Heading come in all the rows need in first row
Need help with where i am going wrong
thank you
below is the code
<?php
$connection = mysql_connect('localhost', 'aria2', 'osvOSUxlY6wYLZzC'); //The Blank string is the password
mysql_select_db('torres');
$query = "SELECT * FROM reports"; //You don't need a ; like you do in SQL
$result = mysql_query($query) or die(mysql_error());;
echo "<table>"; // start a table tag in the HTML
while($row = mysql_fetch_array($result)){ //Creates a loop to loop through results
echo "<table><tr><th>CSQ_Name</th>
<th>CSQ_ID</th>.......
$row..............
//$row['index'] the index here is a field name
}
echo "</table>"; //Close the table in HTML
mysql_close(); //Make sure to close out the database connection
You only need to move the header portion out of the loop:
echo '<table><tr><th>CSQ_Name</th><th>CSQ_ID</th></tr>'; // start a table tag in the HTML
while ($row = mysql_fetch_array($result)) { //Creates a loop to loop
echo '<tr>';
// output data here
echo '<td>...</td><td>...</td>';
echo '</tr>';
}
echo "</table>"; //Close the table in HTML
Related
i already have a while loop that displays select inputs in my form depending on how many passengers the user is booking. Each drop down was supposed to show all data from a column in my database. The problem is that only the first drop down displays the data i fetched which is seats 1 to 30.
Query to get the airline id of the current flight
$result = mysqli_query($conn,"select * from flight_seat_status where flight_number = '$_SESSION[departure]'");
Variables i used to start the counting in the loop
$print = 1; $name = 0;
My while loop with the problem
echo "<h1 class='adminContent_h1'>Please choose a seat</h1>";
while($print <= $_SESSION['passengers']){
echo "<label style = 'width:170px;'>". $_SESSION['firstname'][$name]."'s Seat</label>";
echo "<select class = 'content_dropdown' style = 'width:15%; margin-bottom:20px;' name = 'passengers[]'>";
while($row = mysqli_fetch_assoc($result)){
echo "<option value='".$row['seat_id']."'>".$row['seat_number']."</option>";
}
echo "</select><br>";
$print++;
$name++;
}
it is able to print out a number of drop downs depending on the user but only the first drop down contains the data.
what is wrong with my code? please explain
You have to set the pointer back to 0 for using the result again
// set the pointer back to the beginning
mysqli_data_seek($result, 0);
while($row = mysqli_fetch_assoc($result)){
// do whatever here...
}
Please use below code. All the seats records you have to fetch once outside passenger loop and store in another array and then you have to use seats array inside the passenger loop each time.
echo "<h1 class='adminContent_h1'>Please choose a seat</h1>";
$seats = [];
while($row = mysqli_fetch_assoc($result)){
$seats[] = $row;
}
while($print <= $_SESSION['passengers']){
echo "<label style = 'width:170px;'>". $_SESSION['firstname'][$name]."'s Seat</label>";
echo "<select class = 'content_dropdown' style = 'width:15%; margin-bottom:20px;' name = 'passengers[]'>";
foreach($seats as $res_seat){
echo "<option value='".$res_seat['seat_id']."'>".$res_seat['seat_number']."</option>";
}
echo "</select><br>";
$print++;
$name++;
}
I have a simple project that I am working on and I'm having a hard time finding the code I need to get line breaks in the following table:
<?php
// connect to the database
$host = '###';
$username = '###';
$pass = '####';
mysql_connect($host,$username,$pass) or die(mysql_error());
mysql_select_db("####") or die(mysql_error());
// select everything from the table
$query = "SELECT * FROM Employees";
$result = mysql_query($query) or die(mysql_error());
echo "<table>";
echo "<tr>";
while( ($row = mysql_fetch_array($result)))
{
echo "<td>".$row['employeeid']."</td>";
echo "<td>".$row['firstname']."</td>";
echo "<td>".$row['lastname']."</td>";
echo "<td>".$row['department']."</td>";
}
echo "</tr>";
echo "</table>";
// disconnect from the database
mysql_close();
?>
Everything works correctly and it grabs data from the correct database and table. But when it displays results it is all on the same line ("record1record2record3") and I'd like a line break between employee records.
I've searched this question and it seems like my results all show me an entirely different way of doing this. I've already got the code written and fussed with it a lot to get it working. Can I just make a simple alteration to the above code to get the breaks I want?
The <tr> tags must also be inside the while loop so that they are outputted for each row. They make the rows in the HTML table.
while( ($row = mysql_fetch_array($result)))
{
echo "<tr>";
echo "<td>".$row['employeeid']."</td>";
echo "<td>".$row['firstname']."</td>";
echo "<td>".$row['lastname']."</td>";
echo "<td>".$row['department']."</td>";
echo "</tr>";
}
I have this code to select and output data from database
<?php
require('system/connect.php'); //load the connection file
$sql = ("SELECT * FROM `movie`"); // add mysql code to a variable. In this case it will select ALL columns from the database.
$query = mysql_query($sql); //run the query contained within the variable.
while ($row = mysql_fetch_array($query)) { //store each single row from the database in an array named $row. While there are any rows left, loop through and execute the following code:
$id = $row['movie_id']; //gets name from DB for a single row
$name = $row['movie_name']; //gets age from DB for a single row
$category = $row['movie_category']; //gets age from DB for a single row
//Following code outputs the data to the webpage:
echo $id;
echo $name;
echo $category;
};
?>
The page show: 1titanicromance2zoroaction3blood diamondsaction
I need a way to make a table or array and to insert data directly to it.
Adding in HTML for Table should do the trick. Although, it's crappy coding to mix PHP and HTML.
<?php
require('system/connect.php'); //load the connection file
$sql = ("SELECT * FROM `movie`"); // add mysql code to a variable. In this case it will select ALL columns from the database.
$query = mysql_query($sql); //run the query contained within the variable.
echo '<table>';
while ($row = mysql_fetch_array($query)) { //store each single row from the database in an array named $row. While there are any rows left, loop through and execute the following code:
$id = $row['movie_id']; //gets name from DB for a single row
$name = $row['movie_name']; //gets age from DB for a single row
$category = $row['movie_category']; //gets age from DB for a single row
//Following code outputs the data to the webpage:
echo '<tr>';
echo '<td>' . $id . '</td>';
echo '<td>' . $name . '</td>';
echo '<td>' . $category . '</td>';
echo '</tr>';
};
echo '</table>';
?>
Did you meant HTML table? Then it will looks like this
<?php
require('system/connect.php'); //load the connection file
$sql = ("SELECT * FROM `movie`"); // add mysql code to a variable. In this case it will select ALL columns from the database.
$query = mysql_query($sql); //run the query contained within the variable.
if (mysql_num_rows($query)) { // if there is some rows in result
echo "<table>"; // starting HTML table
while ($row = mysql_fetch_array($query)) { //loop through the result
echo "<tr>".
"<td>".$row['movie_id']."</td>".
"<td>".$row['movie_name']."</td>".
"<td>".$row['movie_category']."</td>".
"</tr>";
}
echo "</table>";// finishing HTML table
}
?>
NOTE: do not use mysql_* functions. They are deprecated. Use PDO or Mysqli instead.
I have a database of images which I want to output as a gallery ...
I want to display each image in its own cell <td>image1</td> and limit the number of cells to 7 per row.
<tr>
<td>image1</td><td>image2</td><td>image3</td><td>image4</td><td>image5</td><td>image6</td><td>image7</td>
</tr>
Then a new row would be created and continue to output all the images.
<tr>
<td>image8</td>
and so on ..
I know how to do a query, but I am lost as to how to assemble the rows into the format I am looking for.
Can anyone please help me it would be greatly appreciated. Thanks.
First run your query, then get the mysql_fetch_assoc in a variable. Then echo your beginning tags for the table and tr. Then create a foreach loop of the query assoc, as another variable such as row, and echo $row['image'] in a td. This will add a new td with the image for every entry in the database. Then echo your closing tags for the tr and table.
$query = mysql_query("SELECT image FROM table_name");
$query_a = mysql_fetch_assoc($query);
echo "<table><tr>"
foreach ($query_a as $row)) {
echo "
<td>" . $row['image'] . "</td>
";
}
echo "</tr></table>";
Not tested, but try something like this
<table>
<?php
// make sure there is at least 1 row first
$cnt = 0;
$while($row = mysql_fetch_assoc($query))
{
if(++$cnt == 1) {
echo '<tr>';
} elseif($cnt % 7 == 0) {
echo '</tr><tr>';
}
// show images in <td>'s
echo "<td>" . $row['image']. "</td>";
}
echo '</tr>';
?>
</table>
Keep it simple:
Query the database to get the desired information, loop through the results, construct a new row come each new loop.
$sql = "Select * from table";
mysql_query($sql) or die(mysql_error());
if(mysql_num_rows !=0)
{
// Found at least one record, create table
echo "<table>";
echo "<tr>";
while($row = mysql_fetch_assoc($sql)
{
$cell_count = 0;
// Create a new row for each record found
echo "<td>" . $row['image_column']. "</td>";
$cell_count++;
if($cell_count == 7)
{
echo "</tr>";
echo "<tr>";
$cell_count = 0;
}
}
// Close the table
echo "</tr>";
echo "</table>";
}
I am trying to loop though my users database to show each username in the table in their own row. I can only get it to show one user but loops through this the number of rows there are. Code is below
<?php
require_once ('../login/connection.php');
include ('functions.php');
$query = "SELECT * FROM users";
$results=mysql_query($query);
$row_count=mysql_num_rows($results);
$row_users = mysql_fetch_array($results);
echo "<table>";
for ($i=0; $i<$row_count; $i++)
{
echo "<table><tr><td>".($row_users['email'])."</td></tr>";
}
echo "</table>";
?>
Thanks
mysql_fetch_array fetches a single row - you typically use it in a while loop to eat all the rows in the result set, e.g.
echo "<table>";
while ($row_users = mysql_fetch_array($results)) {
//output a row here
echo "<tr><td>".($row_users['email'])."</td></tr>";
}
echo "</table>";
You're only fetching one row:
$row_users = mysql_fetch_array($results);
You're never calling a fetch again so you're not really looping through anything.
I'd suggest changing your loop to the following:
echo "<table>";
while ($row = mysql_fetch_array($results)) {
echo "<tr><td>".($row['email'])."</td></tr>";
}
echo "</table>";
The while loop will loop through the results and assign a row to $row, until you run out of rows. Plus no need to deal with getting the count of results at that point. This is the "usual" way to loop through results from a DB in php.
In the new MYSQLI, I use this coding
$query = "SELECT * FROM users";
$results=mysqli_query($con,$query);
$row_count=mysqli_num_rows($results);
echo "<table>";
while ($row = mysqli_fetch_array($results)) {
echo "<tr><td>".($row['id'])."</td></tr>";
}
echo "</table>";
mysqli_query($con,$query);
mysqli_close($con);
Your problem is in this line:
echo "<table><tr><td>".($row_users['email'])."</td></tr>";
You're echoing out a <table> tag again. Remove that so your code looks like this:
echo "<table>";
for ($i=0; $i<$row_count; $i++)
{
echo "<tr><td>".($row_users['email'])."</td></tr>";
}
echo "</table>";
You don't need to output a table within a table the way you're doing it.
$result = mysql_query("SELECT `email` FROM `users`");
$num_emails = mysql_num_rows($result);
echo "<table><caption>There are/is $num_emails email(s)</caption>";
while ($row = mysql_fetch_assoc($result)) {
echo "<tr><td>{$row['email']}</td></tr>";
}
echo '</table>';
Something like that should work.