I have a json file with a lot of records with fields for date, time and isApproved. What I am trying to do is to create a json rray that has dates for all the records that are approved. And the dates have all the hours that are booked for the current date.
So from this... :
[{"fullName":"Jojn Petkobsky","userName":"user1","phone":"12415455","email":"ees#asd.com"date":"11\/16\/2016","time":"1pm ","reason":"ReaReasonReaeason","isApproved":0,"label":"warning","status":"Approved"},{"fullName":"Zoltan Heinkelman","userName":"user2","phone":"12415455","email":"ees#asdd.com"date":"11\/16\/2016","time":"2pm ","reason":"ReaReasonReaeason","isApproved":1,"label":"warning","status":"Approved"}{"fullName":"Jojn Petkobsky","userName":"user1","phone":"12415455","email":"ees#asd.com"date":"11\/16\/2016","time":"1pm ","reason":"ReaReasonReaeason","isApproved":1,"label":"warning","status":"Approved"},{"fullName":"Frank Heinkelman","userName":"user3","phone":"12415455","email":"ees#asddd.com"date":"10\/11\/2016","time":"2pm ","reason":"ReaReasonReaeason","isApproved":1,"label":"warning","status":"Approved"}]
...i can have something like this, so i can have all the booked hours for a given date.
{"12/11/16"😞
{"time" :"10am"},
{"time" :"1pm"},
{"time" :"5pm"}
]
"12/10/16"😞
{"time" :"9am"}
]
}
I tried with something like this, but couldn't really finish it :
$string = file_get_contents("appointments.json");
$json_a = json_decode($string, true);
$date;
$datesTimes = array();
foreach($json_a as $json_r){
if ($json_r['isApproved']==1) {
$date = $json_r['date'];
//another foreach?
}
}
Any help will be appreciated!
As I mentioned in the comments, your JSON is NOT valid so I have fixed it to a point to show how it can be done.
//Fixed JSON as much as I could to show in example.
$json = '
[
{
"fullName": "Jojn Petkobsky",
"userName": "user1",
"phone": "12415455",
"email": "ees#asd.com",
"date": "11\/16\/2016",
"time": "1 pm",
"reason": "ReaReasonReaeason",
"isApproved": "0",
"label": "warning",
"status": "Approved"
},
{
"fullName": "Kitson88",
"userName": "user2",
"phone": "122323325",
"email": "eadasds#asasdasdd.com",
"date": "11\/16\/2016",
"time": "12 pm",
"reason": "ReaReasonReaeason",
"isApproved": "0",
"label": "warning",
"status": "Approved"
},
{
"fullName": "Jamie",
"userName": "user2",
"phone": "122323325",
"email": "eadasds#asasdasdd.com",
"date": "12\/16\/2016",
"time": "8 pm",
"reason": "ReaReasonReaeason",
"isApproved": "0",
"label": "warning",
"status": "Approved"
}
]
';
$array = json_decode($json, true);
//This will be you rnew Array for holding the needed data.
$approved = [];
foreach ($array as $value) {
if ($value['status'] === 'Approved') { //Any check really which will validate Approved
if (array_key_exists($value['date'], $approved)) { //Check if key exists note** will only work on 1D Array
array_push($approved[$value['date']], $value['time']); //If so, then append
} else { //If not, then create it and add value
$approved += [$value['date'] => [$value['time']]];
}
}
}
//Encode back to JSON
$newJson = json_encode($approved);
Output as JSON
{
"11\/16\/2016": ["1 pm", "12 pm"],
"12\/16\/2016": ["8 pm"]
}
http://php.net/manual/en/function.array-key-exists.php
http://php.net/manual/en/function.array-push.php
Related
I have this json code
"result": [
{
"update_id": 74783732,
"message": {
"message_id": 852,
"from": {
"id": ---,
"is_bot": false,
"first_name": "---",
"username": "---",
"language_code": "en"
},
"chat": {
"id": ---,
"first_name": "---",
"username": "---",
"type": "private"
},
"date": 1646306224,
"text": "#username",
"entities": [
{
"offset": 0,
"length": 16,
"type": "mention"
}
]
}
}
]
I can get content from update_id , message, first_name etc.
but I want to get "mention" from type how can i do it?
my code is
here i decode json and get arrays from json and put them in variable and use it in my queries but I cant get mention from entities...
$update = file_get_contents("php://input");
$update_array = json_decode($update, true);
if( isset($update_array["message"]) )
{
$text = $update_array["message"]["text"];
$chat_id = $update_array["message"]["chat"]["id"];
}
if(isset($update_array["message"]["entities"]["type"]) and $update_array=="mention")
{
$get_username = $text;
show_users_by_username($get_username);
}
tnx for helping
$update_array will never be equal to "mention" but $update_array["message"]["entities"]["type"] yes.
Change your condition.
I'm trying to get JSON by name and save it as a variable with everything related to that nest,
what would the best way to accomplish this?
(in my scenario the names are unique)
[{
"name": "Joe",
"age": "30",
"gender": "male"
},
{
"name": "Logan",
"age": "27",
"gender": "male"
}]
to something like this
{
"Joe": [{
"name": "Joe",
"age": "30",
"gender": "male"
}],
"Logan": [{
"name": "Logan",
"age": "27",
"gender": "male"
}]
}
i need to be able to search on the name to get the correct one, the API switches order so can't get it from just id
Hi This might helps you
$list = '[
{
"name":"Joe",
"age":"30",
"gender":"male"
},
{
"name":"Logan",
"age":"27",
"gender":"male"
}]';
$newjson = json_decode($list, true);
$final = [];
foreach ($newjson as $key => $value) {
$final[$value['name']][]=$value;
}
$finaloutput = json_encode($final, true);
echo "<pre>";
print_r($finaloutput);
echo "</pre>";
exit;
The output is
{"Joe":
[{"name":"Joe","age":"30","gender":"male"}],
"Logan":
[{"name":"Logan","age":"27","gender":"male"}]}
The Laravel Collections Library is a very useful lib to use cases like yours.
For this problem you could use the keyBy method!
$json = '[
{
"name":"Joe",
"age":"30",
"gender":"male"
},
{
"name":"Logan",
"age":"27",
"gender":"male"
}
]';
$array = collect(json_decode($json, true))->keyBy('name')->all();
print_r($array); // will be the array with the keys defined by the name!
See https://laravel.com/docs/5.5/collections#method-keyby
I have an URL that returns the JSON object below:
{
"addressList": {
"addresses": [
{
"id": 0000000,
"receiverName": "Name Example",
"country": {
"id": "BRA",
"name": "Brasil"
},
"state": {
"id": "SP"
},
"city": "São Paulo",
"zipcode": "00000000",
"type": "Residential",
"street": "000, St Example",
"number": 00,
"neighborhood": "Example",
"hash": "1bf09357",
"defaultAddress": false,
"notReceiver": false
}
]
}
}
I want to get the state value, how can I retrieve that with PHP?
I tried, something like this, but I couldn't get the state value, that should be SP in this case.
$string = '{ "addressList": { "addresses": [ { "id": xxxxxx, "receiverName": "XXXXX XXXXX", "country": { "id": "BRA", "name": "Brasil" }, "state": { "id": "SP" }, "city": "São Paulo", "zipcode": "03164xxx", "type": "Residential", "street": "Rua xxx", "number": xx, "neighborhood": "xxxxx", "hash": "xxxxx", "defaultAddress": false, "notReceiver": false } ] } }';
$json_o = json_decode($string);
$estado = $json_o->state;
How can I achieve the result I want?
Your JSON is not valid - you can validate it on jsonlint.com (it's invalid due to incorrectly formatted numeric values - "id" : 000000).
From then on, you can decode the value and access your data:
$json_o = json_decode($string);
$estado = $json_o->addressList->addresses[0]->state->id;
If you don't have access to the code that generates the JSON, you can attempt to run a regex to match, replace & wrap the numerical values with ":
$valid_json = preg_replace("/\b(\d+)\b/", '"${1}"', $str);
Note: The above is just an example - you'll have to figure out a case where a numerical value is already wrapped by ".
Your JSON has a couple of syntax errors:
"id": 0000000
"number": 00
JSON doesn't support leading zeros. If precise formatting is important, use strings:
"number": "00"
"id": "0000000"
Alternatively, use well-formed integers in the JSON (saves space) and convert them to formatted strings in PHP.
Once you've fixed your JSON, you can access the state->id value of the first address as I do below. When you decode JSON from an untrusted source, be prepared to do some error handling:
$json_string ="..."; //your source, to be decoded
$json_o= json_decode($json_string);
if(is_null($json_o)): //there was an error decoding
$errno = json_last_error();
$err_msg = json_last_error_msg();
die("Json decode failed: Error #$errno: $err_msg");
endif;
//we get here if json_decode succeeded. To get "SP", do...
$stateID = $json_o->addressList->addresses[0]->state->id;
Try:
$json_o = json_decode($string, true);
$estado = $json_o['addressList']['addresses'][0]['state']['id'];
I have accessed this json file on my website:
[{
"01:03:2016": "410",
"02:03:2016": "200",
"03:03:2016": "380"
}]
I want to use PHP to change the formatting to something like this, where the dates and counts are all values:
[{
"date": "01:03:2016",
"count": "410"
},
{
"date": "02:03:2016",
"count": "200"
},
{
"date": "03:03:2016",
"count": "380"
}]
PHP
$string = file_get_contents("data.json"); // your current json data
$json_a = json_decode($string, true);
$new_json = array();
foreach ($json_a as $key => $value) {
$new_json[] = array("date"=>$key,'count'=>$value);
}
echo json_encode($new_json); //output
data.json file (your current data)
[{
"01:03:2016": "410",
"02:03:2016": "200",
"03:03:2016": "380"
}]
This is the JSON response that I'm getting from database. I want to print these data. For now, there's only 2 entries in my table. So the length of JSON should be 2. As data increases, count has to get increase. SO for showing output, I use a for loop. And I used count() for limiting the iteration of loop only once through the JSON.
MY JSON:
{
"log": [
{
"action": "qq",
"id": "1",
"Time": "2014-05-19T15:40:06+05:30",
"user": {
"firstName": "dani",
"type": {
"zzs": "1",
"typename": "lolo",
"id": "1",
"zzt": "1",
"zzu": "1",
"zzv": "1",
"zzw": "1",
"zzx": "1"
},
"id": "1",
"lastName": "fed",
"password": "lmfao",
"userName": "fyi"
},
"userIpAddress": "101.15.23.45"
},
{
"action": "vv",
"id": "2",
"Time": "2014-05-20T10:16:33+05:30",
"user": {
"firstName": "dani",
"type": {
"zzs": "1",
"typename": "lolo",
"id": "1",
"zzt": "1",
"zzu": "1",
"zzv": "1",
"zzw": "1",
"zzx": "1"
},
"id": "1",
"lastName": "web",
"password": "rolf",
"userName": "asap"
},
"userIpAddress": "192.168.0.181"
}
]
}
MY PHP
$out = json_decode($json_data, true);
$x= count($out);
echo $x;
The value that I get is 1 instead of 2. And as you can see I have an associative array. I was trying to print those datas.
for($i=0; $i<$x; $i++)
{
echo $out['action'];
echo $out['user'][$i]['firstName'] ;
echo $out['user']['type'][$i]['typename'] ;
}
I don't get output. HELP???
I think it may be counting just the "Log"... technically that response is 2 dimensional:
data[0] = log
data[0][0] = log.firstRecord
data[0][1] = log.secondRecord
Try iterating through the second dimension
you have 2 element inside log key in your array.
try this:
$x= count($out['log']);
this will count 2
demo
for your loop you should try like this:
$out = json_decode($json_data, true);
$x= count($out['log']);
$out = $out['log'];
for($i=0; $i<$x; $i++)
{
echo $out[$i]['action'];
echo $out[$i]['user']['firstName'] ;
echo $out[$i]['user']['type']['typename'] ;
}
complete demo