I have one Ajax function which is running properly.but i want when my Ajax response is
<h3>No Couriers found near by you.please select another location</h3>
i want to display some error message else i want to display another map div in else condition.
but every time when i hit Ajax only else condition is working..but when i alert response and see the output it shows this message when
<h3>No Couriers found near by you.please select another location</h3>
but still it not comes in if condition..can anyone help me to do this....
<script>
$('#weight0,#weight1,#weight2,#weight3').click(function() {
var checked = $(this).is(':checked');
if($(this).is(":checked")) {
$.ajax({
type: "POST",
url: '<?php echo Router::url(array("controller" => "Orders","action" => "searchCourier")); ?>',
data: {
frmlat: $("#PoolLatitude").val(),
frmlong: $("#PoolLongitude").val(),
mylocation: $("#PoolLocation").val()
},
dataType: "html",
success: function(response) {
alert(response);
if(response =="<h3>No Couriers found near by you.please select another location</h3>"){
alert(thanks);
} else {
$('#map_canvas').css('display', 'none');//used to hide map after ajax success response.
$("#load_map").html(response);
}
},
complete: function() {
$('.spinicon').hide();
}
});
} else {
$("#secretcode").val("");
}
});
</script>
In your php script, return a boolean flag instead of a string :
<?php
if (some_condition) {
$return = true;
} else {
$return = false;
}
die(json_encode(array('return' => $return)));
And in the ajax success :
...
dataType: 'json',
success: function(data) {
if (data.return) {
alert("return is true");
} else {
alert("return is false");
}
},
...
Hope it helps.
PS : use Json Encode to parse the response and access values easily.
First of all, i suggest you to use status for ajax response something like:
1 for success
0 for failure
Than, as per your statement, your are getting the correct response in:
alert(response);
Than, you must need to check either response having <h3></h3> tags or not.
In your code, the main issue is that, you are using string without quotes in alert alert(thanks); this will return undefined thanks in console and treated as a variable.
This should be alert("thanks");
One more suggestion, it's always better to check browser console when you are not getting success in Ajax or any other script, this will help you to find the errors.
Related
I'm trying to make a like/dislike button in ajax. The ajax is sending my data to a separate file where it is saved in a database and that file sends back the successful response {"status":"success","message":"Like has been saved.","data":{"like":"1"}} that I got from the chrome network response window. However the code in $ajax(...).done isn't working
I have console.logged and var.dumped every bit of code i possibly could. my data IS being sent to my database which should mean that the SQL and the like class is correct. I've also tried simply console.log 'ging the response "res" and putting the rest in comments, but that again gives me nothing
<div>
Like
Dislike
<span class='likes' data-id="<?php echo $post->id ?>"><?php echo $post->getLikes(); ?></span> people like this
</div>
$("a.like, a.dislike").on("click",function(e){
var postId = $(this).data("id");
if($("a.like")){
var type = 1;
}else if($("a.dislike")){
var type = 0;
}
var elLikes = $(this).siblings(".likes");
var likes=elLikes.html();
$.ajax({
method: "POST",
url: "ajax/postlike.php",
data: {postId: postId, type:type},
dataType: "json",
})
.done(function( res ) {
console.log(res);
if(res.status=="succes"){
console.log(res);
if(res.data.like=="1"){
likes++;
elLikes=html(likes);
$("a.like").css("display","none");
$("a.dislike").css("display","inline-block");
} else if(res.data.like=="0"){
likes--;
elLikes=html(likes);
$("a.dislike").css("display","none");
$("a.like").css("display","inline-block");
}
}
});
e.preventDefault();
});
if(!empty($_POST)){
try {
$postId=$_POST['postId'];
$type=htmlspecialchars($_POST['type']);
$userId=$_SESSION['user_id'];
$l = new Like();
$l->setPostId($postId);
$l->setUserId($userId);
$l->setType($type);
$l->save();
$res = [
"status" => "success",
"message" => "Like has been saved.",
"data" =>[
"like" => $type
]
];
}catch (trowable $t) {
$res = [
'status' => 'failed',
'message' => $t->getMessage()
];
}
echo json_encode($res);
var_dump($res);
}
what I expected to happen was that Ajax sent the JSON data to the php code, that put it in a database, which works. Then gives a successful response to the Ajax, also works. The Ajax would then switch out the like/dislike buttons whilst adding or taking 1 like from the span "likes". It however does absolutely nothing
I'm almost 100% certain that the problem is something stupid that I'm overlooking, but i really can't find it.
Typo in 'success' in on line: if(res.status=="succes"){
you can try with this:
error: function(xhr, status, error) {
console.log(error)
},
success: function(response) {
console.log(response)
}
in your Ajax function, to know what happen in the server side with the response.
If you specify a return data type for the ajax request to expect, and the actual returned value isn't what you specified, then your error/fail function will be triggered if you have one. This is because adding dataType: "json" causes you're ajax try and parse your return value as json and when it fails, it triggers your error handler. It's best to omit the dataTaype and then add a try catch with JSON.parse in your done function, to get around this.
E.G
.done(function (string_res) {
console.log(string_res);
try {
var json_obj = JSON.parse(string_res);
console.log(json_obj);
} catch (e) {
console.log('failed to parse');
}
// do work/operations with json_obj not string_res
})
.fail(function (jqXHR, textStatus) {
console.log('failed')
});
I have an AJAX script that should insert data into a mysql database when users are logged in. However it is currently running the success function, even when 'success' => 'false' is returned in the console.
Her is my code
$(document).ready(function() {
$("#addfav").click(function() {
var form_data = {heading: $("#vidheading").text(), embed : $("#vidembed").text()};
jQuery.ajax({
type:"POST",
url:"http://localhost/stumble/Site/add_to_fav",
dataType: "json",
data: form_data,
success: function (data){
alert("This Video Has Been Added To Your Favourites");
console.log(data.status);
},
error: function (data){
if(data.success == false){
alert("You Must Be Logged In to Do That");
console.log(data.status);
};
}
});
})
})
here is the php, bear in mind my project is in codeigniter.
public function add_to_fav(){
header('Content-Type: application/json');
$this->load->model('model_users');
$this->model_users->add_favs();
}
and this is the actual model for adding data to db
public function add_favs(){
if($this->session->userdata('username')){
$data = array(
'username' => $this->session->userdata('username'),
'title' => $this->input->post('heading'),
'embed' => $this->input->post('embed')
);
$query = $this->db->insert('fav_videos',$data);
echo json_encode(array('success'=>'true'));
} else {
echo json_encode(array('success'=>'false'));
}
}
Thank you for any suggestions!
You aren't returning an error.
You are returning a 200 OK with the data {"success": "false"}.
You can either handle that in your jQuery success function or send a different status code (it looks like a 403 error would fit here).
You have to remember error that occurs for asynchronous requests and errors that occur for PHP backend are different. Your error occurs at PHP-level, and PHP returns valid HTML as far as the javascript frontend is concerned. You need to check if the "success" variable in the returned JSON is true.
For some reason Im getting a <br/> tag from nowhere in my response from the PHP function...
Here is the ajax:
var paid_value = 'Paid';
$.ajax({
url: 'http://localhost/myshop/owe_money/add_paid.php',
type: 'post',
data: { paid_value:paid_value } ,
beforeSend: function() {
$("#ajax-result").html('Before');
},
success: function(data) {
$("#ajax-result").html(data);
$('input[name="mark_as_paid"]').val(data);
},
error: function(xhr, ajaxOptions, thrownError) {
$("#ajax-result").html('Error');
}
});
And the PHP:
function add_paid() {
include('../db_connect.php');
$paid_value = $_POST['paid_value'];
if (is_numeric($paid_value)) {
$sql = "UPDATE paid SET first_item = $paid_value";
} else {
$sql = "UPDATE paid SET first_item = '".$paid_value."'";
}
if (mysqli_query($connect, $sql)) {
echo $paid_value;
} else {
echo "Unsuccesful".mysqli_error($connect);
}
die;
}
add_paid();
My response should simply be saying "Paid", but instead is saying "<br /> Paid".
on the face of it, it looks sound. You'll probably find that the br is going in somewhere else. Maybe it's even already in the file?
If it is finding it's way into the $_POST variable, you could temporarily hack the issue to use
$paid_value = strip_tags($_POST['paid_value]);
This answer comes with no warranty whatsoever!
In your jQuery code, change the success block to:
success: function(data) {
$("#ajax-result").html(data);
$('input[name="mark_as_paid"]').val(data);
console.log(data)
},
Open your debugger in the browser and view the console. This will write the value of data as sent from your PHP script, and may or may not have the line break in it. I suspect that the line break may be coming from the fist page but this will allow you to see this.
I cannot see any problem with the code so I think it has to do with the form/input where you are displaying the result - you have not included this.
you can use replace tag in success ajax
data.replace("but the br tag","");
but it will still exist in the database
I'm trying to test an ajax call on post by doing the following just for testing purposes, but for some reason the call is never successful. I've been searching around and there isn't much that I could find that would explain why this isn't working.
$.ajax({
type: "POST",
url: "file.php",
success: function(data) {
if(data == 'true'){
alert("success!");
}
},
error: function(data) {
alert("Error!");
}});
file.php contains the following:
<?php
return true;
?>
Can someone please point me in the right direction. I realize that this may seem simple but I am stumped. Thank.
return true will make the script exit. You need:
echo 'true';
Firstly check your paths. Is file.php residing in the same folder as the file that your javascript is contained in?
If your path is incorrect, you will get a 404 error printed to your javascript console if you are using chrome.
Also you should change your php to:
<?php
echo 'true';
Once your path is correct and your php is amended you should be good to go.
Have you tried by accessing to the file directly and see if it outputs something?
return true shouldn't be use in that case (or any other, it's better to use exit or die), everything get by a AJAX call is hypertext generated by server side, you should use (as they pointed you before echo 'true';)
You could also try a traditional AJAX call XMLHttpRequest (without JQuery) if problem persists, and then check if there is any problem between the request and server..
EDIT: also, do not check by comparison, just make an alert to 'data' to see what it gets.
In addition to the echo 'true' suggestion, you can also try to alert the actual data that's returned to ajax. That way you can see if you have the proper value/type for your if statement.
success: function(data) {
alert(data);
}
try this, the new ajax syntax
$.ajax({ type: "POST", url: "file.php" }).done(function(resp){
alert(resp);
});
Here is correct way:
$.ajax({
type : "POST",
url : "file.php",
success : function (data) {
/* first thing, check your response length. If you are matching string
if you are using echo 'true'; then it will return 6 length,
Because '' or "" also considering as response. Always use trim function
before using string match.
*/
alert(data.length);
// trim white space from response
if ($.trim(data) == 'true') {
// now it's working :)
alert("success!");
}
},
error : function (data) {
alert("Error!");
}
});
PHP Code:
<?php
echo 'true';
// Not return true, Because ajax return visible things.
// if you will try to echo true; then it will convert client side as '1'
// then you have to match data == 1
?>
I'm running the following php script through AJAX and need to integrate some error management into it:
$exists = file_exists('../temp/' . $email . '/index.html');
if($exists) {
echo "ERROR!!!";
} else {
createUserDirectory($email);
}
In the AJAX success function, how can I determine whether the script ran successfully or produced an error?
If it returns OK, I want to perform the redirect as it is at the moment, but if there's an error, I want to instead add the error to a DIV within the document (and not redirect of course...).
$.ajax({
type: "POST",
url: 'generate/build.php',
data: $("#generateStart").serialize(), // serializes the form's elements.
success: function(data)
{
window.location.href="generate-site.php?user=" + data.replace(/^ +/,"") + ""; // Redirect to publish.php and remove any spaces from the URL (bug fix).
}
});
Thanks.
Your PHP script should return a 4xx or 5xx HTTP status code to indicate failure. Then, the error method of jQuery's ajax object will be called.
Inside your success handler, check if(data == 'ERROR!!!').
You probably want to add two parts to this: an error callback on the $.ajax function to see if the request failed on the net and then a check on the return value to see if it failed server validation (if a file exists in this case).
Example:
$.ajax({
...
success : function(data) {
if(data && data != "ERROR!!!") {
//redirect
}
},
error: function(jqXHR, textStatus, errorThrown) {
//Log error, display feedback to user, etc...
}
);