I am getting post data like this
$data = file_get_contents('php://input');
I want the data put back to the stream, so I modified the method following instaed of above method
$stream = fopen('php://temp', 'w+');
stream_copy_to_stream(fopen('php://input', 'r'), $stream);
rewind($stream);
But it is not working. Can any one tell where I did wrong?
This case is need in wordpress plugin developement. If one plugin reads the post data, other plugin not able to get that data.
Thanks
As stated in the documentation, php://input can only be read once and doesn't support seek operations.
The only way to 'read' the input stream multiple times is through passing its copy in your program.
PHP input stream contains request body and your sample will work only if request will contain body.
curl -X POST -H "Content-Type: application/json" -H "Cache-Control: no-cache" -d 'sample body' "YOUR_ADDRESS"
For check add to code:
echo fgets($stream);
php://input is not available with enctype="multipart/form-data".
http://php.net/manual/en/wrappers.php.php
Related
Using third party service; they are providing webhook services; I have given my url to send the response on my page:
Example: https://abcd.com/postback.php
Getting curl response on postback.php; to read the POST data; I am using following code:
$postdata = file_get_contents("php://input");
but not able to read the header & data content.
Sample Response that they are sending:
curl -L -X POST 'https://abcd.com/postback.php' -H 'x-changenow-signature: xcgh123POPI6727kslsldjsd' -H 'Content-Type: application/json' --data-raw '{"status":"finished","payinHash":"31mrEanXyv","payoutHash":"485d8dz","payinAddress":"3Nups0bF","payoutAddress":"1K1LcQSPZVj2dM","fromCurrency":"sol","toCurrency":"btc","amountSend":0.06676453,"amountReceive":0.00010273,"refundAddress":"Bk1qVzc3GULcJQ0NoW4DsepRJHevzAD8ynznEQ1aNzGq","id":"f7bed8a9e4a350","updatedAt":"2022-06-23T11:22:38.728Z","createdAt":"2022-06-23T11:09:56.403Z","expectedReceiveAmount":0.0001024,"isPartner":false}
Please suggest how to get header and data part.
The headers are in $_SERVER. Use $_SERVER['HTTP_X_CHANGENOW_SIGNATURE'] to get the x-changenow-signature header.
The data content is in $postdata. Use
$data = json_decode($postdata);
to convert it to an object. Then you can use $data->status, $data->payinHash, etc. to get the fields of the post data.
POST
On my local machine, I want to use cURL as an HTTP client like so:
curl -X POST -F 'email=derp#example.com' -F 'password=blink182' http://example.com
The above curl statement uses the HTTP POST method which can be retrieved in PHP like so:
echo $_POST['email']; // derp#example.com
echo $_POST['password']; // blink182
php://input
However, what I really wanted is the data from the PHP input stream php:://input and not from the POST method $_POST.
The PHP input stream can be retrieved in PHP like so:
$input = json_decode( file_get_contents( 'php://input' ) );
echo $input->email; // derp#example.com
echo $input->password; // blink182
Which brings me to my question, how to send PHP input stream data using curl?
From the PHP website:
php://input is a read-only stream that allows you to read raw data from the request body. php://input is not available with enctype="multipart/form-data".
So if you specify the Content-Type as application/json using -H "Content-Type: application/json" you ought to get it in the input stream
complete example:
curl -X POST https://reqbin.com/echo/post/json
-H 'Content-Type: application/json'
-d '{"email":"derp#example.com","password":"blink182"}'
Sending POST request data stored in a variable using curl, sends $variable instead json data.
P=`/usr/bin/sudo /usr/bin/curl -X POST -H "Content-Type:application/json" --data-urlencode $data http://127.0.0.1/abc.php`
Trying to send POST request to php, but it receives $data instead json data{"abc":"11","xyz":"20"}.
Had try with '$data', "$data", \'$data\' and \"$data\", where $data = {"abc":"11","xyz":"20"}
Please give an example that works. Thanks in advance.
P=`/usr/bin/sudo /usr/bin/curl -X POST -H "Content-Type:application/json" -d "$O" http://127.0.0.1/abc.php` solves issue.
If you add single quote it won't expand variable, so it requires to add double quote.
I suggest all time reload page or script, as I have seen if you not reload, it work with your last change instead new one.
I've got a cURL request that works from the command line, but I can't figure out how to translate it into the PHP implementation of cURL. I believe that my issue is with the formatting of the data that's being sent, but I'm not 100% sure that is the case. This is the curl command I want to send:
# curl -X PUT -d '{"shared_link": {"access":"open"}}' \
-H "Authorization: Bearer ACCESSCODE" https://api.example.com/files/12345
I know that command works! So here's how I'm trying to reproduce it in PHP (where I have a variety of other curl commands working, but none quite like this).
$url = 'https://api.example.com/files/1234';
$header = array('Authorization: Bearer ACCESSCODE');
$data = array('shared_link'=>array('access'=>'open'));
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_CUSTOMREQUEST,'PUT');
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch,CURLOPT_POSTFIELDS,$data);
curl_setopt($ch,CURLOPT_HTTPHEADER,$header);
$output = curl_exec($ch);
curl_close($ch);
return $output;
What I expect to get (and what I do get, when running the command from the command line) is a JSON response from the API server containing all the info about the file, including a change to the 'shared_link' value. What I get instead is a JSON response containing all the info about the file, with the 'shared_link' value unchanged. This is identical to if I were sending a GET request, or a PUT request where the format of the data was valid, but which didn't match any of the file's fields that were possible to update.
So I don't know if the problem with my request is the format of the data (this is what I think is the most likely) or whether I'm correctly configuring curl to do a PUT. I believe I'm doing that the way I've seen it described in a number of other examples, but it still seems a bit strange to me, so I can't be totally sure I'm doing it correctly. In addition, there could be some other area where I'm making a mistake that I don't recognize!
I've tried a number of different ways of formatting the data, none of which worked for me, including:
// This fails with 400 bad request
$data = http_build_query(array('shared_link'=>array('access'=>'open')));
// So does this
$data = urlencode("shared_link[access]=open");
// This fails because the JSON gets converted into objects,
// which POSTFIELDS won't accept
$data = json_decode('{"shared_link": {"access":"open"}}');
I'm running out of things to try. Can someone help me figure out what I'm doing wrong? And if there's any relevant information that I've left out, just let me know and I'll be happy to provide it.
Thanks in advance.
EDIT:
So the answer, it turns out, was so obvious that I overlooked it!
All I had to do was:
$data = '{"shared_link": {"access": "open"}}'
So yeah, question answered. Thanks CBroe!
In my (sort of) defense, the documentation for CURLOPT_POSTFIELDS (http://php.net/manual/en/function.curl-setopt.php) says that the value for that option has to be either an array or a urlencoded string, which is what I was going on. So I was working under that assumption, which was clearly mistaken, since what worked is definitely neither an array nor a urlencoded string.
You can try this
$post_body = http_build_query(
array(
'shared_link[access]' => 'open'
)
);
After that, pass curl opt as curl_setopt($curl, CURLOPT_POSTFIELDS, urldecode($post_body));
I am having difficulties figuring this out. I can see I am posting XML and I see the length of it but I cannot figure out how to display or access the POST DATA
CONTENT-TYPE: text/xml<br />
CONTENT-LENGTH: 640<br />
separately I have
curl -k -H 'content-type: text/xml' -d 'XML_DATA_HERE' https://ip/page.php
Try
$xml = file_get_contents('php://input');
http://docs.php.net/manual/en/wrappers.php.php says:
php://input allows you to read raw POST data. It is a less memory intensive alternative to $HTTP_RAW_POST_DATA and does not need any special php.ini directives. php://input is not available with enctype="multipart/form-data".