Working on a homepage I came to the following problem:
I want to display a table - the number of table columns can be chosen with checkboxes. Also, my website should work on a mobile phone, so I put in the correspondingly meta line.
Unfortunately, my website do not work properly as it do not shows my horizontal scrollbar..
PHP Code:
echo '<table id="dynamictable">';
echo '<tr>';
foreach($res_category_arr as $columnname)
{
echo '<th>' . $columnname. '</th>';
}
echo '</tr>';
if (mysqli_num_rows($result) > 0)
{
while($data_current_row=mysqli_fetch_assoc($result))
{
echo '<tr>';
foreach($res_category_arr as $tabledata)
{
echo '<td>' . $data_current_row[$tabledata] . '</td>';
}
echo '</tr>';
}
}
echo '</table>';
res_category_arr represents an array, which contains the wanted column names.
CSS Code:
#dynamictable{
width: 100%;
overflow-y: auto;
margin: 0 0 1em;
text-align: center;
}
#dynamictable::-webkit-scrollbar {
-webkit-appearance: none;
width: 14px;
height: 14px;
}
#dynamictable::-webkit-scrollbar-thumb {
border-radius: 8px;
border: 3px solid #fff;
background-color: rgba(0, 0, 0, .3);
}
Take the ID off the table, and put it on a div AROUND the table.
It should do what you're looking for, but you might also want to add a width:100% back to the table as well.
EDIT: Figured I would add a simple working example here.
http://codepen.io/anon/pen/qaGARr?editors=1100#0
.scroll {
overflow-x:auto;
width:100%;
}
table {
width:100%;
min-width:700px;
}
If you go below 700px wide, the scrollbar shows up
Related
As you can see in the picture, there is a box to the right with some text and a lot of white space.
My goal is to have the text under the pictures while I have 3 pictures in a row that are nicely aligned.
When I try this either the pictures aren't aligned anymore or the pictures aren't cropped anymore.
I wanted every picture with the same size and still sharp but, then this issue came up.
#content {
width: 100%;
max-width: 100%;
margin: 20px auto;
}
form {
width: 50%;
margin: 20px auto;
}
form div {
margin-top: 5px;
}
#img_div {
width: 30%;
margin-left: 2%;
margin-right: 1%;
margin-bottom: 3%;
border: 2px solid #d8680c;
float: left;
}
#img_div:after {
content: "";
display: block;
clear: both;
}
img {
float: left;
object-fit: cover;
width: 250px;
height: 250px;
}
#pictext {
word-wrap: break-word;
}
<div id="content">
<?php
while ($row = mysqli_fetch_array($result)) {
echo "<div id='img_div'>";
echo "<img src='fotopage\images/" . $row['image'] . "' >";
echo "<p id='pictext'>" . $row['image_text'] . "</p>";
echo "</div>";
}
?>
</div>
use class instead of using ID
ID must be unique and when you do the loop there will be some other divs with same ID
add it like this
<?php
while ($row = mysqli_fetch_array($result)) {
echo "<div class='img_div'>";
echo "<img src='fotopage\images/" . $row['image'] . "' >";
echo "<p class='pictext'>" . $row['image_text'] . "</p>";
echo "</div>";
}
?>
make sure to reflect them via JS or JQuery depends on what your are using
I'm still learning, please go gentle with me.
When I run my script everything works except the full formatting with my css. In the snipped of code, I would like the . However, when I have the div in the middle of the , as seen below, when I run the page I have two lines of information. Line one contains the flag image, line two contains my outputted "luchthavencode", underlined as desired.
How would I format the css / php/html code so that they all are contained within one line.
If I move the to before the img, everything is in a line as desired -- it's OK that when you hover over the flag the name comes up, also), it also generates two lines.
echo "<td width='100px' bgcolor='#C6DEFF'><img src='http://globe-trekking.com/vg/img/flags/".$row['countryflag']."'> <div class='top10_luchthaven' data-tooltip=\"".htmlspecialchars($row['luchthavennaam'])."\" >".$row['luchthavencode']."</div></td>";
Using the following css styles
.top10_luchthaven {
position: relative;
border-bottom: .1em dotted;
width:30px;
}
.top10_luchthaven:hover:after {
background: url(http://globe-trekking.com/vg/img/hovercard-bg.png) repeat-x;
border-radius: 5px;
bottom: 5px;
color: #fff;
content: attr(data-tooltip);
left: 20%;
padding: 5px 15px;
position: absolute;
z-index: 98;
width: 400px;
}
.top10_luchthaven:hover:before {
border: solid;
border-color: #333 transparent;
border-width: 6px 6px 0 6px;
bottom: 20px;
content: "";
left: 50%;
position: absolute;
z-index: 99;
with the full table php/html code:
echo "<table width='200px' border='0' cellpadding='2' cellspacing='2'>";
echo "<tbody>";
echo "<tr>";
echo "<td bgcolor='#0033FF'><strong class='home_box_header'>#</strong>";
echo "<td bgcolor='#0033FF'><strong class='home_box_header'>Luchthaven</strong>";
echo "<td bgcolor='#0033FF'><strong class='home_box_header'>No.</strong>";
echo "</tr>";
$line = 1;
while($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td bgcolor='#C6DEFF'>$line</td>";
echo "<td width='100px' bgcolor='#C6DEFF'><img src='http://globe-trekking.com/vg/img/flags/".$row['countryflag']."'> <div class='top10_luchthaven' data-tooltip=\"".htmlspecialchars($row['luchthavennaam'])."\" >".$row['luchthavencode']."</div></td>";
echo "<td width='60px' bgcolor='#C6DEFF'>".$row['sum']."</td>";
echo "</tr>";
$line++;
}
echo "</tbody>";
echo "</table>";
The problem is that divs are block level elements by default, which means they line break, so you need to have CSS that instructs those divs to be inline with the image next to it. Try doing this...
.top10_luchthaven {
display: inline;
}
If that doesn't work, then do display: inline-block instead.
I am having an issue with my CSS, It is by far something i am not good at but i cant seem to solve an issue where my Table will not display based on screen width. It used to be static but since changing the values to % of screen it has not made any visual changes to my Table. (UPDATED BASED ON ANSWERS/COMMENTS)
HTML / PHP
//Table Titles row
echo "<div class='tablediv' style='width:100%; border: 5px solid black'><table name ='ipv4' class='tableparent'><td class='tabled' width='100%'>IP Address</td><td class='table'>Subnet</td><td class='table'>PC Name</td><td class='table'>Owner</td><td class='table'>Customer</td><td class='table'>Customer Site</td></tr>";
//loops through search results and echo table
while ($row = mysqli_fetch_array($view)){
$id = $row['companyId'];
$company = $customers[$id];
echo "<tr><td class='tabled'>". $row['ip']."</td><td class='table'>". $row['Subnet']."</td><td class='table'>".$row['hostName']."</td><td class='table'>". $row['owner']."</td><td class='table'>". $company ."</td><td class='table'>".$row['siteName']."</td></tr>";
}
echo"</table></div>";
CSS
.table
{
border:1px solid black;
text-align: left;
padding:10px;
width:12%;
overflow:hidden;
}
.tabled
{
top:500px;
border:1px solid black;
text-align: left;
width:40%;
overflow: hidden;
}
.tableparent
{
border:1px solid black;
border-collapse:collapse;
width: 95%;
text-align: left;
padding:15px;
table-layout:fixed;
}
.tablediv
{
position:absolute;
width: 95%;
top:70px;
}
Currently this displays the table looking like this
Add width="100%" in table tag, it will set full width as parent div width
echo "<div class='tablediv' style='width:100%'><table width='100%' name ='ipv4' class='tableparent'><td class='tabled'>IP Address</td><td class='table'>Subnet</td><td class='table'>PC Name</td><td class='table'>Owner</td><td class='table'>Customer</td><td class='table'>Customer Site</td></tr>";
Found the issue, The page was POST'ed to by ajax. I then found that the result's div of the search was accidentally surrounded by another div, limiting its width. Thanks for the help
I have a CSS related problem, that would look easy, but I have been slamming my head against the wall for the last hour, since the tweaks arround i tried are not applying.
For some odd reason, the select dropdown menu wont stick into the cell, but is placed above the table.See picture below
The loop code to generate the table is build up as followed: (i didnt bother posting the php cause thats not relevant)
echo '<tr class="items">';
echo '<td id="cell11">'.$Date.'</td>';
echo '<td id="cell21">'.$link.'</td>';
echo '<td id="Fright1">'.MakeUserRoleDropdown($StatusId).'</td>';
echo '</tr>';
The CSS is pretty basic:
select { width: 367px; font-family: Verdana; font-size: 12px; color: #666; background: white; border: 1px solid #CECECE; padding: 4px;}
.dropdownrole { width:150px;}
#cell11 { padding-left: 10px; padding-right: 10px; width: 200px; text-align:left;}
#cell21 { padding-left: 10px; padding-right: 10px; width: 200px; text-align:left;}
#Fright1 { padding-left: 10px; padding-right: 10px; width: 200px; text-align:right;}
table.items tr { height: 32px; background:url(../images/tableRow.png); border-top: 1px solid #CCC; padding: 0; margin: 0;}
.items { width: 100%; border-collapse: collapse; color: ##797979; font-family: Verdana; font-size: 11px; }
table { border-spacing:2px;}
dropdownrole is in this case te class applied to the dropdown menu.
As you see, the dropdown wont apply to the row and just is put above the table (even in the code it's not even in the cell) And I cant wrap my head arround why. I made cells already bigger in size (height and width) but no luck.
Did i do something wrong within the CSS?
EDIT
Per request of the dropdown function.
function MakeUserRoleDropdown($StatusId){
echo "<select name='StatusId' class='dropdownrole'>";
$results = LoadRoles();
while($row = mysql_fetch_array($results)){
echo "<option value='".$row['SgroupId']."' ";
if($StatusId == $row['SgroupId']){
echo "selected='selected'";
};
echo ">".$row['SgroupUser']."</option>";
}
echo "</select>";
}
And here is the output in HTML.
I Think the problem is, that you call MakeUserRoleDropdown which contains echos
you proceed to use this method in this string: echo '<td id="Fright1">'.MakeUserRoleDropdown($StatusId).'</td>';
Alter your MakeUserRoleDropdown to this:
function MakeUserRoleDropdown($StatusId){
$str = '';
$str .= "<select name='StatusId' class='dropdownrole'>";
$results = LoadRoles();
while($row = mysql_fetch_array($results)){
$str .= "<option value='".$row['SgroupId']."' ";
if($StatusId == $row['SgroupId']){
$str .= "selected='selected'";
};
$str .= ">".$row['SgroupUser']."</option>";
}
$str .="</select>";
return $str;
}
And you should be good.
I am building a comics website, but am having trouble aligning the images the way I want.
I'm going for this:
I'm trying to get the comics in a row like this (blue)
But all the images are coming out on top of each other:
I thought my CSS was correct...
*{
margin: 0;
padding: 0;
}
body {
background: gray;
text-align: center;
}
#wrapper {
width: 960px;
margin: 0 auto;
text-align: left;
background: white;
}
#comics {
/*top, right, bottom, left*/
margin: 50px 100px 50px 100px;
}
.comicBG {
position: absolute;
border: 1px dotted black;
background: #99FF33;
padding: 25px;
}
PHP:
echo '<td>';
echo '<span class="comicBG"><a href="./templates/viewcomic.php?id=' . $row['imgid'] . '">
<img src="' . $thumbpath.$row['imgthumb'] . '"/></a>' .
'<br />' . $row['imgtitle'] . '</span>';
echo '</td>';
Does anyone know the best way to position individual data elements (like the images)?
Should I be using a table, or a list?
Thanks!
I'd use an unordeder list. And you see all the images at the same place because you've set their position to absolute and you haven't set any coordinates.
You can remove position:absolute and the images should be in rows. And if you use an unorderer list, you can float the li's to the left.