JSON array in array from SQL database using PHP - php

I have the following code:
$retarray = array();
$hoursarray = array();
$res = $this->mysqli->query("SELECT id, title, groupby FROM scheduler_activity WHERE gewerbe = '$this->gewerbe'");
while($row = $res->fetch_object()) {
$foo = $this->mysqli->query("SELECT dow, start, end FROM scheduler_businesshours WHERE activity = '$row->id'");
while($hours = $foo->fetch_object()){
$hoursarray[] = $hours;
}
$retarray[] = $row;
$retarray["businessHours"] = $hoursarray;
}
return $retarray;
And the following JSON output:
{
"0": {
"id": "1",
"title": "Spinning",
"groupby": "Trainingsgruppe"
},
"businessHours": [{
"dow": "[1,2,3]",
"start": "17:00:00",
"end": "18:00:00"
}, {
"dow": "[4,5]",
"start": "17:30:00",
"end": "18:30:00"
}],
"1": {
"id": "2",
"title": "Massage",
"groupby": "Trainingsgruppe"
},
"2": {
"id": "3",
"title": "Yoga",
"groupby": "Trainingsgruppe"
},
"3": {
"id": "4",
"title": "Dance Academy",
"groupby": "Trainingsgruppe"
}
}
So far it looks correct but I need to get rid of the leading numbers like 0, 1, 2, 3
That it will look like this plus the businessHours:
[{
"id": "1",
"title": "Spinning",
"groupby": "Trainingsgruppe"
}, {
"id": "2",
"title": "Massage",
"groupby": "Trainingsgruppe"
}, {
"id": "3",
"title": "Yoga",
"groupby": "Trainingsgruppe"
}, {
"id": "4",
"title": "Dance Academy",
"groupby": "Trainingsgruppe"
}]
What did I do wrong there?
Thank you!

As I understood about your code, we get business hour for each activity, so it's just a small change at line 10:
$retarray = array();
$hoursarray = array();
$res = $this->mysqli->query("SELECT id, title, groupby FROM scheduler_activity WHERE gewerbe = '$this->gewerbe'");
while($row = $res->fetch_object()) {
$foo = $this->mysqli->query("SELECT dow, start, end FROM scheduler_businesshours WHERE activity = '$row->id'");
while($hours = $foo->fetch_object()){
$hoursarray[] = $hours;
}
$row["businessHours"] = $hoursarray; // Change to this, swap line 10 & 11
$retarray[] = $row;
}
return $retarray;
Hope this helps.

You add two keys. One key is numeric the second is businessHours.
$retarray[] = $row;
$retarray["businessHours"] = $hoursarray;
For instance you can add it businessHours to $row
$row["businessHours"] = $hoursarray;
$retarray[] = $row;

Have you try array_values($array)?
$retarray = array();
$hoursarray = array();
$res = $this->mysqli->query("SELECT id, title, groupby FROM scheduler_activity WHERE gewerbe = '$this->gewerbe'");
while($row = $res->fetch_object()) {
$foo = $this->mysqli->query("SELECT dow, start, end FROM scheduler_businesshours WHERE activity = '$row->id'");
while($hours = $foo->fetch_object()){
$hoursarray[] = $hours;
}
$retarray[] = $row;
$retarray["businessHours"] = $hoursarray;
}
return array_values($retarray);

Related

Compare variable of two different array?

Here i want compare two array.
I have two tables one is CATEGORY and second is USER(in which selected multiple category is stored in this format , , , ).
but when the USER want to update their category at that time the earlier selected category should return checked 1 and which is not selected should return checked 0 and here is my code.
case 'cat':
$sql="SELECT category from nesbaty_user where user_id='".$user_id."'";
$qry_res=mysqli_query($con,$sql);
$response1 = array();
while ($array = mysqli_fetch_array($qry_res))
{
foreach (explode(',', $array['category']) as $cat)
{
$response1[]=array('category' => $cat);
$response['Selected_category'] = $response1;
}
}
$qry="SELECT cat_id,category,image_url FROM nesbaty_category";
$qry_res=mysqli_query($con,$qry);
$jsonData = array();
while ($array = mysqli_fetch_assoc($qry_res))
{
$jsonData[] = $array;
$response['category'] = $jsonData;
}
echo json_encode($response);
//echo json_encode(array('data1' =>$response1));
//
mysqli_close($con);
break;
and here is my fetched array from the database.
{
"Selected_category": [
{
"category": "5"
},
{
"category": "6"
},
{
"category": "9"
}
],
"category": [
{
"cat_id": "1",
"category": "Drug",
"image_url": "1.jpg"
},
{
"cat_id": "2",
"category": "Bars",
"image_url": "2.jpg"
},
{
"cat_id": "3",
"category": "Bars",
"image_url": "2.jpg"
},
{
"cat_id": "4",
"category": "Hair Saloon",
"image_url": "2.jpg"
}
]
}
This is for handle this same structure as You provided.
<?php
$response = [];
$sql = "SELECT category from nesbaty_user where user_id='".$user_id."'";
$qry_res = mysqli_query($con, $sql);
$selectedCategories = mysqli_fetch_array($qry_res);
$selectedCategories = explode(',', $selectedCategories['category']);
$qry = "SELECT cat_id,category,image_url FROM nesbaty_category";
$qry_res = mysqli_query($con, $qry);
while ($categories = mysqli_fetch_assoc($qry_res)) {
$categories['checked'] = (int)\in_array($categories['cat_id'], $selectedCategories);
$response[] = $categories;
}
echo json_encode($response);
mysqli_close($con);
If any error writes a comment, I'll fix it.

Sort JSON by ID

I have following JSON file:
[{
"id": 9,
"title": "Birthday",
"description": "Debut Party",
"start": "2017-07-25T15:01",
"end": "2017-08-03T00:01",
"url": "https:\/\/bd.com"
}, {
"id": 11,
"title": "Anniversary",
"description": "First Ann",
"start": "2017-06-28T15:00",
"end": "2017-07-08T02:58",
"url": "https:\/\/anniversary.com\/"
}, {
"id": 5,
"title": "Anniversary",
"description": "First Ann",
"start": "2017-06-28T15:00",
"end": "2017-07-08T02:58",
"url": "https:\/\/anniversary.com\/"
}]
I want them to be sorted by id like 5,9,11 using PHP. How Can I do that?
First decode the JSON
$array = json_decode($json,true);
and then use usort to sort by id or something else.
function sortById($a, $b) {
return $b->id - $a->id;
}
usort($array,"sortById");
SELECT * FROM test ORDER BY `id` DESC;
use this query in you php file.
example :
function getPosts()
{
$connection = mysqli_connect("localhost", "root", "", DatabaseManager::DATABASE_NAME);
$sqlQuery = "SELECT * FROM posts order by 'id' desc;";
$result = $connection->query($sqlQuery);
$postsArray = array();
if ($result->num_rows > 0) {
for ($i = 0; $i < $result->num_rows; $i++) {
$postsArray[$i] = $result->fetch_assoc();
}
}
echo json_encode($postsArray);
}

Generate JSON Array from PHP SQL Loop

I need to generate the following JSON from a PHP loop and SQL DB but I'm having trouble:
[
{
"ItemName": "Websites1",
"Websites1": [
{
"0": "1",
"ID": "1",
"1": "Essential",
"WebsiteName": "Essential 1",
"2": "EI",
"WebsiteCode": "EI"
},
{
"0": "2",
"ID": "2",
"1": "Icon Ibiza",
"WebsiteName": "Icon 1",
"2": "IC",
"WebsiteCode": "IC"
},
{
"0": "3",
"ID": "3",
"1": "So Ibiza",
"WebsiteName": "So 1",
"2": "SO",
"WebsiteCode": "SO"
}
]
},
{
"ItemName": "Websites2",
"Websites2": [
{
"0": "1",
"ID": "1",
"1": "Essential Ibiza",
"WebsiteName": "Essential 2",
"2": "EI",
"WebsiteCode": "EI"
},
{
"0": "2",
"ID": "2",
"1": "Icon Ibiza",
"WebsiteName": "Icon 2",
"2": "IC",
"WebsiteCode": "IC"
},
{
"0": "3",
"ID": "3",
"1": "So Ibiza",
"WebsiteName": "So 2",
"2": "SO",
"WebsiteCode": "SO"
}
]
}
]
I have the relevant data being returned from the DB into PHP fine but I can't work out how to generate the relevant key value pairs and nesting using PHP loops. The code I have so far is:
$this->db->sql = "SELECT ID AS ID, WebsiteName AS SelectText, WebsiteCode AS SelectValue FROM Banners_Websites ORDER BY WebsiteName";
$rs = $this->db->query($this->db->sql);
if ($this->db->row_count != 0) {
$response = array();
$json = array();
while ($row = $this->db->row_read($rs)) {
$json["ID"] = $row["ID"];
$json["SelectText"] = $row["SelectText"];
$json["SelectValue"] = $row["SelectValue"];
//$json[] = $row;
}
$response["Websites1"] = $json;
}
$rs = $this->db->query($this->db->sql);
if ($this->db->row_count != 0) {
$json2 = array();
while ($row = $this->db->row_read($rs)) {
$json2["ID"] = $row["ID"];
$json2["SelectText"] = $row["SelectText"];
$json2["SelectValue"] = $row["SelectValue"];
//$json[] = $row;
}
$response["Websites2"] = $json2;
}
return '[' . json_encode($response) . ']';
I'm obviously doing something very wrong as I only end up with one row for each query. The key value pairs are being overwritten with each loop. Also the nesting isn't correct. Sorry for such a dumb question but I've been trying to figure this out from info online and am stuck.
Thanks,
Noon.
EDIT - Managed to fix this using the annswer provided by Anushil Nandan below but the PHP needed a few extra tweaks to get the required format as folows:
// -----------------------------------------------------------------------------------------------
// BANNERMANGEMENTFORM
function bannerManagementJson($JsonItem) {
$this->db->connect();
$response = array();
//Generate Websites drop-down
$SqlStr = "SELECT WebsiteName AS SelectText, WebsiteCode AS SelectValue FROM Banners_Websites ORDER BY WebsiteName";
$response[] = $this->retrieveFormElementJson($SqlStr,'Websites',1);
//Generate Clients drop-down
$SqlStr = "SELECT ClientName AS SelectText, ID AS SelectValue FROM Banners_BannerClients ORDER BY ClientName";
$response[] = $this->retrieveFormElementJson($SqlStr,'Clients',2);
return json_encode($response);
}
// -----------------------------------------------------------------------------------------------
// RETRIEVEFORMELEMENTJSON
function retrieveFormElementJson($SqlStr,$ElementName,$SelectListNo) {
$this->db->sql = $SqlStr;
$rs = $this->db->query($this->db->sql);
if ($this->db->row_count != 0) {
$json = array();
while ($row = $this->db->row_read($rs)) {
$json[] = $row;
}
$arrayResponse = array("ItemName"=>$ElementName, "SelectList" . $SelectListNo=>$json);
}
return $arrayResponse;
}
your array is being overridden every time it's entering while loop
try:
$json1[] = array();
$json2[] = array();
$this->db->sql = "SELECT ID AS ID, WebsiteName AS SelectText, WebsiteCode AS SelectValue FROM Banners_Websites ORDER BY WebsiteName";
$rs = $this->db->query($this->db->sql);
if ($this->db->row_count != 0) {
$response = array();
$json[] = array();
while ($row = $this->db->row_read($rs)) {
$json[]["ID"] = $row["ID"];
$json[]["SelectText"] = $row["SelectText"];
$json[]["SelectValue"] = $row["SelectValue"];
//$json[] = $row;
}
$response["Websites1"] = $json;
}
$rs = $this->db->query($this->db->sql);
if ($this->db->row_count != 0) {
$json2[] = array();
while ($row = $this->db->row_read($rs)) {
$json2[]["ID"] = $row["ID"];
$json2[]["SelectText"] = $row["SelectText"];
$json2[]["SelectValue"] = $row["SelectValue"];
//$json[] = $row;
}
$response["Websites2"] = $json2;
}
return '[' . json_encode($response) . ']';

How to combine multiple SQL queries into one to output as JSON in PHP code?

I currently have the following table set up:
StartTime EndTime Performer Event Day Location
-----------------------------------------------------
1:00pm 2:00pm Test Test 0 1
11:00pm 12:00am Test Test 0 0
2:00pm 2:30pm Test Test 1 0
11:00pm 12:00am Test Test 2 1
The JSON output looks something like this:
{
"day0": {
"item1": {
"StartTime": "1:00pm",
"EndTime": "2:00pm",
"Performer": "Test",
"Event": "Test",
"Location": 1
},
"item2": {
"StartTime": "11:00pm",
"EndTime": "12:00am",
"Performer": "Test",
"Event": "Test",
"Location": 0
}
},
"day1": {
"item1": {
"StartTime": "2:00pm",
"EndTime": "2:30pm",
"Performer": "Test",
"Event": "Test",
"Location": 0
}
},
"day2": {
"item1": {
"StartTime": "11:00pm",
"EndTime": "12:00am",
"Performer": "Test",
"Event": "Test",
"Location": 1
}
}
}
Since I'm still learning PHP, I wrote some sloppy code by making 3 queries to the database, each time selecting all data where the day was 1, 2, and 3.
Here's an example of code for fetching data for day=0, which is repeated for day=1 and day=2:
echo '{ "day0" : {';
$sql = "select * from table WHERE day = 0";
$result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
$jsonData = array();
$rowCount = $result->num_rows;
$index = 1;
while($row =mysqli_fetch_assoc($result))
{
echo '"item'.$index.'":';
echo json_encode(array("StartTime" => $row['StartTime'], "EndTime" => $row['EndTime'], "Performer" => $row['Performer'], "Event" => $row['Event'], "Location" => intval($row['Location'])));
if ($rowCount != $index)
{
echo ',';
}
++$index;
}
echo ' }';
// Repeated code for day=1
// Repeated code for day=2
echo ' }';
I feel as though this can be achieved with just one query, but being that I'm new, I'm not sure how to implement it.
I started to do something like this:
$sql = "select * from table";
$result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
$jsonData = array();
$numOfRows = $result->num_rows;
$count = 1;
while($row = mysqli_fetch_assoc($result))
{
$outerIndex = 'day'.$row['day'];
if ($row['day'] == '1')
{
// Do something, not sure
}
if ( !isset( $jsonData[$outerIndex] ) )
{
$innerIndex = 'item'.$count.'';
$jsonData[$outerIndex][$innerIndex] = $row;
}
++$count;
}
echo json_encode($jsonData);
However, I just got stuck, and not really sure how to approach it further.
SQL:
$sql = "SELECT * FROM table ORDER BY Day";
Further down on code:
$result_object = [];
$item = 1;
while ($row = $result->fetch_assoc()) {
if(isset($result_object['day'.$row['Day']]))
{
$result_object['day'.$row['Day']]['item'.$item] = $row;
$item++;
}
else
{
$result_object['day'.$row['Day']]['item1'] = $row;
$item = 2;
}
}
You can then output it with:
echo json_encode($result_object, JSON_PRETTY_PRINT); //JSON_PRETTTY_PRINT is not necessary...
You may disagree with me, but I don't think indexing items with item0, item1 and so on.... or day0, day1 ... is a GOOD idea. I personally prefer that the looping through the result would be:
while ($row = $result->fetch_assoc()) {
if(isset($result_object[$row['Day']]))
{
$result_object[$row['Day']]->items[] = $row;
}
else
{
$result_object[$row['Day']] = (object)['day'=>$row['Day'], 'items'=>[$row]];
}
}
In this case, the result would be an array of objects. ie:
[
{
"day": "0",
"items": [
{
"StartTime": "07:23:56",
"EndTime": "17:24:04",
"Performer": "Performer1",
"Event": "Event1",
"Day": "0",
"Location": "1"
},
{
"StartTime": "09:24:30",
"EndTime": "01:04:37",
"Performer": "Performer2",
"Event": "Event2",
"Day": "0",
"Location": "1"
}
]
},
{
"day": "1",
"items": [
{
"StartTime": "10:25:22",
"EndTime": "11:25:29",
"Performer": "Performer2",
"Event": "Event3",
"Day": "1",
"Location": "2"
}
]
},
{
"day": "2",
"items": [
{
"StartTime": "12:26:08",
"EndTime": "13:26:12",
"Performer": "Performer3",
"Event": "Event4",
"Day": "2",
"Location": "1"
}
]
}
]
The reason: you can easily iterate through each values(an array) in whatever language you're going to use.

How create a response json with nested objects in php?

I want create a json response with nested json object and group my actual results by id_hotel
MY ACTUAL JSON RESPONSE
{
"tag": "cities",
"success": 1,
"error": 0,
"items": 2,
"item": [
{
"id": "6194",
"year": "2013",
"city": "London",
"start": "1",
"id_hotel": "20001",
"name": "hotel piccadilly",
"address": "road 4",
"number_fr": "7003",
"district": "london city",
"pr": "GB",
"fres": "1",
"mode": "Night",
"pos": "402",
"pes": "33",
"pis": "21",
"pus": "456"
},
{
"id": "6194",
"year": "2013",
"city": "London",
"start": "1",
"id_hotel": "20001",
"name": "hotel piccadilly",
"address": "road 4",
"number_fr": "7003",
"district": "london city",
"pr": "GB",
"fres": "1",
"mode": "Day",
"pos": "0",
"pes": "1",
"pis": "0",
"pus": "1"
}
]
}
MY PHP CODE for the encoding response
$query = "SELECT * FROM cities WHERE city = 'London'";
$result = mysql_query($query) or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
$response["item"] = array();
while ($row = mysql_fetch_array($result)) {
// temp user array
$product = array();
$product["id"] = $row["id"];
$product["year"] = $row["year"];
$product["city"] = $row["city"];
$product["start"] = $row["start"];
$product["id_hotel"] = $row["id_hotel"];
$product["name"] = $row["name"];
$product["address"] = $row["address"];
$product["number_fr"] = $row["number_fr"];
$product["district"] = $row["district"];
$product["pr"] = $row["pr"];
$product["fres"] = $row["fres"];
$product["mode"] = $row["mode"];
$product["pos"] = $row["pos"];
$product["pes"] = $row["pes"];
$product["pis"] = $row["pis"];
$product["pus"] = $row["pus"];
// push single product into final response array
array_push($response["item"], $product);
}
// success
$response["items"] = mysql_num_rows($result);
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
What I desider
{
"tag": "cities",
"success": 1,
"error": 0,
"items": 2,
"item": [
{
"id": "6194",
"year": "2013",
"city": "London",
"start": "1",
"id_hotel": "20001",
"name": "hotel piccadilly",
"address": "road 4",
"number_fr": "7003",
"district": "london city",
"pr": "GB",
"fres": "1",
"mode": [{
"value" : "Night",
"pos": "402",
"pes": "33",
"pis": "21",
"pus": "456"
},
{ "value" : "Day",
"pos": "0",
"pes": "1",
"pis": "0",
"pus": "1"
}]
}
]
}
thanks in advance for your attention!!
Add option JSON_FORCE_OBJECT in function. You can read about it in http://tr2.php.net/manual/en/json.constants.php .
json_encode($response, JSON_FORCE_OBJECT) ;
1st, I suggest you a small change to save you some lines, and thus, i add some code to achieve what you want
$query = "SELECT * FROM cities WHERE city = 'London'";
$result = mysql_query($query) or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
$response["item"] = array();
$current_id = NULL;
while ($row = mysql_fetch_array($result)) {
if ( $row->id_hotel !== $current_id ){
$response["item"][] = $row;
$response["item"]["mode"] = array();
}
$current_item = end($response["item"]);
$current_item["mode"][] = array("value"=>$row->value, "pes"=>$row->pes);
$current_id = $row->id_hotel;
}
// success
$response["items"] = mysql_num_rows($result);
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
Let me know if it works.
Note: Only used 1 variable for mode, for testing purposes, and didnĀ“t unset the variables that I put into mode array, but should be enough to see if the main idea works. Feeling a bit lazy :P

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