Read value from database, echo - php

Question

Very basic but as a rookie I am struggling. The echo doesnt show any value, just the text. What am I doing wrong?
Connect.php:
<?php
$connection = mysqli_connect('test.com.mysql', 'test_com_systems', 'systems');
if (!$connection){
die("Database Connection Failed" . mysqli_error($connection));
}
$select_db = mysqli_select_db($connection, 'swaut_com_systems');
if (!$select_db){
die("Database Selection Failed" . mysqli_error($connection));
}
?>
Get.php:
<?php
require('connect.php');
$query2 = "SELECT systemid FROM user WHERE username=test";
$result2 = mysqli_query($connection, $query2);
echo ( 'SystemID: '.$result2);
?>

Answer 1

Assuming you have connected to the database successfully then the query is incorrect. You must wrap all text values in quotes like this
<?php
require('connect.php');
$query2 = "SELECT systemid FROM user WHERE username='test'";
$result2 = mysqli_query($connection, $query2);
Now the mysqli_query submits the query to the database where it is run and a result set built. To see the result set you need to read the result set back from the database using one of the fetch functions for example
$row = mysqli_fetch_assoc($result2);
echo 'SystemID: ' . $row['systemid'];
If there are more than one rows in the result set you must do that in a loop like this
while ($row = mysqli_fetch_assoc($result2)){
echo 'SystemID: ' . $row['systemid'];
}

Answer 2

You are printing the mysqli result object. In order to printthe result you have to use:
$row = mysqli_fetch_assoc($result2);
print_r($row);

Answer 3

You need to collect the results of the mysqli_query using the following:
require('connect.php');
$query2 = "SELECT systemid FROM user WHERE username=test";
$result2 = mysqli_query($connection, $query2);
while ($row = mysqli_fetch_assoc($result2))
{
echo "System ID is: " . $row['systemid'];
}