how to print data horizontally and vertically in table - php

Question

I am trying to create table with usernames and data assigned to each username.
I have projects and inside each project there are several processes. So want I want to to is to print table with usernames and projects displayed, and then assign each process to the username. Something like this:
username| project TMNT | project LEON | project MAT |
--------+--------------------+----------------+---------------+
barikan | ANM BLD, BGD CUP | N/A | N/A |
beny | N/A | N/A | BGD CUP |
bob | N/A | ANM BLD | N/A |
Where ANM BLD, BGD CUP are the processes from each project.
What I am able to do is to print projects as headers horizontally and usernames vertically:
<table class="table table-hover">
<thead>
<tr>
<th>Name</th>
<?php
$result = getRecord();
$count = 0;
if (mysqli_num_rows($result) > 0)
while($row = mysqli_fetch_array($result))
{
$projectNo = $row['projectNo'];
$title = $row['title'];
$code = $row['code'];
echo "<th>".$projectNo." ".$title." ".$code."</th>";
$count++;
}
?>
</tr>
</thead>
<tbody>
<?php
$result3 = getLeader();
if (mysqli_num_rows($result3) > 0)
while($row = mysqli_fetch_array($result3))
{
$username = $row['username'];
echo "<tr>
<td>".$username."</td>";
}
?>
</tbody>
And how my database tables look like:
user table
uid| username| salary|
---+---------+-------+
1 | bob | 0 |
2 | barikan | 0 |
3 | beny | 0 |
4 | adam | 0 |
project table
projectNo| title|
---------+------+
1610004 | TMNT |
1610005 | LEON |
1610006 | MAT |
process table(where person is assigned to a process)
projectNo| process | proc_leader|
---------+---------+------------+
1610004 | ANM BLD | barikan |
1610004 | BGD CUP | barikan |
1610005 | ANM BLD | bob |
1610006 | BGD CUP | beny |
I know i can use group_concat function to concat all processes in for same project in one row but how can i print accordingly to each project?
Sql query i am using to concat processes:
"SELECT proc_leader.projectNo, group_concat(proc_leader.process) AS processes, username
FROM user
LEFT OUTER JOIN proc_leader ON user.username=proc_leader.proc_leader
GROUP BY username, proc_leader.projectNo";
EDIT
so what if I have two tables:
process table(where person is assigned to a process)
projectNo| process | proc_leader|
---------+---------+------------+
1610004 | ANM BLD | barikan |
1610004 | BGD CUP | barikan |
1610005 | ANM BLD | bob |
1610006 | BGD CUP | beny |
proc_checker table(where person is assigned to a process in different role)
projectNo| process | proc_checker|
---------+---------+-------------+
1610004 | ANM BLD | adam |
1610004 | BGD CUP | barikan |
1610005 | ANM BLD | barikan |
1610006 | BGD CUP | beny |
So in the final result it should be smth like this(leaders, checkers together):
username| project TMNT | project LEON | project MAT |
--------+------------------------------------------+----------------+---------------------------------+
adam | ANM BLD(chk) | N/A | N/A | |
barikan | ANM BLD(ld), BGD CUP(ld), BGD CUP(chk) | ANM BLD(chk) | N/A |
beny | N/A | N/A | BGD CUP(ld), BGD CUP(chk) |
bob | N/A | ANM BLD(ld) | N/A |
Where ld= leader;
chk=checker
Should I LEFT JOIN both tables? Thanks for help

Answer 1

Assume you have table structure like this (sqlfiddle):
CREATE TABLE `user` (
`uid` INT(11) UNSIGNED NOT NULL PRIMARY KEY,
username VARCHAR(255) NOT NULL UNIQUE,
salary INT(11) UNSIGNED NOT NULL DEFAULT 0
);
CREATE TABLE project (
projectNo INT(11) UNSIGNED NOT NULL PRIMARY KEY,
title VARCHAR(255) NOT NULL UNIQUE
);
CREATE TABLE process (
projectNo INT(11) UNSIGNED NOT NULL,
process VARCHAR(255) NOT NULL,
proc_leader VARCHAR(255) NOT NULL,
FOREIGN KEY(projectNo) REFERENCES project(projectNo),
FOREIGN KEY(proc_leader) REFERENCES `user`(username)
);
CREATE TABLE proc_checker (
projectNo INT(11) UNSIGNED NOT NULL,
process VARCHAR(255) NOT NULL,
proc_checker VARCHAR(255) NOT NULL,
FOREIGN KEY(projectNo) REFERENCES project(projectNo),
FOREIGN KEY(proc_checker) REFERENCES `user`(username)
);
INSERT INTO `user`(uid, username, salary)
VALUES
(1, "bob", 0),
(2, "barikan", 0),
(3, "beny", 0),
(4, "adam", 0);
INSERT INTO project(projectNo, title)
VALUES
(1610004, "TMNT"),
(1610005, "LEON"),
(1610006, "MAT");
INSERT INTO process(projectNo, process, proc_leader)
VALUES
(1610004, "ANM BLD", "barikan"),
(1610004, "BGD CUP", "barikan"),
(1610005, "ANM BLD", "bob"),
(1610006, "BGD CUP", "beny");
INSERT INTO proc_checker(projectNo, process, proc_checker)
VALUES
(1610004, "ANM BLD", "adam"),
(1610004, "BGD CUP", "barikan"),
(1610005, "ANM BLD", "barikan"),
(1610006, "BGD CUP", "beny");
Result snippet with some commets is below:
<?php
// root root :)
$conn = mysqli_connect('127.0.0.1', 'root', 'root', 'test3');
// 1.Get data
// data for final table
// format is [username][projectNo] => [process1, process2, ..., processN]
$result = [];
// map project no to its title
$projectNoToTitle = [];
$sql = '
SELECT uid, username
FROM `user`
ORDER BY username
';
$query = mysqli_query($conn, $sql);
// for each user
while ($data = mysqli_fetch_assoc($query)) {
$sql = '
SELECT a.* FROM
(
(
-- select pairs project - leader
SELECT p.projectNo, p.title, CONCAT(pr.process, "(ld)") AS process
FROM project p
LEFT JOIN process pr ON p.projectNo = pr.projectNo
AND pr.proc_leader = "' . mysqli_real_escape_string($conn, $data['username']) . '"
)
-- union all means we union result of queries, which have structure
-- and don\'t remove duplicates (it\'s faster than UNION and
-- more logical because in our sittuation it won\'t be any duplicates)
UNION ALL
(
-- select pairs project - checker
SELECT p.projectNo, p.title, CONCAT(pch.process, "(chk)") AS process
FROM project p
LEFT JOIN proc_checker pch ON p.projectNo = pch.projectNo
AND pch.proc_checker = "' . mysqli_real_escape_string($conn, $data['username']) . '"
)
) AS a
ORDER BY a.projectNo
';
$query2 = mysqli_query($conn, $sql);
// for each project => process pair of user
while ($data2 = mysqli_fetch_assoc($query2)) {
$username = $data['username'];
$projectNo = $data2['projectNo'];
$projectTitle = $data2['title'];
$process = $data2['process'];
$projectNoToTitle[$projectNo] = $projectTitle;
if (!isset($result[$username])) {
$result[$username] = [];
}
if (!isset($result[$username][$projectNo])) {
$result[$username][$projectNo] = [];
}
if ($process) {
$result[$username][$projectNo][] = $process;
}
}
}
// \1.Get data
// 2. Output table
// create table header
// it's columns should contain all projects
if ($result) {
$header =
'<th>username</th>' .
array_reduce(array_values($projectNoToTitle), function ($p, $n) {
return $p . '<th>project ' . htmlspecialchars($n) . '</th>';
});
// output body
$body = '';
foreach ($result as $username => $usernameData) {
$row = '<td>' . htmlspecialchars($username) . '</td>';
foreach ($projectNoToTitle as $projectNo => $projectTitle) {
$r = (isset($usernameData[$projectNo]) && $usernameData[$projectNo])
? implode(', ', $usernameData[$projectNo])
: 'N/A';
$row .= '<td>' . htmlspecialchars($r) . '</td>';
}
$body .= "<tr>$row</tr>";
}
echo "<table><thead>$header</thead><tbody>$body</tbody></table>";
}
// \2. Output table
Feel free to modify if you found some bugs :)