I am studying Laravel Framework for few hours and i am trying to do what's being done in the tutorial i am watching. I am executing a query through routes.php and it's giving me a different output.
My database has only 1 table and it is named 'customer' and i have a model named 'customer' and a controller named 'CustomerController'
My routes.php code is this
Route::get('customer', function() {
$customer = FirstLaravelApplication\Customer::find(1);
echo '<pre>';
print_r($customer);
But the localhost is giving me an error and it says i don't have any 'customers' table, it automatically added a letter 's' in the end of the table instead of 'customer' only. i really don't have any 'customers' table i don't know why it is passing the wrong name of the table but my code only says 'customer'.
i would appreciate any help! Thanks all!
Laravel/Eloquent ORM uses this convention, as do many ORMs. They pluralize table names.
Open up the Customer.php model and add in:
class Customer extends Model {
// Add this
protected $table = 'customer';
However, it's usually easier to stick with the framework's conventions.
https://laravel.com/docs/5.3/eloquent#eloquent-model-conventions
Related
I have make an cakephp application but the database i am using is of a crm and i cannot change the table names so it is a restriction. My table name is emails_users_1_c . When i tried to call this table name in the model.
It appends the 1 to the users and make it documents_leads1_c i dont know why is it happening although i searched on SO and in the documentation but not able to find out.
Table 'crm.emails_users1_c' doesn't exist".
This is how i am accessing the table.
public function makeDocument($data){
$docuTable = TableRegistry::get('emails_users_1_c');
$docuData = $docuTable->newEntity($data);
$docuTable->save($docuData);
}
Do not use such database table names as table class names / aliases, that doesn't work well with the inflection that is applied internally (camelizing followed by underscoring in this specific case). Use meaningful names that follow the CakePHP naming conventions, that will help you the long run.
Ideally create concrete table classes with proper names, for example UserEmailsTable, and configure the database table name via \Cake\ORM\Table::setTable():
namespace App\Model\Table;
use Cake\ORM\Table;
class UserEmailsTable extends Table
{
public function initialize(array $config)
{
$this->setTable('emails_users_1_c'); // $this->table() before CakePHP 3.4
// ...
}
}
If for whatever reason concrete table classes can't/shouldn't be used, then configure the aliases on the fly, so that you can still easily reuse them:
TableRegistry::config('UserEmails', [
'table' => 'emails_users_1_c'
]);
In any case you should then be able to retrieve the table class instance via the UserEmails alias:
$UserEmails = TableRegistry::get('UserEmails');
See also
Cookbook > Database Access & ORM > Table Objects
Cookbook > Database Access & ORM > Table Objects > Configuring Table Objects
Cookbook > CakePHP at a Glance > CakePHP Conventions
So, going into the problem straight away. someone told me that we dont need to make a pivot table if we only want to have ids of the table. laravel can itself handle this situation. I dont know how this works. I have a table community and another table idea. relation is like this;
One community can contain many ideas and an idea can be found in many
communities.
Relation in idea Model:
public function community() {
return $this->belongsToMany('App\Community')->withTimestamps();
}
Relation in community Model:
public function idea() {
return $this->belongsToMany('App\idea');
}
Now i want to fetch all the records related to a single community to show on its page Let's say the community is Arts.
Here is Controller function:
public function showCommunities($id) {
$community = Community::findOrFail($id)->community()->get();
return view('publicPages.ideas_in_community', compact('community'));
}
When i attach ->community()->get() to the Community::findOrFail($id) Then it throws the error
SQLSTATE[42S02]: Base table or view not found laravel
Any help would be appreciated.
Edit:
Logically, this piece of code Community::findOrFail($id)->community()->get() should be like this Community::findOrFail($id)->idea()->get(). Now it is true but it has little issue. it throws an error
Fatal error: Class 'App\idea' not found
The way you define the many-to-many relation looks ok - I'd just call them communities() and ideas(), as they'll return a collection of objects, not a single object.
Make sure you use correct class names - I can see you refering to your model classes using different case - see App\Community and App\idea.
In order to find related models, Eloquent will look for matching rows in the pivot table - in your case it should be named community_idea and have 3 fields: community_id, idea_id and autoincrement primary key id.
With that in place, you should be able to get all ideas linked to given community with:
$ideas = Community::findOrFail($communityId)->ideas;
If you need communities linked to given idea, just do:
$communities = Idea::findOrFail($ideaId)->communities;
You can read more about how to use many-to-many relationships here: https://laravel.com/docs/5.1/eloquent-relationships#many-to-many
someone told me that we dont need to make a pivot table if we only want to have ids of the table
The above is not true (unless I've just misunderstood).
For a many-to-many (belongsToMany) their must be the two related table and then an intermediate (pivot) table. The intermediate table will contain the primary key for table 1 and the primary key for table 2.
In laravel, the convention for naming tables is plural for your main tables i.e. Community = 'communities' and Idea = 'ideas'. The pivot table name will be derived from the alphabetical order of the related model names i.e.
community_idea.
Now, if you don't want/can't to follow these conventions that's absolutely fine. For more information you can refer to the documentation: https://laravel.com/docs/5.2/eloquent-relationships#many-to-many
Once you're happy that you have the necessary tables with the necessary fields you can access the relationship by:
$ideas = $community->ideas()->get();
//or
$ideas = $community->ideas;
So you controller would look something like:
public function showCommunities($id)
{
$community = Community::findOrFail($id);
//The below isn't necessary as you're passing the Model to a view
// but it's good for self documentation
$community->load('ideas');
return view('publicPages.ideas_in_community', compact('community'));
}
Alternatively, you could add the ideas to the array of data passed to the view to be a bit more verbose:
public function showCommunities($id)
{
$community = Community::findOrFail($id);
$ideas = $community->ideas
return view('publicPages.ideas_in_community', compact('community', 'ideas));
}
Hope this helps!
UPDATE
I would imagine the reason that you're receiving the App\idea not found is because the model names don't match. It's good practice (and in certain environments essential) to Capitalise you class names so make sure of the following:
Your class name is Idea and it's file is called Idea.php
The class has it's namespace declared i.e. namespace App;
If you've added a new class and it's not being found you might need to run composer dump-autoload from the command line to update the autoloader.
I'm starting to learn Laravel. I've run through the example instructions from the site successfully and now I'm trying a second run through and I'm running into an issue.
I'm trying to connect to a database called zipCodes and has one table called zipCodeDetails.
In my Laravel project I have a model containing the following code:
<?php
class ZipCodeDetails extends Eloquent {}
And in my routes.php file I have the following code:
Route::get('zipCodes', function (){
$zipCodes = ZipCodeDetails::all();
return View::make('zipCodes')->with('zipCodes', $zipCodes);
});
The error I'm running into is when I try to load the URL:
http://localhost:8888/zipCodes
In my browser I'm getting the error code:
SQLSTATE[42S02]: Base table or view not found: 1146 Table 'zipcodes.zip_code_details' doesn't exist (SQL: select * from `zip_code_details`)
There's nothing written in my code where I define the database zipCodes as zipcodes or the table zipCodesDetails as zip_code_details. Something in laravel is changing the database and table names.
Does anyone know why this is happening and how I can prevent it? I don't want to just rename the database or table names because while that may get me by in testing it's not a viable solution in practice.
Thanks!
This is the behaviour that uses if no table is being explicitly defined. In your ZipCodeDetails class, you can set the table name that this model will be using.
class ZipCodeDetails extends Eloquent
{
protected $table = 'zipCodesDetails';
}
I new in yii framework. i create an application in yii framework. i created model, controller, views using gii. After that i alter database table. I deleted 2 column and add 3 new columns. After that overwrite the model using the gii. But when i am trying to save into that table it show property(which was old column that I deleted) is not defined. Plz provide me a solution for this.
You need to define all columns in the validation rules() method in your model, have a look and make sure that you have defined a rule for every column in the table there, for example (if it's a string with max length 128):
public function rules()
{
return array(
...
array('myField', 'length', 'max'=>128),
...
);
}
See some info about validation rules.
Also, for forms if you're using CActiveForm widget and calling fields like so:
echo $form->labelEx($model,'myField');
echo $form->textField($model,'myField');
Then you'll need to make sure that a label is defined in the model too, in the attributeLabels() method, for example:
public function attributeLabels()
{
return array(
...
'myField'=>'My Field',
...
);
}
Lastly, if you want the field to be searchable, you'll need to add a statement to the search() method in the model, for example:
public function search()
{
...
$criteria->compare('myField',$this->myField);
...
}
Make sure you have all of those elements present and you shouldn't get the '* is not defined' error.
Also, if you're using schema caching in your main config file, you'll have to clear your cache before the app will see your new database structure.
Your changes should also be set at the Views since there are forms, widgets using the old properties !! (for this exact save issue, you will need to fix _form.php which is the partial responsible from your model Save & Update actions.
You can either do the same as you did with the model: (regenerate it using gii) or you can edit it manually (i recommend you get used to this since in the future you will have code you don't want to loose just because of altering a column name. simple Find & edit in most of the text editors will do the job).
May be you need to read a bit more about how MVC works in general & in Yii in special
This is because you are using schema-cache. Your table schema is cached in Yii. You need to flush AR cache. Either flush full schema cache or use
Yii::app()->db->schema->getTable('tablename', true); in start of your action. This will update model schema-cache.
how can I access any table from database in my model?
For example, I have Indexcontroller and code inside it:
$results = $this->Index->query("SELECT COUNT(*) FROM my_own_table");
Error: Database table indices for model Index was not found.
So, as I understand, I can access only table with naming related to model/controller name. But what to do if I can't modify the table naming and I want to access it's data?
You're not limited to using a model that's directly associated with your controller (this is just default behaviour); you can use any model.
To achieve what you want, create a new model for this table, eg. MyOwnTable, and in your controller, you can add this property to the class:
public $uses = array('Index', 'MyOwnTable');
Now you can access MyOwnTable using CakePHP's built in ActiveRecord functionality:
$results = $this->MyOwnTable->find('count');
If you have other tables you want to access, simply create models for those and add them to the $uses property. (You can also use $this->loadModel('Model') inside the action if you prefer).
If you have a table name that isn't very readable (eg. my_tb_own_1_x or some such), you can call the model class something human readable (eg. MyTable), and add the $useTable property to the model:
public $useTable = 'my_tb_own_1_x';
/* and change the default primary key if you have an unusual one */
public $primaryKey = 'my_tb_own_1_x_idx_pk';
See the CakePHP manual for more info on how to change default model and controller behaviour:
1.3 - Model Attributes
2.0 - Model Attributes
1.3 - Controller Attributes
2.0 - Controller Attributes
Nope. You can access different tables. However, CakePHP stumbles over the fact that the table that is associated by default to the Index model doesn't exist.
In other words, the model Index expects a table 'indices' to exist (and an error is thrown when it doesn't). You can do one of two things:
Create a table indices
Add the following to your Index model: var $useTable = false;
If you have any use for an indices table I'd go with option 1. If you're not going to use the indices table, go with option 2.
If you go with either step 1 or 2, your example should start working.