I am trying to add an if else statement to a file in Magento.
Basically I want it to display different content depending on the body class.
For example, if the body element had a specific class, such as in:
<body class="specific-class">
Then within that body block, then the contents of it might display:
<section class="banner banner-inner <?php Mage::helper('function')->convert_category_name($category_name); ?>">
<div class="wrapper">
<?php echo $this->getChildHtml('breadcrumbs') ?>
<?php echo $this->getLayout()->getBlock('breadcrumbs')->toHtml(); ?>
</div>
<div class="bottom-rip"></div>
</section>
But if the body had a different class, or no class at all, it would default to:
<div class="no_content">
<?php echo="<h1>No content</h1>"; ?>
</div>
Does anyone know the syntax for performing such an operation?
Related
i use the following code with custom fields:
But the problem is; when did not put any content in one of custom field it need be hide.
the class style of the other effect it, and that is something I don’t want to show.
<div class = "class2">
<? php the_sub_field ('filed2'); ?>
</div>
<div class = "class1">
<? php the_sub_field ('filed1'); ?>
</div>
I want hide one of both custom filed when on of them is empty.
How can i hide it?
<?php if (get_sub_field ('filed2') || get_sub_field('filed1'));{ ?>
<div class = "class2">
<? php the_sub_field ('filed2'); ?>
</div>
<div class = "class1">
<? php the_sub_field ('filed1'); ?>
</div>
<?php } ?>
You would want to wrap it in an if statement.
You can also do (if you need the conditional logic on a per-field basis):
<?php if (get_sub_field ('filed2'));{ ?>
<div class = "class2">
<? php the_sub_field ('filed2'); ?>
</div>
<?php }; if (get_sub_field ('filed1'));{ ?>
<div class = "class1">
<? php the_sub_field ('filed1'); ?>
</div>
<?php }; ?>
I have a loop in my view that outputs all the content gathered from the database:
<?php foreach($content as $contentRow): ?>
<?php
echo $contentRow->value;
?>
<?php endforeach; ?>
This works fine for HTML strings like:
<h2><strong>Example Text</strong></h2>
however I have some image content that I would like to display and I have tried the following database entries to no avail:
<img src="<?php echo site_url('pathToImage/Image.png'); ?>" alt="Cover">"
<img src="site_url('pathToImage/Image.png')" alt="Cover\">"
I feel like I am missing a step on how to use PHP values in this way.
How do I access the URL of the image and use that to show the image?
Full Code Edit
<?php
$CI =& get_instance();
?>
<div class="container">
<div class="row">
<div class="col-md-9">
<div class="col-md-2"></div>
<div class="col-md-20">
<!--<form class="form-center" method="post" action="<?php echo site_url(''); ?>" role="form">-->
<!-- <h2 class="">Title</h2>
<h2 class=""SubTitle/h2>-->
<?php echo $this->session->userdata('someValue'); ?>
<!--//<table class="" id="">-->
<?php foreach($content as $contentRow): ?>
<tr>
<td><?php
echo $contentRow->value;
?></td>
</tr>
<?php endforeach; ?>
<!--</table>-->
<!--</form>-->
</div>
<div class="col-md-2"></div>
</div>
</div>
</div><!-- /.container -->
and the values are being read out in $contentRow->value;
I have to verify this, but to me it looks like you are echo'ing a string with a PHP function. The function site_url() is not executed, but simply displayed. You can execute it by running the eval() function. But I have to add this function can be very dangerous and its use is not recommended.
Update:
To sum up some comments: The use of eval() is discouraged! You should reconsider / rethink your design. Maybe the use of tags which are replaced by HTML are a solution (Thanks to Manfred Radlwimmer). Always keep in mind to never trust the data you display, always filter and check!
I'm not going to accept this answer as #Philipp Palmtag's answer helped me out alot more and this is more supplementary information.
Because I'm reading data from the database it seems a sensible place to leave some information about what content is stored. In the same table that the content is stored I have added a "content type" field.
In my view I can then read this content type and render appropriately for the content that is stored. If it is just text I can leave it as HTML markup, images all I need to do is specify the file path and then I can scale this as I see fit.
I have updated my view to something akin to this and the if/else statement can be added to in the future if required:
<?php foreach($content as $contentRow): ?>
<?php if ($contentRow->type != "image"): ?>
<?php echo $contentRow->value; ?>
<?php else: ?>
<?php echo "<img src=\"".site_url($contentRow->value)."\">"; ?>
<?php endif; ?>
<?php endforeach; ?>
I am using Bootstrap but under the roots.io wordpress template using a 'wrapperless theme'
i am trying to achieve this http://roots.io/ - where there are sections of colour but the page content itself isn't full width.
the answer I have been given is to make the container class 100% - but this just makes all the content full width.
Im really stuck and ive been trying to figure this out for hours. - I know that sounds noobish and it is, but I can't get past this point.
all the page templates take their its style from base.php, code here
<?php get_template_part('templates/head'); ?>
<body <?php body_class(); ?>>
<!--[if lt IE 8]><div class="alert alert-warning"><?php _e('You are using an <strong>outdated</strong> browser. Please upgrade your browser to improve your experience.', 'roots'); ?></div><![endif]-->
<?php
do_action('get_header');
// Use Bootstrap's navbar if enabled in config.php
if (current_theme_supports('bootstrap-top-navbar')) {
get_template_part('templates/header-top-navbar');
} else {
get_template_part('templates/header');
}
?>
<div class="wrap container" role="document">
<div class="content row">
<div class="main <?php echo roots_main_class(); ?>" role="main">
<?php include roots_template_path(); ?>
</div><!-- /.main -->
<?php if (roots_display_sidebar()) : ?>
<aside class="sidebar <?php echo roots_sidebar_class(); ?>" role="complementary">
<?php include roots_sidebar_path(); ?>
</aside><!-- /.sidebar -->
<?php endif; ?>
</div><!-- /.content -->
</div><!-- /.wrap -->
<?php get_template_part('templates/footer'); ?>
</body>
</html>
so Im just not sure how to get past it in any of the page templates
About the first part of your question: "100% width colored parts".
Cause Bootstrap use the box-sizing: border-box model every html-element gets 100% width of its parent by default. So wrap your .container div's in other element (div, header, etc). This wrapper is a direct child of the body and gets 100% width. See: http://bootply.com/87196
<header role="banner" class="banner">
<div class="container" style="background-color:red;">
Header example
</div>
</header>
<div style="background-color:blue;">Elements get 100% width by default</div>
The second part about your page templates. The code you show use the get_template_part(). This function is a core function of WordPress. See http://codex.wordpress.org/Function_Reference/get_template_part#Using_loop.php_in_child_themes. You will find where your templates should be located.
But i think read http://roots.io/roots-101/#theme-templates first.
Thank you, I had a few solutions offered to me yesterday also, in case anyone else looks at this.
my own was simply to remove the .container class from the base.php file. - this just stopped the content of every page being constrained in a container by default. - this way I was able to add sections to the page at full browser width, and add .container inside them to constrain the actual content.
lines 16 and 17 of original base.php
<div class="wrap <?php if ( ! is_front_page() ): ?>container<?php endif; ?>" role="document">
<div class="content <?php if ( ! is_front_page() ): ?>row<?php endif; ?>">
In app.less
.home .main {
padding: 0;
}
Then add your sections like so:
<section class="semantic-section-class">
<div class="container">
<!-- your content -->
</div>
</section>
I have created a few php files Following are their names:
standard_head.php (which contains basic standard html code)
header.php
navbar.php
sidebar.php
footer.php
standard_footer.php (which contains closing html tags)
Page content will vary in every page and would also include html content.
I am trying to create a lot of php pages which will use all of the above pages directly.
Now I can use them directly using include statement for each of them, but I was wondering if it was possible to include all of them together with one just statement ?
<?php include('../includes/standard_head.php'); ?>
<?php include('includes/header.php'); ?>
<div id="wrapper">
<?php include('includes/nav.php'); ?>
<div id="content">
<!-- my page content -->
</div> <!-- end #content -->
<?php include('includes/sidebar.php'); ?>
</div> <!-- End #wrapper -->
<?php include('includes/footer.php'); ?>
<?php include('../includes/standard_footer.php'); ?>
You could so this (note that this is a very basic example and that I wouldn't use this myself without taking into account meta tags, page titles etc.)
template.php
<?php include('../includes/standard_head.php'); ?>
<?php include('includes/header.php'); ?>
<div id="wrapper">
<?php include('includes/nav.php'); ?>
<div id="content">
<?php echo $content; ?>
<!-- my page content -->
</div> <!-- end #content -->
<?php include('includes/sidebar.php'); ?>
</div> <!-- End #wrapper -->
<?php include('includes/footer.php'); ?>
<?php include('../includes/standard_footer.php'); ?>
Then, on a page (say index.php, for example):
index.php
<?php
$content = '<h1>Welcome</h1>';
include 'template.php';
?>
P.S: If you go down this route, make sure that you check out the Output Control Functions first.
Just create a PHP file that has a list of them i.e.
<?php include("this file");
include("the other file");
?>
And then just add that file.
Not really an answer to your question, but you could use a template engine like Twig.
http://twig.sensiolabs.org/
Try using more complex template system like Smarty or some MVC framework like Zend (this is not required but would allow you to create complex sources more easily) and then build script like this:
<?php include('../includes/standard_head.php'); ?>
<?php include('includes/header.php'); ?>
<div id="wrapper">
<?php include('includes/nav.php'); ?>
<div id="content">
<?php echo $menu->getCustomEntries(); ?>
</div>
Where $menu will be your custom object containing methods for displaying menus and submenus...
There is no straight way to include multiple files, as include / require functions except only one argument. though you can use following logic.
`#include_all_files.php
include('../includes/standard_head.php');
include('includes/header.php');
...
use above file in other files
include('includes/include_all_files.php');
`
I have a PHP page with HTML content in it. Now I run some PHP codes between HTMLs and I get some results. The fact is, when I try to get a respond from this page by AJAX it'll show me the whole page content and plus the result I was looking for. What can I do to prevent the page from writing extra content. I know whenever something get printed on page it'll go as respond to the AJAX call but I want a way to somehow fix this.
My page file (name: page.php):
<?php echo $Content->GetData('HEADER'); ?>
<div id="Content">
<div id="Page">
<?php if($Content->GetData('PAGE','IS_TRUE')) : ?>
<?php if(NULL !== $Content->GetData('PAGE','TITLE')) : ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeTitle"); ?>
<div id="Title" dir="rtl">
<?php echo $Content->GetData('PAGE','TITLE'); ?>
</div>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterTitle"); ?>
<?php endif; ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeContent"); ?>
<?php echo $Content->GetData('PAGE','CONTENT'); ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterContent"); ?>
</div>
</div>
<?php else : ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
There is no page like this in our archives.
</div>
</div>
<?php endif; ?>
</div>
</div>
<?php echo $Content->GetData('FOOTER'); ?>
If I write an address in my browser like this localhost/cload/blog?action=rate it'll go through my redirection list and show the page.php with blog plugin loaded. The problem is I want to call my blog plugin by AJAX through this address but it will first render the page data.
Sorry if this is messy.
I'd suggest modifying page.php to be some functions, primarily a data processing function, and then an output function. Then, when you load the page, put a check in for whether it's an AJAX request, and if so, echo the data you want as JSON, otherwise render the page using the output function.
Alternatively, you could create a second, separate page, but that could be more difficult to maintain than a single file.
Yes, you should check whether your request is a ajax request, if it is so you should change your response to return only the result whatever want.
This php code will give an rough idea on this.
if($request->isXmlHttpRequest()){
return new Response(json_encode($data_array));
}
Hope this will help.