PHP - __call() confusion - php

I have some confusion with __call() and everything I search about it tells me it should work
<?php
class A {
abstract public function C();
private function B(){
echo "B";
}
public function __call($method,$arguments){
if(method_exists("C", $method)) {
$this->B();
return call_user_func_array(array("C",$method),$arguments);
}
}
}
class B extends A{
public function C(){
echo "C";
}
}
$b = new B();
$b->C();
//the result I get:
// C
//the result I want;
// BC
?>
So, what I want as result is that I call function C but B get's echo'd out first. It worked at some point even, I am just really confused at what is going on. The php manual isn't that clear about it either, at least not what I am trying to do.
note: The most confusing is, the above __call method is not reponsive anymore, if I do a test message in there, doesn't print it.
As said, I've got it to work at some magical moment. Can someone point me to what I am doing wrong, or is it possible? ( I have changed some stuff over time, so that might have changed the scenario.

I think you're confusing what __call does. It's for inaccessible methods. So let's take A
class A {
abstract public function C();
private function B(){
echo "B";
}
public function __call($method,$arguments){
if(method_exists("C", $method)) {
$this->B();
return call_user_func_array(array("C",$method),$arguments);
}
}
}
Now, your B() is private but C() in your child is not
class B extends A{
public function C(){
echo "C";
}
}
The problem is your code never touches B() the method. You're calling B() the class
$b = new B();
$b->C();
To get __call to work you need to do
$b = new B();
$b->B(); // invokes __call()

__call() is only invoked when the function isn't specified/accessible --
See: http://us2.php.net/manual/en/language.oop5.overloading.php#language.oop5.overloading.methods
You cannot do what you are attempting to do.

Related

PHP - Call a method from the class where i instantiated my object

I have 2 classes declared like in the example below.
class A{
protected $process;
public function __construct() {
......
$this->process=new B();
}
public function do_something(){
....
}
}
class B{
// content not important
// I need to call do_something from class A
}
My question is, how can I call from class B the method do_something() from class A? Is it possible?
From your example it is impossible for instance of B to know that it is instantiated and stored by an instance of class A. You need to create that connection explicitly in some way.
I didn't think this would even work, but apparently you can pass instance of A to B before A is even done with its constructor:
class A {
protected $process;
public function __construct() {
$this->process = new B( $this );
}
public function do_something() {
var_dump( 'do_something' );
}
public function test() {
$this->process->test();
}
}
class B {
public function __construct( A $a ) {
$this->a = $a;
}
public function test() {
$this->a->do_something();
}
}
$a = new A();
$a->test(); // do_something
It's hard to give an advice on what the best approach for your particular case would be, as we don't know what either A or B does.
There's a few ways to achieve this. One way would be to make B and extension of A - thereby allowing all methods of the class A to be callable on the object B. Another way is to create a new object of A inside B and call that method. Or you can pass
Here's an example where B is extended from A. By doing this, all properties and methods of A can be called on B, unless overwritten in B.
class A {
public function doSomething(){
echo "doSomething() called in A";
}
}
class B extends A {
public function someMethod() {
$this->doSomething();
}
}
$b = new B();
$b->someMethod();
The above would output doSomething() called in A.
Or, you can create an object A and call that method inside B.
class B {
public function someMethod() {
$a = new A();
$a->do_something();
}
}
$b = new B();
$b->someMethod();
After reading all the answers and doing some research i think that the best method for me was the use of Traits
"Traits are a mechanism for code reuse in single inheritance languages such as PHP. A Trait is intended to reduce some limitations of single inheritance by enabling a developer to reuse sets of methods freely in several independent classes living in different class hierarchies."
So i declared a Trait with the method do_something and call that method from Both class A and Class B
Thanks

PHP call parent class method

class Foo {
protected static $a = 1;
protected $b = 2;
public function func() { return 'foo' . static::$a . $this->b; }
}
class Bar extends Foo {
protected static $a = 3;
protected $b = 4;
public function func() { return 'bar' . static::$a . $this->b; }
}
$obj = new Bar();
$obj->func(); // returns of course 'bar34'
Is there any option in PHP to call func() from Foo class?
In C++ I would cast $obj to Foo and simply call func()
Bar* obj = new Bar();
Foo* obj2 = (Bar*) obj;
obj2->func(); // returns 'foo14';
If you want to get down and dirty with Reflection then it's possible, but I'd strongly argue that this shouldn't be used anywhere near any production code. If you've got an instance of a child class, then you've got it for a reason, and if it's overridden a parent method then that has also happened for a reason.
Assuming you already know all this, then with that disclaimer out of the way, this should work in any remotely recent version of PHP:
class Foo { public function func() { echo 'I am the parent'; } }
class Bar extends Foo { public function func() { echo 'I am the child'; } }
// Create instance of child class
$bar = new Bar;
// Create reflection class
$reflected = new ReflectionClass(get_class($bar));
// Get parent method
$method = $reflected->getParentClass()->getMethod('func');
// Invoke method on child object
$method->invokeArgs($bar, []);
// I am the parent
See https://3v4l.org/NP6j8
This to me looks like a design issue more than anything else.
However if I were to handle this in a way that were easily readable and without rethinking my design I would do:
<?php
class Foo {
public function func() { return 'foo'; }
}
class Bar extends Foo {
public function func() { return 'bar'; }
public function parentFunc() { return parent::func(); }
}
$obj = new Bar();
$obj->parentFunc(); // returns of course 'foo'
Loek's answer also works, but doesn't call the method on the objects parent. It just calls the method on the classes parent. It all depends on the functionality you are looking for.
You could also do something like:
<?php
class Foo {
public function func() { return 'foo'; }
}
class Bar extends Foo {
public function func($parent = false) {
if ($parent) {
return parent::func();
}
return 'bar';
}
}
$obj = new Bar();
$obj->func(true); // returns of course 'foo'
Which is similar but without the need for the extra method.
Personally though I feel this issue likely requires a rethink in code design more than a coding solution.
-- edit --
To elaborate on 'a rethink in code design', I would ask myself "Why do I need an object that has two methods with the same name, but different functionalities? Is this not a job for two different objects? Trace the issue backwards until you find the design issue. Or the point at which the decision needs to be made as to which object your framework requires.
This isn't exactly what I'd call pretty, but it works and is relatively similar to what you described for C++; It works by calling get_parent_class() and then abusing PHP's ability to create objects from strings.
<?php
class Foo {
public function func() { echo 'foo'; }
}
class Bar extends Foo {
public function func() { echo 'bar'; }
}
$obj = new Bar();
$obj->func(); // Prints 'bar'
$parentClassString = get_parent_class($obj);
$newObj = new $parentClassString; // Gotta love PHP for magic like this
$newObj->func(); // Prints 'foo'
See this snippet to see it in action.
EDIT
It's a lot of work, but you could use so called Late Static Binding, perhaps more clearly explained in Jokerius's answer here. This requires you to write a crapload of custom code though, which I don't think is preferential. Overall the short answer seems to be: it isn't really possible.
I don't know should it help you but try to add this function in Bar class
public function callParent($function){
return parent::$function();
}
and call
echo $obj->callParent("func");
[UPDATED]
Also you can write cast function yourself
something like this
public function castAs($newClass) {
$obj = new $newClass;
foreach (get_object_vars($this) as $key => $name) {
$obj->$key = $name;
}
return $obj;
}

Invoke inherited member functions using $this->my_func() or parent::my_func()?

I've been creating abstract classes and interfaces to force consistency within my Wordpress plugins, but I'm never sure if I should be invoking inherited functions by using parent::some_function() or using $this->some_function()? Since jumping back and forth between the two looks super messy/confusing.
For Example:
Using getter/setters should I be:
$this->get_my_var(); // indicating nothing about its origins except through comments
or
parent::get_my_var(); // indicating you can find it in the parent
They're not the same thing.
class A {
protected function foo() {
return "a";
}
}
class B extends A {
protected function foo() {
return parent::foo() . "b";
}
public function bar() {
return $this->foo();
}
}
$b = new B();
var_dump($b->bar()); // "ab"
If instead you had:
class B extends A {
...
public function bar() {
return parent::foo();
}
}
var_dump($b->bar()); // just "a"
The foo function of B adds something to the foo function of A. This is a common pattern.
Whether calling parent::foo in bar is good or not depends on your design choices, I personally think it's a little iffy. Calling parent::foo in foo is fine by the way.
I only use parent:: in constructors, destructors and static methods. For everything else I trust people to know how object inheritance works. I would use $this->get_my_var();

How to call the __invoke method of a member variable inside a class

PHP 5.4.5, here. I'm trying to invoke an object which is stored as a member of some other object. Like this (very roughly)
class A {
function __invoke () { ... }
}
class B {
private a = new A();
...
$this->a(); <-- runtime error here
}
This produces a runtime error, of course, because there's no method called a. But if I write the call like this:
($this->a)();
then I get a syntax error.
Of course, I can write
$this->a->__invoke();
but that seems intolerably ugly, and rather undermines the point of functors. I was just wondering if there is a better (or official) way.
There's three ways:
Directly calling __invoke, which you already mentioned:
$this->a->__invoke();
By assigning to a variable:
$a = $this->a;
$a();
By using call_user_func:
call_user_func($this->a);
The last one is probably what you are looking for. It has the benefit that it works with any callable.
FYI in PHP 7+ parenthesis around a callback inside an object works now:
class foo {
public function __construct() {
$this -> bar = function() {
echo "bar!" . PHP_EOL;
};
}
public function __invoke() {
echo "invoke!" . PHP_EOL;
}
}
(new foo)();
$f = new foo;
($f -> bar)();
Result:
invoke!
bar!
I know this is a late answer, but use a combination of __call() in the parent and __invoke() in the subclass:
class A {
function __invoke ($msg) {
print $msg;
}
}
class B {
private $a;
public function __construct() { $this->a = new A(); }
function __call($name, $args)
{
if (property_exists($this, $name))
{
$prop = $this->$name;
if (is_callable($prop))
{
return call_user_func_array($prop, $args);
}
}
}
}
Then you should be able to achieve the syntactic sugar you are looking for:
$b = new B();
$b->a("Hello World\n");

PHP5 static methods inheritance. Overloading. Getting called class name

I have good oop understanding but poor understanding of its implementation in php...
I have the following code, hope it's self documented =).
I need to have BB in the output
class A{
// I can't copy function::classname() to all my descendant classes
static function classname(){
echo __CLASS__;
}
}
class B extends A{
static function test(){
self::classname();
}
function test1(){
self::classname();
}
//i have A LOT of static and non-static functions using self::classname() in their code
// I can't copy all them to base class
}
$v = new B();
B::test();
$v->test1();
I'm stuck with static:: and self:: syntax
PS: another crazy question I've come across:
Suppose I have
function doSomething(){
echo $this->id;
}
Sometimes it gets into the static contexts. Yes, I know, that's because my bad application design. But is it possible to create a second(mirror, overloading) function
static function doSomething(){
echo false;
}
It means that using
$obj->doSomething() returns id and using Class::doSomething() returns false
Question 3:
Is it possible to get property default value in static context an property value in non-static context automatically?
Have a look at late static binding.
class A {
static function classname() {
echo __CLASS__;
}
static function test1() {
static::classname();
}
}
class B extends A {
static function classname() {
echo __CLASS__;
}
}
$v = new B();
B::test1();
$v->test1();
Or as pointed out by Long Ears in the comments, assuming php 5.3.0+ you can use get_called_class()
class A {
static function classname() {
echo get_called_class();
}
// this can be defined in either class A or B without affecting the output
static function test1() {
static::classname();
}
}
class B extends A {
}
$v = new B();
B::test1();
$v->test1();
Outputs:
BB
Regarding your second "crazy" question, see the Magic Methods. Basically, you would need to implement something like:
class Foo
{
public function __call($name, $arguments)
{
// call the _$name function
}
public static function __callStatic($name, $arguments)
{
// call the _{$name}_static function
}
private function _bar()
{
}
private static function _bar_static()
{
}
}
$foo = new Foo();
$foo->bar();
Foo::bar();
it's possible to add a static method like this
class Foo {
public static function __callStatic() {
// ....
}
}
// in Other file
// Call the static method
Foo-->__callStatic()
and call it on an other file (In php ) ?

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