i was struggling to make a regex which extract the digits bettween the last set of parentheses from a string, and this is what i came with until now:
^.*?\([^\d]*(\d+)[^\d]*\).*$
E.g.:
This is, (123456) a string (78910);
It returns 123456 , which is great but i need it to look at the last set and return 78910.Also , i want the regex to ignore everything but digits:
This is, (123bleah456) a string (789da10);
Should return: 78910
UPDATE
Using regex:
(\d+)(?!.*\d)
For string:
Telefon Mobil (123)Apple iPhone 6 128GB Gold(1567)asd234
Will return 234 when it should be 1567
Rubular
You can extract the last one by use of greed:
.*\(\K\d+
See demo at regex101
\K resets beginning of the reported match.
For your more specific updated case slightly modifiy the regex and strip out non-digits.
$str = "This is, (123bleah456) a string (789da10);";
if(preg_match('/.*\(\K\d[^)]*/', $str, $out))
$res = preg_replace('/\D+/', "", $out[0]);
See demo at eval.in
Related
i'm trying to get the string between two words in a entire string:
Ex.:
My string:
...'Total a Facturar 123,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado'...
I'm using
/(?<=Total a Facturar )(.*?) Recepcionado/
I need the highlighted characters (26,860161,16080,580310,760)
and i get 221,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado with my pattern.
The numbers of the string are always different, i need the numbers that are together without a space.
Thanks
EDIT:
Here is the entire string: eval.in/802292
I hope this will be helpful
Regex demo or Regex demo 2
Regex: (?:\d+(?:\,\d+){2,})
For above question you can also use it like this (?:\d+(?:\,\d+){4})
1. (?:\d+) this will match digits one or more.
2. (?:\,\d+){2,} Adding this in expression will match patterns like , and digits {2,} for 2 or more than 2 times.
PHP code: Try this code snippet here
<?php
ini_set('display_errors', 1);
$string = "Total a Facturar 123,061 221,063 26,860161,16080,580310,760 358,297 Recepcionado";
preg_match("#(?:\d+(?:\,\d+){2,})#", $string, $matches);
print_r($matches);
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = "/([\w]+)\s([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)/";
preg_match($rgx, $txt, $res);
var_dump($res);
I would like to simplify this pattern by avoiding repeating "([0-9]+)" because i don't know how many they are.
Any one can say me how ?
Here is a direct answer to the question, as you have stated it:
/[\w]+\s[0-9]+(?:\.[0-9]+)+/
However, note that I have removed all of the numbered capture groups. This could be problematic, depending on what you're actually trying to achieve.
It is not possible to "count" with capture groups in regular expressions, so you would need to write some other code (i.e. not just one match, with one regex, and using back-references) to deal with this if you wish to run any queries like "What digits appear after the fifth "."?"
There are two ways you can do this. If you just need to verify that the string matches the pattern, this regex will do the job: \w+\s(?:[0-9]+\.?)+
However, if you need to split the string in to it's component parts (in my interpretation, the beginning word followed by the sequence of decimal separated numbers), then you could use this pattern: (\w+)\s((?:[0-9]+\.?)+)
The second pattern will return the beginning word, toto1 in group 1, followed by the decimal separated numbers in group 2 555.4545.555.999.7465.432.674 which you could then split in PHP if required: $sequence = explode('.', $matches[2]);
What you need can be obtained with a preg_split with a regex matching 1 or more whitespaces or dots:
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = '/[\s.]+/';
$res = preg_split($rgx, $txt);
print_r($res);
See the PHP demo
If you need a regex approach, you can use a \G based regex with preg_match_all:
'~(?|([\w]+)|(?!\A)\G[\s.]*([0-9]+))~'
See the regex demo and a PHP demo:
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = '~(?|(\w+)|(?!\A)\G[\s.]*([0-9]+))~';
preg_match_all($rgx, $txt, $res);
print_r($res[1]);
Pattern details:
The (?|...) is a branch reset group to reset group IDs in all the branches
(\w+) - Group 1 matches 1+ word chars
| - or (then goes Branch 2)
(?!\A)\G - the end of the previous successful match
[\s.]* - zero or more whitespaces or dots
([0-9]+) - Group 1 (again!) matching 1 or more digits.
I'm attempting to extract [digit][digit][colon][digit][digit] from a string if it is present. The Regex should match:
02:59
03:24
So far I've got quite lost, though I've realised \d will return me a single digit, and \d{2} should find me 2, but I've got stuck with adding in the separator : and finding 2 more digits to fit into my preg_match:
$trackTime = preg_match($regexEludingMe, $track, $matches);
Example $track is:
10. Break Your Heart 03:42 should match 03:42
Just add the separator : and duplicate the first part that you've already figured out \d{2}:\d{2}. Don't forget delimiters:
preg_match('/\d{2}:\d{2}/', $track, $trackTime);
print_r($trackTime);
I am trying to grab a number that can be in the format $5,000.23 as well as say, $22.43 or $3,000
Here's my regular expression, this is in PHP.
preg_match('/\$([0-9]+)([\.,]*)?([0-9]*)?([\.])?([0-9]*)?/', $blah, $blah2);
It seems to match numbers in the format $5,500.23 perfectly fine, however it doesn't seem to match any other numbers well, like $0.
How do I make everything optional? Shouldn't grouping () and using a question mark do that?
This should do the trick:
\$[\d,.]*[\d]
Debuggex Demo
Specific PHP Example:
$re = "/\\$[\\d,.]*[\\d]/";
$str = "\$1 klsjdfgsjdfg \$100 kjdfhglsjdfg \$1,000 jljsdfg \$1,000.00 ldfjhsdf";
preg_match_all($re, $str, $matches);
Regex 101 Demo
I have variable strings like the below:
The.Test.String.A01Y18.123h.WIB-DI.DO5.1.K.314-ECO
The.Regex.F05P78.123h.WIB-DI.DO5.1.K.314-EYT
Word.C05F78.342T.DSW-RF.EF5.2.F.342-DDF
I would like to extract this part of these string in PHP dynamically and i was looking at using regex but haven't had much success:
The.Test.String.A01Y18
The.Regex.F05P78
Word.C05F78
And ultimately to:
The Test String A01Y18
The Regex F05P78
Word C05F78
The first part of the text will be variable in length and will separate each word with a period. The next part will always be the same length with the pattern:
One letter, 2 number, one letter, 2 numbers pattern (C05F78)
Any thing in the string after that is what I would like to remove.
that's it
$x=array(
"The.Test.String.A01Y18.123h.WIB-DI.DO5.1.K.314-ECO",
"The.Regex.F05P78.123h.WIB-DI.DO5.1.K.314-EYT",
"Word.C05F78.342T.DSW-RF.EF5.2.F.342-DDF"
);
for ($i=0, $tmp_count=count($x); $i<$tmp_count; ++$i) {
echo str_replace(".", " ", preg_replace("/^(.+?)([a-z]{1}[0-9]{2}[a-z]{1}[0-9]{2})\..+$/i", "\\1\\2", $x[$i]))."<br />";
}
Using this regular expression should work, replacing each of your strings with the first capturing group:
^((?:\w+\.)+\w\d{2}\w\d{2}).*
See demo at http://regex101.com/r/fR3pM6
This is valid too:
preg_match("\.*[\w\d]{6}", stringVariable)
.* for all digits atleast we found a composition of letters and words of 6 characters ([\w\d]{6})
Result:
Match 1: The.Test.Stsrisng.A01Y18
Match 2: The.Regex.F05P78
Match 3: Word.C05F78