Good day!
I have a form where I have first name and last name but I am sending the first name value only in same field on next page like code below
<label>Owned By:</label>
<br />
<input class="input" type="text" name="ownerPrint" readonly value="<?php echo (isset($_GET['first_name'])) ? htmlentities($_GET['first_name']) : ''; ?>"/>
This works first for first name. How can I do the same for last_name in same line? Becuase above html code is one field with label owned by and this should show both first and last names concatenated
Code which is coming from previous file
echo '<td class="forscreen">Add Accessories</td>';
Just concatenate the two inputs:
<?php
if (isset($_GET['first_name'], $_GET['last_name'])) {
$full_name = htmlentities($_GET['first_name'] . " " . $_GET['last_name']);
} else {
$full_name = '';
}
?>
Then use $full_name in the value attribute of the input:
<input class="input" type="text" name="ownerPrint" readonly value="<?php echo $full_name; ?>"/>
Related
Good Day,
I have a textbox and I am fetching its value in next page.
Pls see code first below
View.php
echo '<td class="forscreen">Add Accessories</td>';
When you click add accessories, you get value of emp_number on next page where on next page I have:
<input class="input" type="text" name="emp_numberPrint" id="emp_number" readonly value="<?php echo (isset($_GET['emp_number'])) ? htmlentities($_GET['emp_number']) : ''; ?>"/>
Now, I want the same if I have another textbox named owner and I am trying the below code:
echo '<td class="forscreen">Add Accessories</td>';
<input class="input" type="text" name="ownerPrint" readonly value="<?php echo (isset($_GET['ownerPrint'])) ? htmlentities($_GET['first_name']) : ''; ?>"/>
Here first_name is to be fetched from last page in same way as emp_number is coming but it is not working,
Surely I am making mistake. Please guide me
Thanks
As per your approach, you have to pass it in query string to get this on next page.
For View.php
echo '<td class="forscreen">Add Accessories</td>';
On the next page
<input class="input" type="text" name="ownerPrint" readonly value="<?php echo (isset($_GET['first_name'])) ? htmlentities($_GET['first_name']) : ''; ?>"/>
In Second Case
echo '<td class="forscreen">
<a href="equipments.php?emp_number=' .$row['emp_number'].$row['first_name'] . '">
Add Accessories</a></td>';
You are passing the values wrongly
You must pass the variables like this
<a href="equipments.php?emp_number=<?php echo $row['emp_number']; ?>
&first_name=<?php echo $row['first_name'] ; ?>">
Add Accessories</a>
you can get values in next page is like
$_GET['emp_number'];
$_GET['first_name'];
Here, I want to get value of textbox, but I coudn't.
Where am I wrong?
Is it must to use session if i want to get value of textbox?
<input type="submit" id="processorder" name="processorder" class="submit-green" value="Process Order"/>
<?php
foreach ($order_list as $row)
{
?>
<td class="align-center">
<input type="text" name="text[]" autocomplete="off" id="txtid_<?php echo $row['id']; ?>" readonly value="<?php echo $text;?>">
</td>
</tr>
<?php
$i++;
}
?>
if(isset($_POST['processorder']))
{
$txtvalue = $_GET['text[]'];
echo "helo".print_r($txtvalue);
}
this is wrong,
$txtvalue = $_GET['text[]'];
it should be
$txtvalue = $_GET['text'];
^ no [] here
Replace $_GET['text[]'] to $_GET['text']
The field would not be called text[] to PHP. It would just be called text, but would be an array instead of a string.
Try this:
if(isset($_POST['processorder']))
{
$arrayvalue = $_GET['text'];
foreach($arrayvalue as $txtvalue){
echo "helo" . $txtvalue . "<br>";
}
}
As your text input name is text[] with a bracket, it indicates that it is sending as an array, so to get the value you need
if (!empty($_POST["test"][0]) ) {
$test_value = $_POST["test"][0];
}
I am using 0 here since your code only shows one input text, for the server-end will only receive one array value
why you use array name="text[]" if you don't want to get multiple data using "text" than make it name="text"
<input type="text" name="text" autocomplete="off" id="txtid_<?php echo $row['id']; ?>" readonly value="<?php echo $text;?>">
get value using
$_GET['text'] // get value
or
you want to multiple data using same name "Array"(mean using array)
<input type="text" name="text" autocomplete="off" id="txtid_<?php echo $row['id']; ?>" readonly value="<?php echo $text;?>">
get value using
$_GET['text'][0] // 0 is a index value
I assume I have something stupid happening due to my lack of experience.
On a form on members.php I have:
$column = 0;
echo "<Form Name =member Method =POST ACTION = individual.php>";
echo "<table>";
echo "<tbody>";
while($row = $rs->fetch_assoc()) {
if ($column == 0) {
echo "<tr>";
}
echo '<td><INPUT TYPE = Submit NAME="'. $row['num'].'" VALUE ="'. $row['name'].'" id=Submit></td>';
$column++;
if ($column >= 5) {
echo "</tr>";
$row++;
$column=0;
}
}
echo "</tbody>";
echo "</table>";
echo "</form>";
On individual.php I have
print_r($_POST);
With the result being Array ( [16] => LUKE ) which is what is expected.
but when I try to
$name=$_POST['name'];
$num=$_POST['num'];
echo "<br>".$name." ".$num."<br>";
I do not get any results.
I mainly want to get $row['num'] but also did ['name'] to make sure I didn't transpose what I was trying to achieve.
I basically want to take what was selected on previous form and insert into a
select * from table where number=$num;
The name of your input fields are not num and name, instead, they are the values of these two keys in the array $row. That is why you are unable to retrieve these values on the backend.
Change your code to:
<input type="hidden" name="name" value="<?php echo $row['name']; ?>;">
<input type="hidden" name="num" value="<?php echo $row['num']; ?>;">
<input type="submit" value="Submit!" name="submit_form">
For obtain POST value for 'name' and 'num', you have to write:
<input type="text" name="name" value="<?php echo $row['name']; ?>">
<input type="text" name="num" value="<?php echo $row['num']; ?>">
type can be 'text' or 'hidden'
Enjoy your code!
If you want your form to return values that you can access using $_POST['name'] and $_POST['num'], you need to set name and num as input names on your form, and the appropriate values as the input values. If you don't want to add them as visible/editable values in your form, the usual way to do it is to use inputs of type hidden:
<form action="individual.php">
<input type="hidden" name="num" value="16" />
<input type="hidden" name="name" value="LUKE" />
<input type="submit" />
</form>
As it is, $_POST does contain the values that you're want, but they're not in an accessible format, because you've set 16 as an input name, so it turns into a key in the $_POST associative array. The form above will set num and name as keys in $_POST, and 16 and LUKE respectively as the values.
I have inside loop some fields for send inside form with other fields :
<?php
for($f=1;$f<=3;$f++)
{
?>
<input type="text" name="friend['email_<?php echo $f;?>']" value="<?php echo $_POST['friend']['email_'.$f.''];?>">
<?php
}
?>
When i send from form i need get the value of each field if no empty , i think the problem it´s in no recover the value send from the form , i don´t know if i writte right
Ony it´s that problem , thank´s , the best regards
I think the problem here is that you have single quotes around email_<?php echo $f; ?> - in POST data, these are not needed. So, you would have:
<form action="myPage.php" method="POST">
<?php for ($f=1;$f<=3;$f++) { ?>
<input type="text" name="friend[email_<?php echo $f; ?>]" value="<?php echo ... ?>">
<?php } ?>
<input type="submit">
</form>
PHP will parse POST data into associative arrays, so you will get back a 'friend' object in $_POST. You can access this like so:
<?php
$friends = isset($_POST['friend']) ? $_POST['friend'] : array();
print_r($friends);
?>
I'm not sure if i'm getting it right. You must send your form data in order to manipulate it. For example if you want to print all the form data:
Client Side:
<form action="boo.php" method="POST">
<input type="text" name="name">
<input type="text" name="age">
<input type="submit">
</form>
Server Side:
<?php
$name = "";
$age = "";
if( isset($_POST['name']) && isset($_POST['age']) )
{
$name = htmlspecialchars($_POST['name']);
$age = htmlspecialchars($_POST['age']);
}
echo 'Your name is ' . $name . ' and your age is ' . $age;
?>
If you are trying to retain the values even after invalid input you can just echo the input in value attribute of the input field.
I have searched across the entire web and I cant seem to find a solution. I am pretty much searching a database for individuals. I can use last name for instance and then if two people have the same last name they both will print on my page. I want to be able to select the individual I would want ( or am for instance ) and click next ( a hyperlink to a page with blank forms ) which is where I would like the info of the individual I selected ( and what was printed on the page ) in the forms pre filled. It allows a more user friendly approach then having to re type the data and also avoid miss spelling of company name or drivers license for example. I have put my code up many times but here it is again.this is the code for the finding and printing of the search results. no radio button yet, as i am trying to figure that out.
<div id="results" style="width:750px;height:225px; text-align: center">
<?php
$host = "localhost"; //server
$db = ""; //database name
$user = ""; //databases user name
$pwd = ""; //password
mysql_connect($host, $user, $pwd) or die(mysql_error());
mysql_select_db($db) or die(mysql_error());
$searchTerm = trim($_GET['searchname']);
// Check if $searchTerm is empty
if($searchTerm == "")
{
echo "Enter name you are searching for.";
exit();
}
else
{
//$sql = "SELECT * FROM contractor WHERE CONCAT(FIRSTNAME,' ',LASTNAME,' ',
ARRIVAL) like '%$searchTerm%' GROUP BY FIRSTNAME";
$sql= "SELECT * FROM contractor WHERE CONCAT(FIRSTNAME,' ',LASTNAME,' ', ARRIVAL)
like '%$searchTerm%'";
$query = mysql_query($sql);
$count=mysql_num_rows($query);
//array_unique($count);
if(($count)>=1)
{
$output = "";
while($row = mysql_fetch_array($query))
{
$output .= "First Name: " . $row['FIRSTNAME'] . "<br />";
$output .= "Last Name: " . $row['LASTNAME'] . "<br />";
$output .= "Arrival: " . $row['ARRIVAL'] . "<br />";
}
echo $output;
//echo array_unique($output);
}
else
echo "There was no matching record for the name " . $searchTerm;
}
?>
</div>
this is the code for my form field which of course is a empty form that is just being submitted to the database after submission.
<form action="insert_submit.php" method="post" style="margin-left:35px;">
First Name: <input type = "text" name="FIRSTNAME" id="FIRSTNAME" />
Last Name: <input type = "text" name="LASTNAME" id="LASTNAME"/>
Purpose: <input type = "text" name="PURPOSE" id="PURPOSE"/>
<br>
</br>
Company: <input type = "text" name="COMPANY" id="COMPANY" />
DL #: <input type = "text" name="DRIVERL" id="DRIVERL" />
<br>
</br>
<input type="radio" name="STATUS" id="STATUS" value="Checked In">Log In
<br></br>
<input type="radio" name="STATUS" id="STATUS" value="Checked Out">Log Out
<br></br>
<input type="submit" value="Submit" >
<br>
</br>
</form>
so your output line would be something like (clean up to suit your formatting)
$output .= '<a href="'.$_SERVER['PHP_SELF'].'?userid='.$row['UNIQUEID'].'">
First Name: '.$row['FIRSTNAME'].'<br />
Last Name: '.$row['LASTNAME'].'<br />
Arrival: '.$row['ARRIVAL'].</a><br />';
and you build into the page a condition that if you have the UNIQUEID coming in to look up and fill out the form such as
Company: <input type = "text" name="COMPANY" id="COMPANY" value="<?PHP echo $row['COMPANY']; ?>" />
edit to suit your database of course
sample code formatting
if(something){
do something
}else{
while(){
} # end while
} # easy to see this matches the if/else set of brackets
additional information for prepopulating
easiest would probably be on the same page. look for the userid coming into the page
if(!isset($_GET['userid'])){
# meaning we do not have a userid from a url that we generated above
# insert all your code to generate the links
}else{
# meaning we *have* a userid from a url that we generated above
# do your database query based on the userid such as
$sql='select * from mytable where userid=?';
$result=sqlsrv_query($db,$sql,array($_GET['userid']),array('Scrollable'=>'static'));
# or use mysqli, pdo or whatever... just watch for sql injection
$row=sqlsrv_fetch_array($result,SQLSRV_FETCH_ASSOC));
# assuming we will not have more than one element returned
?>
First Name: <input type = "text" name="FIRSTNAME" id="FIRSTNAME" value="<?PHP echo $row['firstName']; ?>"/>
and so forth... that should get you started
So basically what you need is in the first page a lis of identical names, or ideally one name, like:
content, content, content,
FirstName, LastName
FirstName, LastName
And than if you click on either of them, than the user is redirected to another page, containing all the details of the selected person, in a form. If I am getting you right.
I would not use checkbos on the first page, simply make the person's name a hyperlink like:
http://domain.com/userdetails?userid=666
So you pass on the user id to the second page. The php code on the second page can thank draw user details from the database and populate the form.
For that purpose you can either generate the form in an echo line-by-line manner, or use DomDocument tofind and fill the relevant value fields.
Second page form generation:
you select the row with the id, than fetch it into an array, named $array.
$array = mysql_fetch_array($query); //this query selected the row for the user with the id
echo '<form method="POST">'."\n";
echo '<input name="firstname" type="text" value="'.$array['firstname'].'">'."\n";
echo '<input name="lastname" type="text" value="'.$array['lastname'].'">'."\n";
echo '</form>';
I hope you get the idea now.