Displays the data array in the default table with looping - php

Question

I have 1 array data may also be more and want to present it on the table, I tried to make the default table by 5 column, but when I try the same result 5 column all its data. should have 3 column 2 column is empty, what is lacking in my script?
This myscript
<?php
$no = 1;
for($x=1; $x<=5; $x++) {
foreach ($mydata as $row) {
echo '<tr>';
echo '<td>'.$no.'</td>';
echo '<td>'.$row->id.'</td>';
echo '<td>'.$row->name.'</td>';
echo '<td>'.$row->class.'</td>';
echo '</tr>';
$no++;
}
}
?>
the results of the script
NO | ID | NAME | ClASS |
____|____ |______|_______|
1 | 001 | Paul | x |
2 | 001 | Paul | x |
3 | 001 | Paul | x |
4 | 001 | Paul | x |
5 | 001 | Paul | x |
I expected
NO | ID | NAME | ClASS |
____|____ |______|_______|
1 | 001 | Paul | x |
2 | | | |
3 | | | |
4 | | | |
5 | | | |

Answer 1

Try this:
<?php
$no = 1;
for ($x=1; $x <= 5; $x++) {
if (isset($mydata[$x-1])) {
$row = $mydata[$x-1];
echo '<tr>';
echo '<td>'.$no.'</td>';
echo '<td>'.$row->id.'</td>';
echo '<td>'.$row->name.'</td>';
echo '<td>'.$row->class.'</td>';
echo '</tr>';
} else {
echo '<tr>';
echo '<td>'.$no.'</td>';
echo '<td></td>';
echo '<td></td>';
echo '<td></td>';
echo '</tr>';
}
$no++;
}
?>
You need to check if the data is set based off $x var and then render empty row or populated.

Answer 2

You don't need nested loops. Just a single loop from 1 to 5, and each iteration shows the corresponding element of the array, or empty cells if there's no such element.
for ($x = 1; $x <= 5; $x++) {
echo "<tr>";
echo "<td>" . $x . "<td>";
if (isset($mydata[$x-1])) {
$row = $mydata[$x-1];
echo '<td>'.$row->id.'</td>';
echo '<td>'.$row->name.'</td>';
echo '<td>'.$row->class.'</td>';
} else { // show empty fields
echo "<td></td><td></td><td></td>";
}
echo "</tr>";
}
There's also no need for separate variables $x and $no.