Select and insert in one query SQL - php

Question

I have a web page where a user clicks on a map, the latitute and longitude are passed to text fields, and along with some other details the data is submitted to the database. I have a formula for calculating the nearest town, and I have a little sample table of towns with their latitudes and logitudes.
At the moment I can display the nearest town and distance, but I can't get it to send to the database. I think I need to put the two queries together but I don't know how. Please be kind, I know my code is terrible and I have lots of security issues which I'm going to try to address later. Thank you!
<?php
$conn = Connect();
/**
* Use the Haversine Formula to display the 100 closest matches to $origLat, $origLon
* Only search the MySQL table $tableName for matches within a 10 mile ($dist) radius.
*/
$origLat = $conn->real_escape_string($_POST['lat']);
$origLon = $conn->real_escape_string($_POST['lng']);
// This is the maximum distance (in miles) away from $origLat, $origLon in which to search
$dist = 50;
$query = "SELECT Townland, lat, lng, 3956 * 2 *
ASIN(SQRT( POWER(SIN(($origLat - lat)*pi()/180/2),2)
+COS($origLat*pi()/180 )*COS(lat*pi()/180)
*POWER(SIN(($origLon-lng)*pi()/180/2),2)))
as distance FROM townland WHERE
lng between ($origLon-$dist/cos(radians($origLat))*69)
and ($origLon+$dist/cos(radians($origLat))*69)
and lat between ($origLat-($dist/69))
and ($origLat+($dist/69))
having distance < $dist ORDER BY distance limit 1";
$result = mysqli_query($conn, $query) or die(mysql_error());
while($row = mysqli_fetch_assoc($result)) {
echo $row['Townland']." > ".$row['distance']."<BR>";
}
$User_ID = $conn->real_escape_string($_POST['User_ID']);
$Species_Name = $conn->real_escape_string($_POST['Species_Name']);
$No_Of_Birds = $conn->real_escape_string($_POST['No_Of_Birds']);
$newdate = $conn->real_escape_string($_POST['Sighting_Date']);
//Converts date to 'yyyy-mm-dd' acceptable to mysql
$newdate=date('Y-m-d',strtotime($newdate));
$Sighting_Details = $conn->real_escape_string($_POST['Sighting_Details']);
$lat = $conn->real_escape_string($_POST['lat']);
$lng = $conn->real_escape_string($_POST['lng']);
$townland = $row['Townland'];
$query = "INSERT into sighting
(User_ID, Species_Name, No_Of_Birds,
Sighting_Date, Sighting_Details,
lat, lng, Townland)
VALUES('" . $User_ID . "','" . $Species_Name . "','" . $No_Of_Birds . "','"
. $newdate . "','" . $Sighting_Details . "','"
. $lat . "','" . $lng . "','" . $townland . "')";
$success = $conn->query($query);
if (!$success) {
die("Couldn't enter data: ".$conn->error);
}
header("Location: ../View/thankYouSubmitSighting.php");
$conn->close();
exit();
while($row = mysqli_fetch_assoc($result)) {
echo $row['Townland']." > ".$row['distance']."<BR>";
}
mysqli_close($conn);
?>

Answer 1

If you need insert the result from query in a table eg: my_table
could be you need an insert select query ( a single sql command composed by two part )
"INSERT into my_table (Townland, lat, lng, distance)
SELECT Townland, lat, lng, 3956 * 2 *
ASIN(SQRT( POWER(SIN(($origLat - lat)*pi()/180/2),2)
+COS($origLat*pi()/180 )*COS(lat*pi()/180)
*POWER(SIN(($origLon-lng)*pi()/180/2),2)))
as distance FROM townland WHERE
lng between ($origLon-$dist/cos(radians($origLat))*69)
and ($origLon+$dist/cos(radians($origLat))*69)
and lat between ($origLat-($dist/69))
and ($origLat+($dist/69))
having distance < $dist ORDER BY distance limit 1";