How to show $classname only once - php

Question

I am trying to echo $classname only once.
So it shows like this for example.
Puppy Dog
1st blah blah
2nd whoever
3rd extra
at present it shows like:
Puppy Dog
1st blah blah
Puppy Dog
2nd whoever
Puppy Dog
3rd extra
<?php
// SO UPDATE THE QUERY TO ONLY PULL THAT SHOW'S DOGS
$query = "SELECT c.* , p.* FROM result c,dogs p WHERE c.dog_id=p.dog_id";
$result = mysqli_query($connection, $query) or trigger_error
("Query Failed! SQL: $query - Error: ". mysqli_error
($connection), E_USER_ERROR);
if ($result) {
while ($row = mysqli_fetch_assoc($result)) {
$placement = $row['placement'];
$classname = $row['class_name'];
$dog_name = $row['dog_name'];
$award = $row['award'];
?>
<table>
<tr>
<td><strong><?php echo $classname ?></strong> </td><br>
</tr>
<tr>
<td><strong><?php echo $placement, $award ?></strong> <?php echo $dog_name ?></td>
</tr>
</table>
<?php }}} ?>

Answer 1

Use counter to check if it is already displayed:
$ctr = 0;
while{
$classname = $row['class_name'];
if($ctr == 0){
echo $classname;
$ctr++;
}
//display the rest
...
}

Answer 2

So, don't know why are you using <table> inside the while loop, this will print as per your no's of rows.
Here is the basic example, you can store the values in an array than use it with your HTML:
Example:
<?php
if ($result) {
$myarr = array();
while ($row = mysqli_fetch_assoc($result)) {
$myarr[$row['class_name']][] = $row; //store values into an array against each class in group
}
}
foreach ($myarr as $key => $value) {
echo "Class Name: ". $key."<br/>"; // will print class name
foreach ($value as $fvalue) {
echo "Placement: ".$row['placement']."<br/>";; // placement
echo "Dog Name: ".$row['dog_name']."<br/>"; // dog name
echo "Award: ".$row['award']."<br/>";; // award
}
}
?>
Other solution is using incremental variable in while loop as mentioned in other answers.

Answer 3

You can keep track record by index in while loop like :
<?php
// SO UPDATE THE QUERY TO ONLY PULL THAT SHOW'S DOGS
$query = "SELECT c.* , p.* FROM result c,dogs p WHERE c.dog_id=p.dog_id";
$result = mysqli_query($connection, $query) or trigger_error
("Query Failed! SQL: $query - Error: ". mysqli_error
($connection), E_USER_ERROR);
if ($result) {
$i = 1;
while ($row = mysqli_fetch_assoc($result)) {
$placement = $row['placement'];
$classname = $row['class_name'];
$dog_name = $row['dog_name'];
$award = $row['award'];
?>
<table>
<tr>
<td><strong><?php if($i==1) { echo $classname; } ?></strong> </td><br>
</tr>
<tr>
<td><strong><?php echo $placement, $award ?></strong> <?php echo $dog_name ?></td>
</tr>
</table>
<?php $i++; }}} ?>

Answer 4

The Opening and Closing <Table> Tags should be outside your Loop if you expect to have just one Table. Even the <tr> Tags should encompass the <td> Tags if you wish to have rows containing 2 Cells like the Code below shows:
<?php
// SO UPDATE THE QUERY TO ONLY PULL THAT SHOW'S DOGS
$query = "SELECT c.* , p.* FROM result c,dogs p WHERE c.dog_id=p.dog_id";
$result = mysqli_query ($connection, $query) or trigger_error
("Query Failed! SQL: $query - Error: ".
mysqli_error($connection), E_USER_ERROR);
?>
<table>
<?php
if ($result) {
while ($row = mysqli_fetch_assoc($result)) {
$placement = $row['placement'];
$classname = $row['class_name'];
$dog_name = $row['dog_name'];
$award = $row['award'];
?>
<tr>
<td>
<strong><?php echo $classname ?></strong>
<!-- DO YOU NEED THIS <BR>TAG HERE? <br> -->
</td>
<td>
<strong><?php echo $placement, $award ?></strong><?php echo $dog_name ?>
</td>
</tr>
<!-- EXCEPT IF YOU WISH TO HAVE ONE COLUMN, THE ROW BELOW IS UNNECESSARY -->
<!--
<tr>
<td>
<strong><?php echo $placement, $award ?></strong> <?php echo $dog_name ?>
</td>
</tr>
-->
<?php
} // CLOSE THE WHILE LOOP;
} // CLOSE THE IF STATMENT;
?>
</table>