How to add else into PHP Code line? - php

Question

I have this following code
<td>
<?php if($rec->telegram){ ?><img class="social" src="<?php echo base_url(); ?>social/telegram.jpg" /><?php } ?>
<?php if($rec->google_pluse){ ?><img class="social" src="<?php echo base_url(); ?>social/g.jpg" /><?php } ?>
<?php if($rec->instagram){ ?><img class="social" src="<?php echo base_url(); ?>social/insta.jpg" /><?php } ?>
<?php if($rec->facebook){ ?><img class="social" src="<?php echo base_url(); ?>social/f.jpg" /><?php } ?>
</td>
I would like to add "else" into this code that if ALL those icons facebook, instagram, google plus and facebook weren't available then it will show another image file like "nophoto.jpg"
Note: If all those icons (4 icons) weren't available then it will show nophoto.jpg
I highly appreciate if someone guide me how to add else into above code.
Regards

Answer 1

It'll be easier to just add an extra if:
if (!($rec->telegram || $rec->instagram || $rec->facebook || $rec->google_plus)) { //etc
But really you want to attach that kind of logic to the $rec object, so that it's neatly separated and it's easier to add new types of social media in the future. Hopefully your $rec object is indeed backed by a class and not just a stdClass from a database result or cast.
public function hasNoSocialIcon() {
return !($rec->telegram || $rec->instagram || $rec->facebook || $rec->google_plus);
}
And then use that in your template:
<?php if ($rec->hasNoSocialIcon()) { ?>
<img class="social" src="<?php echo base_url(); ?>social/nophoto.jpg" />
<?php } ?>

Answer 2

You should take the use of PHP's conditional operators like this:
<?php
$icons_available = (
!empty($rec->telegram) &&
!empty($rec->google_plus) &&
!empty($rec->instagram) &&
!empty($rec->facebook)
);
?>
<td>
<?php if(!$icons_available) { ?>
<a href="default-pic.jpg">
<img class="social" src="default-pic.jpg" />
</a>
<?php } else { ?>
<?php $url = echo base_url() . 'social/telegram.jpg'; ?>
<a href="<?php echo $url; ?>">
<img class="social" src="<?php echo $url ?>" />
</a>
<?php $url = echo base_url() . 'social/google_plus.jpg'; ?>
<a href="<?php echo $url ?>">
<img class="social" src="<?php echo $url ?>" />
</a>
<?php $url = echo base_url() . 'social/instagram.jpg'; ?>
<a href="<?php echo $url ?>">
<img class="social" src="<?php echo $url ?>" />
</a>
<?php $url = echo base_url() . 'social/facebook.jpg'; ?>
<a href="<?php echo $url ?>">
<img class="social" src="<?php echo $url ?>" />
</a>
<?php } ?>
</td>
Hope this helps!