Yii2. dektrium/user. Custom controller action redirects to the login page - php

Problem
Every custom action redirects back to the login page.
My code
I've extended my custom controller from the dektrium\user\controllers\RegistrationController
My web.php
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => false,
'rules' => [
],
],
...
'modules' => [
'user' => [
'class' => 'dektrium\user\Module',
'controllerMap' => [
'registration' => 'app\controllers\user\RegistrationController'
],
],
],
Custom controller
namespace app\controllers\user;
use dektrium\user\controllers\RegistrationController as BaseAdminController;
class RegistrationController extends BaseAdminController
{
public function actionPlan()
{
echo 'Test';
}
}
Overrode methods works good, but each custom action (site.com/user/registration/plan) redirects back to the login page.

If you want change the access control rules you should change properly eg: in your site controller add plan to the rules accessible without authenctication
class SiteController extends Controller
{
/**
* #inheritdoc
*/
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'actions' => ['login','plan', 'error'],
'allow' => true,
],
[
'actions' => ['logout', 'index'],
'allow' => true,
'roles' => ['#'],
],
],
],
'verbs' => [
'class' => VerbFilter::className(),
'actions' => [
'logout' => ['post'],
],
],
];
}
see this for more http://www.yiiframework.com/doc-2.0/guide-security-authorization.html
http://www.yiiframework.com/doc-2.0/yii-filters-accesscontrol.html

Another implementation
class SiteController extends Controller
{
/**
* #inheritdoc
*/
public function behaviors()
{
$behaviors = [
'access' => [
'rules' => [
[
'actions' => ['login', 'plan', 'error'],
'allow' => true,
],
],
],
];
return ArrayHelper::merge($behaviors, parent::behaviors());
}
}

Related

How to change access controller redirect/login URL in Yii2?

I have two login systems in my Yii2 application. First is default login system using User table, and second uses sms_account table. In custom controller I've created action for login, actionLogin(). I've added access control for my custom controller, but I'm having problem that when a person is not logged in, it redirects to site/login. I want to change redirect to custom-controller/login URL in Yii2 access control. My code is:
public function behaviors()
{
return [
'verbs' => [
'class' => VerbFilter::className(),
'actions' => [
'delete' => ['post'],
],
],
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'actions' => ['login'],
'allow' => false,
'roles' => ['#']
],
[
'actions' => ['home'],
'allow' => true,
'roles' => ['#']
]
]
]
];
}
Can anyone tell me how to change access control URL?
You should simply configure your user component :
'user' => [
// ...
'loginUrl' => ['custom-controller/login'],
],
Read more about yii\web\User::$loginUrl.
And it should be :
[
'actions' => ['login'],
'allow' => true,
'roles' => ['?']
],
Read more about Authorization in Yii2.
This is my updated answer . I thinks it's help you
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'only' => ['index','logout','client-create'], // your own action which permission the login
'rules' => [
[
'actions' => ['index','logout','client-create'], // your own action which permission the login
'allow' => true,
'roles' => ['#'],
],
],
'denyCallback' => function($rule, $action) {
Yii::$app->response->redirect(['login/login']);
},
],
];
}
Try this code.
Note:roles
[
'actions' => ['home'],
'allow' => true,
'roles' => ['?']
'matchCallback' => function ($rule, $action) {
return $this->redirect('index.php?r=controller/action');
}
]

How to redirect to a specific method Yii2 (Advanced Template) ?

How to navigate to index method without automatic login in frontend contoller ?
Extends behaviors method in SiteController:
use yii\filters\AccessControl;
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'actions' => ['index'],
'allow' => true,
],
[
'allow' => true,
'roles' => ['#'],
],
],
],
];
}
So index action will be available to everyone, instead other pages will require authentication

Close backend with AccessControl

I can trying simple code.
I have an AccessController which having behaviors():
class AccessController extends BackendController
{
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'allow' => true,
'roles' => ['#'],
],
]
],
];
}
/*public function init()
{
parent::init();
if( Yii::$app->getUser()->getIsGuest() )
{
return $this->redirect('/auth');
}
return true;
}*/
public function actions()
{
return [
'WysiwygUpload' => [
'class' => WysiwygUpload::className(),
]
];
}
}
AS I understand, if I didn't declare 'only' key, that is mean to all actions and controllers.
But nothing happen: no one error, nothing
Your controller AccessController work only for yourApp/backend/access request not for all controllerAction..
If you want deny the access to guest in AdminController you shuold apply the behavior of AdminController
class AdminController extends Controller
{
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'allow' => true,
'roles' => ['#'],
],
]
],
];
}
........
Then when a guest try accessing to yourApp/backend/admin this is not permitted

Yii2 REST queryparamauth with rules

As I know simple authentication for REST like in this guide
public function behaviors()
{
$behaviors = parent::behaviors();
$behaviors['authenticator'] = [
'class' => QueryParamAuth::className(),
];
return $behaviors;
}
But I want provide some rules to handle guest access? like access control from authorization guide like this
$behaviors['access'] = [
'class' => AccessControl::className(),
'rules' => [
// allow authenticated users
[
'allow' => true,
'actions' => ['some-action'],
'roles' => ['?'],
],
[
'allow' => true,
'roles' => ['#'],
],
// everything else is denied
],
];
If I access some_guest_action as guest without access-token, it will be fine,
but if I access with access-token, Yii::$app->user->getId() always return null value
My complete code like this
public function behaviors()
{
$behaviors = parent::behaviors();
$behavior['authenticator'] = [
'class' => QueryParamAuth::className(),
];
$behaviors['access'] = [
'class' => AccessControl::className(),
'rules' => [
// allow authenticated users
[
'allow' => true,
'actions' => ['some-action'],
'roles' => ['?'],
],
[
'allow' => true,
'roles' => ['#'],
],
// everything else is denied
],
];
return $behaviors;
}
public function actionSomeAction()
{
return Yii::$app->user->getId();
}

Yii2 Advanced Template: Adding stand-alone web pages

I added help.php under backend/views/site and I declare a function under SiteController.php to be able to recognize the link
public function behaviors()
{
return [
'access' => [
'class' => AccessControl::className(),
'rules' => [
[
'actions' => ['login', 'error'],
'allow' => true,
],
[
'actions' => ['logout', 'index'],
'allow' => true,
'roles' => ['#'],
],
],
],
'verbs' => [
'class' => VerbFilter::className(),
'actions' => [
'logout' => ['post'],
],
],
];
}
public function actionHelp()
{
return $this->render('help');
}
The link is now accessible but it gives me an error
Forbidden(#403) and it says "You are not allowed to perform this action."
Now, I would like to ask if how will I be able to view the web pages that I've created. Thanks in advance.
The problem is related with AccessControl filter.
You can add help action to the this list of allowed actions for example like this:
[
'actions' => ['login', 'error', 'help'],
'allow' => true,
],
You can read more and check how access rules are applied in according documentation section.

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