As part of a class I've been asked to create a simple file upload system that uploads files in a single button to a folder called ./files. I've been able to do this and I have been able to keep it all contained in one a3.php file with this:
<form action="a3.php" method="post" enctype="multipart/form-data">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload" name="submitFile">
</form>
Which opens up a file dialog and only requires the user to press two buttons
I use the following function to run the upload function.
if(isset($_POST['submitFile']))
{
uploadFile();
}
The uploadFile() function simply uses move_uploaded_file to move to file to the ./files folder. Currently without any questions asked.
My issue is that my attempts to make the buttons for the file upload a single one have been stymied. I have attempted to use the following code to resolve the issue:
<form name="frm" action="a3 - Copy.php" method="post" enctype="multipart/form-data">
<input type="file" name="uploadFile" onchange="frm.submit();">
</form>
Which, while it refreshes the page as if an action is being performed, appears to do nothing. I have attempted to look into how exactly .submit() works but haven't gotten any closer to understanding any intricacies it may have while a part of onchange.
I've looked around and I've found code that can upload in a single button, and I've found code that can upload using an internal php function, but none that does both.
You can try using a button but not displaying it. When the file input is changed, using javascript trigger a click on the hidden button, like in the code below:
<form name="frm" action="a3 - Copy.php" method="post" enctype="multipart/form-data">
<input type="submit" name="submitFile" style="display:none" id="submit">
<input type="file" name="uploadFile" onchange="document.getElementById('submit').click()">
</form>
<?php
if(isset($_POST['submitFile']))
{
uploadFile();
}
?>
You're basically looking for an ajax upload. You can do this using javascript (on modern browser), and the easiest thing would probably be using a library like jquery. Otherwise, you can do it using an iframe.
Here are a few similar questions with example scripts-
Using HTML5 file uploads with AJAX and jQuery
jQuery Ajax File Upload
Related
I am trying to debug my front-end of a HTML/PHP web face and have run into an issue. Currently, the user is able to upload a file, which is then sent to a separate upload function (to process and upload their file to an AWS instance), and then redirects the user to another page.
On the page, I have two options for the user to click- the first of which unhides an option for the user to select and upload their file. This option uploads to the AWS instance and functions normally. The second option unhides some text about download/upload instructions, along with an option for the user to select and upload their file.
Both options do functionally the same thing, with only difference being the second option unhides some text in addition to revealing exactly the same button. Only the first option posts and uploads like normal; the second doesn't upload to the bucket and just returns 'zero' in plain text to the screen. Has anyone experienced anything like this and/or has any advice on how to fix it? Thanks!
Below are the two code snippets for the upload forms:
<form id="Site" method="POST" enctype="multipart/form-data">
<div id="file_input"><input id="files" type="file" name="file"/></div>
<label for="files">SELECT ZIP FILE TO UPLOAD</label>
<br>
<input type="submit" value="submit" name="submitSite">
</form>
and the one that doesn't work (exactly the same?)
<p> Download Instructions Go Here</p><br>
<form id="Site" method="POST" enctype="multipart/form-data">
<div id="file_input"><input id="files" type="file" name="file"/></div>
<label for="files">SELECT ZIP FILE TO UPLOAD</label>
<br>
<input type="submit" value="submit" name="submitSite">
</form>
And the POST function itself is:
<?php
session_start();
$_SESSION['Username'] = '';
$userID = $userID; // change this to be set in database
//set progress
$_SESSION['progress'] = 'upload_section';
'/survey_interface_shared_libraries/progress_emails/store_progress.php';
if (isset($_POST['submitSite'])) { // upload file
Please let me know if you need any further context!
I have a page that has a form on it. One of the things I need to include on the page is the ability to upload a file. I am trying to do this by using another form with an in it. When the user selects the file, I want to get the file name and then perform the actual upload. From what I read, I cannot submit a form within a form, because the submit button in the inner form will also submit the outer form. I have tried looking for options and found the following page.
Can I trigger a form submit from a controller?
I thought that if I used this type of directive, then submitted it with the commit, then it should work....my problem is that for some reason when I try to access the form in my controller, it is showing as undefined. I think I need the form so that I can get the file name of the selected file...there may be a different way to achieve this than what I have tried but I haven't found it yet...
The latest controller, directive, and HTML files are below.
Controller:
$scope.uploadIt = function($form) {
console.log($form);
if ($form.$valid) {
$form.commit();
}
};
HTML:
<form editable-form name="editableForm" onaftersave="update" >
<tr>
: other fields here....
</tr>
<tr>
<td>
<form ng-form-commit name='fileForm' action="scripts/upload_file.php" method="post" enctype="multipart/form-data">
<label for="exampleInputFile">File input</label>
<input type="file" id="file" name="file">
<p class="help-block">Upload a file to link it with this project.</p>
<input type="text" name="prgGuid" id="prgGuid" value="{{programId}}" style="display:none;">
<input type="button" ng-click="uploadIt(fileForm)" name="submit" value="Upload File" class="btn btn-default">
</form>
</td>
</tr>
</form>
Directive:
app.directive("ngFormCommit", [function(){
return {
require:"form",
link: function($scope, $el, $attr, $form) {
$form.commit = function() {
$el[0].submit();
};
}
};
}]);
One more this that I will need to do....when the file is actually uploaded, I will actually be changing the file name so it is unique. Once the file is uploaded, I will need to pass back the new file name to my controller so I can store/display it. So I will need the original name the user selected and the new name...my php file will pass it back. I was thinking at first that maybe I could use a $http.post to submit the form and get the information back, but I couldn't get the file name the user selected. I was thinking if I could use the http.post to process the php file, then I wouldn't run into the form inside form, submit issue.
Please can someone tell me the easiest way to accomplish uploading a file with the form inside form constraints I have? I have been trying various things from posts I have seen but on here but I haven't found anything similar....please help. Thanks.
Hello I needed code for automatically chose file and upload it to desired link. How to do that?
html code:
<html>
<head><title>Uploading</title></head>
<body>
<form method="post" enctype="multipart/form-data" action="uploadFile.php">
<input type="file" name="file" id="file">
<input type="submit" value="Submit">
</form>
</body>
</html>]
In above code at this line
<input type="file" name="file" id="file">
this path is fixed and can't be changed as user tries. so when user click on "Submit" button the file has to upload.
How to do this?
TL;DR: What you are trying to do is absolutely impossible - for a good reason.
If this was possible, you could create a hidden upload field pointing to a file containing valuable data (e.g. the browser's cookie database) and submit the form using JavaScript (or make the user submit it without knowing about that upload) and copy any file the user has access to.
I am using nginx upload module (http://www.grid.net.ru/nginx/upload.en.html) with this plugin https://github.com/drogus/jquery-upload-progress to upload files on my server successfully with progressbar. here is my form:
<form id="upload" enctype="multipart/form-data" action="/upload/" method="post">
<input type="file" name="file_1">
<input type="submit" value="Upload">
</form>
Now i wants to use an option to download remote files with progressbar so my form is this:
<form id="download" action="/upload/" method="post">
<textarea rows="2" cols="20" name="links"></textarea>
<input type="submit" value="Upload">
</form>
So if i give a file i.e http://domain.com/file.zip in links textarea and after hit submit it should display me progressbar for downloading files.
I notice from my first upload method there is some data being generated from a link (http://domain.com/progress?X-Progress-ID=0c1ecb6da3f3ffc3848ceb337541ab1d) like this for files being uploaded but i am not sure if i can use this to show download progressbar:
new Object({ 'state' : 'uploading', 'received' : 674808, 'size' : 2028876 } )
Thank you for any help.
Best Regards
EDIT FIX
Found the solution here, https://gist.github.com/1030450 need to use curl, save the progress in file then call with ajax to get current progress...will post my solution later on :)
Found the solution here, https://gist.github.com/bdunogier/1030450 need to use curl, saved the progress in file then called with ajax to get current progress.
I try to create an upload progress bar with PHP and jQuery. However, I have a problem when I bring it to the form data. The code is similar like this:
<form method="post" action="upload.php" enctype="multipart/form-data" id="upload-form" target="upload-frame">
Suburb:<input type="text" name="txtSuburb" id="txtSuburb">
Picture:
<input type="hidden" id="uid" name="UPLOAD_IDENTIFIER" value="<?php echo $uid; ?>">
<input type="file" name="file">
<input type="button" name="submit" value="Upload!">
<iframe id="upload-frame" name="upload-frame">
</iframe>
<input type="submit" name="DataSubmit" value="Submit Data"/>
</form>
As you can see, I got 2 submit buttons. If I keep the form like this then the form can't submit data to server. It just submits the file to iFrame. If I change the action and target of the form then the upload progress function will not work.
Could anyone please help me to find the solution for this?
I want the user can click on upload button to upload their file. Then they can take the rest to fill the form. When everything is done, they can click on another submit data button to submit their data (included the file) to the server.
Make sure that you have only one input element of type submit within your form.
If you want the first button to trigger some Javascript, use a regular input element or even a styled link and attach a Javascript event to it's onclick event, then prevent it's default behavior, e.g. by returning false.
Like this only the second button will actually submit your form which should do what you're describing.
In general I'd second #Treffynnon's suggestion to use a existing library for this purpose. These hacks have a tendency to get pretty nasty, especially when it comes to crossbrowser compatibility.