how to compare array for single result using if statement - php

Question

i was doing validation for user form after each validation i used to store "valid" in a array index and at last comparing them like this:
if(isset($fullname)){
if ($valid["name"]=="valid"&&$valid["username"]=="valid"&&$valid["password"]=="valid"&&$valid["email"]=="valid") {
session_start();
$_SESSION["reg_name"] = $fullname1;
$_SESSION["reg_username"] = $username1;
$_SESSION["reg_email"] = $email1;
$_SESSION["reg_password"] = $password1;
$_SESSION["reg_gender"] = $_REQUEST['gender'];
header("location:validation&insertion.php");
}
Well i will check validation and then make session .
My question is there any short way to check the whole array across a single value like "valid"?
I hope you have understand my question.Comment it if it is not asked well.
Do not rate as negative.Please ignore my grammar mistakes.I hate those who edit my question's grammar.

Answer 1

You can just count the number of unique values and check if it's equal to 1, then check one value if it is "valid".
if (count(array_unique($valid)) === 1 && $valid["name"] === "valid") {
session_start();
$_SESSION["reg_name"] = $fullname1;
$_SESSION["reg_username"] = $username1;
$_SESSION["reg_email"] = $email1;
$_SESSION["reg_password"] = $password1;
$_SESSION["reg_gender"] = $_REQUEST['gender'];
header("location:validation&insertion.php");
}
Or just simply check if a "notvalid" value is found in the array:
if (!in_array("notvalid", $valid)) {
session_start();
$_SESSION["reg_name"] = $fullname1;
$_SESSION["reg_username"] = $username1;
$_SESSION["reg_email"] = $email1;
$_SESSION["reg_password"] = $password1;
$_SESSION["reg_gender"] = $_REQUEST['gender'];
header("location:validation&insertion.php");
}