
'postcode' as "Postcode"
FROM SO_business as t1 inner join
(
SELECT * FROM SO_busness_branches as t3
inner join
(
SELECT
t5.branch_id as inner_branch,
count(t5.branch_id) as workers_in,
max(t6.job_types) as job_types,
max(t7.id) as mainbranch
FROM
SO_people_branches as t5
inner join SO_people_details as t6
on t5.id = t6.id
inner join SO_busness_branches as t7
on t5.branch_id = t7.branch_id
WHERE
t6.job_types LIKE '%C%'
GROUP BY
t5.branch_id
) as t4
on t3.id = t4.inner_branch
WHERE t4.workers_in >= 3
) as t2
on t1.id = t2.branch_id
Explanation:
-.1 the Most inner SQL Counts ALL branches with workers ( number of workers init ) and Job_type = %c% and joines the MAIN id of the branch.
-.2 the second SQL gets that info and only selects all branches with workers >= 3
-.3 the outer SQL selects all inner INFOS and gives back ALL branches/main with the branchID-Main from the Inner SQL. AND connects them to the Business table so u can Display all Infos likepostcode from there

Answer 2

hope that this works as it's not as easy to interpret the relationships with the name of the columns in your question.
With this script you can add any group of main/branch to search into
SELECT b.id, b.name, 'postcode' as postcode
FROM business b
INNER JOIN business_branches bb ON (bb.branch_id = b.id)
WHERE bb.id IN (
SELECT bb1.id FROM people_details pd
INNER JOIN people_branches pb ON (pb.id = pd.id)
INNER JOIN business_branches bb1 ON (bb1.branch_id = pb.branch_id)
INNER JOIN business b1 ON (b1.id = bb1.branch_id)
WHERE
pd.job_types like '%C%' AND
bb1.id IN (1,4) -- You can add as many group of businesses (main/branch combinations) using the main branch key
GROUP BY pb.branch_id HAVING count(pb.branch_id) >= 3
)