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function is_decimal( $it )
{
return is_numeric( $it ) && floor( $it ) != $it;
}
if (is_decimal == true){
echo "Decimal";
}
This gives me an error even though the int is not a decimal (float). Can someone help me. Thanks
It works fine for a decimal but not for an int.
Simple, when you call a function with a parameter you have to pass a parameter!
function is_decimal( $spaces )
{
return is_numeric( $spaces ) && floor( $spaces ) != $spaces;
}
$tst_var = 1.99
if (is_decimal($tst_var) == true){
echo "Error 3: Decimal causing Error as carpark can't have decimal spaces available.";
}
just use if(is_numeric( $spaces )){ ... } work for int, float even if they are represented by string
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Closed 7 years ago.
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I am just trying to figure out how I can get the actual digits of a figure that has been calculated within php and formatted to have 2 decimal places.
so say its calculated it to be 45.76 I am trying to figure out how I can get the 76 from it for an if statement. Basically I want it to look and just say that if it's 00 then remove them, if not, show them.
Thanks
Try :
function showDecimals($v){
$n = abs($v);
$whole = floor($n);
$fraction = $n - $whole;
return $fraction > 0
}
And...
if (showDecimals(10.15)){
//Show
}else{
//Remove?
}
You want to show a whole number if there is no decimal place, and 2 decimals of precision if not?
Method 1
function formatNumber($n) {
$n = round($n*100)/100;
return ''+$n;
}
This simply rounds it to 2 decimals of precision. Zero truncation is automatic.
Usage
echo formatNumber(0); //0
echo formatNumber(0.5); //0.5
echo formatNumber(0.894); //0.89
echo formatNumber(0.896); //0.9
echo formatNumber(1.896); //1.9
Method 2
Or if you 1.9 to display as 1.90, I suppose this would work:
function formatNumber($n) {
if ($n == 0)
return ''+$n;
$str = ''.round($n*100)/100;
$dotpos = strrpos('.', $str);
if (strlen(substr($str, $dotpos+1)) === 2)
$str .= '0';
return $str;
}
Usage:
echo formatNumber(0); //0
echo formatNumber(0.5); //0.50
echo formatNumber(0.894); //0.89
echo formatNumber(0.896); //0.90
echo formatNumber(1.896); //1.90
Edit: Accidentally posted broken version of method 2, should be fixed now.
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This first comparison will check if the value is 14 in length and the User ID is 1
if ($checkValueLenght === 14 && $UserID[0] === "1") { code... }
but I want it to check if it is 1 or 2, and I cant get this to work ...
if ($checkValueLenght === 14 && $UserID[0] === "1" || "2") { code... }
it goes trough the code whatever letter or number the UserID starts with, but not if it is not exactly 14 in length. What am I doing wrong?
You need this ...
if ($checkValueLenght === 14 && ($UserID[0] === "1" || $UserID[0] === "2")) { code... }
or better, this ...
if ($checkValueLenght === 14 && in_array($UserID[0],["1","2"]) { code... }
assuming that the value of $UserID[0] is indeed a string.
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i try sum numbers with the same string , for get one only number to the end , for example this :
<?php
$result.="1";
$result.="4";
$result.="8";
$result.="346";
$end +=result;
echo $end;
?>
I try do this but no get never the result ok , only show all numbers but not the result of the sum , by this my question , i don´t know if i writte something bad or similar
Thank´s for the help , regards
You are concatenating instead of adding.
<?php
$result+=1; // Need the += here instead of .=
$result+=4;
$result+=8;
$result+=346;
$end +=result; // Like you already did here.
echo $end;
The problem is that you are trying to add up STRINGs not INTs. You have to convert the values.
$result+=intval("1");
$result+=intval("4");
$result+=intval("8");
$result+=intval("346");
$end =$result;
echo $end;
This is not how you are supposed to do it, if you really want to store every number, just use an array :
<?php
$myNumber = [];
$myNumber[] = 1;
$myNumber[] = 4;
$sum = 0;
foreach($myNumber as $r)
$sum += $r;
echo $sum;
?>
$sum will now contain the sum of every number. You could also use the array_sum function to perform this operation.
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I am getting an error that shows only if this DateTime format function is called a second time. It works fine on the first one, which is something I am assuming because the error only occurs on the line of the second call.
if( ! function_exists('month_dropdown')){
function month_dropdown($field_name = 'month', $selected = '01', $value_format = 'm', $atts = ''){
for($i=1;$i<=12;$i++){
$numObj = DateTime::createFromFormat('!'.$value_format, $i);
$val = $numObj->format($value_format);
$nameObj = DateTime::createFromFormat('!F', $i);
$text = $nameObj->format('F');
$months[$val] = $text;
}
return form_dropdown($field_name, $months, $selected, $atts);
}
}
This is the error I am getting:
Fatal error: Call to a member function format() on a non-object in ...application\frontend\helpers\MY_html_helper.php on line 73
Line 73 is where the variable $text is defined.
You're using the wrong formatting character. With month integers, use n
m and n
Numeric representation of a month, with or without leading zeros
Example: 01 through 12 or 1 through 12
For example
$nameObj = DateTime::createFromFormat('!n', $i);
$text = $nameObj->format('F');
Demo here ~ https://eval.in/188555
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I'm writing code to show the prices of some products. If the price is 0 it doesn't show anything.
<? if ($book->price_euro != 0) {$europrice = number_format($book->price_eur, 2); echo "€$europrice";}?>
<? if ($book->price_gbp != 0) {$gbpprice = number_format($book->price_gbp, 2); echo "£$gbpprice";}?>
<? if ($book->price_usd != 0) {$usdprice = number_format($book->price_usd, 2); echo "$$usdprice";}?>
This echoes "€0.00 £33.00 $66.00 ". The € price is set to 99. I can see no reason whatsoever that this should echo as 0! Am I doing something wrong? Bad syntax?
$europrice = number_format($book->price_eur, 2
shouldn't it be $book->price_euro ?
Typo in Euro
number_format($book->price_eur, 2); // This is what you have.
number_format($book->price_euro, 2); // This is what you need.
I don't see anything wrong with this code without seeing more. But maybe your variable?
<? if ($book->price_euro != 0) {$europrice = number_format($book->price_eur, 2); echo "€$europrice";}?>
price_eur should be price_euro?
number_format($book->price_eur, 2);
should be
number_format($book->price_euro, 2);
The null value is causing your problem.
You might still be getting null values or something else try using empty instead
<? if (empty($book->price_euro)) {$europrice = number_format($book->price_euro, 2); echo "€$europrice";}?>
<? if (empty($book->price_gbp)) {$gbpprice = number_format($book->price_gbp, 2); echo "£$gbpprice";}?>
<? if (empty($book->price_usd)) {$usdprice = number_format($book->price_usd, 2); echo "$$usdprice";}?>