correct query for join two querys - php

Question

I have this query for select a list
$sql="select * from buy_log where (client_id not in
(select selected_client_id from action_log where media_id=buy_log.media_id and client_id=$client_id )
and totalVisit>0 and coin_id=3 or coin_id=4 or coin_id=5)";
and this is my second select
while($row=mysqli_fetch_assoc($result)){
$media_id = $row['media_id'];
$sql2 = "select * from comment_media,comment_list where comment_list.id=comment_media.id and media_id='$media_id' order by rand() limit 2";
}
i try to use join for one query and this is my try :
SELECT S.*,WW.Comments,WW.Comments_id
FROM buy_log S
INNER JOIN
(
SELECT M.media_id,GROUP_CONCAT(W.Comment SEPARATOR '!###!') as Comments,GROUP_CONCAT(W.id SEPARATOR ',') as Comments_id
FROM comment_list W,comment_media as M
Where W.id=M.id and M.media_id='$media_id' and W.used = 0
) WW
ON S.media_id = WW.media_id
where (client_id not in
(select selected_client_id from action_log where media_id=S.media_id and client_id='1234' )
and totalVisit>0 and coin_id=3 or coin_id=4 or coin_id=5)
but here is my problem
Where W.id=M.id and M.media_id='$media_id' and W.used = 0
I don't know how can i set $media_id
any solution ?
UPDATE
Tables Info :
Tables Info : Pic

Answer 1

This should work:
You're extracting media id from that original query, looping through results and using the media id to assign the value $media_id in the php loop, where you perform another query.
The join seems syntactically right just need to reference the buy_log table inside the subquery.
SELECT S.*,WW.Comments,WW.Comments_id
FROM buy_log S
INNER JOIN
(
SELECT M.media_id,GROUP_CONCAT(W.Comment SEPARATOR '!###!') as Comments,GROUP_CONCAT(W.id SEPARATOR ',') as Comments_id
FROM comment_list W,comment_media as M
Where W.id=M.id and M.media_id= S.media_id and W.used = 0
) WW
ON S.media_id = WW.media_id
where (client_id not in
(select selected_client_id from action_log where media_id=S.media_id and client_id='1234' )
and totalVisit>0 and coin_id=3 or coin_id=4 or coin_id=5)

Answer 2

I guess that first query can be rewritten as follows... does it help?
SELECT b.media_id
FROM buy_log b
LEFT
JOIN action_log a
ON a.selected_client_id = b.client_id
AND a.media_id = b.media_id
AND a.client_id = $client_id
WHERE b.totalVisit > 0
AND b.coin_id IN(3,4,5)
AND a.selected_client_id IS NULL;