I'm new to backend programming and CodeIgniter is my first framework. This is new to me. Right now, the thing that I'm working is that I need to create a query based on the JSON encoded data saved at my table.
I have here a segmentation form that should build a query to look/search for the customers profiles based on the condition set
Segmentation form
$segment = array(
...
'filters' => json_encode($post['filters']), //to insert the filters in json
...
);
if ($this->model->addSegments($segment))
The filters saved in the database are like this :
{"data":[{"data":{"condition":"0","attribute":"gender","sign":"=","value":"Male"},"type":"condition","operator":"0","filter":{"operator":"0"}}],"type":"match","operator":"0"}
Looking for the answers, I found this forum and I relate it to the problem that I had: http://www.codingforums.com/php/202207-turning-json-object-into-nested-sql-where-clause.html
Calling the same like function (solution at the link) to the controller using this lines:
$filter = $this->model->getSegmentsFilters($id_segment);
$filters = $this->model->parseFilterToQuery(json_decode($filter['filters'], true));
With the parameter TRUE from the json_decode, It throws the filters in array and using print_r shown like this:
Array (
[0] => Array (
[data] => Array (
[condition] => 0
[attribute] => firstname
[sign] => =
[value] => John )
[type] => condition
[operator] => 0
[filter] => Array (
[operator] => 0 )
)
[1] => Array (
[data] => Array (
[condition] => 0
[attribute] => gender
[sign] => =
[value] => Male )
[type] => condition
[operator] => condition
[filter] => Array (
[operator] => 0 )
)
)
the $sql inside if(is_array) doesn't show any value to concatenate with. I want it to concatenate with another query as a WHERE clause like this idea.
$sql = "SELECT * FROM customers WHERE" . parseFilterToQuery($filters);
If you think that the solution/procedure that I came up is correct. My question is that inside the if(is_array) condition,
how should I work on it with associative JSON array?
Related
I have a multidimensional array stored in $accounts variable :
Array
(
[0] => Array
(
[id] => 1
[account] => ACR016
[desc] => Salary
)
[1] => Array
(
[id] => 2
[account] => ACR017
[desc] => Bonuses
)
)
I'd like to find/get the "desc" value by using its "account" inside $accounts,
In SQL i will go like this :
SELECT desc FROM table WHERE account = 'ACR016';
How to do that with PHP without do the SQL query (because the array already stored in variable) and without looping ?
Use https://www.php.net/manual/en/function.array-column.php for this.
As this is a builtin function it should perform better than doing your own loop.
Example:
$accountDescriptions = array_column($accounts,'desc','account');
Will result in:
Array
(
[ACR016] => Salary
[ACR017] => Bonuses
)
Alternatively you can use:
Example:
$accountDescriptions = array_column($accounts,null,'account');
Then you will get all data keyed with account instead of numeric index.
I am getting data from an api (that I cannot query agains, just get lump of data), and then I need to query against those data like I would do using database. Only It would be great if I could do it recursively.
Data example
[0] => Array
(
[id] => 1
[url] => https://domain.com/api/1.0/item/1/
[name] => some_item
[category] => some category
[created_by] => Array
(
[id] => 1
[screen_name] => tomino
)
[current_user_domain_access] => Array
(
[is_active] => 1
[is_administrator] => 1
)
[alerts_enabled] => 0
)
(much shortened version)
I receive an array of objects like that and then I need to select/filter/search by values.
Something like this
SomeModel::find(['category'=>'some category','current_user_domain_access' => ['is_administrator' => 1]]);
Is that something that would be possible in PHP? I was thinking about flattening the array, but then there might be key conflicts
1) select data : You can select data by (array_name->id),(array_name->url) and so on...
2)Filter : add conditions according to requirement
3)search : in_array(),array_search
I have a result of an SQL query that looks like this
Array
(
[0] => stdClass Object
(
[field_number] => 1
[value] => Joe
)
[1] => stdClass Object
(
[field_number] => 2
[value] => Bloggs
)
[2] => stdClass Object
(
[field_number] => 3
[value] => 12566
)
[3] => stdClass Object
(
[field_number] => 4
[value] => 2000-07-24
)
)
It wont always return all the fields as some are not required therefore not saved to the database.
I know that first name is stored with field number 1. How can I look this up in the object.
EG
$first_name = $result => field_number == 1
I know thats not right, but Im sure there must be a simple way to get this info?
Thanks
If the values in the array are not in order (eg array[0] does not always contain field_number 1) then you will need to iterate the array:
foreach($array as $item){
if($item->field_number==1){
$first_name = $item->value;
break;
}
}
However, if this is the result of an SQL query, probably you need to rewrite the query to give you data in a more useable form
I've come across a weird scenario I do not know how to code around. I'm creating a JSON API for a wordpress site. I'm using the Connections plugin and trying to pull out the "original" image filename. The output of my sql command is this:
{
["options"]=>
string(396) "a:4:{s:5:"entry";a:1:{s:4:"type";s:12:"organization";}s:5:"group";a:1:{s:6:"family";a:0:{}}s:4:"logo";a:2:{s:6:"linked";b:0;s:7:"display";b:0;}s:5:"image";a:3:{s:6:"linked";b:1;s:7:"display";b:1;s:4:"name";a:4:{s:9:"thumbnail";s:25:"invoicelogo_thumbnail.jpg";s:5:"entry";s:21:"invoicelogo_entry.jpg";s:7:"profile";s:23:"invoicelogo_profile.jpg";s:8:"original";s:24:"invoicelogo_original.jpg";}}}"
}
}
I'm using the following command to acquire that:
querystr = "SELECT options FROM {$wpdb->prefix}connections WHERE id= '{$_GET['companyID']}'";
$options = $wpdb->get_results($querystr);
I'm not sure how to pull out the "original" part of this code though as it's not all that organized. Any help would be appreciated.
What you are seeing is the results of a php serialize call
To get at the original name just do this.
$decodedOptions = unserialize($options);
$original = $decodedOptions["image"]["name"]["original"];
Hope that helps
As a side note the deserialized data looks like
Array
(
[entry] => Array
(
[type] => organization
)
[group] => Array
(
[family] => Array
(
)
)
[logo] => Array
(
[linked] =>
[display] =>
)
[image] => Array
(
[linked] => 1
[display] => 1
[name] => Array
(
[thumbnail] => invoicelogo_thumbnail.jpg
[entry] => invoicelogo_entry.jpg
[profile] => invoicelogo_profile.jpg
[original] => invoicelogo_original.jpg
)
)
)
I am playing around with a quotes database relating to a ski trip I run. I am trying to list the quotes, but sort by the person who said the quote, and am struggling to get the paginate helper to let me do this.
I have four relevant tables.
quotes, trips, people and attendances. Attendances is essentially a join table for people and trips.
Relationships are as follows;
Attendance belongsTo Person hasMany Attendance
Attendance belongsTo Trip hasMany Attendance
Attendance hasMany Quote belongs to Attendance
In the QuotesController I use containable to retrieve the fields from Quote, along with the associated Attendance, and the fields from the Trip and Person associated with that Attendance.
function index() {
$this->Quote->recursive = 0;
$this->paginate['Quote'] = array(
'contain' => array('Attendance.Person', 'Attendance.Trip'));
$this->set('quotes', $this->paginate());
}
This seems to work fine, and in the view, I can echo out
foreach ($quotes as $quote) {
echo $quote['Attendance']['Person']['first_name'];
}
without any problem.
What I cannot get to work is accessing/using the same variable as a sort field in paginate
echo $this->Paginator->sort('Name', 'Attendance.Person.first_name');
or
echo $this->Paginator->sort('Location', 'Attendance.Trip.location');
Does not work. It appears to sort by something, but I'm not sure what.
The $quotes array I am passing looks like this;
Array
(
[0] => Array
(
[Quote] => Array
(
[id] => 1
[attendance_id] => 15
[quote_text] => Hello
)
[Attendance] => Array
(
[id] => 15
[person_id] => 2
[trip_id] => 7
[Person] => Array
(
[id] => 2
[first_name] => John
[last_name] => Smith
)
[Trip] => Array
(
[id] => 7
[location] => La Plagne
[year] => 2000
[modified] =>
)
)
)
I would be immensely grateful if someone could suggest how I might be able to sort by the the first_name of the Person associated with the Quote. I suspect my syntax is wrong, but I have not been able to find the answer. Is it not possible to sort by a second level association in this way?
I am pretty much brand new with cakephp so please be gentle.
Thanks very much in advance.
I've had the similar problem awhile back. Not with sort though. Try putting the associated table in another array.
echo $this->Paginator->sort('Name', 'Attendance.Person.first_name');
change to:
echo $this->Paginator->sort('Name', array('Attendance' => 'Person.first_name'));
Hope this helps
i'm also looking for help with this.
so far i've found that you can sort multi level associations in controller's pagination options after using the linkable plugin https://github.com/Terr/linkable.
but it breaks down when you try to sort form the paginator in the view. i'm using a controller for magazine clippings. each clipping belongs to an issue and each issue belongs to a publication.
$this->paginate = array(
"recursive"=>0,
"link"=>array("Issue"=>array("Publication")),
"order"=>array("Publication.name"=>"ASC",
"limit"=>10);
after debugging $this->Paginator->params->paging->Clipping in the view, you can see that the sort is described in two separate places, "defaults" and "options". the sort info needs to be present in both for it to work in the view.
here is after setting order in controller:
[Clipping] => Array
(
[page] => 1
[current] => 10
[count] => 6685
[prevPage] =>
[nextPage] => 1
[pageCount] => 669
[defaults] => Array
(
[limit] => 10
[step] => 1
[recursive] => 0
[link] => Array
(
[Issue] => Array
(
[0] => Publication
)
)
[order] => Array
(
[Publication.name] => ASC
)
[conditions] => Array
(
)
)
[options] => Array
(
[page] => 1
[limit] => 10
[recursive] => 0
[link] => Array
(
[Issue] => Array
(
[0] => Publication
)
)
[order] => Array
(
[Publication.name] => ASC
)
[conditions] => Array
(
)
)
)
and here is after using $this->Paginator->sort("Publication","Publication.name");.
notice the options array is empty.
[Clipping] => Array
(
[page] => 1
[current] => 10
[count] => 6685
[prevPage] =>
[nextPage] => 1
[pageCount] => 669
[defaults] => Array
(
[limit] => 10
[step] => 1
[recursive] => 0
[link] => Array
(
[Issue] => Array
(
[0] => Publication
)
)
[order] => Array
(
[Publication.name] => DESC
)
[conditions] => Array
(
)
)
[options] => Array
(
[page] => 1
[limit] => 10
[recursive] => 0
[link] => Array
(
[Issue] => Array
(
[0] => Publication
)
)
[order] => Array
(
)
[conditions] => Array
(
)
)
does one really need to modify the paginator class to make this work?
UPDATE:
i found out the problem:
in the core cake controller paginator merges default and options to create the find query.
but the options array is empty when using linkable to sort. because options is listed after default it overrides default and the empty array replaces the default array of options.
solution to this is extending the paginate function inside of app_controller.php and unsetting the options array order value if it is empty:
(line 1172 in cake/libs/controller/controller.php)
if(empty($options["order"])){
unset($options["order"]);
}
then the options will not be overwritten by thte blank array.
of course this should not be changed inside of controller.php, but put it in app_controller.php and move it to your app folder.
On CakePHP 3 this problem can be solved by adding 'sortWhitelist' params to $this->paginate on your controller.
$this->paginate = [
// ...
'sortWhitelist' => ['id', 'status', 'Attendance.Person.first_name']
];
And then in your view:
echo $this->Paginator->sort('Name', 'Attendance.Person.first_name');
This is noted in the docs:
This option is required when you want to sort on any associated data, or computed fields that may be part of your pagination query:
However that could be easily missed by tired eyes, so hope this helps someone out there!