Loop over one array as if it was a multidimensional array - php

Question

I have an array like:
$array = array(
'name' => 'Humphrey',
'email' => 'humphrey#wilkins.com
);
This is retrieved through a function that gets from the database. If there is more than one result retrieved, it looks like:
$array = array(
[0] => array(
'name' => 'Humphrey1',
'email' => 'humphrey1#wilkins.com'
),
[1] => array(
'name' => 'Humphrey2',
'email' => 'humphrey2#wilkins.com'
)
);
If the second is returned, I can do a simple foreach($array as $key => $person), but if there is only one result returned (the first example), I can't run a foreach on this as I need to access like: $person['name'] within the foreach loop.
Is there any way to make the one result believe its a multidimensional array?

Answer 1

Try this :
if(!is_array($array[0])) {
$new_array[] = $array;
$array = $new_array;
}

Answer 2

I would highly recommended making your data's structure the same regardless of how many elements are returned. It will help log terms and this will have to be done anywhere that function is called which seems like a waste.
You can check if a key exists and do some logic based on that condition.
if(array_key_exists("name", $array){
//There is one result
$array['name']; //...
} else {
//More then one
foreach($array as $k => $v){
//Do logic
}
}
You will have the keys in the first instance in the second yours keys would be the index.

Answer 3

Based on this, try:
function isAssoc(array $arr)
{
if (array() === $arr) return false;
return array_keys($arr) !== range(0, count($arr) - 1);
}
if(isAssoc($array)){
$array[] = $array;
}

Answer 4

First check if the array key 'name' exists in the given array.
If it does, then it isn't a multi-dimensional array.
Here's how you can make it multi-dimensional:
if(array_key_exists("name",$array))
{
$array = array($array);
}
Now you can loop through the array assuming it's a multidimensional array.
foreach($array as $key => $person)
{
$name = $person['name'];
echo $name;
}

Answer 5

The reason of this is probably because you use either fetch() or fetchAll() on your db. Anyway there are solutions that uses some tricks like:
$arr = !is_array($arr[0]) ? $arr : $arr[0];
or
is_array($arr[0]) && ($arr = $arr[0]);
but there is other option with array_walk_recursive()
$array = array(
array(
'name' => 'Humphrey1',
'email' => 'humphrey1#wilkins.com'
),
array(
'name' => 'Humphrey2',
'email' => 'humphrey2#wilkins.com'
)
);
$array2 = array(
'name' => 'Humphrey2',
'email' => 'humphrey2#wilkins.com'
);
$print = function ($item, $key) {
echo $key . $item .'<br>';
};
array_walk_recursive($array, $print);
array_walk_recursive($array2, $print);