I'm using these codes.
$blog = mysql_query("SELECT * FROM blog ORDER BY id");
while($sutun = mysql_fetch_array($blog)) {
$fake = $sutun["date"];
echo "$fake";
}
When i use echo"$fake"; I can see all of my rows. But when I use <?php echo "$fake" ?> , It shows just 1 row for me.
I want to all of my rows while I'm using <?php echo "$fake" ?>.
Beacuse The echo"$fake"; in with in a loop it will echo at every iteration thats why you can see all your rows but <?php echo"$fake"; ?> executed when the loop is done so only the last row will be echoed;
You should seperate your logic like
<?php
$blog = mysql_query("SELECT * FROM blog ORDER BY id");
while($sutun = mysql_fetch_array($blog)) {
$fake = $sutun["date"];
?>
<?php
echo $fake;
}
Related
I am trying to show it all with while loop on a dynamic page, but it wont show anything at all..
if (isset($_GET['id'])) {
$genre = $_GET['id'];
$sql = "SELECT * FROM movstream_genre WHERE ID = '$genre'";
$result = $db->query($sql);
$row = $result->fetch_assoc();
}else{
$sql = "SELECT ID, genre FROM movstream_genre";
$result = $db->query($sql);
}
<html>
<body>
<ul>
<?php while ( $row = $result->fetch_assoc() ): ?>
<li><?=$row['genre'];?></li>
<?php endwhile; ?>
</ul>
</body>
</html>
Anyone know why it wont show anything on the dynamic page, but if the page is not dynamic it works fine :)
Thanks.
If dynamic page means that your sending an id in Url an you are not getting result.
I think that the problem is that you are using $row = $result->fetch_assoc(); in if condition and also in while.
Please use fetching in one place. Better be in while loop.
Hope it helps.
I figured it out
if (isset($_GET['id'])) {
$genre = $_GET['id'];
$sql = "SELECT ID, genre FROM movstream_genre";
$result = $db->query($sql);
}
This it how it needs to look when its a dynamic page :)
well i think it is, it works now.
please echo the result ...
<li><?php echo $row['genre'];?></li>
And in href, it is only genre OR genre.php
In the first query..
$sql = "SELECT * FROM movstream_genre WHERE ID = '$genre'";
$result = $db->query($sql);
$row = $result->fetch_assoc();// this line not required
comment this line
$row = $result->fetch_assoc();
It looks like you haven't enclosed the first part of your PHP code in <?php ?> tags
I want to do a a query to a mysql database that returns multiple rows and columns. I then want to assign the results to a variable and echo them out later in the page. However, the method I am using is long, tedious, and for this project impractical. here is what I am doing.
$result = mysql_query("SELECT * FROM people WHERE open_or_closed !='Closed' ORDER BY
number",$c) or die("two");
$number=mysql_num_rows($result);
if($mynumber>0){
$data= mysql_fetch_array($result,MYSQL_ASSOC);
$full_name1=mysql_result($result,0, 'full_name');
$phone_number1=mysql_result($result,0, 'phone_number');
$one=1;
}
if($mynumber>1){
$full_name2=mysql_result($result,1, 'full_name');
$phone_number2=mysql_result($result,1, 'phone_number');
$two=2;
}
Later when I want to echo it, I will not know if there is a record there or not, so I will have to
<?php if($one==1){echo '<div id="blackline"></div>';}?>
<div id="titletext"><?php echo $full_name1; ?></div><br />
<div id="datetext"><?php echo $phone_number1; ?></div>
Try this
$result = mysql_query("SELECT * FROM people WHERE open_or_closed !='Closed' ORDER BY
number",$c) or die("two");
$number=mysql_num_rows($result);
if($number>0)
{
$i=0;
while($row_result = mysql_fetch_array($result))
{
$full_name[$i][] = $row_result['full_name'];
$phone_number[$i][] = $row_result['phone_number'];
$i++;
}
}
How about this? This is at the top of my codes but i think this is helpless. Every time the third order comes in the calculation is all wrong.
<?php
include("dbconnection.php");
if ($_SESSION["loggedin"] != "true")
header("Location:memberlogin.php");
$cust_id = $_SESSION["cust_id"];
Selecting all from the database
$result = mysql_query("select customer.*, product.*, order_details.* from customer, product, order_details where customer.cust_id=$cust_id and product.pro_id=product.pro_id and order_details.order_details_id = order_details.order_details_id")or die(mysql_error());
$row = mysql_fetch_assoc($result);
?>
<?php
$x=1;
$bill_total=5.00;
$order_stotal=$row["order_stotal"];
$result = mysql_query("select product.*,order_details.* from product,order_details
where order_details.pro_id= product.pro_id ");
while($row=mysql_fetch_assoc($result))
{
?>
I need it to echo all the possible subtotal. I think i just need to edit this or something i'm not quite sure
<?php
$x++;
$bill_total +=$order_stotal;
}
?>
RM  
<?php
echo number_format($bill_total,2);
?>
Then this one here is the function of the button
<?php
if(isset($_POST["submitbtn"]))
{
$bill_id=rand(1000,9999);
$bill_date=date("Y-m-d");
$bill_state=$_POST["bill_state"];
$bill_city=$_POST["bill_city"];
$bill_add=$_POST["bill_add"];
$bill_post=$_POST["bill_post"];
mysql_query("insert into bill
(cust_id, bill_date, bill_total, bill_state, bill_city, bill_add,
bill_post)
values('$cust_id','$bill_date',
'$bill_total', '$bill_state', '$bill_city','$bill_add','$bill_post')")or die(mysql_error());
}
?>
$bill_total +=$row['order_stotal'];
This should work for combining all the values from that line in the rows retrieved by the database.
(You also need to remove the reference to $row['order_stotal'] from before the query, unless you're using a different query from another part of the script to set it.)
I'm trying to display information from a table in my database in a loop, but for certain information, I'm referencing other tables. When I try to get data from other tables, any data following will disappear. here is the code I am using:
`
//Below is the SQL query
$listing = mysql_query("SELECT * FROM Musicians");
//This is displaying the results of the SQL query
while($row = mysql_fetch_array($listing))
{
?>
...html here...
<? echo $row['name']; ?>
<? echo $row['Town']; ?>
<?
$CountyRef = $row['CountyId'];
$county = mysql_query("SELECT * FROM County WHERE CouInt='$CountyRef'");
while($row = mysql_fetch_array($county))
{
echo $row['CouName'];
}
?>
<?php echo $row['instrument']; ?>
<?php echo $row['style']; ?>`
My problem is that everything after the second while loop is not displaying. Anyone have any suggestions?
Thanks
Second loop should say $row2. $row is being overwritten. Both variables should be named different from each other.
You can acomplish that with a one single query:
SELECT *,
(SELECT CouName FROM County WHERE CouInt=mus.CountyId) as Country
FROM Musicians mus;
You final code should looks like:
<?php
$listing = mysql_query("SELECT *,
(SELECT CouName FROM County WHERE CouInt=mus.CountyId) as Country
FROM Musicians mus;");
//This is displaying the results of the SQL query
while($row = mysql_fetch_assoc($listing))
{
echo $row['name'];
echo $row['Town'];
echo $row['Country']; //Thats all folks xD
echo $row['instrument'];
echo $row['style'];
} ?>
Saludos ;)
And that?:
while($row2 = mysql_fetch_array($county)) {
echo $row2['CouName'];
}
I have a code that I have used over and over again before and now it's messing up. All I want to do is list information from the database into the table on the page, but now it will only show one result, instead of all the results it has found.
<table>
<tr><td style="background-color:#009745; color:#FFFFFF"><center><strong>Address Book</strong></center></td></tr>
<tr>
<?php
$getids = mysql_query("SELECT id, first_name, last_name FROM accounts WHERE s1='$id' ORDER BY id DESC", $db);
if (mysql_num_rows($getids) > 0) {
while ($gids = mysql_fetch_array($getids)) {
$ab_id = $gids['id'];
$ab_fn = $gids['first_name'];
$ab_ln = $gids['last_name'];
}
?>
<td><?= $ab_id ?> - <?= $ab_fn . " " . $ab_ln ?></td>
<?php
} else {
?>
<td><center>No Contacts</center></td>
<?php
}
?>
</tr>
</table>
please help me with this.
Thank You for your help :)
I love this site!! I can always get answers when I need them.
I saw two thing wrong
you are using mysql_fetch_array and later you are using string indexes to print the result
print the things in loop it is overriding values and just storing last row
if (mysql_num_rows($getids) > 0) {
while ($gids = mysql_fetch_assoc($getids)) {
$ab_id = $gids['id'];
$ab_fn = $gids['first_name'];
$ab_ln = $gids['last_name'];
echo '<td>'.$ab_id.' -'. $ab_fn.''.$ab_ln.' </td>';
}
In this messy code you're closing the while loop too early:
while ($gids = mysql_fetch_array($getids)) {
$ab_id = $gids['id'];
$ab_fn = $gids['first_name'];
$ab_ln = $gids['last_name'];
}
Only the last retrieved row is used later on. Also, don't use mysql_fetch_array if you're not accessing the numeric indeces of your result. Use mysql_fetch_assoc instead.